MySQL: Create running sum for all dates in range? - mysql

I have a table Service, that stores records of sales and referral types that led to the sale. I need to know the total number of sales that resulted from a given referral type over a range of dates. The relevant data in Service looks like the following:
+------+-------+------------+
| uuid | sr_id | s_saledate |
+------+-------+------------+
| | 1 | 2020-01-01 |
| | 1 | 2020-01-01 |
| | 2 | 2021-01-01 |
| | 2 | 2021-01-01 |
| | 1 | 2021-01-01 |
+------+-------+------------+
I want to count the number of sales for each referral type (sr_id) in a given date range.
If my date range is 2020-01-01 thru 2021-01-01, my output should be something like:
+------+-------+------------+----------------------+
| uuid | sr_id | date | num_sales_as_of_date
+------+-------+-----------------------------------+
| | 1 | 2020-01-01 | 2 |
| | 1 | 2020-01-02 | 2 |
| | 1 | 2020-01-03 | 2 |
........................................................ < many rows for days in range
1 2021-01-01 | 3
| | 2 | 2020-01-01 | 0 |
| | 2 | 2020-01-02 | 0 |
........................................................ < many rows for days in range
| | 2 | 2020-01-01 | 2 |
+------+-------+-----------------------------------+
There should be a row for each referral type on each date in the range.
Right now my query looks like:
SELECT s.sr_id,
s.s_saledate AS date,
Count(s.uuid)
OVER (
partition BY s.sr_id
ORDER BY s.s_saledate) AS num_sales_as_of_date
FROM Service s
How do I get the running sum for each referral type on days that had no Service with that particular referral type id?
*** EDIT FOR CLARIFICATION***
For example, in the first table I give there is no Service row in the Service table with sr_id = '1' AND s_saledate === "2020-01-02". There were two rows from prior days where sr_id = '1'. (2020-01-01). My output row for "2020-01-02" is:
sr_id date num_sales_as_of_date
1 | 2020-01-02 | 2 |

You need to left join your Services table from a table with all the dates in the range and a table with all the referral types, so that you get a row with every combination of date and referral type:
WITH RECURSIVE dates AS (
SELECT date('2020-01-01') AS date
UNION ALL
SELECT dates.date + INTERVAL 1 DAY
FROM dates
WHERE dates.date <= '2020-01-05'
)
SELECT ServiceReferral.sr_id,
dates.date,
Count(s.uuid)
OVER (
partition BY ServiceReferral.sr_id
ORDER BY dates.date) AS num_sales_as_of_date
FROM dates
CROSS JOIN ServiceReferral
LEFT JOIN Service s ON s.s_saledate=dates.date AND s.sr_id=ServiceReferral.sr_id
fiddle
If you do this a lot, it may be more convenient to create an actual table dates with all the dates from 0000-01-01 to 9999-12-31 and use that instead (selecting dates in the desired range in the where clause).

Related

How to select rows with the latest date and calculate another field based on the row

I have two tables i.e vehicle and vehicle_maintenance.
vehicle
-----------------------------------
| v_id | v_name | v_no |
-----------------------------------
| 1 | car1 | car123 |
-----------------------------------
| 2 | car2 | car456 |
-----------------------------------
vehicle_maintenance
-----------------------------------------------------------------------
| v_main_id | v_id | v_main_date | v_main_remainder |
-----------------------------------------------------------------------
| 1 | 1 | 2020/10/10 | 1 |
| 2 | 1 | 2020/10/20 | 2 |
| 3 | 2 | 2020/10/04 | 365 |
| 4 | 2 | 2020/10/15 | 5 |
-----------------------------------------------------------------------
I want to get each car maintenance details i.e car2 maintenance date is 2020/10/15 and i want to check next maintenance date based on v_main_remainder field. That means next maintenance date will be 2020/10/20 ( add 5 day to the maintenance date). I want to also calculate the no of days left from next maintenance date. Suppose today is 2020/10/10 then it will show 10 days left.
Here is my query
SELECT
v.v_id,
v.v_name,
v.v_no,
max(vm.v_main_date) as renewal_date,
datediff(
DATE_ADD(
max(vm.v_main_date), INTERVAL +vm.v_main_remainder day
),
now()
) as day_left
FROM vehicle as v, vehicle_maintenance as vm
GROUP BY v.v_id
But the problem is vm.v_main_remainder in date_add function taken from first row.
Here is the result
-----------------------------------------------------------------------
| v_id | v_name | v_no | renewal_date | day_left |
-----------------------------------------------------------------------
| 1 | car1 | car123 | 2020/10/20 | 11 |
-----------------------------------------------------------------------
| 2 | car2 | car456 | 2020/10/15 | 370 |
-----------------------------------------------------------------------
As a starter, your query is obviously missing a join condition between the two tables, so that's a cartesian product. This type of problem is much easier to spot when using explicit joins.
Then: you want to filter on the latest maintenance record per car, so aggregation is not appropriate.
One option uses window functions, available in MySQL 8.0:
select v.v_id, v.v_name, v.v_no, vm.v_main_date as renewal_date,
datediff(vm.v_main_date + interval vm.v_main_remainder day, current_date) as day_left
from vehicle as v
inner join (
select vm.*, row_number() over(partition by v_id order by v_main_date desc) rn
from vehicle_maintenance
) as vm on vm.v_id = v.v_id
where vm.rn = 1
Note that I changed now() to current_date, so datediff() works consistently on dates rather than datetimes.

Sql check a value in column is greater than number of rows

i am building a web app where customer can book a service from a business(vendor). but first vendor need to add
what services he provide, where he able to deliver those services, and from which time (start time) to which time(end time) how many users is available
so i am confusing that suppose a customer book a service for some particular time and when another customer book a service from that vendor we need to calculate is the number of users available
in this time period is greater than count of already booking (which are not completed yet) in that particular time
i have these three table
users = (for both customer & vendors)
id | name | address | role_id
1 | Customer | some address | 1
2 | Vendor | Some Address | 2
3 | Another Customer | Some address | 1
4 | Another Vendor | address | 2
vendor_available_time = (only for vendor)
id | date_start_time | date_end_time | no_of_users |vendor_id
1 | 2019-10-16 00:00:00 | 2019-19-16 23:59:59 | 3 | 2
1 | 2019-10-16 09:00:00 | 2019-19-16 17:00:00 | 1 | 4
1 | 2019-10-17 00:00:00 | 2019-19-17 23:59:59 | 3 | 2
1 | 2019-10-17 09:00:00 | 2019-19-17 17:00:00 | 2 | 4
bookings = (for both)
id | booking_status | booking_datetime | customer_id | vendor_id
1 | job started | 2019-10-16 10:00:00 | 1 | 2
1 | completed | 2019-10-15 10:00:00 | 1 | 2
1 | accepted | 2019-10-16 09:00:00 | 3 | 2
1 | work in progress | 2019-10-16 09:00:00 | 3 | 2
please help me with a query
where i can get all vendors whose no_of_users is greater than count(bookings) where booking_datetime >= date_start_time and booking_datetime < date_end_time and booking_status is not in ['completed', 'rejected', 'cancelled']
Any suggestion will be really appreciated can i get those result from one query, should i use multiple queries or should i change my database structure
The output i want is just a user_ids whose are available for that time period and whose no of users is greater than already count of bookings for that time
Is this what you want?
Select b.vendor_id from
bookings b join vendor_available_time v on b.vendor_id=v.id
where b.booking_datetime >= v.date_start_time and
b.booking_datetime < v.date_end_time
and b.booking_status not in ['completed', 'rejected', 'cancelled']
group by b.vendor_id having count(distinct b.id) <=count(b.customer_id)

mysql - Calculating profit of sales between dates

I have a table that looks like this:
+--------+---------------------+-------+--------+-----------+
| PartNo | Date | Inv | Retail | Wholesale |
+--------+---------------------+-------+--------+-----------+
| 1 | 2018-05-12 00:00:00 | 15 | $100 | $90 |
| 2 | 2018-05-12 00:00:00 | 20 | $200 | $150 |
| 3 | 2018-05-12 00:00:00 | 25 | $300 | $200 |
| 1 | 2018-05-13 00:00:00 | 10 | $95 | $90 |
| 2 | 2018-05-14 00:00:00 | 15 | $200 | $150 |
| 3 | 2018-05-14 00:00:00 | 20 | $300 | $200 |
+--------+---------------------+-------+--------+-----------+
And I want it to look like this with a Mysql query:
+--------+------+--------+
| PartNo | Sold | Profit |
+--------+------+--------+
| 1 | 5 | $25 |
| 2 | 5 | $250 |
| 3 | 5 | $500 |
+--------+------+--------+
I need to group by PartNo while calculating the difference between totals and profits over a date range.
The unit profit has to be calculated by subtracting the wholesale from retail on the last day (or record) of the date range.
I feel like this should be easy but the differences over the date ranges are confusing me and handling records within the date range that don't start or end exactly on the date range input are losing me.
Any help would be super appreciated.
Thank you.
You can look up the situation at the start and at the end of the period If no start situation is found, assume no stock. If no end situation is found, that means no sales during the period.
For example for the period starting 2018-05-13 and ending 2018-05-14:
select parts.PartNo
, coalesce(FirstSale.Total, 0) - coalesce(LastSale.Total, FirstSale.Total, 0) as Sold
, (coalesce(FirstSale.Total, 0) - coalesce(LastSale.Total, FirstSale.Total, 0)) *
coalesce(LastSale.Retail - LastSale.Wholesale, 0) as Profit
from (
select PartNo
, max(case when Date < '2018-05-13' then Date end) as FirstEntry
, max(case when Date <= '2018-05-14' then Date end) as LastEntry
from Sales
group by
PartNo
) parts
left join
Sales FirstSale
on FirstSale.PartNo = parts.PartNo
and FirstSale.Date = parts.FirstEntry
left join
Sales LastSale
on LastSale.PartNo = parts.PartNo
and LastSale.Date = parts.LastEntry
Example at SQL Fiddle.
SELECT c.partno as partno,MAX(c.inv)-MIN(c.inv) as sold,SUM(CASE WHEN c.date = c.last_date THEN profit else 0 END)*(MAX(c.inv)-MIN(c.inv)) as profit
FROM (SELECT partno,date,inv,retail-wholesale as profit,MAX(date) OVER (partition by partno) AS last_date FROM test1)c
GROUP BY c.partno
ORDER BY c.partno;
Using the window function, first append a new column to track the max date for each partno. So the inner query inside FROM will produce rows like these with one column added to the the original dataset,
| 1 | 2018-05-12 00:00:00 | 15 | $100 | $90 | **2018-05-13 00:00:00** |
The highlighted field is the one added to the dataset which is the last date in the date range for that part number!
Now from this result, we can pull out profit by checking for the row in which date column is equal to the new column we appended, which is essentially calculating the profit for the last date by subtracting wholesale from retail and multiplying with items sold.
PS : The logic for items sold is grouping by partno and subtracting MIN(Inv) from MAX(Inv)
Link to SQL Fiddle

subtract 2 DB rows from each other for each unique partner_ID? MYSQL

I have a MYSQL table where I need to get to subtract values from 2 different rows.
This is my DB table:
Tablename: ext_partnertotals
| Partner_ID | Partnername | Month | Year | Total |
|------------|-------------|-------|------|-------|
| 1 | Partner 1 | 1 | 2018 | 10 |
| 1 | Partner 1 | 2 | 2018 | 12 |
| 2 | Partner 2 | 1 | 2018 | 18 |
| 2 | Partner 2 | 2 | 2018 | 12 |
It should get this with a query:
| Partner_ID | Partnername | up/down |
|------------|-------------|---------|
| 1 | Partner 1 | +2 |
| 2 | Partner 2 | -6 |
I need to get the Subtract value of 2 different months for each Partner.
Every Partner has a tablerow for each month and a value for that month.
Now I need to get If they went up or went down in value since the month before.
Can someone write me a query?
Since you're unable to improve your terrible schema, I recommend you use a (very ugly/hard to maintain and very slow) correlated subquery:
SELECT Partner_ID, Partnername, Year, Month, Total - (
SELECT Total
FROM ext_partnertotals AS prev
WHERE prev.Partner_ID = cur.Partner_ID AND CASE cur.Month
WHEN 1 THEN prev.Year = cur.Year - 1 AND prev.Month = 12
ELSE prev.Year = cur.Year AND prev.Month = cur.Month - 1
END
) AS `up/down` FROM ext_partnertotals AS cur
See it on sqlfiddle.

mysql query get range between date not from table

I have payment table info like this
ID Costumer | start_pay | Payment
1 | 2014-01-01 | 1.500
2 | 2013-12-01 | 900
that information they must pay every month, i want calculating it for range between start_pay to CURDATE
if CURDATE is 2014-03-01 (Y-m-d) the result I want like this
ID Costumer | start_pay | Payment | total_to_pay | month_count
1 | 2014-01-01 | 1.500 | 4.500 | 3
2 | 2013-12-01 | 900 | 3.600 | 4
can i do that with mysql query?
Try
SELECT *,TIMESTAMPDIFF(MONTH, DATE_SUB(start_pay,INTERVAL 1 MONTH), CURDATE()) AS
month_count,Payment * month_count AS total_to_pay FROM TABLE
Note that if the difference is less than a month it will output 0
PERIOD_DIFF is basically made for this type of calculation:
SELECT PERIOD_DIFF(DATE_FORMAT(CURDATE(),'%Y%m'), DATE_FORMAT(start_pay, '%Y%m')) from your table;