I have payment table info like this
ID Costumer | start_pay | Payment
1 | 2014-01-01 | 1.500
2 | 2013-12-01 | 900
that information they must pay every month, i want calculating it for range between start_pay to CURDATE
if CURDATE is 2014-03-01 (Y-m-d) the result I want like this
ID Costumer | start_pay | Payment | total_to_pay | month_count
1 | 2014-01-01 | 1.500 | 4.500 | 3
2 | 2013-12-01 | 900 | 3.600 | 4
can i do that with mysql query?
Try
SELECT *,TIMESTAMPDIFF(MONTH, DATE_SUB(start_pay,INTERVAL 1 MONTH), CURDATE()) AS
month_count,Payment * month_count AS total_to_pay FROM TABLE
Note that if the difference is less than a month it will output 0
PERIOD_DIFF is basically made for this type of calculation:
SELECT PERIOD_DIFF(DATE_FORMAT(CURDATE(),'%Y%m'), DATE_FORMAT(start_pay, '%Y%m')) from your table;
Related
I have a table Service, that stores records of sales and referral types that led to the sale. I need to know the total number of sales that resulted from a given referral type over a range of dates. The relevant data in Service looks like the following:
+------+-------+------------+
| uuid | sr_id | s_saledate |
+------+-------+------------+
| | 1 | 2020-01-01 |
| | 1 | 2020-01-01 |
| | 2 | 2021-01-01 |
| | 2 | 2021-01-01 |
| | 1 | 2021-01-01 |
+------+-------+------------+
I want to count the number of sales for each referral type (sr_id) in a given date range.
If my date range is 2020-01-01 thru 2021-01-01, my output should be something like:
+------+-------+------------+----------------------+
| uuid | sr_id | date | num_sales_as_of_date
+------+-------+-----------------------------------+
| | 1 | 2020-01-01 | 2 |
| | 1 | 2020-01-02 | 2 |
| | 1 | 2020-01-03 | 2 |
........................................................ < many rows for days in range
1 2021-01-01 | 3
| | 2 | 2020-01-01 | 0 |
| | 2 | 2020-01-02 | 0 |
........................................................ < many rows for days in range
| | 2 | 2020-01-01 | 2 |
+------+-------+-----------------------------------+
There should be a row for each referral type on each date in the range.
Right now my query looks like:
SELECT s.sr_id,
s.s_saledate AS date,
Count(s.uuid)
OVER (
partition BY s.sr_id
ORDER BY s.s_saledate) AS num_sales_as_of_date
FROM Service s
How do I get the running sum for each referral type on days that had no Service with that particular referral type id?
*** EDIT FOR CLARIFICATION***
For example, in the first table I give there is no Service row in the Service table with sr_id = '1' AND s_saledate === "2020-01-02". There were two rows from prior days where sr_id = '1'. (2020-01-01). My output row for "2020-01-02" is:
sr_id date num_sales_as_of_date
1 | 2020-01-02 | 2 |
You need to left join your Services table from a table with all the dates in the range and a table with all the referral types, so that you get a row with every combination of date and referral type:
WITH RECURSIVE dates AS (
SELECT date('2020-01-01') AS date
UNION ALL
SELECT dates.date + INTERVAL 1 DAY
FROM dates
WHERE dates.date <= '2020-01-05'
)
SELECT ServiceReferral.sr_id,
dates.date,
Count(s.uuid)
OVER (
partition BY ServiceReferral.sr_id
ORDER BY dates.date) AS num_sales_as_of_date
FROM dates
CROSS JOIN ServiceReferral
LEFT JOIN Service s ON s.s_saledate=dates.date AND s.sr_id=ServiceReferral.sr_id
fiddle
If you do this a lot, it may be more convenient to create an actual table dates with all the dates from 0000-01-01 to 9999-12-31 and use that instead (selecting dates in the desired range in the where clause).
I have a table that looks like this:
+--------+---------------------+-------+--------+-----------+
| PartNo | Date | Inv | Retail | Wholesale |
+--------+---------------------+-------+--------+-----------+
| 1 | 2018-05-12 00:00:00 | 15 | $100 | $90 |
| 2 | 2018-05-12 00:00:00 | 20 | $200 | $150 |
| 3 | 2018-05-12 00:00:00 | 25 | $300 | $200 |
| 1 | 2018-05-13 00:00:00 | 10 | $95 | $90 |
| 2 | 2018-05-14 00:00:00 | 15 | $200 | $150 |
| 3 | 2018-05-14 00:00:00 | 20 | $300 | $200 |
+--------+---------------------+-------+--------+-----------+
And I want it to look like this with a Mysql query:
+--------+------+--------+
| PartNo | Sold | Profit |
+--------+------+--------+
| 1 | 5 | $25 |
| 2 | 5 | $250 |
| 3 | 5 | $500 |
+--------+------+--------+
I need to group by PartNo while calculating the difference between totals and profits over a date range.
The unit profit has to be calculated by subtracting the wholesale from retail on the last day (or record) of the date range.
I feel like this should be easy but the differences over the date ranges are confusing me and handling records within the date range that don't start or end exactly on the date range input are losing me.
Any help would be super appreciated.
Thank you.
You can look up the situation at the start and at the end of the period If no start situation is found, assume no stock. If no end situation is found, that means no sales during the period.
For example for the period starting 2018-05-13 and ending 2018-05-14:
select parts.PartNo
, coalesce(FirstSale.Total, 0) - coalesce(LastSale.Total, FirstSale.Total, 0) as Sold
, (coalesce(FirstSale.Total, 0) - coalesce(LastSale.Total, FirstSale.Total, 0)) *
coalesce(LastSale.Retail - LastSale.Wholesale, 0) as Profit
from (
select PartNo
, max(case when Date < '2018-05-13' then Date end) as FirstEntry
, max(case when Date <= '2018-05-14' then Date end) as LastEntry
from Sales
group by
PartNo
) parts
left join
Sales FirstSale
on FirstSale.PartNo = parts.PartNo
and FirstSale.Date = parts.FirstEntry
left join
Sales LastSale
on LastSale.PartNo = parts.PartNo
and LastSale.Date = parts.LastEntry
Example at SQL Fiddle.
SELECT c.partno as partno,MAX(c.inv)-MIN(c.inv) as sold,SUM(CASE WHEN c.date = c.last_date THEN profit else 0 END)*(MAX(c.inv)-MIN(c.inv)) as profit
FROM (SELECT partno,date,inv,retail-wholesale as profit,MAX(date) OVER (partition by partno) AS last_date FROM test1)c
GROUP BY c.partno
ORDER BY c.partno;
Using the window function, first append a new column to track the max date for each partno. So the inner query inside FROM will produce rows like these with one column added to the the original dataset,
| 1 | 2018-05-12 00:00:00 | 15 | $100 | $90 | **2018-05-13 00:00:00** |
The highlighted field is the one added to the dataset which is the last date in the date range for that part number!
Now from this result, we can pull out profit by checking for the row in which date column is equal to the new column we appended, which is essentially calculating the profit for the last date by subtracting wholesale from retail and multiplying with items sold.
PS : The logic for items sold is grouping by partno and subtracting MIN(Inv) from MAX(Inv)
Link to SQL Fiddle
I need a complete count of each person_id from the database according to the date wise report
SELECT date, person_id, count(person_id)
FROM visits
group by date, person_id
I tried this one but this couldn't give the result what I expected.
Date | person_id| count(person_id)
2018-01-01 | 33000 | 10 |
2018-01-01 | 712000 | 111 |
2018-01-01 | 730000 | 30 |
2018-01-01 | 743000 | 5 |
2018-01-01 | 755000 | 123 |
you need total append to your query result? For example:
Date | person_id| count(person_id) | total
2018-01-01 | 33000 | 10 | 1000
2018-01-01 | 712000 | 111 | 1000
right? if so, I don't think it's a good idea only using sql query. On my case, I will query twice asynchronously，and then merge the result.
like this:
query1:
SELECT date, person_id, count(person_id)
FROM visits
group by date, person_id
query2:
SELECT count(person_id) as total
FROM visits
and then merge the results by program.
I have the following MySQL table:
+---------------------+-----------+
| timestamp | sensor_id |
+---------------------+-----------+
| 2010-04-09 01:42:31 | M049 |
| 2010-04-09 01:43:31 | M049 |
| 2010-04-09 01:44:31 | M049 |
| 2010-04-09 01:59:31 | M049 |
| 2010-04-10 01:10:31 | M049 |
| 2010-04-10 01:40:31 | M049 |
| 2010-04-10 01:42:31 | M049 |
| 2010-04-11 16:43:31 | M049 |
+---------------------+-----------+
I know how to query the db to get a count of the entries for a specific daytime intervall and group the result by date.
An example to query the event count between 1 am and 2 pm would look like this:
SELECT
date(timestamp) as date,
count(timestamp) as count
FROM
event_data
WHERE
EXTRACT(HOUR FROM TIME(timestamp)) BETWEEN 1 AND 14
GROUP BY
date
The query returns the following table:
+------------+-------+
| date | count |
+------------+-------+
| 2010-04-09 | 4 |
| 2010-04-10 | 3 |
+------------+-------+
Now I only want to count an event every 15 minutes.
The desired result would be:
+------------+-------+
| date | count |
+------------+-------+
| 2010-04-09 | 2 |
| 2010-04-10 | 2 |
+------------+-------+
How do I alter my query to get these results?
You have a good start to group by date and query for the hours you want. Similarly, you can write a query that gets the intervals. I would start by writing a case statement that reads each row you want, and adds a column specifying which interval of the hour it is. (0:14 - 1, 15:29 - 2...) like this:
SELECT timeCol,
HOUR(timeCol) AS hour,
CASE WHEN MINUTE(timeCol) BETWEEN 0 AND 14 THEN 1
WHEN MINUTE(timeCol) BETWEEN 15 AND 29 THEN 2
WHEN MINUTE(timeCol) BETWEEN 30 AND 44 THEN 3
ELSE 4 END AS minute
FROM myTable;
This gives you something like this:
| timeCol | hour | minute |
+---------------------+------+--------+
| 2010-04-09 01:42:31 | 1 | 3 |
| 2010-04-09 01:43:31 | 1 | 3 |
| 2010-04-09 01:44:31 | 1 | 3 |
Once you have that, you can select the distinct hour/minute pairs in each day, and that will give you what you want, as long as you use your WHERE clause accordingly:
SELECT DATE(timeCol) AS dateCol, COUNT(DISTINCT hour, minute) AS numEvents
FROM(
SELECT timeCol,
HOUR(timeCol) AS hour,
CASE WHEN MINUTE(timeCol) BETWEEN 0 AND 14 THEN 1
WHEN MINUTE(timeCol) BETWEEN 15 AND 29 THEN 2
WHEN MINUTE(timeCol) BETWEEN 30 AND 44 THEN 3
ELSE 4 END AS minute
FROM myTable) tmp
WHERE HOUR(timecol) BETWEEN 1 AND 14
GROUP BY dateCol;
Here is an SQL Fiddle example.
I would just like to add that you don't have to record the intervals as 1, 2, 3, 4. Make sure you use something readable, that will make sense to you again in the future. For example, maybe something like this would be better:
WHEN MINUTE(timeCol) BETWEEN 0 and 14 THEN 'firstInterval'...
I need help with a SQL statement. The goal is to count the amount of alarms of each date. My table looks something like this:
|----DATE----|---COUNTER---|---ALARM_ID---|
|2012-01-01 | 30 | 1 |
|2012-01-01 | 20 | 2 |
|2012-01-01 | 10 | 3 |
|2012-01-02 | 5 | 1 |
|2012-01-02 | 25 | 2 |
|2012-01-02 | 12 | 3 |
|2012-01-03 | 33 | 1 |
|2012-01-03 | 43 | 2 |
|2012-01-03 | 11 | 3 |
And I'm looking for a SQL statement that gives this result:
|----DATE----|---COUNTER---|
|2012-01-01 | 60 |
|2012-01-02 | 42 |
|2012-01-03 | 87 |
I've been working on this SELECT date, SUM(counter) FROM all_stats but all I get is:
|----DATE----|---COUNTER---|
|2012-01-01 | 60 |
Do I have to create a loop to go through all dates and count?
Thanks in advance, Steve-O
SELECT date, SUM(counter)
FROM all_stats
GROUP BY date
Try this instead
SELECT date, SUM(counter) FROM all_stats GROUP BY date;
"GROUP BY date" puts all the individual dates on a separate line and does the sum separately per date.
select date, sum(counter)
from all_stats
group by date