2 where conditions from 1 column SQL [duplicate] - mysql

Question

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How can I get multiple counts with one SQL query?
(12 answers)
Closed 2 months ago.
I am trying to see 2 conditional columns using the WHERE clause from 1 column.
For example:
I have a dataset where I have a long list of calls. I would like to see two different columns where the first column shows a count of all those calls who are equal or longer that 0 seconds and a second column that shows a count of all those calls that are equal or longer to 120 seconds.
That is my first query:
SELECT distinct year(date) Year, monthname(date) as Month, count(calls) Leads
FROM database.calls
where duration >= 120
and year(date) = 2022
group by month(date)
order by max(date);
second query:
(The only difference it's on the 3rd line where duration is equal to 0)
SELECT distinct year(date) Year, monthname(date) as Month, count(calls) Leads
FROM database.calls
where duration >= 0
and year(date) = 2022
group by month(date)
order by max(date);
Expected Result:
Year
Month
Calls(0sec)
Calls(120sec)
2022
January
654
521
2022
February
895
465
2022
March
562
321

Answer 1

For obtaining conditional sums you can use conditional aggregation: specify a condition inside your aggregate function, so that it aggregates only the eligible values.
SELECT YEAR(date) AS Year_,
MONTHNAME(date) AS Month_,
SUM(IF(duration > 0, 1, 0)) AS Calls0Sec,
SUM(IF(duration > 120, 1, 0)) AS Calls120Sec
FROM database.calls
WHERE YEAR(date) = 2022
GROUP BY YEAR(date), MONTHNAME(date)
ORDER BY MAX(date);
Note: you need to add every selected and non-aggregated field inside the GROUP BY clause, otherwise you can expect either DBMS errors or wrong data.