From this table
groupId
flag
flagValue
1
0
500
2
0
100
1
1
10
2
1
50
3
0
100
1
1
200
3
1
1000
2
1
50
I need this result
groupId
flag1
flag0
valFlag1
valFlag0
totalFlags
1
2
1
210
500
3
2
2
1
100
100
3
3
1
1
1000
100
2
where
flag1 is number of times flag is 1 for a particular group
flag0 is number of times flag is 0 for a particular group
valFlag1 is sum of flagVal when flag is 1
valFlag0 is sum of flagVal when flag is 0
totalFlags is sum of total flags associated with a group
I am stuck as to how to actually count values based on an IF condition.
Anyhelp is appreciated. Thanks.
I have used a table named group_table with your values
Try using this:
SELECT
g.`groupId`,
SUM(g.`flag`=1 ) AS flag1,
SUM(g.`flag`=0) AS flag0,
SUM(CASE WHEN g.`flag`=1 THEN g.`flagValue` ELSE 0 END) AS valFalg1,
SUM(CASE WHEN g.`flag`=0 THEN g.`flagValue` ELSE 0 END) AS valFalg0,
COUNT(*) AS totalFlags
FROM
`group_table` g
GROUP BY g.`groupId`
If you have to use the IF,
SELECT
g.`groupId`,
IF(g.`flag`=1,1,0 ) AS flag1,
IF(g.`flag`=0,1,0) AS flag0,
SUM(IF(g.`flag`=1,g.`flagValue`,0 )) AS valFalg1,
SUM(IF(g.`flag`=0,g.`flagValue`,0 )) AS valFalg0,
COUNT(*) AS totalFlags
FROM
`group_table` g
GROUP BY g.`groupId`, flag1, flag0
They'll produce the same result
Related
I have a table with millions of rows (SF_COLLECTIONS)
ID MEMBERID COLLECTIONID CARDID STATE (D / M) HOWMANY
1 1 1 1 D 1
2 1 1 2 D 2
3 2 1 1 M 1
4 2 1 2 M 1
5 2 2 3 D 1
6 1 2 3 M 2
and I want to know for every COLLECTIONID the SUM of HOWMANY field for STATE=D and STATE=M
So I try this approach
select COLLECTIONID,
sum(if(STATE='D',HOWMANY,0)) as HMD,
sum(if(STATE='M',HOWMANY,0)) as HMM
from SF_COLLECTIONS
group by COLLECTIONID
and it takes about 15 seconds to answer
Any suggestions to get better performances?
Thanks in advance
Please try this:
SELECT COLLECTIONID,
SUM(CASE WHEN STATE='D' THEN HOWMANY END) AS HMD,
SUM(CASE WHEN STATE='M' THEN HOWMANY END) AS HMM
FROM SF_COLLECTIONS
GROUP BY COLLECTIONID;
Duration / Fetch Time
0.00068 sec / 0.000012 sec
Your existing_query:
SELECT COLLECTIONID,
SUM(IF(STATE='D',HOWMANY,0)) AS HMD,
SUM(IF(STATE='M',HOWMANY,0)) AS HMM
FROM SF_COLLECTIONS
GROUP BY COLLECTIONID;
Duration / Fetch Time
0.00072 sec / 0.000012 sec
Only 6 rows there is 0.00004 difference :
For 10 million rows, I think It is noticeable:)
In the Data shown,we need to do a continuous pattern check of Leaves,
for eg:
CASE
WHEN count("Leaves") BETWEEN 1 AND 2 THEN '1-2'
WHEN count("Leaves") BETWEEN 3 AND 5 THEN '3-5'
WHEN count("Leaves") >5 THEN '>5'
ELSE 'Above 5' END AS "Leave Occurence",
On Jan 1st and 2nd employee has taken 2 leaves togather which belongs to
'1-2'Bucket,
similarly 8,9,10,11th JAN it is contineous for 4 Days hence in '3-4'Bucket
and contineously more than 5 Leaves belongs to [<5]Bucket
Now we need the count of each Bucket for Month wise.
Here 1-2Bucket is 2
3-4Bucket is 1
<5 Bucket is also 1
We used this code ,but it gives the SUM,But not checking the contineous pattern
Year Month Leaves
2011 1-Jan 1
2-Jan 1
3-Jan 0
4-Jan 0
5-Jan 0
6-Jan 0
7-Jan 0
8-Jan 1
9-Jan 1
10-Jan 1
11-Jan 1
12-Jan 0
13-Jan 0
14-Jan 0
15-Jan 1
16-Jan 1
17-Jan 1
18-Jan 1
19-Jan 1
20-Jan 1
21-Jan 0
22-Jan 0
23-Jan 1
24-Jan 1
You can identify each group of leaves by counting the number of non-leaves before it. Then you have aggregation:
select min(date), max(date), count(*) as numdays
from (select t.*,
(select count(*)
from t t2
where t2.date <= t.date and t2.leave = 0
) as grp
from t
where t.leave = 1
) t
group by grp;
You can then format the results however you like. This gives you one row per continuous "leave" period.
Let's say I have the following data.
id name_id completed
1 10 1
2 10 0
3 15 1
4 10 0
5 20 1
6 15 0
7 20 1
8 15 0
I'm trying to find a count by the name id, which is pretty simple
SELECT name_id, COUNT(*) FROM db
GROUP BY name_id
Now, I have a second component which I want to include in the query.
For name_id 10, I want to count just those values where completed is 1. For the other name_id's, I want to select them regardless of whether they are 0 or 1.
So I should end up with:
name_id count(*)
10 1
15 3
20 2
Name_id 10 only has a count of 1 because it's just the 1 which is completed, while the other counts include both 0 and 1.
Can anyone help with this task.
Thanks!
You can use a CASE expression inside of your aggregate function.
SELECT name_id,
sum(case
when name_id = 10
then case when completed = 1 then 1 else 0 end
else 1 end) Total
FROM db
GROUP BY name_id;
See SQL Fiddle with Demo.
Exclude the rows where name_id = 10 and completed = 0:
SELECT name_id, COUNT(*) FROM db
WHERE NOT (completed = 0 AND name_id = 10)
GROUP BY name_id
SELECT name_id, COUNT(*) FROM db
WHERE name_id != 10 or completed = 1
GROUP BY name_id
Count when name_id is not 10. If it is 10, count when completed = 1:
SELECT
name_id,
COUNT(CASE WHEN name_id <> 10 or completed = 1 THEN 1 END)
FROM db
GROUP BY name_id
I am trying to compare 2 rows and display the same ones.I did browse but was not able to find the right solution.
Table A
Count status Division
20 A 1
30 B 2
10 c 1
12 z 1
From the above table I want to display whose division is same.
Count status Division
20 A 1
10 c 1
12 z 1
Try this
Select * from TableA
Group By Division
Having Count(*) > 1
Select * from TableA
Group By Division
having Count(*) = 1
Here i used case statement , it worked for me
select CompanyCode ,'Commission Pec', Year
,sum(case when CommissionType='Commission Recevied' then JAN else 0 end)/sum(case when CommissionType='Net Payments from WM' and isnull(JAN,0)<>0 then JAN else 1 end)
from Commission_Consolidate
group by CompanyCode,Year
end
I'm trying to put together a MYSQL query that will count the number of Non-Null (or better yet, non-zero) values in select fields in a single row and then sort from lowest to highest (based on the count). For example, I have a table with 5 fields... ID, Name, Score_1, Score_2, Score_3. I want to count how many times the value "0" exists in Score_1, Score_2 and Score_3 for each record, then sort from most non zero values to least.
ID Name Score_1 Score_2 Score_3
1 Dan 8 7 0
2 Joe 0 0 3
3 Chris 0 0 0
4 Mike 4 5 5
I assume the query has to look something like this...
Select ID, Name, Score_1, Score_2, Score_3 where (???) ORDER BY (???)
Output should look like this (ID 4 is displayed first since it has the least amount of non-zero entries)...
ID Name Score_1 Score_2 Score_3
4 Mike 4 5 5
1 Dan 8 7 0
2 Joe 0 0 3
3 Chris 0 0 0
I'm somewhat new to mysql query's, so any help would be greatly appreciated. I thought the COUNT function would help, but that function appears to count columns from all rows. Perhaps there is a way to use the COUNT function and limit it to a singel row so it can be sorted by that row count?
This should do what you want:
SELECT ID, Name, Score_1, Score_2, Score_3
FROM Table1
ORDER BY (Score_1 = 0) + (Score_2 = 0) + (Score_3 = 0)
Result:
ID Name Score_1 Score_2 Score_3
4 Mike 4 5 5
1 Dan 8 7 0
2 Joe 0 0 3
3 Chris 0 0 0
try This:
Select id, Count1, Count2, Count3, Count4
From
(Select
Sum(Case When IsNull(Score_1,0) = 0 Then 1 Else 0 End) Count1,
Sum(Case When IsNull(Score_2,0) = 0 Then 1 Else 0 End) Count2,
Sum(Case When IsNull(Score_3,0) = 0 Then 1 Else 0 End) Count3,
Sum(Case When IsNull(Score_4,0) = 0 Then 1 Else 0 End) Count4
From Table
Group By Id) Z -- This column (Id) better not be the PK for this table!!!
Order By Count1 + Count2 + Count3 + Count4