I'm trying to put together a MYSQL query that will count the number of Non-Null (or better yet, non-zero) values in select fields in a single row and then sort from lowest to highest (based on the count). For example, I have a table with 5 fields... ID, Name, Score_1, Score_2, Score_3. I want to count how many times the value "0" exists in Score_1, Score_2 and Score_3 for each record, then sort from most non zero values to least.
ID Name Score_1 Score_2 Score_3
1 Dan 8 7 0
2 Joe 0 0 3
3 Chris 0 0 0
4 Mike 4 5 5
I assume the query has to look something like this...
Select ID, Name, Score_1, Score_2, Score_3 where (???) ORDER BY (???)
Output should look like this (ID 4 is displayed first since it has the least amount of non-zero entries)...
ID Name Score_1 Score_2 Score_3
4 Mike 4 5 5
1 Dan 8 7 0
2 Joe 0 0 3
3 Chris 0 0 0
I'm somewhat new to mysql query's, so any help would be greatly appreciated. I thought the COUNT function would help, but that function appears to count columns from all rows. Perhaps there is a way to use the COUNT function and limit it to a singel row so it can be sorted by that row count?
This should do what you want:
SELECT ID, Name, Score_1, Score_2, Score_3
FROM Table1
ORDER BY (Score_1 = 0) + (Score_2 = 0) + (Score_3 = 0)
Result:
ID Name Score_1 Score_2 Score_3
4 Mike 4 5 5
1 Dan 8 7 0
2 Joe 0 0 3
3 Chris 0 0 0
try This:
Select id, Count1, Count2, Count3, Count4
From
(Select
Sum(Case When IsNull(Score_1,0) = 0 Then 1 Else 0 End) Count1,
Sum(Case When IsNull(Score_2,0) = 0 Then 1 Else 0 End) Count2,
Sum(Case When IsNull(Score_3,0) = 0 Then 1 Else 0 End) Count3,
Sum(Case When IsNull(Score_4,0) = 0 Then 1 Else 0 End) Count4
From Table
Group By Id) Z -- This column (Id) better not be the PK for this table!!!
Order By Count1 + Count2 + Count3 + Count4
Related
From this table
groupId
flag
flagValue
1
0
500
2
0
100
1
1
10
2
1
50
3
0
100
1
1
200
3
1
1000
2
1
50
I need this result
groupId
flag1
flag0
valFlag1
valFlag0
totalFlags
1
2
1
210
500
3
2
2
1
100
100
3
3
1
1
1000
100
2
where
flag1 is number of times flag is 1 for a particular group
flag0 is number of times flag is 0 for a particular group
valFlag1 is sum of flagVal when flag is 1
valFlag0 is sum of flagVal when flag is 0
totalFlags is sum of total flags associated with a group
I am stuck as to how to actually count values based on an IF condition.
Anyhelp is appreciated. Thanks.
I have used a table named group_table with your values
Try using this:
SELECT
g.`groupId`,
SUM(g.`flag`=1 ) AS flag1,
SUM(g.`flag`=0) AS flag0,
SUM(CASE WHEN g.`flag`=1 THEN g.`flagValue` ELSE 0 END) AS valFalg1,
SUM(CASE WHEN g.`flag`=0 THEN g.`flagValue` ELSE 0 END) AS valFalg0,
COUNT(*) AS totalFlags
FROM
`group_table` g
GROUP BY g.`groupId`
If you have to use the IF,
SELECT
g.`groupId`,
IF(g.`flag`=1,1,0 ) AS flag1,
IF(g.`flag`=0,1,0) AS flag0,
SUM(IF(g.`flag`=1,g.`flagValue`,0 )) AS valFalg1,
SUM(IF(g.`flag`=0,g.`flagValue`,0 )) AS valFalg0,
COUNT(*) AS totalFlags
FROM
`group_table` g
GROUP BY g.`groupId`, flag1, flag0
They'll produce the same result
I want to have a sum of a column that is based if the value of another column is this/that. Here's my table structure
id leave_hours leave_type overtime_hours employee_id
1 7.6 1 0 3
2 5 2 0 3
3 0 0 2.3 3
I have this query already but I need to have a column that will only sum if leave type is 1 and if the leave type is 2
SELECT employee_id, SUM(overtime_hours) AS ot_hrs, SUM(leave_hours if leave_type == 1) AS
leave_1, SUM(leave_hours if leave_type == 2) AS leave_2
FROM table
GROUP BY employee_id
Result should be:
employee_id ot_hrs leave_1 leave_2
3 2.3 7.6 5
Thanks for your inputs.
You need to use conditional aggregation to sum the different leave_hours separately:
SELECT employee_id,
SUM(overtime_hours) AS ot,
SUM(CASE WHEN leave_type = 1 THEN leave_hours ELSE 0 END) AS leave_1,
SUM(CASE WHEN leave_type = 2 THEN leave_hours ELSE 0 END) AS leave_2
FROM `table`
GROUP BY employee_id
Output:
employee_id ot leave_1 leave_2
3 2.3 7.6 5
Demo on dbfiddle
Note that if you use floating point numbers to store the hours, you may need to ROUND the results.
you can use max() with case when
SELECT employee_id,
max(overtime_hours) AS ot,
max(CASE WHEN leave_type = 1 THEN leave_hours END) AS leave_1,
max(CASE WHEN leave_type = 2 THEN leave_hours END) AS leave_2
FROM table_name
GROUP BY employee_id
output
employee_id ot leave_1 leave_2
3 2.3 7.599999904632568 5
I have a column which has positive & negative numbers. Is it possible to have sum of all the positive numbers in Col1, negative numbers in Col2 and (Col1 - Col2) in Col3. Then sort by the last Col.
Current table New Table
ID Score ID Pos Neg Diff
1 3 3 5 0 5
1 1 1 4 1 3
1 -1 2 2 1 1
2 1
2 -1
2 1
3 3
3 1
3 1
This gives me the total but i would like to list the Pos and Neg numbers as well.
SELECT ID, SUM(Score) as total FROM results
GROUP BY ID ORDER BY total DESC
Just use a standard pivot query with separate conditional aggregations for the positive and negative numbers.
SELECT
ID,
SUM(CASE WHEN Score >= 0 THEN Score ELSE 0 END) AS Pos,
SUM(CASE WHEN Score < 0 THEN -1*Score ELSE 0 END) AS Neg,
SUM(Score) AS Diff
FROM results
GROUP BY ID
ORDER BY ID
Demo
I have this data:
id date userid result
1 2015-05-01 1 a
2 2015-05-02 1 b
3 2015-05-03 1 b
4 2015-05-03 1 a
5 2015-05-04 1 a
I need to get users sorted by result:
id a b
1 1 1
2 1 1
You want conditional aggregation:
SELECT user_id, sum(result = 'win') AS wins, sum(result = 'loss') as losses
FROM table
GROUP BY user_id
ORDER BY wins DESC
LIMIT 4;
I would do it like this:
SELECT user_id,
SUM(CASE WHEN result='win' THEN 1 ELSE 0 END) AS wins,
SUM(CASE WHEN result='loss' THEN 1 ELSE 0 END) AS losses
FROM table1
GROUP BY user_id
ORDER BY wins DESC
LIMIT 4
Fiddle is here: http://sqlfiddle.com/#!9/00ac7/8
Let's say I have the following data.
id name_id completed
1 10 1
2 10 0
3 15 1
4 10 0
5 20 1
6 15 0
7 20 1
8 15 0
I'm trying to find a count by the name id, which is pretty simple
SELECT name_id, COUNT(*) FROM db
GROUP BY name_id
Now, I have a second component which I want to include in the query.
For name_id 10, I want to count just those values where completed is 1. For the other name_id's, I want to select them regardless of whether they are 0 or 1.
So I should end up with:
name_id count(*)
10 1
15 3
20 2
Name_id 10 only has a count of 1 because it's just the 1 which is completed, while the other counts include both 0 and 1.
Can anyone help with this task.
Thanks!
You can use a CASE expression inside of your aggregate function.
SELECT name_id,
sum(case
when name_id = 10
then case when completed = 1 then 1 else 0 end
else 1 end) Total
FROM db
GROUP BY name_id;
See SQL Fiddle with Demo.
Exclude the rows where name_id = 10 and completed = 0:
SELECT name_id, COUNT(*) FROM db
WHERE NOT (completed = 0 AND name_id = 10)
GROUP BY name_id
SELECT name_id, COUNT(*) FROM db
WHERE name_id != 10 or completed = 1
GROUP BY name_id
Count when name_id is not 10. If it is 10, count when completed = 1:
SELECT
name_id,
COUNT(CASE WHEN name_id <> 10 or completed = 1 THEN 1 END)
FROM db
GROUP BY name_id