Get the middle value from query build on two select subqueries - mysql

Question

I have the following query:
select
qry1.product, qry1.date, qry2.monthly_income, qry1.monthly_cost,
round(qry2.monthly_income / qry1.monthly_cost) as x_ratio
from
(select
ap.product,
DATE_FORMAT(min(ai.date), '%m-%Y') as date,
ROUND(SUM(ai.ad_spend)) as monthly_cost
from
ad_insight ai
join
ads_products ap on ai.ad_id = ap.ad_id
group by
ap.product, YEAR(ai.date), MONTH(ai.date)) as qry1
inner join
(select
pi.name,
round(sum(pi.value)) as monthly_income,
DATE_FORMAT(min(pi.date), "%m-%Y") as date
from
product_insight pi
where
pi.name in (select distinct anp.product from ads_products anp)
group by
pi.name, YEAR(pi.date), MONTH(pi.date)) as qry2 on qry1.product = qry2.name and qry1.date = qry2.date;
I want to find the middle value of x_ratio(median of x_ratio) in the upper query.
Up till now, I have done something like this:
select qry1.product, round(avg(qry2.monthly_income/qry1.monthly_cost)) as x_ratio, count(qry1.date) as occurrences
from (
SELECT ap.product,
DATE_FORMAT(min(ai.date), '%m-%Y') as date,
ROUND(SUM(ai.ad_spend)) as monthly_cost
FROM ad_insight ai
JOIN ads_products ap ON ai.ad_id = ap.ad_id
GROUP BY ap.product, YEAR(ai.date), MONTH(ai.date)
) as qry1
inner join (
select pi.name,
round(sum(pi.value)) as monthly_income,
DATE_FORMAT(min(pi.date), "%m-%Y") as date
from product_insight pi
where pi.name in (select distinct anp.product from ads_products anp)
group by pi.name, YEAR(pi.date), MONTH(pi.date)
) as qry2 on qry1.product=qry2.name and qry1.date=qry2.date
group by qry1.product
order by x_ratio asc, occurrences desc;
As you can see I have used avg function, but in my case is not helpful, because x_ratio has a very wide spectrum of values.
Here you have fiddle
I want to result table look like this:
+---------+----------------+-------------+
| product | middle_x_ratio | occurrences |
+---------+----------------+-------------+
| prod2 | 1 | 1 |
| prod1 | 4 | 5 |
+---------+----------------+-------------+