Add two columns for sum of money by year - mysql

Question

Below is my query that groups my customers together, and sums their total money spent over the last two years. Works like a charm. However I need a little more which goes over my sql knowledge.
Is there any way to select three more columns and populate it with the money they spent for each of those years (2010, 2011, 2012)?
SELECT SUM(price) AS money_spent_total, co.customer_id, cu.first_name, cu.last_name, cu.email_primary, cu.phone_primary, co.date_paid
FROM customer_order AS co
INNER JOIN customer AS cu ON (cu.customer_id = co.customer_id)
WHERE cu.customer_id != 32518 AND co.date_paid > "2010-1-1" AND co.date_paid < "2013-1-1"
GROUP BY co.customer_id

Answer 1

You need to GROUP BY YEAR(date_paid) in addition to customer_id. You should also not be selecting any columns which are not in your GROUP BY. In addition, you can use the BETWEEN operator instead of > and < for your date range.
SELECT Year(co.date_paid),
co.customer_id,
Sum(price) AS money_spent_total
FROM customer_order AS co
INNER JOIN customer AS cu
ON ( cu.customer_id = co.customer_id )
WHERE cu.customer_id != 32518
AND co.date_paid BETWEEN '2010-01-01' AND '2013-01-01'
GROUP BY Year(co.date_paid),
co.customer_id
To get the columns in your original SELECT, you would do something like (not tested):
SELECT a.date_year_paid,
a.customer_id,
a.money_spent_total,
cu.first_name,
cu.last_name,
cu.email_primary,
cu.phone_primary
FROM (SELECT Year(co.date_paid) AS date_year_paid,
co.customer_id,
Sum(price) AS money_spent_total
FROM customer_order AS co
INNER JOIN customer AS cu
ON ( cu.customer_id = co.customer_id )
WHERE cu.customer_id != 32518
AND co.date_paid BETWEEN '2010-01-01' AND '2013-01-01'
GROUP BY Year(co.date_paid),
co.customer_id) a
LEFT JOIN customer cu
ON cu.customer_id = a.customer_id
If you were doing the INNER JOIN just for customer info, then it can be dropped.
SELECT a.customer_id,
a.date_year_paid,
a.money_spent_total,
cu.first_name,
cu.last_name,
cu.email_primary,
cu.phone_primary
FROM (SELECT customer_id, YEAR(date_paid) AS date_year_paid, SUM(price) AS money_spent_total
FROM customer_order
GROUP BY customer_id, YEAR(date_paid)) a
LEFT JOIN customer cu
ON cu.customer_id = a.customer_id
Lastly, if you want to group the years into columns:
SELECT a.customer_id,
a.y2010 AS '2010_money_paid',
a.y2011 AS '2011_money_paid',
a.y2012 AS '2012_money_paid',
cu.first_name,
cu.last_name,
cu.email_primary,
cu.phone_primary
FROM (SELECT customer_id,
Sum(CASE
WHEN Year(date_paid) = 2010 THEN price
ELSE 0
end) AS 'y2010',
Sum(CASE
WHEN Year(date_paid) = 2011 THEN price
ELSE 0
end) AS 'y2011',
Sum(CASE
WHEN Year(date_paid) = 2012 THEN price
ELSE 0
end) AS 'y2012'
FROM customer_order
GROUP BY customer_id) a
LEFT JOIN customer cu
ON cu.customer_id = a.customer_id
Result
| CUSTOMER_ID | 2010_MONEY_PAID | 2011_MONEY_PAID | 2012_MONEY_PAID | FIRST_NAME | LAST_NAME | EMAIL_PRIMARY | PHONE_PRIMARY |
------------------------------------------------------------------------------------------------------------------------------
| 1 | 9000 | 3000 | 2000 | Bob | Smith | bob#smith.com | 1112223333 |
| 2 | 4000 | 5000 | 1000 | Tom | Jones | tom#jones.com | 2223334444 |
See the demo