SQLAlchemy session handling in desktop application - sqlalchemy

I'd like some advice about SQLAlchemy session handling in a single user desktop (PyQt5) application.
The application is a music player where track data is stored in the database. Key is that the application has a concept of "next track" and will need to retrieve data (path, length, title, etc) when that track is played. The next track may be changed at any time by the user.
Currently, the application wraps functions using the ORM in a with Session() as session: context manager. That means that if the application stores the "next track" object, that object is detached when it is needed later.
Options:
wrap object access in an if object not in session: and add() it or get() it if necessary.
set expire_on_commit to False
start a session when the application starts and hold that session open indefinitely
Is any one of those alternatives better/worse that the others? Have I missed a better way of handling this?

Related

Foundry Workshop - Prevent duplicate data entry

I am building a Workshop App which will be used for data entry by a large number of operational staff members (> 200).
I would like to implement the following set-up:
The staff will enter the data on existing Ontology Objects. To facilitate this, I embedded a Foundry Form into the Object View, and set-up a corresponding write-back data set.
The Ontology Objects in question will be displayed in an Object Table in Workshop.
The staff member will select an Object from the Object Table.
The selected Object will be opened in an Object View.
The staff member will enter data on the Object View (Foundry Form being displayed here).
I need to make sure that no concurrent data entry can/will happen. How can I achieve this?
I am thinking about removing any Object which is opened in the Object View from the Object Table, but I am not sure if this is the best solution to the problem or how to achieve the removal from the table.
I am assuming that this must be a common problem and there would be a Design Pattern/Standard Functionality to solve this.
You'll have the best behavior here if you replace your Foundry Form with Foundry Actions. These actions are defined in the Ontology Management App and provide a more robust security model for managing object edits and are more tightly integrated into the various object-layer tools in Foundry.
Then in your Object View, rather than using the Foundry Forms widget, choose to create a new "Workshop-backed" Object View tab - this option is under the dropdown next to the New Tab button - and within the Workshop module use the Inline Action Form to embed the action form that you've configured in the Ontology Management App, supplying the variable representing the current object as the default for the object parameter in the Action.
With regards to simultaneous edits, in Actions, when the form is populated (i.e. when that tab is opened), the version of the underlying object(s) are registered. When the edit request is submitted, the current version of the object is checked, and if the version is different (i.e. there have been edits applied since the form was loaded) the user will be presented with message to the effect that the object has been updated and the edits will not be applied.
This protects against the case of a user overwriting a near-simultaneous edit without reviewing the changes first and does so at the writeback layer, rather than with logic in your application front-end.
There is not currently an approach to reflect real-time user interaction between two Workshop sessions. For instance, there is no way for the session of User A to "know" that User B has opened Object X in their session and is making a change.
If you wanted to do something for a bit of convenience or display signaling, you could create a small object type related to your main object - something like "Edit Lock" that looks like:
| id | primary_object_id | user_id | timestamp | timeout
And then in your Workshop app, there's a button above the table that says "Edit Selected Object".
When you click this button, you trigger an Action to create a new "edit lock" object populated with the current user and the current timestamp and say a timeout of 15 minutes from now.
Then in the object view for the primary object in question, on the same tab where you have the edit form embedded, you can create a variable that gets the edit locks associated with that object via a search around and use a Function to create a boolean variable if there is an "active" edit lock. And use this to conditionally show a banner to the user or otherwise give them a visual indication that another user has indicated they're making changes.
This won't push to the other session, and it'd be just for display purposes, the real protection still comes from the underlying object versioning that Actions enforces, but it might be a nice user affordance to layer on top if you really expect to commonly run into this situation.

How to find out the availability status of a Web API from a Windows Store application

I have a Line-of-Business (LoB) Windows 8.1 Store application I developed for a client. The client side-loads it on several Windows 10 tablets. They use it in an environment where WiFi is spotty at best and they would like to get some sort of notification inside the app, regardless of what page they are on, notification that will let them know that they've lost connectivity to the network. I have created a method on my Web API that is not hitting the repository (database). Instead, it quickly returns some static information regarding my Web API, such as version, date and time of the invocation and some trademark stuff that I'm required to return. I thought of calling this method at precise intervals of time and when there's no response, assume that the Web API connectivity is lost. In my main page, the first one displayed when the application is started, I have the following stuff in the constructor of my view model:
_webApiStatusTimer = new DispatcherTimer();
_webApiStatusTimer.Tick += OnCheckWebApiStatusEvent;
_webApiStatusTimer.Interval = new TimeSpan(0, 0, 30);
_webApiStatusTimer.Start();
Then, the event handler is implemented like this:
private async void OnCheckWebApiStatusEvent(object sender, object e)
{
// stop the timer
_webApiStatusTimer.Stop();
// refresh the search
var webApiInfo = await _webApiClient.GetWebApiInfo();
// add all returned records in the list
if (webApiInfo == null)
{
var messageDialog = new MessageDialog(#"The application has lost connection with the back-end Web API!");
await messageDialog.ShowAsync();
// restart the timer
_webApiStatusTimer.Start();
}
}
When the Web API connection is lost, I get a nice popup message that informs me that the Web API is no longer available. The problem I have is that after a while, especially if I navigate away from the first page but not necessary, I get an UnauthorizedAccessException in my application.
I use the DispatcherTimer since my understanding is that this is compatible with
UI threads, but obviously, I still do something wrong. Anyone cares to set me on the right path?
Also, if you did something similar and found a much better approach, I'd love to hear about your solution.
Thanks in advance,
Eddie
First, If you are using Windows Store Apps, then you could possibly use a Background task to check poll for the status of the web api instead of putting this responsibility on your view model, its not the viewmodels concern
Second, if you are connecting from your Windows store app to your API then one successful authentication/ authorization for the first time, how and where do you store the token (assuming you are using token authentication). If you are (and ideally you should), is there a timer that you start which is set to the token expiration time? Is your local storage getting flushed somehow and loosing the aurthorization data?
Need more information.

Passing back value from Browse-Child VM chain to caller

MVVMCross
Windows Store
Android
I have a VM that browses a hierarchy (BrowseVm) and supports forward navigation via
ShowViewModel<LeafDetailVM>
to a leaf detail ViewModel (LeafDetailVM).
When the user is on the LeafDetail View they should be able to say "I want this one" and they will be returned to the View that initiated BrowseVm.
I cannot simply Forward Navigate to the Initiator because that would leave me with an invalid back stack. I cannot have the BrowseVM view as a NoHistory page as I need it be in the back stack to support going back from the LeafDetail view.
My plan is to have the initiator start BrowseVm with a GUID. BrowseVm will pass that GUID onto LeafDetailVM.
In the "I want this one" command I will raise a Message, containing the GUID, that both BrowseVM and the initiator are subscribed to. Then I will close LeafDetailVM.
When BrowseVM receives the notification of the message it will compare the GUID and if it matches it will close itself.
When the initiator receives the notification it will deal with the now chosen data.
Does this make sense? Have I missed a much simpler way of doing this?
This is similar to How to pass a parameter from a viewmodel to its parent viewmodel but that does not deal with the back stack.
Thanks
I suggest you try stop mentally coupling how the views work on a platform to the view-models.
With the custom presenter mechanism in MvvmCross, in the app (platform specific code) you can handle navigation to a certain view-model in different ways, including closing views, modify backstack, etc.
You can interpret navigation to a view-model in whatever way you want \ need.
You can for example pass from view-model some parameters in the ShowViewModel request which the view-presenter (IMvxViewPresenter) can interpret in different ways in the Show() to display a view-model.
In your case, you can actually navigate to initiator VM passing the selected info. In the view presenter, you can modify the backstack in the way you need.
On Android, make sure you read and know about all LaunchMode flags, for example LaunchMode.SingleTask which allows you bring the initiator activity to front without creating a new one.
It's not clear to me, is BrowseVm a parent view-model to the LeafDetailVM?
More info would be needed to understand exactly your scenario.

dojo jsonrest store with periods of no internet connectivity

At the moment I don't know if this is a Dojo issue, a browser issue, or both.
I have a dojo.store.JsonRest data store of items:
//Create stores
var json = new JsonRest(options);
//Memory store
var memory = Observable(new Memory({}));
//Observable cache
var cache = new Cache(json, memory);
The store of items may be shared with different users simultaneously, so the store is periodically updated by issuing something like:
store.query({..})
When I want to add a new item to it, I use
dojo.xhr('POST',{
url:...,
postData:...,
handleAs:'json',
headers:{...},
failOk:true,
timeout:15*1000
});
This works fine. However, I would like to gracefully handle the case when the post occurs during the loss of an internet connection. In particular, I do not want the store to automatically try to post again when a connection is established again; I want the user to retry manually.
In Chrome, it appears that the POST is aborted, and regardless of an internet connection being subsequently established again, the deferred object from the POST appears to be discarded, and the new item is never added to the datastore.
In Firefox, it appears that the POST is aborted. But when the datastore is refreshed, e.g. by invoking:
store.query({...})
the new item, whose POST was aborted, is then added to the store. It's as if the query() call is quietly adding the new item to the datastore when an internet connection is established again.
I'm not observing this behavior in Chrome. And in order to get uniform behavior across different browsers, I would like to know if there is a way to ensure that once a POST is aborted, it's existence and memory is completely obliterated in Firefox.
I'm not sure why you have a separate method of adding an item to the store?
When you do a get on the Cache, if the item does not exist in the memory store, then a request is made by the JsonRest store and the returned item is stored in the memory store. There should be no need to do a separate xhr request, infact query() calls on the cache always go through the JsonRest store, you'd need to override the caches query function to make it check the memory store first. If you just want to add to the store, then a put or add would suit your needs, and do what your xhr post is doing.
Also if you are not happy with the way failed requests are handled by the JsonRest store, just extend it and override its get, query, add, remove or put function(s), handling request responses in your own way.

AngularJS form wizard save progress

I have a service in AngularJS that generates all the steps needed, the current state of each step (done, current, show, etc) and an associated directive that actually implements the service and displays the data of the service. But, there are 2 steps that are divided in 4 and 3 steps each:
Step one
Discounts
Activities
Duration
Payment Length
Step two
Identification
Personal data
Payment
How can I "save" the state of my form in case the person leaves the site and comes back later? Is it safe to use localStorage? I'm no providing support for IE6 or 7. I thought of using cookies, but that can end up being weak (or not)
Either local storage or cookies should be fine. I doubt this will be an issue, but keep in mind that both have a size limit. Also, it goes without saying that the form state will only be restored if the user returns on the same browser, and without having deleted cookies / local storage.
Another option could be to save the information server side. If the user is signed in, you can make periodic AJAX calls with the data and store the state on the server. When the user finishes all steps, you can make an AJAX call telling the server to delete any saved data it might have. This allows you to restore state even if the user returns on a different browser, as long as he is signed in.
Regardless of what direction you go with this, you can use jQuery's serialize method to serialize the form into a string and save it using your choice of storage.