i have this following table
id kelurahan status
1 Pegambiran Netral
2 Pegambiran Netral
3 Kejaksan Positif
4 Kesenden Positif
5 Pegambiran Negatif
i want to get result like this
kelurahan count_positif count_netral count_negatif total
Pegambiran 0 2 1 3
Kejaksan 1 0 0 1
Kesenden 1 0 0 1
i tried this query
SELECT kelurahan,
(SELECT COUNT(status) FROM tbl_monitoring WHERE status = 'Positif' GROUP BY kelurahan LIMIT 1) AS count_positif,
(SELECT COUNT(status) FROM tbl_monitoring WHERE status = 'Netral' GROUP BY kelurahan) AS count_netral,
(SELECT COUNT(status) FROM tbl_monitoring WHERE status = 'Negatif' GROUP BY kelurahan) AS count_negatif,
COUNT(kelurahan) AS total
FROM tbl_monitoring GROUP BY kelurahan
i get the result like this
any help would be appreciated, thanks.
You should use SUM, not COUNT.
Tested on dbfiddle
SELECT
kelurahan,
SUM(CASE WHEN status = 'Positif' THEN 1 ELSE 0 END) AS count_positif,
SUM(CASE WHEN status = 'Netral' THEN 1 ELSE 0 END) AS count_netral,
SUM(CASE WHEN status = 'Negatif' THEN 1 ELSE 0 END) AS count_negatif,
SUM(1) AS total
FROM tbl_monitoring
GROUP BY kelurahan;
Related
Im trying to write a query that returns a count depending on the value of a feedback field that ranges from 0-5 (0 meaning that it was not rated).
I want:
Count of all rows ( anything rated 1 or greater)
Count of all rows rated as 1 (anything = 1)
And all rows rated as 1 and also is the first iteration of a given task (anything rated =1 and iteration = 0)
I have written this query but I am getting the same value for all counts:
select
DATE_FORMAT(created_at,'%M') as Month,
COUNT(CASE WHEN rate > 0 THEN 1 ELSE 0 END) AS total,
COUNT(CASE WHEN rate = 1 THEN 1 ELSE 0 END) AS Rated_1,
COUNT(CASE WHEN client_feedback = 1 AND index = 0 THEN 1 ELSE 0 END) AS first_iteration_rated_1
from tablexxx
where created_at between date('2022-04-01') and date('2022-10-01')
GROUP BY Month
Try to use SUM() instead of COUNT().
Count() will count up regardless of the value being 0 or 1.
you can have two approaches:
method 1: use NULL in else part of the CASE
select
DATE_FORMAT(created_at,'%M') as Month,
COUNT(CASE WHEN rate > 0 THEN 1 ELSE null END) AS total,
COUNT(CASE WHEN rate = 1 THEN 1 ELSE null END) AS Rated_1,
COUNT(CASE WHEN client_feedback = 1 AND index = 0 THEN 1 ELSE null END) AS first_iteration_rated_1
from tablexxx
where created_at between date('2022-04-01') and date('2022-10-01')
GROUP BY Month
method 2: use sum instead of count
select
DATE_FORMAT(created_at,'%M') as Month,
SUM(CASE WHEN rate > 0 THEN 1 ELSE 0 END) AS total,
SUM(CASE WHEN rate = 1 THEN 1 ELSE 0 END) AS Rated_1,
SUM(CASE WHEN client_feedback = 1 AND index = 0 THEN 1 ELSE 0 END) AS first_iteration_rated_1
from tablexxx
where created_at between date('2022-04-01') and date('2022-10-01')
GROUP BY Month
I have a table as follows
table_user
id name status flag country
====================================================================================================
1 AB 1 0 US
2 BC 1 0 UK
3 CD 0 0 IN
4 DE 3 0 BR
5 EF 3 0 UK
6 FG 2 0 IN
7 GH 4 0 IN
I want to count the no. of records where
status = 1 as totalactiverecords,
status = 0 as totalinactiverecords,
status = 3 as totalrecentactiverecords,
status = 2 as totalemailnotverifiedrecords,
status = 4 as totalemailverifiedrecords,
, and country is UK, all in a single SELECT statement.
Is there any specific way to do it?
I have thought of something like
SELECT COUNT(*) as totalactiverecords WHERE status=1
COUNT(*) as totalinactiverecordsWHERE status=0,
COUNT(*) as totalemailnotverifiedrecords WHERE status=2,
COUNT(*) as totalrecentactiverecords WHERE status=3,
COUNT(*) as totalemailverifiedrecords WHERE status=4
FROM table_user where country=IN
,but that does not seem to work.
You can try this query:
SELECT count(case status when '1' then 1 else null end) as totalactiverecords,
count(case status when '0' then 1 else null end) as totalinactiverecords,
count(case status when '2' then 1 else null end) as totalemailnotverifiedrecords,
count(case status when '3' then 1 else null end) as totalrecentactiverecords,
count(case status when '4' then 1 else null end) as totalemailverifiedrecords
FROM table_user where country='IN'
I usually use CASE WHEN in this kind of problem:
SELECT sum(case when status = 1 then 1 end) as totalactiverecords,
COUNT sum(case when status = 0 then 1 end) as totalinactiverecords,
COUNT sum(case when status = 2 then 1 end) as totalemailnotverifiedrecord,
COUNT sum(case when status = 3 then 1 end) as totalrecentactiverecords,
COUNT sum(case when status = 4 then 1 end) as totalemailverifiedrecords
FROM table_user where country=IN
i have a query like below
select project_task_id,
status_id,
sum(case when StatusID=1 then 1 else 0 end) as task_id=1,
sum(case whenStatusID=2 then 1 else 0 end) as task_id=2,
sum(case when StatusID=3 then 1 else 0 end) as task_id=3,
sum(case when StatusID=4 then 1 else 0 end) as task_id=4,
sum(case when StatusID=5 then 1 else 0 end) as task_id=5,
sum(case when StatusID=6 then 1 else 0 end) as task_id=6,
sum(case when StatusID=7 then 1 else 0 end) as task_id=7,
from"Projects".work_unit_status
group by project_task_id,status_id;
I'm getting the below attached output:
https://i.stack.imgur.com/1wfD1.png
and I want to get the below expected output:
https://i.stack.imgur.com/Zql9z.png
include zero's if the status_id is blank
please any one help on this
Try this: use the addition of all sum column
select project_task_id,status_id,
isnull(sum(case when StatusID=1 then 1 else 0 end),0)+
isnull(sum(case whenStatusID=2 then 1 else 0 end),0) +
isnullsum(case when StatusID=3 then 1 else 0 end),0) +
isnullsum(case when StatusID=4 then 1 else 0 end),0)+
isnullsum(case when StatusID=5 then 1 else 0 end),0) +
isnullsum(case when StatusID=6 then 1 else 0 end),0) +
isnullsum(case when StatusID=7 then 1 else 0 end),0) as count_status
from"Projects".work_unit_status group by project_task_id,status_id
use in with your case
with t1 as (
select project_task_id,
status_id,
sum(case when StatusID in (1,2,3,4,5,6,7) then 1 else 0)
as sum_s
from "Projects".work_unit_status
group by project_task_id,status_id
) ,
t2 as
(
select * from (
select 1 as statusid
union
select 2
union
select 3
union
select 4
union
select 5
union
select 6
union
select 7 ) t
) select t1.project_task_id,
t2.statusid,
case when t1.sum_s>0 or not null
then sum_s else 0 end as total
t2 full join t1 on t2.statusid=t1.status_id
Without knowing the exact table structure I assumed that status_id and statusId refer to the same column. (If they are different columns, we need to use StatusId in the COUNT.)
Based on the expected output, you want to count the status_id and group by project_task_id. To make sure that every status is represented for every task, first, we need to create a subquery of all possible project_task_id/status_id combinations. Then we use that with the aggregate values of the original table.
select
ps.project_task_id,
ps.status_id,
count(w.status_id) as total
from (
select distinct
project_task_id,
s.status_id
from work_unit_status
cross join (select distinct status_id from work_unit_status) s
) ps
left join work_unit_status w
on ps.project_task_id = w.project_task_id and ps.status_id = w.status_id
group by
ps.project_task_id,
ps.status_id
If you really need to hardcode the statuses from 1 to 7, use the query below.
select
ps.project_task_id,
ps.status_id,
count(w.status_id) as total
from (
select distinct
project_task_id,
s.status_id
from work_unit_status
cross join (
select 1 as status_id
union select 2
union select 3
union select 4
union select 5
union select 6
union select 7
) s
) ps
left join work_unit_status w
on ps.project_task_id = w.project_task_id and ps.status_id = w.status_id
group by
ps.project_task_id,
ps.status_id
order by
ps.project_task_id,
ps.status_id
Given SQL: Is there a way to bring in the total of the result set?
SELECT
SUM(CASE
WHEN status = 3 THEN 1
ELSE 0
END) AS Open,
SUM(CASE
WHEN status = 4 THEN 1
ELSE 0
END) AS Close
FROM
Table1
WHERE
id = 2;
Result:
Open,Close
5,5
Desired Result:
Open,Close,Total
5,5,10
just add another case statement
SELECT
SUM(CASE
WHEN status = 3 THEN 1
ELSE 0
END) AS Open,
SUM(CASE
WHEN status = 4 THEN 1
ELSE 0
END) AS Close
SUM(CASE
WHEN status IN (3, 4) THEN 1
ELSE 0
END) AS Total
FROM
Table1
WHERE
id = 2;
You can use a CTE:
WITH sumCase AS (
SELECT
SUM(CASE
WHEN status = 3 THEN 1
ELSE 0
END) AS Open,
SUM(CASE
WHEN status = 4 THEN 1
ELSE 0
END) AS Close
FROM
Table1
WHERE
id = 2;)
SELECT Open,Close, Open + Close AS Total FROM Table1;
http://www.mysqltutorial.org/mysql-cte/
using sub-query
select open,close,open+close as total from
(
SELECT
SUM(CASE WHEN status = 3 THEN 1
ELSE 0
END ) AS Open,
SUM(CASE WHEN status = 4 THEN 1
ELSE 0
END) AS Close
FROM
Table1
WHERE id = 2 ) as T
Say I have a table called votes, and a column in that table called vote_type which can either be 0 or 1. How can I fetch the COUNT of vote_type where vote_type is 1?
Right now, I can select the count of vote_type overall, but not the count of vote_type where it is 1 or 0, via this query:
SELECT COUNT(votes.vote_id) AS vote_count
FROM votes
WHERE <some condition>
ORDER BY vote_count
How can I select the total number of vote_types, the number of vote_types = 1, the number of vote_types = 0, and the total vote_value (votetypes = 1 minus votetypes = 0), and order it by the total vote_value?
EDIT: Note that 1 & 0 are not intrinsic values of a vote, but boolean expressions for a positive vote and a negative vote.
I don't know what exactly are you trying to do, but if you want to count all the votes with Vote_Type=1
try
SELECT COUNT(votes.vote_id) AS vote_count
FROM votes
WHERE votes.vote_type=1
or if you need to sum the votes
SELECT SUM(votes.vote_type) AS vote_sum
FROM votes
WHERE votes.vote_type=1
SELECT COUNT(*) TotalVotes,
SUM(CASE WHEN vote_type = 1 THEN 1 ELSE 0 END) TotalVoteOne,
SUM(CASE WHEN vote_type = 0 THEN 1 ELSE 0 END) TotalVoteZero,
SUM(CASE WHEN vote_type = 1 THEN 1 ELSE 0 END) -
SUM(CASE WHEN vote_type = 0 THEN 1 ELSE 0 END) TotalVoteValue
FROM votes
-- WHERE ....
-- ORDER ....
When you say order it by the total vote_value -- it actually doesn't makes sense since the total number of rows in the result is only one.
You can also wrap this in a subquery,
SELECT TotalVotes,
TotalVoteOne,
TotalVoteZero,
(TotalVoteOne - TotalVoteZero) AS TotalVoteValue
FROM
(
SELECT COUNT(*) TotalVotes,
SUM(CASE WHEN vote_type = 1 THEN 1 ELSE 0 END) TotalVoteOne,
SUM(CASE WHEN vote_type = 0 THEN 1 ELSE 0 END) TotalVoteZero
FROM tableName
-- WHERE ....
-- ORDER BY TotalVoteValue DESC
) a
Try to start with something like this:
SELECT SUM(CASE WHEN votetype = 1 then 1 else 0 end) AS vote_count_1,
SUM(CASE WHEN votetype = 0 then 1 else 0 end) AS vote_count_0
FROM votes
WHERE <some condition>
ORDER BY vote_count
Edit: Added a net_vote column, which I think is the "vote1 minus vote0" number you are after.
Select
Sum(Case v.vote_type When 1 then 1 else -1 end) as net_vote
From
Votes v
Where
<some condition>
I've removed the order by, because this is only going to return one row.
$query = "SELECT *FROM votes WHERE vote_type=1 || vote_type=0";
$result = mysql_query($query);
$row = mysql_fetch_assoc($result);
$WhereVoteIsOne=$row['vote_type'];
foreach ($WhereVoteIsOne as $votesCount) { echo $votesCount."<br/>";}