Say I have a table called votes, and a column in that table called vote_type which can either be 0 or 1. How can I fetch the COUNT of vote_type where vote_type is 1?
Right now, I can select the count of vote_type overall, but not the count of vote_type where it is 1 or 0, via this query:
SELECT COUNT(votes.vote_id) AS vote_count
FROM votes
WHERE <some condition>
ORDER BY vote_count
How can I select the total number of vote_types, the number of vote_types = 1, the number of vote_types = 0, and the total vote_value (votetypes = 1 minus votetypes = 0), and order it by the total vote_value?
EDIT: Note that 1 & 0 are not intrinsic values of a vote, but boolean expressions for a positive vote and a negative vote.
I don't know what exactly are you trying to do, but if you want to count all the votes with Vote_Type=1
try
SELECT COUNT(votes.vote_id) AS vote_count
FROM votes
WHERE votes.vote_type=1
or if you need to sum the votes
SELECT SUM(votes.vote_type) AS vote_sum
FROM votes
WHERE votes.vote_type=1
SELECT COUNT(*) TotalVotes,
SUM(CASE WHEN vote_type = 1 THEN 1 ELSE 0 END) TotalVoteOne,
SUM(CASE WHEN vote_type = 0 THEN 1 ELSE 0 END) TotalVoteZero,
SUM(CASE WHEN vote_type = 1 THEN 1 ELSE 0 END) -
SUM(CASE WHEN vote_type = 0 THEN 1 ELSE 0 END) TotalVoteValue
FROM votes
-- WHERE ....
-- ORDER ....
When you say order it by the total vote_value -- it actually doesn't makes sense since the total number of rows in the result is only one.
You can also wrap this in a subquery,
SELECT TotalVotes,
TotalVoteOne,
TotalVoteZero,
(TotalVoteOne - TotalVoteZero) AS TotalVoteValue
FROM
(
SELECT COUNT(*) TotalVotes,
SUM(CASE WHEN vote_type = 1 THEN 1 ELSE 0 END) TotalVoteOne,
SUM(CASE WHEN vote_type = 0 THEN 1 ELSE 0 END) TotalVoteZero
FROM tableName
-- WHERE ....
-- ORDER BY TotalVoteValue DESC
) a
Try to start with something like this:
SELECT SUM(CASE WHEN votetype = 1 then 1 else 0 end) AS vote_count_1,
SUM(CASE WHEN votetype = 0 then 1 else 0 end) AS vote_count_0
FROM votes
WHERE <some condition>
ORDER BY vote_count
Edit: Added a net_vote column, which I think is the "vote1 minus vote0" number you are after.
Select
Sum(Case v.vote_type When 1 then 1 else -1 end) as net_vote
From
Votes v
Where
<some condition>
I've removed the order by, because this is only going to return one row.
$query = "SELECT *FROM votes WHERE vote_type=1 || vote_type=0";
$result = mysql_query($query);
$row = mysql_fetch_assoc($result);
$WhereVoteIsOne=$row['vote_type'];
foreach ($WhereVoteIsOne as $votesCount) { echo $votesCount."<br/>";}
Related
i have this following table
id kelurahan status
1 Pegambiran Netral
2 Pegambiran Netral
3 Kejaksan Positif
4 Kesenden Positif
5 Pegambiran Negatif
i want to get result like this
kelurahan count_positif count_netral count_negatif total
Pegambiran 0 2 1 3
Kejaksan 1 0 0 1
Kesenden 1 0 0 1
i tried this query
SELECT kelurahan,
(SELECT COUNT(status) FROM tbl_monitoring WHERE status = 'Positif' GROUP BY kelurahan LIMIT 1) AS count_positif,
(SELECT COUNT(status) FROM tbl_monitoring WHERE status = 'Netral' GROUP BY kelurahan) AS count_netral,
(SELECT COUNT(status) FROM tbl_monitoring WHERE status = 'Negatif' GROUP BY kelurahan) AS count_negatif,
COUNT(kelurahan) AS total
FROM tbl_monitoring GROUP BY kelurahan
i get the result like this
any help would be appreciated, thanks.
You should use SUM, not COUNT.
Tested on dbfiddle
SELECT
kelurahan,
SUM(CASE WHEN status = 'Positif' THEN 1 ELSE 0 END) AS count_positif,
SUM(CASE WHEN status = 'Netral' THEN 1 ELSE 0 END) AS count_netral,
SUM(CASE WHEN status = 'Negatif' THEN 1 ELSE 0 END) AS count_negatif,
SUM(1) AS total
FROM tbl_monitoring
GROUP BY kelurahan;
We have a table with data from different nodes and one of the column will have status report as "compliant or non-compliant", sample data as below
I want to filter the table in such a way that if any of the checks on a node shows non compliant, it should be flagged as non-compliant and rest as compliant. Using below query i am able to do it
SELECT COUNT(*) AS total_nodes,
SUM(fully_compliant = 0) AS Non_compliant_nodes,
SUM(fully_compliant = 1) AS compliant_nodes
FROM (
SELECT Node, CASE WHEN SUM(Status = 'Compliant') = COUNT(*) THEN 1 ELSE 0 END AS fully_compliant
FROM your_table GROUP BY Node
)
Now, i want to group and split the result by dept as below, how can i achieve this
I think you're looking for this:
select dept,
count(*) as total_nodes,
sum(case when non_compliant_chk = 0 then 1 else 0 end) as compliant_nodes,
sum(case when non_compliant_chk > 0 then 1 else 0 end) as non_compliant_nodes
from (
select dept,
node,
sum(case when 'Non-Compliant' then 1 else 0 end) as non_compliant_chk
from your_table
group by dept,
node
) v
group by dept;
With few modifications to what Brian suggested, I am able to get the desired result
select dept,
count(*) as total_nodes,
sum(case when non_compliant_chk = 0 then 1 else 0 end) as compliant_nodes,
sum(case when non_compliant_chk > 0 then 1 else 0 end) as non_compliant_nodes
from (
select dept,
node,
COUNT(CASE WHEN Compliance-Status = 'Non-Compliant' THEN 1 END) 'non_compliant_chk'
from table WHERE DOR >= DATE(NOW()) - INTERVAL 7 DAY
group by Dept,
Node
) v
group by Dept;
i have a query like below
select project_task_id,
status_id,
sum(case when StatusID=1 then 1 else 0 end) as task_id=1,
sum(case whenStatusID=2 then 1 else 0 end) as task_id=2,
sum(case when StatusID=3 then 1 else 0 end) as task_id=3,
sum(case when StatusID=4 then 1 else 0 end) as task_id=4,
sum(case when StatusID=5 then 1 else 0 end) as task_id=5,
sum(case when StatusID=6 then 1 else 0 end) as task_id=6,
sum(case when StatusID=7 then 1 else 0 end) as task_id=7,
from"Projects".work_unit_status
group by project_task_id,status_id;
I'm getting the below attached output:
https://i.stack.imgur.com/1wfD1.png
and I want to get the below expected output:
https://i.stack.imgur.com/Zql9z.png
include zero's if the status_id is blank
please any one help on this
Try this: use the addition of all sum column
select project_task_id,status_id,
isnull(sum(case when StatusID=1 then 1 else 0 end),0)+
isnull(sum(case whenStatusID=2 then 1 else 0 end),0) +
isnullsum(case when StatusID=3 then 1 else 0 end),0) +
isnullsum(case when StatusID=4 then 1 else 0 end),0)+
isnullsum(case when StatusID=5 then 1 else 0 end),0) +
isnullsum(case when StatusID=6 then 1 else 0 end),0) +
isnullsum(case when StatusID=7 then 1 else 0 end),0) as count_status
from"Projects".work_unit_status group by project_task_id,status_id
use in with your case
with t1 as (
select project_task_id,
status_id,
sum(case when StatusID in (1,2,3,4,5,6,7) then 1 else 0)
as sum_s
from "Projects".work_unit_status
group by project_task_id,status_id
) ,
t2 as
(
select * from (
select 1 as statusid
union
select 2
union
select 3
union
select 4
union
select 5
union
select 6
union
select 7 ) t
) select t1.project_task_id,
t2.statusid,
case when t1.sum_s>0 or not null
then sum_s else 0 end as total
t2 full join t1 on t2.statusid=t1.status_id
Without knowing the exact table structure I assumed that status_id and statusId refer to the same column. (If they are different columns, we need to use StatusId in the COUNT.)
Based on the expected output, you want to count the status_id and group by project_task_id. To make sure that every status is represented for every task, first, we need to create a subquery of all possible project_task_id/status_id combinations. Then we use that with the aggregate values of the original table.
select
ps.project_task_id,
ps.status_id,
count(w.status_id) as total
from (
select distinct
project_task_id,
s.status_id
from work_unit_status
cross join (select distinct status_id from work_unit_status) s
) ps
left join work_unit_status w
on ps.project_task_id = w.project_task_id and ps.status_id = w.status_id
group by
ps.project_task_id,
ps.status_id
If you really need to hardcode the statuses from 1 to 7, use the query below.
select
ps.project_task_id,
ps.status_id,
count(w.status_id) as total
from (
select distinct
project_task_id,
s.status_id
from work_unit_status
cross join (
select 1 as status_id
union select 2
union select 3
union select 4
union select 5
union select 6
union select 7
) s
) ps
left join work_unit_status w
on ps.project_task_id = w.project_task_id and ps.status_id = w.status_id
group by
ps.project_task_id,
ps.status_id
order by
ps.project_task_id,
ps.status_id
I want to get results for likes by a specific user-id and all likes and dislikes of a specific page id.
My structure looks like this:
`pages`: (id, title)
`pages_likes`: (id, page_id, uid, status)
If the status is -1 it's a dislike of a specific page, if it's 1 it's a like.
So, to get all likes this is my query:
SELECT COUNT(id) FROM pages_likes WHERE status = '1'
But now I also want to get if user-id 3 for example likes this page with
SELECT COUNT(id) FROM pages_likes WHERE status = '1' AND uid='3'
How can I achieve both in one query? I guess there has to be changed something right after the SELECT statement?
If you want to do this in a single query, use conditional aggregation:
SELECT SUM(CASE WHEN uid = '3' THEN 1 ELSE 0 END) AS threeLikes,
SUM(CASE WHEN uid <> '3' THEN 1 ELSE 0 END) AS otherLikes
FROM pages_likes
WHERE status = '1'
Another option would be to use a UNION, cf. the answer given by #bernie
Update:
If you want page likes and dislikes in the same query, you can try:
SELECT SUM(CASE WHEN uid = '3' AND status = '1' THEN 1 ELSE 0 END) AS threeLikes,
SUM(CASE WHEN uid <> '3' AND status = '1' THEN 1 ELSE 0 END) AS otherLikes
SUM(CASE WHEN uid = '3' AND status = '0' THEN 1 ELSE 0 END) AS threeDislikes,
SUM(CASE WHEN uid <> '3' AND status = '0' THEN 1 ELSE 0 END) AS otherDisikes
FROM pages_likes
I think this would work:
SELECT '' user, COUNT(id) likes
FROM pages_likes
WHERE status = '1'
GROUP BY 1
UNION ALL
SELECT uid user, COUNT(id) likes
FROM pages_likes
WHERE status = '1' AND uid='3'
GROUP BY 1
I would do it this way:
SELECT COUNT(*) AS total_likes, SUM(uid=3) AS uid3_likes
FROM pages_likes
WHERE status=1 AND page_id=1234
Re your comment:
Here's an example of showing total likes, and total dislikes. It's similar to the answer from #TimBiegeleisen.
SELECT SUM(status=1) AS total_likes,
SUM(CASE WHEN uid=3 AND status=1 THEN 1 END) AS uid3_likes
SUM(CASE WHEN uid=3 AND status=-1 THEN 1 END) AS uid3_dislikes
FROM pages_likes
WHERE page_id=1234
This question already has answers here:
Is there an alternative to TOP in MySQL?
(4 answers)
Closed 6 years ago.
SELECT
user_id,
count(*) total,
sum(case when type = 'yes' then 1 else 0 end) as type_1,
sum(case when type = 'no' then 1 else 0 end) as type_2
FROM history
GROUP by user_id
How get TOP 100 rows from this query which have max count type = 'yes' ?
You can use LIMIT to limit the number of results and use an ORDER BY to order it so the results are in descending order of total.
SELECT
user_id,
count(*) total,
sum(case when type = 'yes' then 1 else 0 end) as type_1,
sum(case when type = 'no' then 1 else 0 end) as type_2
FROM history
GROUP by user_id
ORDER BY type_1 DESC
LIMIT 100
You should add WHERE statement to your query to add conditional statement
Also, I can see that you are using mysql, so that means you should order your data by argument descending and limit result to 100
SELECT
user_id,
count(*) total,
sum(case when type = 'yes' then 1 else 0 end) as type_1,
sum(case when type = 'no' then 1 else 0 end) as type_2
FROM history
WHERE type='yes'
GROUP by user_id
ORDER BY total DESC
LIMIT 100
SELECT
user_id,
count(*) total,
sum(case when type = 'yes' then 1 else 0 end) as type_1,
sum(case when type = 'no' then 1 else 0 end) as type_2
FROM history
GROUP by user_id
ORDER by type_1 DESC
LIMIT 100