How to get calculated data from one column in database - mysql

Question

im new in sql. I cannot get data with format what i want in one step. Now i'm using more sql commands. I want to get all data in one command because i cant to connect them in subquery with group by. Somebodys can help me?
example of Table i have:
id
order_id
order_status
1
1
0
2
1
0
3
1
0
4
1
1
5
1
1
6
2
0
7
2
0
8
2
1
Table i want to have after sql query:
order_id
count
of
progress(%)
1
2
5
40
2
1
3
33
queries i use:
SELECT order_id, COUNT(status) as count
FROM `orders`
WHERE status = 1
GROUP by order_id;
SELECT order_id, COUNT(status) as of
FROM `orders`
GROUP by order_id;
SELECT order_id,
CAST((SELECT COUNT(status) FROM `orders` WHERE status = 1) /
(SELECT COUNT(status) FROM `orders`) *100 as int) AS progress FROM orders
group by order_id;
but last working properly only if i use where to single order id.
I want to make this data in one sql query to format i showed up.
Thanks a lot guys!

Answer 1

You don't need subqueries to do this, SQL's ordinary aggregate functions already work as you want with your group by clause:
SELECT order_id,
SUM(order_status) AS `count`,
COUNT(*) AS `of`,
SUM(order_status) / COUNT(order_status) * 100 as `progress`
FROM orders
group by order_id;
See example at http://sqlfiddle.com/#!9/d1799db/4/0

Answer 2

you need to use multiple subqueries
here's a query that I used and worked on your example on the onecompiler.com website
-- create
CREATE TABLE EMPLOYEE (
order_id INTEGER,
order_status INTEGER
);
-- insert
INSERT INTO EMPLOYEE VALUES (1,0 );
INSERT INTO EMPLOYEE VALUES (1, 0);
INSERT INTO EMPLOYEE VALUES (1, 0);
INSERT INTO EMPLOYEE VALUES (1, 1);
INSERT INTO EMPLOYEE VALUES (1,1 );
INSERT INTO EMPLOYEE VALUES (2, 0);
INSERT INTO EMPLOYEE VALUES (2, 0);
INSERT INTO EMPLOYEE VALUES (2, 1);
select *
from EMPLOYEE;
SELECT order_id, count, off , count/off
from(
select distinct order_id as order_id,
(select count(order_id) from EMPLOYEE C WHERE A.order_id=C.order_id AND order_status =1) as 'count',
(select count(order_id) from EMPLOYEE B WHERE A.order_id=B.order_id ) as 'off'
FROM EMPLOYEE A
) AA
;

Answer 3

You need to use sum and count with group by.
create table orders(
id int,
order_id int,
order_status int);
insert into orders values
(1,1,0),
(2,1,0),
(3,1,0),
(4,1,1),
(5,1,1),
(6,2,0),
(7,2,0),
(8,2,1);
select
order_id,
sum(order_status) count,
count(order_id) "of",
(100 * sum(order_status))
/ count(order_id) progress
from orders
group by order_id
order by order_id;
order_id | count | of | progress
-------: | ----: | -: | -------:
1 | 2 | 5 | 40.0000
2 | 1 | 3 | 33.3333
db<>fiddle here

Answer 4

i was described my problem without some details, w i want to join with other table but i see only record with status
oders_details
| id | order_describe | order_date |
|:----:|:--------------:|:----------:|
| 1 | sample 1 | 2022-02-28 |
| 2 | sample 2 | 2022-02-28 |
| 3 | sample 3 | 2022-03-01 |
| 4 | sample 4 | 2022-03-02 |
orders_status
| id | order_id |order_status|
|:---:|:---------------:|:----------:|
| 1 | 1 | 0 |
| 2 | 1 | 0 |
| 3 | 1 | 0 |
| 4 | 1 | 1 |
| 5 | 1 | 1 |
| 6 | 2 | 0 |
| 7 | 2 | 0 |
| 8 | 2 | 1 |
table i want after query
orders_view
| id |order_id|order_describe| order_date | count | of | progress |
|-----|--------|--------------|------------|-------|----|:--------:|
| 1 | 1 | sample 1 | 2022-02-28| 2 | 5 | 40 |
| 2 | 2 | sample 2 | 2022-02-28| 1 | 3 | 33 |
| 3 | 3 | sample 3 | 2022-03-01| null |null| null |
| 4 | 4 | sample 4 | 2022-03-02| null |null| null |
i want to get some hint what i have todo, to get finally table or view, not complete solution, to better understand sql lang