I don't know if the question wording is correct or not, but I want to do the following:
I have a table named sales It contain following columns:
------------------------------------------------
| PRODUCT_NAME | PRODUCT_QUANTITY | ExpierDate |
------------------------------------------------
if I SELECT * FROM sales then the result will be :
------------------------------------------------
| PRODUCT_NAME | PRODUCT_QUANTITY | ExpierDate |
------------------------------------------------
| TestName | 5 | 2021-6-12 |
| TestName | 2 | 2024-10-18 |
------------------------------------------------
What I need to do is to select query and get the result look like this :
------------------------------------------------
| PRODUCT_NAME | PRODUCT_QUANTITY | ExpierDate |
------------------------------------------------
| TestName | 1 | 2021-6-12 |
| TestName | 2 | 2021-6-12 |
| TestName | 3 | 2021-6-12 |
| TestName | 4 | 2021-6-12 |
| TestName | 5 | 2021-6-12 |
| TestName | 1 | 2024-10-18 |
| TestName | 2 | 2024-10-18 |
------------------------------------------------
Is this even possible ?
How can I do this..!?
I would recommend directly using a recursive CTE:
with recursive cte as (
select product_name, product_quantity, expire_date, 1 as n
from sales s
union all
select product_name, product_quantity, expire_date, n + 1
from cte
where n < product_quantity
)
select *
from cte
order by product_name, product_quantity, expire_date, n;
Here is a db<>fiddle.
As I mention in comment, with cte create pseudo data to fill up the row is really easy:
with RECURSIVE quan(quantity) AS (
SELECT 1
UNION ALL
SELECT quantity+1 FROM quan WHERE quantity < 10 --you may have to increase this
)
SELECT tb.PRODUCT_NAME ,quan.quantity as PRODUCT_QUANTITY,tb.ExpierDate
FROM [tb] -- your result table
JOIN quan on tb.PRODUCT_QUANTITY >= quan.quantity
ORDER BY tb.time,quan.quantity
here is db<>fiddle with pseudo data.
using int column as time column in pseudo data but I think query itself will still work.
In recursive cte you may have to increase the where part to create more pseudo quantity data depend on your max quantity.
Related
im new in sql. I cannot get data with format what i want in one step. Now i'm using more sql commands. I want to get all data in one command because i cant to connect them in subquery with group by. Somebodys can help me?
example of Table i have:
id
order_id
order_status
1
1
0
2
1
0
3
1
0
4
1
1
5
1
1
6
2
0
7
2
0
8
2
1
Table i want to have after sql query:
order_id
count
of
progress(%)
1
2
5
40
2
1
3
33
queries i use:
SELECT order_id, COUNT(status) as count
FROM `orders`
WHERE status = 1
GROUP by order_id;
SELECT order_id, COUNT(status) as of
FROM `orders`
GROUP by order_id;
SELECT order_id,
CAST((SELECT COUNT(status) FROM `orders` WHERE status = 1) /
(SELECT COUNT(status) FROM `orders`) *100 as int) AS progress FROM orders
group by order_id;
but last working properly only if i use where to single order id.
I want to make this data in one sql query to format i showed up.
Thanks a lot guys!
You don't need subqueries to do this, SQL's ordinary aggregate functions already work as you want with your group by clause:
SELECT order_id,
SUM(order_status) AS `count`,
COUNT(*) AS `of`,
SUM(order_status) / COUNT(order_status) * 100 as `progress`
FROM orders
group by order_id;
See example at http://sqlfiddle.com/#!9/d1799db/4/0
you need to use multiple subqueries
here's a query that I used and worked on your example on the onecompiler.com website
-- create
CREATE TABLE EMPLOYEE (
order_id INTEGER,
order_status INTEGER
);
-- insert
INSERT INTO EMPLOYEE VALUES (1,0 );
INSERT INTO EMPLOYEE VALUES (1, 0);
INSERT INTO EMPLOYEE VALUES (1, 0);
INSERT INTO EMPLOYEE VALUES (1, 1);
INSERT INTO EMPLOYEE VALUES (1,1 );
INSERT INTO EMPLOYEE VALUES (2, 0);
INSERT INTO EMPLOYEE VALUES (2, 0);
INSERT INTO EMPLOYEE VALUES (2, 1);
select *
from EMPLOYEE;
SELECT order_id, count, off , count/off
from(
select distinct order_id as order_id,
(select count(order_id) from EMPLOYEE C WHERE A.order_id=C.order_id AND order_status =1) as 'count',
(select count(order_id) from EMPLOYEE B WHERE A.order_id=B.order_id ) as 'off'
FROM EMPLOYEE A
) AA
;
You need to use sum and count with group by.
create table orders(
id int,
order_id int,
order_status int);
insert into orders values
(1,1,0),
(2,1,0),
(3,1,0),
(4,1,1),
(5,1,1),
(6,2,0),
(7,2,0),
(8,2,1);
select
order_id,
sum(order_status) count,
count(order_id) "of",
(100 * sum(order_status))
/ count(order_id) progress
from orders
group by order_id
order by order_id;
order_id | count | of | progress
-------: | ----: | -: | -------:
1 | 2 | 5 | 40.0000
2 | 1 | 3 | 33.3333
db<>fiddle here
i was described my problem without some details, w i want to join with other table but i see only record with status
oders_details
| id | order_describe | order_date |
|:----:|:--------------:|:----------:|
| 1 | sample 1 | 2022-02-28 |
| 2 | sample 2 | 2022-02-28 |
| 3 | sample 3 | 2022-03-01 |
| 4 | sample 4 | 2022-03-02 |
orders_status
| id | order_id |order_status|
|:---:|:---------------:|:----------:|
| 1 | 1 | 0 |
| 2 | 1 | 0 |
| 3 | 1 | 0 |
| 4 | 1 | 1 |
| 5 | 1 | 1 |
| 6 | 2 | 0 |
| 7 | 2 | 0 |
| 8 | 2 | 1 |
table i want after query
orders_view
| id |order_id|order_describe| order_date | count | of | progress |
|-----|--------|--------------|------------|-------|----|:--------:|
| 1 | 1 | sample 1 | 2022-02-28| 2 | 5 | 40 |
| 2 | 2 | sample 2 | 2022-02-28| 1 | 3 | 33 |
| 3 | 3 | sample 3 | 2022-03-01| null |null| null |
| 4 | 4 | sample 4 | 2022-03-02| null |null| null |
i want to get some hint what i have todo, to get finally table or view, not complete solution, to better understand sql lang
resulttable:
+-------------+-----------+
| resultSetID | projectID |
+-------------+-----------+
| 1 | 1 |
| 1 | 2 |
| 1 | 3 |
| 2 | 1 |
| 2 | 2 |
| 3 | 1 |
| 3 | 2 |
| 3 | 3 |
+-------------+-----------+
Query:
SELECT
COUNT( projectID )
FROM
resulttable
WHERE
projectID = 3
... correctly returns 2. However, I want the counts of each ID without using the WHERE condition, how do I do that?
Do you just want group by?
SELECT projectId, COUNT( * )
FROM resulttable
GROUP BY projectID;
The following query is used to get all the data for the projectId but if you want to get a specific query data without where you can use having instead
SELECT projectId, COUNT( * )
FROM resulttable
GROUP BY projectId having projectId = 3;
The following query should work for you:
SELECT projectID, SUM(resultSetID)
FROM resulttable
GROUP BY projectID;
Hi everybody,
I have this visitors table:
ID | Date | Purpose
1 | 20/10/2016 | Purpose1
2 | 22/10/2016 | Purpose1
3 | 25/10/2016 | Purpose2
4 | 12/11/2016 | Purpose1
5 | 14/11/2016 | Purpose2
6 | 16/11/2016 | Purpose2
Currently I'm using this query:
select case
when date like '%/10/2016' then '10/2016'
when date like '%/11/2016' then '11/2016'
end as month, count(*) as total
from visitors
where
date like '%/10/2016'
or date like '%/11/2016'
GROUP by month
I can only get month and total column count from query above. How can I achieve this output?
Month | Total | Purpose1 | Purpose2
10/2016 | 3 | 2 | 1
11/2016 | 3 | 1 | 2
Thanks!
Consider the following...
DROP TABLE IF EXISTS my_table;
CREATE TABLE my_table
(ID INT NOT NULL AUTO_INCREMENT PRIMARY KEY
,Date DATE NOT NULL
,Purpose VARCHAR(12) NOT NULL
);
INSERT INTO my_table VALUES
(1,'2016-10-20','Purpose1'),
(2,'2016-10-22','Purpose1'),
(3,'2016-10-25','Purpose2'),
(4,'2016-11-12','Purpose1'),
(5,'2016-11-14','Purpose2'),
(6,'2016-11-16','Purpose2');
SELECT DATE_FORMAT(date,'%Y-%m') month
, SUM(purpose = 'purpose1') purpose1
, SUM(purpose = 'purpose2') purpose2
, COUNT(*) total
FROM my_table
GROUP
BY month;
+---------+----------+----------+-------+
| month | purpose1 | purpose2 | total |
+---------+----------+----------+-------+
| 2016-10 | 2 | 1 | 3 |
| 2016-11 | 1 | 2 | 3 |
+---------+----------+----------+-------+
..or (and in my view, better, provided you have access to application code)...
SELECT DATE_FORMAT(date,'%Y-%m') month
, purpose
, COUNT(*) total
FROM my_table
GROUP
BY month
, purpose;
+---------+----------+-------+
| month | purpose | total |
+---------+----------+-------+
| 2016-10 | Purpose1 | 2 |
| 2016-10 | Purpose2 | 1 |
| 2016-11 | Purpose1 | 1 |
| 2016-11 | Purpose2 | 2 |
+---------+----------+-------+
Transposing tables isn't very fast. It is better to do so in some small program.
If you do a
select case
when date like '%/10/2016' then '10/2016'
when date like '%/11/2016' then '11/2016'
end as month, count(*) as total, Purpose
from visitors
where
date like '%/10/2016'
or date like '%/11/2016'
GROUP by month, Purpose
You'll have a good starting point.
You might need to add an ORDER BY clause (depending on your DBMS).
If (and only if) you only have two purposes in your table and the table isn't huge in size, you can create two views and join them.
I have the following table:
+---------+--------------+----------+
| item_id | location_id | price |
+---------+--------------+----------+
| 1 | 1 | 100 |
| 1 | 1 | 250 |
| 1 | 2 | 50 |
| 2 | 1 | 250 |
| 2 | 1 | 1000 |
| 3 | 1 | 1000 |
| 3 | 2 | 100 |
+---------+--------------+----------+
I can reduce this down to the minimum values using this query
SELECT
item_id, location_id, MIN(price) AS Price
from
table
GROUP BY item_id , location_id
This gets me
+---------+--------------+----------+
| item_id | location_id | price |
+---------+--------------+----------+
| 1 | 1 | 100 |
| 1 | 2 | 50 |
| 2 | 1 | 250 |
| 3 | 1 | 1000 |
| 3 | 2 | 100 |
+---------+--------------+----------+
I want to reduce this further. I am using the rows with a location_id of 1 as a reference row. For each row that has an item_id matching the reference row's item_id but a different location id. I want to compare that row's price with the reference row's price. If the price is lower than the reference row's price, I want to filter that row out.
My final result should include the reference row for each item id and any rows that met the criteria of the price being lower than the reference row price.
I have a hunch that I can use the HAVING clause to do this but I am having trouble compiling the statement. How should I construct the HAVING statement?
Thanks in advance
Nah, having can't help you like this, having is for things like you need filter min() result for something
e.g:
select id,min(price) from table where date = '2016-3-18' group by id having min(price) = 50
it will show you the records that min(price)=50
let's back to your case, there are lots of way to do that,
1. left join
select a.item_id,a.location_id,a.price
from table a
left join table b
on a.location_id = b.location_id and a.price > b.price
where b.price is null
2. exists
select a.item_id,a.location_id,a.price
from table a
where exists(
select 1 from
(select location_id,min(price)as price from table group by location_id)b
where a.location_id = b.location_id and a.price = b.price
)
normally i ll recommand you use exists
I have a Mysql table with the following data.
|ID | Date | BillNumber|BillMonth | Amount | Name |AccNum |
| 2 |2015-09-25| 454345 | 092015 | 135.00 |Andrew Good| 735976|
| 3 |2015-09-26| 356282 | 092015 | 142.00 |Peter Pan | 123489|
| 4 |2015-08-11| 312738 | 082015 | 162.00 |Andrew Good| 735976|
| 5 |2015-07-12| 287628 | 072015 | 220.67 |Andrew Good| 735976|
| 6 |2015-06-12| 100756 | 062015 | 556.34 |Andrew Good| 735976|
What I wanted to achieve is to retrieve the data of Andrew Good with AccNum 735976 for the BillMonth of 092015, provided that the user can entry any of his BillNumber(past/current).
If the reason that that row is of interest is because it is the latest of his rows, try:
select *
from tbl t
where name = ( select name
from tbl
where billnumber = 100756 -- can be any of his
)
and date = ( select max(date)
from tbl x
where x.name = t.name
)
(the billnumber can be any of his)