Apache HttpClient get status code along with all redirection url - apache-httpclient-4.x

Question

I want to get the status code of each redirected URL (with URL). I know there is a way through which we can get all redirection URLs by passing HttpClientContext but I want a status code as well. Is there any way to get a status code as well along with url?
var httpget = new HttpGet("www.dummy-url.com");
try (final var closeableHttpResponse = closeableHttpClient().execute(httpget, context);) {
final var instream = closeableHttpResponse.getEntity().getContent();
instream.close();
List<URI> redirectURIs = context.getRedirectLocations();
EntityUtils.consumeQuietly(closeableHttpResponse.getEntity());
}

Answer 1

Use a custom response interceptor to capture all incoming response messages
CloseableHttpClient httpclient = HttpClients.custom()
.addInterceptorLast(new HttpResponseInterceptor() {
#Override
public void process(HttpResponse response, HttpContext context) throws HttpException, IOException {
HttpClientContext clientContext = HttpClientContext.adapt(context);
RouteInfo route = clientContext.getHttpRoute();
HttpRequest request = clientContext.getRequest();
HttpHost targetHost = route.getTargetHost();
try {
URI uri = new URIBuilder(request.getRequestLine().getUri())
.setScheme(targetHost.getSchemeName())
.setHost(targetHost.getHostName())
.setPort(targetHost.getPort())
.build();
System.out.println(uri + " -> " + response.getStatusLine());
} catch (URISyntaxException ex) {
// unexpected. do some recovery
}
}
})
.build();
try {
HttpGet httpget = new HttpGet("http://google.com/");
httpclient.execute(httpget, new ResponseHandler<Void>() {
#Override
public Void handleResponse(HttpResponse response) throws ClientProtocolException, IOException {
return null;
}
});
System.out.println("----------------------------------------");
} finally {
httpclient.close();
}
http://google.com:80/ -> HTTP/1.1 301 Moved Permanently
http://www.google.com:80/ -> HTTP/1.1 200 OK
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