Is it possible to do curved shadows? I've currently got this design where it's an inset shadow on an element but it has curves, some on the element however, so aren't on the element (the inversed ones)
What i've currently got is an element with a border radius on the top-left and bottom-left and then I using a before and after block with a background radial-gradient to create the effect however, it begins to look stupid when I apply the shadows. Any ideas of what I can do to try and achieve the effect in the image below?
Example image of what I mean:
body { display: flex; justify-content: center; align-items: center; height: 100vh;}
.container {
background: red;
width: 200px;
height: 200px;
display: flex;
justify-content: flex-end;
align-items: center;
}
.block {
width: 160px;
height: 140px;
background: white;
border-top-left-radius: 20px;
border-bottom-left-radius: 20px;
position: relative;
}
.block:after,
.block:before {
content: "";
position: absolute;
right: 0;
width: 20px;
height: 20px;
background: blue;
}
.block:before {
background: radial-gradient(circle at top left, red 0%, red 75%, white 75%, white 100%);
top: -20px;
}
.block:after {
background: radial-gradient(circle at bottom left, red 0%, red 75%, white 75%, white 100%);
bottom: -20px;
}
<div class="container">
<div class="block">
<p style="font-size: 54px; text-align: center; marign: 0;">👋</p>
</div>
</div>
Related
I have this:
.test {
width: 400px;
height: 400px;
background-color: white;
display: inline-block;
background-size: 100px 30px;
background-repeaT: no-repeat;
background-position: center 30px, center center, center 140px;
border: solid 1px black;
position: relative;
overflow: hidden;
}
.test:after {
content: "";
position: absolute;
left: 0px;
top: 0px;
width: 100%;
height: 100%;
background: linear-gradient(25deg, yellow 50%, transparent 50%);
mix-blend-mode: difference;
transition: all 1s;
}
<div class="test one"></div>
I found the pen online, and want to adjust it for my own usage, however, cannot figure out a few things.
I want to move the blue box lower, so it is not as high, but still keep the same shape. So I tried background position, as one would, and it doesn't change anything. I'm relatively an amateur in css so it is probably a silly question, but a question none the less! Appreciate the help
It's because that shape is made with linear gradient as background, so you just need to adjust gradient percentages:
From
background: linear-gradient(25deg, yellow 50%, transparent 50%);
to
background: linear-gradient(25deg, yellow 20%, transparent 20%);
.test {
width: 400px;
height: 400px;
background-color: white;
display: inline-block;
background-size: 100px 30px;
background-repeaT: no-repeat;
background-position: center 30px, center center, center 140px;
border: solid 1px black;
position: relative;
overflow: hidden;
}
.test:after {
content: "";
position: absolute;
left: 0px;
top: 0px;
width: 100%;
height: 100%;
background: linear-gradient(25deg, yellow 20%, transparent 20%);
mix-blend-mode: difference;
transition: all 1s;
}
<div class="test one"></div>
Is there a css where I could size and position the border-left property? Or a "hack"? Below shows what I'd like to have. The black rectangle represents the column and the red, the border I'd like to have on that column. Possible?
If not, could I add another div inside then give that div the border property?
You can use :before pseudo element with position: absolute
.column {
position: relative;
height: 200px;
width: 100px;
border: 1px solid black;
display: flex;
align-items: center;
justify-content: center;
}
.column:before {
content: '';
height: 50px;
width: 3px;
background: red;
position: absolute;
left: 0;
top: 50%;
transform: translateY(-50%);
}
<div class="column">Column</div>
You can also do this with gradients and background-clip.
div {
width: 100px;
height: 300px;
border-width: 2px;
border-style: solid;
border-color: black black black transparent;
background-image: linear-gradient(white, white), linear-gradient(to bottom, black 30%, red 30%, red 60%, black 0);
background-clip: padding-box, border-box;
}
<div></div>
How do I make half a hexagon shape with a border and over top a rectangle shape with a border and an image inside the half hexagon shape using CSS and HTML5
I have no code for this as I have tried but cannot figure out how to do it
I added an image of what I would like to be able to do.
You can create a trapezoid fairly easily with a rectangle and 2 CSS triangles made with some transparent borders using :before and :after.
Working Example:
body {
background: black;
}
.rectangle {
background: #ECECEC;
height: 20px;
}
.trapezoid {
width: 50px;
height: 50px;
position: relative;
margin: 0 auto;
background: #ECECEC;
}
.trapezoid:before,
.trapezoid:after {
content: '';
display: block;
position: absolute;
top: 0;
border: 25px solid transparent;
border-top-color: #ECECEC;
}
.trapezoid:before {
right: 100%;
border-right-color: #ECECEC;
}
.trapezoid:after {
left: 100%;
border-left-color: #ECECEC;
}
<div class="rectangle">
<div class="trapezoid"></div>
</div>
updated with shape and border-colors
div {
margin-top:1em;;
text-align: center;
padding: 0.5em;
border-top:1px solid lightgray;
background: linear-gradient(to bottom, #ECECEC 50%, lightgray 50%, lightgray 51%, transparent 52%);
}
img {
position: relative;
display: block;
margin: 10px auto;
z-index: 1;
}
span {
text-align: center;
display: inline-block;
width:320px;
position: relative;
overflow: hidden;
border-top:1px solid lightgray;
background: linear-gradient(to left, lightgray, lightgray) bottom center, linear-gradient(40deg, transparent 50px, lightgray, 50px, lightgray 52px, #ECECEC 52px)bottom left, linear-gradient(-40deg, transparent 50px, lightgray, 50px, lightgray 52px, #ECECEC 52px)bottom right;
background-repeat: no-repeat;
background-size: 50% 2px, 50% 100%, 50% 100%;
}
<div>
<span>
<img src="http://lorempixel.com/55/46/technics/1" alt="ico"/>
</span>
</div>
older codes
a single pseudo and overflow:hidden, can do it too:
div {
text-align: center;
padding: 0.5em;
background: linear-gradient(to bottom, gray 50%, black 50%);
}
img {
position: relative;
display: block;
padding: 0.5em 0;
z-index: 1;
}
span {
text-align: center;
display: inline-block;
padding: 0 3em;
position: relative;
overflow: hidden;
}
span:before {
position: absolute;
content: '';
bottom: 0;
left: 50%;
margin-left: -75px;
height: 150px;
width: 150px;
background: gray;
transform: rotate(45deg);
}
<div>
<span>
<img src="http://lorempixel.com/40/50/nature/3" alt="ico"/>
</span>
</div>
or a gradient (easier probably to draw borders or shadows if needed)
div {
text-align: center;
padding: 0.5em;
background: linear-gradient(to bottom, gray 50%, black 50%);
}
img {
position: relative;
display: block;
padding: 0.5em 0;
z-index: 1;
}
span {
text-align: center;
display: inline-block;
padding: 0 3em;
position: relative;
overflow: hidden;
background: linear-gradient(40deg, transparent 1.5em, gray 1.5em)bottom left, linear-gradient(-40deg, transparent 1.5em, gray 1.5em)bottom right;
background-repeat: no-repeat;
background-size: 50% 100%;
}
<div>
<span>
<img src="http://lorempixel.com/40/50/nature/3" alt="ico"/>
</span>
</div>
Here is a solution using pseudo elements with skew. The image can be overlayed without problems
.rect {
width: 100%;
height: 20px;
background-color: lightgrey;
border-bottom: 1px solid grey;
position: relative;
}
.hex {
width: 200px;
height: 40px;
position: absolute;
left: 50%;
transform: translateX(-50%);
}
.hex:before, .hex:after {
content: "";
position: absolute;
width: 200px;
height: 40px;
border-style: solid;
border-color: grey;
border-width: 0px 0px 1px 0px;
transform-origin: bottom center;
background-color: lightgrey;
}
.hex:before {
transform: skew(10deg);
border-left-width: 1px;
}
.hex:after {
transform: skew(-10deg);
border-right-width: 1px;
}
<div class="rect">
<div class="hex"></div>
</div>
You can create half octagon using :after.
.halfOctagon {
width: 100px;
height: 50px;
background: #f35916;
position: relative;
top:25px;
left:50px;
}
.halfOctagon:after {
content: "";
position: absolute;
bottom: 0;
left: 0;
border-top: 29px solid #f35916;
border-left: 29px solid #eee;
border-right: 29px solid #eee;
width: 42px;
height: 0;
}
you can try live example in https://jsfiddle.net/kb2tzxq4/
To move the half octagon adjust top and left in css for .halfOctagon
I need to squash a div in vertically, using css3, the div need to have 100% width to fit in full window, but i don't know how. Thanks.
http://i.stack.imgur.com/vqUs8.png
(Updated, due to the request with an image behind the <div>)
A possible way if the background has only one color (white in this case)
div {
background-color: #000;
height: 200px;
margin: 40px 0 0;
position: relative;
overflow: hidden;
width: 100%;
}
div::before,
div::after {
border-radius: 140px / 20px;
content: "";
display: block;
height: 100px;
position: absolute;
width: 100%;
}
div::before {
box-shadow: 0 50px 0 10px #FFFFFF inset;
bottom: -80px;
}
div::after {
box-shadow: 0 -50px 0 10px #FFFFFF inset;
top: -80px;
}
http://jsfiddle.net/kmjLqrq2/
The css above uses two pseudoelements to make two ellipses above the <div>.
The problem now, if we have a background-image hiding behind the <div> is that our two ellipses will overlap our image.
Enter radial-gradient:
We can change our two pseudoelements now and give them an transparent ellipse as a background-image which will "fade" to black.
div::before,
div::after {
background-size: 100% 50px;
background-repeat: no-repeat;
content: "";
display: block;
height: 25px;
position: absolute;
width: 100%;
}
div::before {
background-image: -webkit-radial-gradient(center center, ellipse cover, rgba(0,0,0,0) 75%, #000 76%);
background-position: center bottom;
top: -25px;
}
div::after {
background-image: -webkit-radial-gradient(center center, ellipse cover, rgba(0,0,0,0) 75%, #000 76%);
background-position: center top;
bottom: -25px;
}
http://jsfiddle.net/kmjLqrq2/1/
(Note that the example above is only for Webkitbrowsers to keep it simple, please remember to use all vendor prefixes)
The code below will create an arrow right below an <a> element:
JSFiddle
.btn {
position: relative;
display: inline-block;
width: 100px;
height: 50px;
text-align: center;
color: white;
background: gray;
line-height: 50px;
text-decoration: none;
}
.btn:after {
content: "";
position: absolute;
bottom: -10px;
left: 0;
width: 0;
height: 0;
border-width: 10px 50px 0 50px;
border-style: solid;
border-color: gray transparent transparent transparent;
}
Hello!
The problem is that we have to indicate the link width to get an arrow of a proper size because we cannot indicate the border width in pixels.
How to make a responsive triangle percent based?
You could use a skewed and rotated pseudo element to create a responsive triangle under the link :
DEMO (resize the result window to see how it reacts)
The triangle maintains it's aspect ratio with the padding-bottom property.
If you want the shape to adapt it's size according to it's content, you can remove the width on the .btn class
.btn {
position: relative;
display: inline-block;
height: 50px; width: 50%;
text-align: center;
color: white;
background: gray;
line-height: 50px;
text-decoration: none;
padding-bottom: 15%;
background-clip: content-box;
overflow: hidden;
}
.btn:after {
content: "";
position: absolute;
top:50px; left: 0;
background-color: inherit;
padding-bottom: 50%;
width: 57.7%;
z-index: -1;
transform-origin: 0 0;
transform: rotate(-30deg) skewX(30deg);
}
/** FOR THE DEMO **/
body {
background: url('http://i.imgur.com/qi5FGET.jpg');
background-size: cover;
}
Hello!
For more info on responsive triangles and how to make them, you can have a look at
Triangles with transform rotate (simple and fancy responsive triangles)
Another solution to this would be to use a CSS clip-path to clip a triangle out of a coloured block. No IE support however, but could be used for internal tools etc.
DEMO
Written with SCSS for ease.
.outer {
background: orange;
width: 25%;
position: absolute;
top: 50%;
left: 50%;
transform: translate(-50%, -50%);
padding: 1em;
p {
margin: 0;
text-align: center;
color: #fff;
}
&:after {
content: '';
position: absolute;
top: 100%;
left: 0;
right: 0;
padding-bottom: 10%;
background: orange;
-webkit-clip-path: polygon(0% 0%, 100% 0%, 50% 100%);
clip-path: polygon(0% 0%, 100% 0%, 50% 100%);
}
}
I found solution that works with any width/height. You can use two pseudo-elements with linear-gradient background, like this, (fiddle):
.btn {
position: relative;
display: inline-block;
width: 100px;
height: 50px;
text-align: center;
color: white;
background: gray;
line-height: 50px;
text-decoration: none;
}
.btn:before {
content: "";
position: absolute;
top: 100%;
right: 0;
width: 50%;
height: 10px;
background: linear-gradient(to right bottom, gray 50%, transparent 50%)
}
.btn:after {
content: "";
position: absolute;
top: 100%;
left: 0;
width: 50%;
height: 10px;
background: linear-gradient(to left bottom, gray 50%, transparent 50%)
}
A modified version of the below code can help you to achieve this
HTML
<div class="triangle-down"></div>
CSS
.triangle-down {
width: 10%;
height: 0;
padding-left:10%;
padding-top: 10%;
overflow: hidden;
}
.triangle-down:after {
content: "";
display: block;
width: 0;
height: 0;
margin-left:-500px;
margin-top:-500px;
border-left: 500px solid transparent;
border-right: 500px solid transparent;
border-top: 500px solid #4679BD;
}
For further reading on responsive triangles: CSS triangles made responsive
(archived link)
I tried the other answers and found them to be either too complex and/or unwieldy to manipulate the shape of the triangle. I decided instead to create a simple triangle shape as an svg.
The triangle height can be set to an absolute value, or as a percentage of the rectangle so it can be responsive in both directions if necessary.
html, body{
height:100%;
width:100%;
}
.outer{
width:20%;
height:25%;
background:red;
position:relative;
}
.inner{
height:100%;
width:100%;
background-color:red;
}
.triangle-down{
height:25%;
width:100%;
position:relative;
}
.triangle-down svg{
height:100%;
width:100%;
position:absolute;
top:0;
}
svg .triangle-path{
fill:red;
}
<div class="outer">
<div class="inner"></div>
<div class="triangle-down">
<svg xmlns="http://www.w3.org/2000/svg" preserveAspectRatio="none" viewBox="0 0 2 1">
<g>
<path class="triangle-path" d="M0,0 l2,0 l-1,1 z" />
</g>
</svg>
</div>
Tested FF, Chrome, IE, Edge, mob Safari and mob Chrome
Another option would be to use background liner gradients, and flex positioning to make sure that the triangle always scales to its parent container. No matter how wide or narrow you make that container, the triangle always scales with it. Here is the fiddle:
https://jsfiddle.net/29k4ngzr/
<div class="triangle-wrapper-100">
<div class="triangle-left"></div>
<div class="triangle-right"></div>
</div>
.triangle-wrapper-100 {
width: 100%;
height: 100px;
display:flex;
flex-direction: column;
flex-wrap: wrap;
}
.triangle-right {
right: 0px;
background: linear-gradient(to right bottom, #6940B5 50%, transparent 50%);
width: 50%;
height: 100px;
}
.triangle-left {
left: 0px;
background: linear-gradient(to right bottom, #6940B5 50%, transparent 50%);
width: 50%;
height: 100px;
transform: scaleX(-1);
}
I took #Probocop's answer and come up with the following:
<style>
.btn {
background-color: orange;
color: white;
margin-bottom: 50px;
padding: 15px;
position: relative;
text-align: center;
text-decoration: none;
}
.btn:after {
background-color: inherit;
clip-path: url('data:image/svg+xml;utf8,%3Csvg xmlns="http://www.w3.org/2000/svg"%3E%3Cdefs%3E%3CclipPath id="p" clipPathUnits="objectBoundingBox"%3E%3Cpolygon points="0 0, 1 0, 0.5 1" /%3E%3C/clipPath%3E%3C/defs%3E%3C/svg%3E#p'); /* fix for firefox (tested in version 52) */
clip-path: polygon(0% 0%, 100% 0%, 50% 100%);
content: '';
height: 50px;
left: 0;
position: absolute;
right: 0;
top: 100%;
}
</style>
Hello!
This works in Chrome and I've added a fix for Firefox. It doesn't work in Edge, however if you decrease the height of the down arrow then it doesn't look so bad.
Please note that if you are using bootstrap you will need to either change the name or override some of the styles it applies. If you decide to rename it then you also need to add the following to the .btn style:
box-sizing: content-box;