I want to show a text with vertical orientation, but, all examples I find on the internet display the text vertically, but like it was written from up to bottom
I want exactly the opposite
I combine writing-mode with text-orientation, but I can't get the result I want
Thanks in advance,
Rafael
You can try use transform and rotate
.word {
margin: 50px -30px;
-ms-transform: rotate(-90deg);
transform: rotate(-90deg);
background-color: whitesmoke;
width: 100px;
text-align: center;
}
<div class="word">hello world</div>
More about how to use this here
I did it
Just used transform
transform: rotate(-90deg)
Which is the same as rotating 270deg
Related
Is it possible to cut a triangle from a <div> like in the picture below?
The background is actually not just colour, but in my case is a blurred picture, so I can’t simply cover the green <div> with a brown triangle image. Is there some other CSS way to achieve this effect? Thanks.
The illusion of it is possible: http://jsfiddle.net/2hCrw/4/
Tested with: IE 9, 10, Firefox, Chrome, Safari on PC and iPad.
::before and ::after pseudo elements are skewed to provide a side of the triangle each.
Wrapper used for clipping skewed pseudo elements. You may be able to avoid this by using your outer container as the wrapper.
Elements can still be styled with borders, shadows, etc.
Anything underneath will show through properly.
Demo with borders and drop shadow: http://jsfiddle.net/2hCrw/8/
This demo also adds a tweak for iPad with Retina to prevent a gap between the element and the pseudo elements (either caused by drop shadow bleed or sub-pixel rendering behavior).
<div id="wrapper">
<div id="test">test</div>
</div>
#wrapper {
overflow: hidden;
height: 116px;
}
#test {
height: 100px;
background-color: #ccc;
position: relative;
}
#test::before {
content:"";
position: absolute;
left: -8px;
width: 50%;
height: 16px;
top: 100px;
background-color: #ccc;
-webkit-transform: skew(-40deg);
-moz-transform: skew(-40deg);
-o-transform: skew(-40deg);
-ms-transform: skew(-40deg);
transform: skew(-40deg);
}
#test::after {
content:"";
position: absolute;
right: -8px;
width: 50%;
height: 16px;
top: 100px;
background-color: #ccc;
-webkit-transform: skew(40deg);
-moz-transform: skew(40deg);
-o-transform: skew(40deg);
-ms-transform: skew(40deg);
transform: skew(40deg);
}
As an alternative, you can use a transparent image and "extend" the element above it with pseudo elements. I have answered a similar question regarding a circle cut from an element and show support options down to IE7 (as well as future options for true clipping/masking in CSS).
You can do something like this with CSS masks (examples):
http://codepen.io/anon/pen/vgbEH (anti-triangle mask)
http://codepen.io/anon/pen/pEufn (triangle mask)
I used clip-path: polygon(…) property but only my Chrome seems to support it; you could instead create polygon images and reference them with mask-image for broader support.
It isn't possible to cut from divs in css, but it is possible to use an image overlaying the div to make it look like it has been cut.
.triangle{
background-image: url('cut.png');
width: 24px; height: 24px;
z-index: 1;
position: absolute; top: 32px; left: 15px;
}
It looks like there’s a bit of a drop shadow on your <div> as well, which I’m guessing the triangle should respect.
CSS doesn’t currently provide a way to achieve this directly. One approach would be to create an image of the green bottom area of the <div> with the triangle cut-out in it (using e.g. Photoshop), set it as the background of a <div> inside your original <div>, and position it outside of your original <div>.
Here’s a JS Fiddle example that hopefully explains the idea:
http://jsfiddle.net/7y6nz/
I am attempting to manipulate a div with css to avoid using an image to mimic the one below. So far I have it skewed, but is there any way to grab a corner and position it below the horizontal line? The shape appears to be a square with the lower left corner a tad bit skewed. I cant seem to figure out how to pull that one corner with out skewing the top corner as well.
skewed div shsape
Heres what I have so far:
.educationcontentdiv {
background-color: #f9da0b;
padding: 30px;
-webkit-transform: skewY(1deg);
-moz-transform: skewY(1deg);
-ms-transform: skewY(1deg);
-o-transform: skewY(1deg);
transform: skewY(1deg);
}
I have also tried to only skew the one side and it works well, but the corner is still on the same line as its opposing side:
margin: 0 0 0 -20px;
-webkit-transform: skew(20deg);
-moz-transform: skew(20deg);
-o-transform: skew(20deg);
background: red;
overflow:hidden;
position:relative;
Any Help would be appreciated
This looks like what you might be looking for: Matrix transformation
http://www.useragentman.com/blog/2011/01/07/css3-matrix-transform-for-the-mathematically-challenged/
My code should do the following:
A background big semi-black bar that is rotated 5 degrees.
JSFiddle
<div class="con-fluid"><div class="_978y"></div></div>
.con-fluid{
width: 100%;
}
._978y{
background-color: #2d2d2d;
width: 200%;
height: 296px;
position: absolute;
-webkit-transform: rotate(5.13deg);
-moz-transform: rotate(5.13deg);
-ms-transform: rotate(5.13deg);
-o-transform: rotate(5.13deg);
transform: rotate(5.13deg);
}
/*as you can see, the rotation code is universal to make sure it works on almost all browsers/
The issue: it's not filling on both its ends. You can see it clearly in the code preview.
what I want is basically filling this empty area so it doesn't look off the chart. Any thoughts?
Thanks in advance.
I don't quite understand your query, however, I think you are asking about the missing "triangle" on the top right of the rectangle. It is there because you rotated the rectangle.
To hide it, put margin-top: -10px; within the css for ._978y, moving the rectangle up 10px.
I created a featured block with HTML5 and CSS3. This block includes a background-image and some text heading. You can see it live here: http://codepen.io/anon/pen/yNWxBb
As you can see I am now using margin-top to center the text in the vertical middle of the block. And make use of the pseudo-class ::after to add a transparant dark overlay above the background-image.
I know you can vertical align a div using table in combination with table-cell and vertical-align: middle, but than it messed my markup.
Does anyone know how to fix this? And is this the right markup to do this? Or should you recommend an other markup and manner to add the transparant background to the image?
Look out to you answer/advice.
Thank you in advance.
Two possible solutions to your problem:
http://www.smashingmagazine.com/2013/08/absolute-horizontal-vertical-centering-css/
http://philipwalton.github.io/solved-by-flexbox/demos/vertical-centering/
And yes, you might want to alter the markup in order to make this possible but both articles I'm pointing you to come with example code.
I do believe this is your solution. Just replace this class in your css and it will work fine I guess.
.features figcaption header {
position: absolute;
top: 50%;
-moz-transform: translateY(-50%);
-ms-transform: translateY(-50%);
-o-transform: translateY(-50%);
-webkit-transform: translateY(-50%);
transform: translateY(-50%);
margin-left: auto;
margin-right: auto;
font-size: 24px;
line-height: 34px;
color: #FFF;
//position: absolute;
//top: 28%;
}
Is there a way i can draw the black "background" behind the image using pure CSS ?
I am persuaded that it can be done using the :before pseudo-class. But i can't make it work. I have also tried using shadows, but the final result is not similar what i am trying to achieve.
Scope and requirements:
Modern browsers, no javascript, no jQuery, no plugins and no extra HTML markup.
Before answering:
I know there are zillion ways to achieve what i am trying to do, however i am really looking forward for a pure CSS solution. As stated before, trying to avoid extra markup and javascript for something as simple as that. Thanks!
Here is a fiddle and the code below.
img {
position: absolute;
top: 100px;
left: 100px;
-webkit-transform-origin: center left;
-moz-transform-origin: center left;
-ms-transform-origin: center left;
-o-transform-origin: center left;
transform-origin: center left;
-webkit-transform: rotate(-2deg);
-moz-transform: rotate(-2deg);
-ms-transform: rotate(-2deg);
-o-transform: rotate(-2deg);
transform: rotate(-2deg);
}
img:before {
background: #000;
-webkit-transform-origin: center left;
-moz-transform-origin: center left;
-ms-transform-origin: center left;
-o-transform-origin: center left;
transform-origin: center left;
-webkit-transform: rotate(-4deg);
-moz-transform: rotate(-4deg);
-ms-transform: rotate(-4deg);
-o-transform: rotate(-4deg);
transform: rotate(-4deg);
width: 300px;
height: 300px;
content: ".";
}
<!doctype html>
<html>
<body>
<img width="300" height="150" src="http://upload.wikimedia.org/wikipedia/en/7/70/Example.png" />
</body>
</html>
It seems like the before: element is ignored on img tags - http://jsfiddle.net/GVdYe/
Added a div (sorry :-)
The problem you're having is related to how pseudo-elements work.
Before and after elements are rendered inside their parent. So:
div:before{ content:'before'; }
div:after{ content:'after'; }
renders basically like this:
<div> <span>before</span> Hello <span>after</span> </div>
You can't put other elements in img, because img is a replaced element, and therefore can't apply pseudo-elements to it. Read the spec.
So, the easiest option would be to wrap the image in an <a> (as images sometimes are) and apply your before style to the a.
Alternatively, accept the non-rotated shadow box-shadow provides.
CSS has limitations unfortunately, so you're going to have to compromise somewhere, either in design (I would argue this is the way to go) or in markup.
<style>
html (or body) {
background: url();
}
</style>
I don't know if you just want it behind the image or the entire browser. If you want it behind the image only then you will need a wrapper or at least another <div>, <span> or <img>