Laravel Query get row based on 2 dependent column - mysql

Question

Help me to query this.
I have a Laravel app where have a table that has 3 columns (quartal, year, value).
quartal
year
value
1
2019
3
2
2019
5
3
2019
5
4
2019
10
1
2020
7
2
2020
5
For example, I want to get the value from quartal 3 years 2019 to quartal 2 years 2020
how to make the query for this case?
for the year I can use between but for the quartal, It depends on the year.
here is my current query. but it does not work really well
DB::table($table)
->whereBetween('year',[$startYear, $endYear])
->whereBetween('quartal',[$startQuartal, $endQuartal])
->get();

Answer 1

What you need to do is you need to create a compound column from quartal and year and then query that.
DB::table($table)
->whereRaw("concat(year,quartal) >= ?", "$startYear$startQuartal")
->whereRaw("concat(year,quartal) <= ?", "$endYear$endQuartal")
->get();
You can refer this for the SQL query https://www.db-fiddle.com/f/4GRH5RKqQi2Fc6wVvxK8C2/0

Answer 2

you can do it with filter function also and it an easy way just like
$startYear = 2019
$endyear = 2020
$startQuartar = 3
$endQuartar = 2
DB::table($table)
->whereBetween('year',[$startYear, $endYear])
->get()->filter(function($query) use
($startYear,$endYear,$startQuartar,$endQuartar){
if($query->year == $startYear and $query->quartar < $startQuartar){
return false;
}
if($query->year == $endYear and $query->quartar > $endQuartar){
return false;
}
return true;
});

Answer 3

How about adding the quartal to the year?
DB::table($table)
->whereBetween(
DB::raw('year + (quartal - 1) / 4'),
[
$startYear + ($startQuartal - 1) / 4,
$endYear + ($endQuartal - 1) / 4
]
)
->get();