Google Sheets script - For each used cell in range 1, if cell value exists in range 2, get range 2 match's row number - google-apps-script

Question

I feel I have this script almost working as intended, but I am unsure as to where to place certain components of the procedure within the for loop to achieve the desired result. Tunnel vision is very much in effect right now, it's entirely possible I am overthinking a simple task. Please let me know if I can describe the issue more clearly. Any suggestions or pointers towards an existing resource are helpful.
Setup: Sheet one contains a dynamic vertical list of text values starting in cell I3 going down. Sheet two contains a dynamic vertical list of text values starting in range A2 going down, and has a similar set of text values in the same rows in column B.
Goal:
Get the value of each used cell in Sheet1 column I (range one)
Get the value of each used cell in Sheet2 column A (range two)
For each used cell in range one, check the value of each range one
cell to see if the value exists in range two
If a match exists, get the row number of the cell in range two that
contains the value (there will only ever be a single match if a match
exists)
Get the value of the cell on that same row in Sheet2 column B
Set the above value as the cell value in the row containing the value
found in both ranges on Sheet1 Column M
Below is what I have been able to come up with. I am able to get it to function up to the last step. It seems the matching rowNumber variable is not updating with each for loop.
// Get values of range one
var lastRowRangeOne = sheetone.getRange('I3').getNextDataCell(SpreadsheetApp.Direction.DOWN).getRow();
var rangeOneValues = sheetone.getRange('I3:I' + lastRowClientColumn).getValues();
// Get values of range two
var sheettwo = spreadsheet.getSheetByName('Sheet2');
var sheettwoLastRow = sheettwo.getLastRow();
var sheettwoList = sheettwo.getRange('A2:A' + sheettwoLastRow).getValues();
var sheettwoListFlat = sheettwoList.map(function(row) {return row[0];});
for (var i = 0; i< rangeOneValues.length ; i++){ // for each row in range one
if (sheettwoListFlat[i] == rangeOneValues[i]) { // if the range one value exists in range two
var rowNumber = sheettwoListFlat.indexOf(rangeOneValues[i]) + 3; // get the row number of the matching value found in range two
var sheetOneColumnMValue = sheettwo.getRange('B' + rowNumber).getValue(); // get the cell value of the same row in sheet two column B
var sheetOneRowNumber = i + 3; // get the row number of the range one value
sheetone.getRange('M' + sheetOneRowNumber).setValue(sheetOneColumnMValue); // set the cell value of sheet one column M row x, where x is sheetOneRowNumber
}
}

Answer 1

If you print the value of sheettwoListFlat, it has only 5 elements. Once the iterator of for loop reaches 5 or more it will automatically set if (sheettwoListFlat[i] == rangeOneValues[i]) { to false. Also the statement will only work if the elements of the same index of both arrays are equal.
It would be also more efficient if you search the Sheet1 using the values of Sheet2 since Sheet2 has lesser value.
Here I used TextFinder to find the text within a range.
Using Sheet2 values as search key
Code:
function myFunction() {
var spreadsheet = SpreadsheetApp.getActiveSpreadsheet();
var sheetone = spreadsheet.getSheetByName('Sheet1');
var lastRowRangeOne = sheetone.getRange('I2').getNextDataCell(SpreadsheetApp.Direction.DOWN).getRow();
var rangeOneValues = sheetone.getRange('I2:I' + lastRowRangeOne);
var sheettwo = spreadsheet.getSheetByName('Sheet2');
var sheettwoLastRow = sheettwo.getLastRow();
var sheettwoList = sheettwo.getRange('A2:B' + sheettwoLastRow).getValues();
for (var i = 0; i < sheettwoList.length; i++){
var find = rangeOneValues.createTextFinder(sheettwoList[i][0]).findNext()
if(find){
var sheetOneRowNumber = find.getRow();
sheetone.getRange('M' + sheetOneRowNumber).setValue(sheettwoList[i][1]);
}
}
}
Using Sheet1 values as search key
Code:
function myFunction() {
var spreadsheet = SpreadsheetApp.getActiveSpreadsheet();
var sheetone = spreadsheet.getSheetByName('Sheet1');
var lastRowRangeOne = sheetone.getRange('I2').getNextDataCell(SpreadsheetApp.Direction.DOWN).getRow();
var rangeOneValues = sheetone.getRange('I2:I' + lastRowRangeOne).getValues();
var sheettwo = spreadsheet.getSheetByName('Sheet2');
var sheettwoLastRow = sheettwo.getLastRow();
var sheettwoList = sheettwo.getRange('A2:B' + sheettwoLastRow);
for (var i = 0; i< rangeOneValues.length ; i++){ // for each row in range one
var find = sheettwoList.createTextFinder(rangeOneValues[i][0]).findNext();
if(find){
var rowNumber = find.getRow()
var sheetOneColumnMValue = sheettwo.getRange('B' + rowNumber).getValue(); // get the cell value of the same row in sheet two column B
var sheetOneRowNumber = i + 2;
sheetone.getRange('M' + sheetOneRowNumber).setValue(sheetOneColumnMValue);
}
}
}
Output:
Note: Both produce the same output but using Sheet2 values as search key is more faster than the other.

Answer 2

function compareTwoCols() {
const c1 = 'COL1';//column names
const c2 = 'COL3';
const ss1 = SpreadsheetApp.openById(gobj.globals.datagenid);//data set 1
const sh1 = ss1.getSheetByName('Sheet1');
const [hd1, ...vs1] = sh1.getDataRange().getValues();
let col1 = {};
hd1.forEach((h, i) => { col1[h] = i });
const ds1 = vs1.map((r, i) => {
return r[col1[c1]];
});
const ss2 = SpreadsheetApp.openById(gobj.globals.ssid);//data set 2
const sh2 = ss2.getSheetByName('Sheet0');
const [hd2, ...vs2] = sh2.getDataRange().getValues();
let col2 = {};
hd2.forEach((h, i) => { col2[h] = i });
const ds2 = vs2.map((r, i) => {
return r[col2[c2]]
});
let matches = { pA: [] };
let idx = -1;
ds1.forEach((e, i) => {
let from = '';
do {
idx = ds2.indexOf(e, from);
if (~idx) {
if (!matches.hasOwnProperty(e)) {
matches[e] = [];
matches[e].push({ val1: e, row1: i + 2, col1: col1[c1] + 1, row2: idx + 2, col2: col2[c2] +1 });
matches.pA.push(e);
} else {
matches[e].push({ val1: e, row1: i + 2, col1: col1[c1] + 1, row2: idx + 2, col2: col2[c2] + 1});
}
from = idx + 1;
}
} while (~idx);
});
Logger.log(JSON.stringify(matches));
}
Spreadsheet1 Sheet1:
COL1
COL2
COL3
COL4
COL5
3
4
2
3
4
2
6
6
1
4
5
1
7
5
5
9
8
7
9
5
7
9
0
8
1
8
2
8
7
9
5
8
7
9
9
1
2
0
8
6
2
7
4
0
3
8
2
0
2
6
Spreadsheet2 Sheet0:
COL1
COL2
COL3
COL4
COL5
5
1
2
7
6
4
5
7
8
2
6
3
8
1
5
0
7
6
3
6
4
7
6
1
7
5
6
9
2
1
3
0
2
2
8
4
5
0
8
1
1
3
9
2
2
3
6
7
0
3
Matches Object:
{
"2":[
{
"val1":2,
"row1":3,//ds1 row 3
"col1":1,
"row2":2,//ds2 row 4
"col2":3
},
{
"val1":2,
"row1":3,//ds1 row 3
"col1":1,
"row2":8,//ds2 row 8
"col2":3
},
{
"val1":2,
"row1":10,
"col1":1,
"row2":2,
"col2":3
},
{
"val1":2,
"row1":10,
"col1":1,
"row2":8,
"col2":3
}
],
"7":[
{
"val1":7,
"row1":6,
"col1":1,
"row2":3,
"col2":3
},
{
"val1":7,
"row1":6,
"col1":1,
"row2":11,
"col2":3
}
],
"8":[
{
"val1":8,
"row1":7,
"col1":1,
"row2":4,
"col2":3
},
{
"val1":8,
"row1":11,
"col1":1,
"row2":4,
"col2":3
}
],
"9":[
{
"val1":9,
"row1":5,
"col1":1,
"row2":7,
"col2":3
},
{
"val1":9,
"row1":5,
"col1":1,
"row2":10,
"col2":3
}
],
"pA":[//just an array of all of the matches
2,
9,
7,
8
]
}