I have no idea how to write it in Laravel Query Builder. Here's the SQL query:
select l.id, l.title, is1.similarity
FROM l
left join is1 on (l.id = is1.listing_id1 and is1.listing_id2 = 225678) or (l.id = is1.listing_id2 and is1.listing_id1 = 225678)
If I simply translate your SQL query to Laravel Query Builder query It would look like this.
DB::table('l')->select('l.id', 'l.title', 'is1.similarity')
->leftJoin('is1', function ($leftJoin) {
$leftJoin->on('l.id', '=', 'is1.listing_id1')->where('is1.listing_id2', '=', '225678')
->orOn('l.id','=', 'is1.listing_id2')->where('is1.listing_id1','=', '225678'); })
->get();
I guess, it would be something like this:
DB::table('l')
->('l.id', 'l.title', 'is1.similarity')
->join('is1', function ($join) {
$join->on('l.id', '=', 'is1.listing_id1') ->where('is1.listing_id2', '=', '225678')
->orOn('l.id','=', 'is1.listing_id2')->where('is1.listing_id1', '=', '225678');
})->get();
Don't forget to import this:
use Illuminate\Support\Facades\DB;
More information can be find here.
Related
I want to transform my MySql query into a Query in Laravel but I really don't know how to do this. I don't know how to rename in FROM like in SQL
My query is the following one :
SELECT f2.* FROM formation f2 WHERE f2.theme_id IN
(SELECT f.theme_id FROM user_formation uf JOIN formation f ON uf.formation_id = f.id WHERE uf.user_id = 2)
AND f2.id NOT IN
(SELECT formation_id FROM user_formation WHERE user_id = 2);
I tried something like this but ...
$q = Formation::query()
->from('formation AS f2')
->whereIn('f2.theme_id', function($r)
{
$r->select('f.theme_id')->from('user_formation AS uf')
->join('formation', function($join)
{
$join->on('uf.formation_id', '=', 'f.id')
->where ('uf.user_id', '=', $id)
});
});
->whereNotIn('f2.id', function($s){
$s->select('formation.id')
->from('user_formation')
->where('user_id', '=', $id)
})->get();
thanks for help.
If you want to run this raw query you can run:
$res = DB::select('
SELECT f2.*
FROM formation f2
WHERE f2.theme_id IN
(SELECT f.theme_id FROM user_formation uf JOIN formation f ON uf.formation_id = f.id WHERE uf.user_id = 2)
AND f2.id NOT IN
(SELECT formation_id FROM user_formation WHERE user_id = 2)');
Or you can rewrite this query in laravel query builder Eloquent ORM:
Formations::query()
->whereIn('formations.theme_id', function($q){
$user_formations_table = (new UserFormation)->getTable();
$formation_table = (new Formation)->getTable();
$q->select('paper_type_id')
->from($user_formations_table)
->join($formation_table, "$user_formations_table.formation_id", '=', "$formation_table.id")
->where("$user_formations_table.user_id", 2);
})->whereNotIn('formations.id', function($q){
$user_formations_table = (new UserFormation)->getTable();
$q->select('formation_id')
->where("$user_formations_table.user_id", 2);
})
->get();
Note that I have used models Formations, UserFormation, Formation Because you have used 3 different tables, you should add this models and specify tables to run ORM query
I advice to run first RAW query if there is no another need to run it with Eloquent
Hope this helps you
First of all, you need to fix your code indentations so you don't confuse yourself. Second, you placed semicolon in the wrong places. Third, you need to pass $id inside function because of the variable scope.
$q = Formation::query()
->whereIn('f2.theme_id', function($r) use ($id) {
$r->select('f.theme_id')->from('user_formation AS uf')
->join('formation', function($join) use ($id) {
$join->on('uf.formation_id', '=', 'f.id')
->where('uf.user_id', '=', $id);
}
);
})
->whereNotIn('f2.id', function($s) use ($id) {
$s->select('formation.id')
->from('user_formation')
->where('user_id', '=', $id);
})->get();
Note : If you are using VSCode, I suggest to use PHP Intelephense as it will help with autocomplete, syntax check, etc.
I have the following raw SQL query:
select a.id user_id, a.email_address, a.name_first, a.name_last, count(b.id) number_of_videos, sum(b.vimeo_duration) total_duration, sum(b.count_watched) total_playbacks
from users a,
videos b
where a.id = b.tutor_id
and a.email_address in ('candace_rennie#yahoo.com', 'tjm#hiltoncollege.com', 'matthewjameshenshall#gmail.com', 'nkululeko#syafunda.co.za', 'khulile#syafunda.co.za', 'nzakheni#syafunda.co.za')
group by a.id;
This correctly gets 6 rows from the database. I'm trying to convert this to a Laravel database query like so:
$totals = DB::table('users')
->select(DB::Raw('users.id as user_id'), 'users.email_address', 'users.name_first', 'users.name_last', DB::Raw('count(videos.id) as number_of_videos'), DB::Raw('sum(videos.vimeo_duration) as total_duration'), DB::Raw('sum(videos.count_watched) as total_playbacks'))
->join('videos', 'users.id', '=', 'videos.tutor_id')
->where('users.id', 'videos.tutor_id')
->whereIn('users.email_address', array('candace_rennie#yahoo.com', 'tjm#hiltoncollege.com', 'matthewjameshenshall#gmail.com', 'nkululeko#syafunda.co.za', 'khulile#syafunda.co.za', 'nzakheni#syafunda.co.za'))
->groupBy('users.id')
->get();
This however return 0 rows. Is there anything I'm missing?
It should be smth like below even tho groupBy user id does not help much as id is unique.
$aggregates = [
DB::raw('count(b.id) as number_of_videos'),
DB::raw('sum(b.vimeo_duration) as total_duration'),
DB::raw('sum(b.count_watched) as total_playbacks'),
];
$simpleSelects = ['users.email_address', users.id, 'users.name_first', 'users.name_last'];
$emails = ['candace_rennie#yahoo.com', 'tjm#hiltoncollege.com'....]
$users = Users::select(array_merge($simpleSelects, $aggregates))
->leftJoin('videos as b', function ($join) use ($emails) {
$join->on('b.tutor_id', 'a.id')
->whereIn('users.email_address', $emails);
})
->groupBy('users.id')
->get();
Try to remove this line:
->where('users.id', 'videos.tutor_id')
List item
after sql code convert into laravel
DB::select('posts.id','posts.title','posts.body')
->from('posts')
->where('posts.author_id', '=', 1)
->orderBy('posts.published_at', 'DESC')
->limit(10)
->get();
How can I convert the following query into a laravel eloquent query?
SELECT demand_costings.pr_number as Demand_Costing,work_types.work_types,
SUM(demand_costings.pr_quantity_in_pcs) as Total
FROM demand_costings
INNER JOIN work_types
ON demand_costings.worktype_id=work_types.id
GROUP BY work_types.work_types;
You can use laravel's DB facade:
$data = DB::table('table_name')
->select(DB::raw('emand_costings.pr_number as Demand_Costing,work_types.work_types,SUM(demand_costings.pr_quantity_in_pcs) as Total FROM demand_costings INNER JOIN work_types ON demand_costings.worktype_id=work_types.id'))
->groupBy('work_types')
->get();
Try this:
DB::table('demand_costings')
->select([
'pr_number as Demand_Costing',
'work_types',
'SUM(pr_quantity_in_pcs) as Total'
])
->join('work_types', 'demand_costings.worktype_id', '=', 'work_types.id')
->groupBy('work_types.work_types')
->get();
I am trying to write the following sql query in laravel:
select
`workers`.`first_name`,
`workers`.`last_name`,
`occupations`.`approval_date`,
`occupations`.`certification_date`,
`occupations`.`expiration_date`,
`occupations`.`type`,
`workers`.`photo`
from `worker_print_queue`
inner join `workers` on `worker_print_queue`.`worker_id` = `workers`.`id`
inner join `occupations` on `worker_print_queue`.`certification` = `occupations`.`type` AND `workers`.`id` = `occupations`.`worker_id`
I have written it in eloquent in the following manner:
$records = \DB::table('worker_print_queue')
->join('workers', 'worker_print_queue.worker_id', '=', 'workers.id')
->join('occupations', function($join){
$join->on('workers.id', '=', 'occupations.worker_id')
->where('worker_print_queue.certification', '=', 'occupations.type');
})
->select('workers.first_name', 'workers.last_name', 'occupations.approval_date',
'occupations.certification_date', 'occupations.expiration_date', 'occupations.type', 'workers.photo')
->get();
But I am receiving no results. I'm sure there is something I'm missing, just not sure what it is.
The issue is that this line
->where('worker_print_queue.certification', '=', 'occupations.type');
is comparing the column 'worker_print_queue.certification' to the value 'occupations.type'.
If you change it to use the on clause you should be fine:
->on('worker_print_queue.certification', '=', 'occupations.type');
Hi i have troubles converting this query to Laravel, my query works fine, but idk how to convert to a laravel query:
select p.id, p.enunciado, p.created_at, c.categoria, s.categoria
from preguntas_seleccion p, categorias c,sub_categorias s
where p.categorias_id = c.id and p.sub_categorias_id = s.id and c.id = s.categorias_id
Do you really need the last condition? Anyway, it should work like this (untested code!):
$query = \DB::table('preguntas_seleccion as p')->select("p.id","p.enunciado","p.created_at", "c.categoria","s.categoria");
$query->join('categorias', function($join)
{
$join->on('p.categorias_id', '=', 'c.id');
$join->on('c.id', '=', "s.categorias_id");
});
$query->join('sub_categorias as s', 'p.sub_categorias_id', '=', 's.id');
return $query->get();