error of 1824: failed to open the referenced table - mysql

Not sure what i'm doing wrong here. Im trying to understand the relationships between tables? Please help thank you
DROP DATABASE IF EXISTS `sql_retail`;
CREATE DATABASE `sql_retail`;
USE `sql_retail`;
SET NAMES utf8 ;
SET character_set_client = utf8mb4 ;
CREATE TABLE `RETAIL_ORDER` (
`OrderNumber` int(4) NOT NULL,
`StoreNumber` int(2) NOT NULL,
`StoreZip` char(9) NOT NULL,
`OrderMonth` char(12) NOT NULL,
`OrderYear` int(4) NOT NULL,
`OrderTotal` float(10) NOT NULL,
PRIMARY KEY (`OrderNumber`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4 COLLATE=utf8mb4_0900_ai_ci;
INSERT INTO `RETAIL_ORDER` VALUES (1000, 10, 98110, 'December', 2017, 445.00);
INSERT INTO `RETAIL_ORDER` VALUES (2000, 20, 02335, 'December', 2017, 310.00);
INSERT INTO `RETAIL_ORDER` VALUES (3000, 10, 98110, 'January', 2018, 480.00);
CREATE TABLE `ORDER_ITEM` (
`OrderNumber` int(11) NOT NULL,
`SKU` int(7) NOT NULL,
`Quantity` int(6) NOT NULL,
`Price` float(10) NOT NULL,
`Extended Price` float(10) NOT NULL,
PRIMARY KEY (`OrderNumber`),FOREIGN KEY(`OrderNumber`)REFERENCES RETAIL_ORDER(`OrderNumber`),
FOREIGN KEY(`SKU`)REFERENCES SKU_DATA(`SKU`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4 COLLATE=utf8mb4_0900_ai_ci;
INSERT INTO `ORDER_ITEM` VALUES (1000, 201000, 1, 300.00, 300.00);
INSERT INTO `ORDER_ITEM` VALUES (1000, 202000, 1, 130.00, 130.00);
INSERT INTO `ORDER_ITEM` VALUES (2000, 101100, 4, 50.00, 200.00);
INSERT INTO `ORDER_ITEM` VALUES (2000, 101200, 2, 50.00, 100.00);
INSERT INTO `ORDER_ITEM` VALUES (3000, 100200, 1, 300.00, 300.00);
INSERT INTO `ORDER_ITEM` VALUES (3000, 101100, 2, 50.00, 100.00);
INSERT INTO `ORDER_ITEM` VALUES (3000, 101200, 1, 50.00, 50.00);
CREATE TABLE `SKU_DATA` (
`SKU` int(11) NOT NULL,
`SKU_Description` varchar(50) NOT NULL,
`Department` varchar(20) NOT NULL,
`Buyer` varchar(15) NOT NULL,
PRIMARY KEY (`SKU`),FOREIGN KEY(`Buyer`)REFERENCES BUYER(`BuyerName`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4 COLLATE=utf8mb4_0900_ai_ci;
INSERT INTO `SKU_DATA` VALUES (100100, 'Std. Scuba Tank, Yellow', 'Water Sports', 'Peter Hansen');
INSERT INTO `SKU_DATA` VALUES (100200, 'Std. Scuba Tank, Magenta', 'Water Sports', 'Peter Hansen');
INSERT INTO `SKU_DATA` VALUES (100300, 'Std. Scuba Tank, Light Blue', 'Water Sports', 'Peter Hansen');
INSERT INTO `SKU_DATA` VALUES (100400, 'Std. Scuba Tank, Dark Blue', 'Water Sports', 'Peter Hansen');
INSERT INTO `SKU_DATA` VALUES (100500, 'Std. Scuba Tank, Light Green', 'Water Sports', 'Peter Hansen');
INSERT INTO `SKU_DATA` VALUES (100600, 'Std. Scuba Tank, Dark Green', 'Water Sports', 'Peter Hansen');
INSERT INTO `SKU_DATA` VALUES (101100, 'Dive Mask, Small Clear', 'Water Sports', 'Nancy Meyers');
INSERT INTO `SKU_DATA` VALUES (101200, 'Dive Mask, Med Clear', 'Water Sports', 'Nancy Meyers');
INSERT INTO `SKU_DATA` VALUES (201000, 'Half dome tent', 'camping', 'Cindy Lo');
INSERT INTO `SKU_DATA` VALUES (202000, 'Half dome tent vestibule', 'camping', 'Cindy Lo');
INSERT INTO `SKU_DATA` VALUES (203000, 'Half dome tent vestibule wide', 'camping', 'Cindy Lo');
INSERT INTO `SKU_DATA` VALUES (301000, 'Light fly climbing harness', 'climbing', 'Jerry Martin');
INSERT INTO `SKU_DATA` VALUES (302000, 'Locking Carabiner, Oval', 'climbing', 'Jerry Martin');
CREATE TABLE `BUYER` (
`BuyerName` varchar(15) NOT NULL,
`Department` varchar(15) NOT NULL,
`Position` varchar(15) NOT NULL,
`Supervisor` varchar(15) NOT NULL,
PRIMARY KEY (`BuyerName`),FOREIGN KEY(`Supervisor`)REFERENCES BUYER(`BuyerName`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4 COLLATE=utf8mb4_0900_ai_ci;
INSERT INTO `SKU_DATA` VALUES ('Cindy Lo', 'Purchasing', 'Buyer 2', 'Mary Smith');
INSERT INTO `SKU_DATA` VALUES ('Jerry Martin', 'Purchasing', 'Buyer 1', 'Cindo Lo');
INSERT INTO `SKU_DATA` VALUES ('Mary Smith', 'Purchasing', 'Manager','' );
INSERT INTO `SKU_DATA` VALUES ('Nancy Meyers', 'Purchasing', 'Buyer 1', 'Pete Hansen');
INSERT INTO `SKU_DATA` VALUES ('Pete Hansen', 'Purchasing', 'Buyer 3', 'Mary Smith');

You have some errors.
First you assign a foreign key to a table that don't exists yet and second you have duplicate values into your inserts for your primary keys.
I have fixed your table creation, check your insert datas.
Follow below approach to create your tables and then do the inserts:
DROP DATABASE IF EXISTS sql_retail ;
CREATE DATABASE sql_retail ;
USE sql_retail ;
SET NAMES utf8 ;
SET character_set_client = utf8mb4 ;
CREATE TABLE `RETAIL_ORDER` (
`OrderNumber` int(4) NOT NULL,
`StoreNumber` int(2) NOT NULL,
`StoreZip` char(9) NOT NULL,
`OrderMonth` char(12) NOT NULL,
`OrderYear` int(4) NOT NULL,
`OrderTotal` float(10) NOT NULL,
PRIMARY KEY (`OrderNumber`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4 COLLATE=utf8mb4_0900_ai_ci;
CREATE TABLE `ORDER_ITEM` (
`OrderNumber` int(11) NOT NULL,
`SKU` int(7) NOT NULL,
`Quantity` int(6) NOT NULL,
`Price` float(10) NOT NULL,
`Extended Price` float(10) NOT NULL,
PRIMARY KEY (`OrderNumber`),
FOREIGN KEY(`OrderNumber`)REFERENCES RETAIL_ORDER(`OrderNumber`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4 COLLATE=utf8mb4_0900_ai_ci;
CREATE TABLE `SKU_DATA` (
`SKU` int(11) NOT NULL,
`SKU_Description` varchar(50) NOT NULL,
`Department` varchar(20) NOT NULL,
`Buyer` varchar(15) NOT NULL,
PRIMARY KEY (`SKU`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4 COLLATE=utf8mb4_0900_ai_ci;
ALTER TABLE ORDER_ITEM ADD FOREIGN KEY(`SKU`)REFERENCES SKU_DATA(`SKU`);
CREATE TABLE `BUYER` (
`BuyerName` varchar(15) NOT NULL,
`Department` varchar(15) NOT NULL,
`Position` varchar(15) NOT NULL,
`Supervisor` varchar(15) NOT NULL,
PRIMARY KEY (`BuyerName`),
FOREIGN KEY(`Supervisor`)REFERENCES BUYER(`BuyerName`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4 COLLATE=utf8mb4_0900_ai_ci;
ALTER TABLE SKU_DATA ADD FOREIGN KEY(`Buyer`)REFERENCES BUYER(`BuyerName`);
Demo: https://www.db-fiddle.com/f/7yUJcuMJPncBBnrExKbzYz/28

Related

Can not add foreign key in mySQL [duplicate]

This question already has answers here:
MySQL Error 1215: Cannot add foreign key constraint
(29 answers)
Is storing a delimited list in a database column really that bad?
(10 answers)
Closed 2 years ago.
I want to add foreign key like this
and this is my table user_idea
CREATE TABLE IF NOT EXISTS `user_idea` (
`idea_id` int(5) NOT NULL AUTO_INCREMENT,
`user_id` varchar(30) DEFAULT NULL,
`title` varchar(40) DEFAULT NULL,
`innovators` varchar(30) DEFAULT NULL,
`idea_categories` varchar(30) DEFAULT NULL,
`status` int(5) DEFAULT NULL,
`description` varchar(50) DEFAULT NULL,
PRIMARY KEY (`idea_id`),
KEY `innovators` (`innovators`),
KEY `idea_categories` (`idea_categories`),
KEY `user_id` (`user_id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=8 ;
--
-- Dumping data untuk tabel `user_idea`
--
INSERT INTO `user_idea` (`idea_id`, `user_id`, `title`, `innovators`, `idea_categories`, `status`, `description`) VALUES
(1, 'jack', 'Video Annotations', 'jack', '1;2', 1, 'Video Annotations Description'),
(2, 'jack', 'Optimize waterfall model', 'jack;jackson', '3', 0, 'Optimize waterfall model Description'),
(3, 'jackson', 'Automation', 'jackson', '1', 1, 'Automation Description'),
(4, 'jackson', 'Design Patterns', 'jackson', '1', 0, 'Design Patterns Description'),
(5, 'alice', 'Identify Video Objects', 'alice;jack', '2', 1, 'Identify Video Objects Description'),
(6, 'bob', 'Tin Can LMS', 'bob', '1', 1, 'Tin Can LMS Description'),
(7, 'bob', 'Text Summarization', 'bob', '2;3', 0, 'Text Summarization Description');
--
-- Ketidakleluasaan untuk tabel pelimpahan (Dumped Tables)
--
--
-- Ketidakleluasaan untuk tabel `user_idea`
--
ALTER TABLE `user_idea`
ADD CONSTRAINT `user_id` FOREIGN KEY (`user_id`) REFERENCES `user_info` (`id`);
my table idea_category
enter image description here
CREATE TABLE IF NOT EXISTS `idea_categories` (
`category_id` int(5) NOT NULL AUTO_INCREMENT,
`category_name` varchar(50) DEFAULT NULL,
PRIMARY KEY (`category_id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=4 ;
INSERT INTO `idea_categories` (`category_id`, `category_name`) VALUES
(1, 'Project Lifecycle'),
(2, 'Video'),
(3, 'Language Analysis');
My table user_info:
enter image description here
CREATE TABLE IF NOT EXISTS `user_info` (
`id` varchar(30) NOT NULL,
`full_name` varchar(30) DEFAULT NULL,
`dep_id` int(5) DEFAULT NULL,
`point` int(5) DEFAULT NULL,
PRIMARY KEY (`id`),
KEY `dep_id` (`dep_id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
INSERT INTO `user_info` (`id`, `full_name`, `dep_id`, `point`) VALUES
('alice', 'Alice W', 2, 1),
('bob', 'Bob S.', 2, 2),
('jack', 'JACK D.', 2, 2),
('jackson', 'M.S.Jackson', 3, 3);
but I got an error cannot add foreign key? Please help

Having trouble with creating tables using foreign key [duplicate]

This question already has answers here:
How can I add a foreign key when creating a new table?
(5 answers)
Closed 4 years ago.
I am trying creating two tables, aluno = student and usuario = user. MySQL Workbench keep showing me that codigo in table usario doesn´t exist. Anyone can help me plz?
drop database `web2`;
CREATE DATABASE `web2` DEFAULT CHARSET latin1;
USE `web2`;
CREATE TABLE `aluno` (
`id_aluno` bigint(20) not null auto_increment,
`nome` varchar(100) not null,
`cpf` varchar(20) not null,
`rg` varchar(20) not null,
`dataDeNascimento` date not null,
`endereco` varchar(50),
`cidade` varchar(150),
`telefoneFixo` varchar(14),
`telefoneCelular` varchar(14),
`email` varchar(30) not null,
PRIMARY KEY (`id_aluno`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=1;
INSERT INTO `aluno` (`id_aluno`, `nome`, `cpf`, `rg`,`dataDeNascimento`, `endereco`, `cidade`, `telefoneFixo`,
`telefoneCelular`,`email`) VALUES ('1', 'Marcela', '255665696363', '2153263699',
'1985-07-08', 'Rua Hum', 'Belo Horizonte', '(35)54321-9876', '(35)54321-9876','marcela#bh.mg');
INSERT INTO `aluno` (`id_aluno`, `nome`, `cpf`, `rg`,`dataDeNascimento`, `endereco`, `cidade`, `telefoneFixo`,
`telefoneCelular`,`email`) VALUES ('2', 'Paulo', '275865696361', '2183255599','1983-02-05', 'Rua Dois', 'Bela Vista', '(11)12345-6789',
'(11)12345-6789', 'paulo#saopaulo.sp');
INSERT INTO `aluno` (`id_aluno`, `nome`, `cpf`, `rg`,`dataDeNascimento`, `endereco`, `cidade`, `telefoneFixo`,
`telefoneCelular`,`email`) VALUES ('3', 'Marcos', '275812656361', '2183255599','1983-02-12', 'Rua Dois', 'Bela Vista', '(11)12345-6790',
'(11)12345-6789', 'paulo#saopaulo.sp');
INSERT INTO `aluno` (`id_aluno`, `nome`, `cpf`, `rg`,`dataDeNascimento`, `endereco`, `cidade`, `telefoneFixo`,
`telefoneCelular`,`email`) VALUES ('4', 'Rodolfo', '569865696361', '2183255599','1983-05-28', 'Rua Dois', 'Bela Vista', '(11)12345-6791',
'(11)12345-6789', 'paulo#saopaulo.sp');
INSERT INTO `aluno` (`id_aluno`, `nome`, `cpf`, `rg`,`dataDeNascimento`, `endereco`, `cidade`, `telefoneFixo`,
`telefoneCelular`,`email`) VALUES ('5', 'Larissa', '275865696361', '2183255599','1983-02-01', 'Rua Dois', 'Bela Vista', '(11)12345-6792',
'(11)12345-6789', 'paulo#saopaulo.sp');
CREATE TABLE `usuario` (
`id` bigint(20) not null auto_increment,
`login` varchar(10) not null,
`senha` varchar(10) not null,
PRIMARY KEY (`id`),
FOREIGN KEY (`codigo`) REFERENCES aluno (`id_aluno`),
UNIQUE KEY (`login`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=1;
INSERT INTO `usuario` (`id`, `login`, `senha`, `codigo` ) VALUES ('1', 'marcela', '54321', '1');
INSERT INTO `usuario` (`id`, `login`, `senha`, `codigo` ) VALUES ('2', 'paulo', '12345', '2');
INSERT INTO `usuario` (`id`, `login`, `senha`, `codigo` ) VALUES ('3', 'gustavo', '52321', '3');
INSERT INTO `usuario` (`id`, `login`, `senha`, `codigo` ) VALUES ('4', 'leandro', '19315', '4');
INSERT INTO `usuario` (`id`, `login`, `senha`, `codigo` ) VALUES ('5', 'bruna', '14045', '5');
Are you missing the "codigo" column name in "CREATE TABLE usuario"
...
`codigo` bigint(20)
...
You need codigo defined in create table statement:
CREATE TABLE `usuario` (
`id` bigint(20) not null auto_increment,
`login` varchar(10) not null,
`senha` varchar(10) not null,
`codigo` bigint(20)
PRIMARY KEY (`id`),
FOREIGN KEY (`codigo`) REFERENCES aluno (`id_aluno`),
UNIQUE KEY (`login`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=1;
The reason for this is that foreign keys are constraints applied to columns, so the table first needs the column to which the foreign key constraint is applied.

SQL query join condition

I have a database of the following relations:
Bar(Name, Address, Licence)
Beer(Name,Manufacture)
Drinker(Name,Address)
Frequents(DrinkerName,BarName)
Likes(DrinkerName,BeerName)
Sells(BarName,BeerName,Amount)
Serves(BarName,BeerName)
The Sample DDL Statements:
CREATE TABLE `Bar` (
`Name` varchar(255) NOT NULL,
`Address` varchar(255) DEFAULT NULL,
`Licence` varchar(255) DEFAULT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
INSERT INTO `Bar` (`Name`, `Address`, `Licence`) VALUES
('Deluxe', 'Luxvagen 2', 'Yes'),
('Grace', 'Gracevagen 2', 'Yes'),
('KrogBar', 'Barvagen 2', 'Yes');
CREATE TABLE `Beer` (
`Name` varchar(255) NOT NULL,
`Manufacture` varchar(255) DEFAULT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
INSERT INTO `Beer` (`Name`, `Manufacture`) VALUES
('Carlsberg', 'Coppers'),
('Heiniken', 'Spendrups'),
('Miller', 'DaMill');
CREATE TABLE `Boor` (
`Name` varchar(255) NOT NULL,
`Age` int(11) DEFAULT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
CREATE TABLE `Drinker` (
`Name` varchar(255) NOT NULL,
`Address` varchar(255) DEFAULT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
INSERT INTO `Drinker` (`Name`, `Address`) VALUES
('Alex', 'Överbar 2'),
('Bam', 'Påbar 2'),
('Emil', 'Mittibar 2'),
('Max', 'Ibar 2'),
('Petra', 'Förebar 2'),
('Rebecca', 'Efterbar 2'),
('Sam', 'Underbar 2');
CREATE TABLE `Frequents` (
`DrinkerName` varchar(255) NOT NULL DEFAULT '',
`BarName` varchar(255) NOT NULL DEFAULT ''
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
INSERT INTO `Frequents` (`DrinkerName`, `BarName`) VALUES
('Emil', 'Deluxe'),
('Max', 'Deluxe'),
('Rebecca', 'Deluxe'),
('Alex', 'Grace'),
('Petra', 'Grace'),
('Bam', 'KrogBar'),
('Sam', 'KrogBar');
CREATE TABLE `Likes` (
`DrinkerName` varchar(255) NOT NULL DEFAULT '',
`BeerName` varchar(255) NOT NULL DEFAULT ''
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
INSERT INTO `Likes` (`DrinkerName`, `BeerName`) VALUES
('Bam', 'Carlsberg'),
('Emil', 'Carlsberg'),
('Rebecca', 'Carlsberg'),
('Emil', 'Heiniken'),
('Max', 'Heiniken'),
('Petra', 'Heiniken'),
('Sam', 'Heiniken'),
('Alex', 'Miller');
CREATE TABLE `Sells` (
`BarName` varchar(100) DEFAULT NULL,
`BeerName` varchar(100) DEFAULT NULL,
`Amount` int(11) DEFAULT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
INSERT INTO `Sells` (`BarName`, `BeerName`, `Amount`) VALUES
('KrogBar', 'Miller', 3),
('KrogBar', 'Carlsberg', 2),
('KrogBar', 'Heiniken', 1),
('Deluxe', 'Heiniken', 1);
CREATE TABLE `Serves` (
`BarName` varchar(255) NOT NULL DEFAULT '',
`BeerName` varchar(255) NOT NULL DEFAULT ''
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
INSERT INTO `Serves` (`BarName`, `BeerName`) VALUES
('Grace', 'Carlsberg'),
('KrogBar', 'Carlsberg'),
('Deluxe', 'Heiniken'),
('Grace', 'Heiniken'),
('KrogBar', 'Heiniken'),
('KrogBar', 'Miller');
I want to find drinkers that frequent only bars that serve beer that they like (the assumption is that each drinker frequents at least one bar).
How can I construct such a query? I know that I have to use Joins and Sub-queries, I am not new to either of them but all my implementations have not yielded the correct results.
Is this what you looking for;
Select DISTINCT bar.Name,bar.Address,frequents.DrinkerName, likes.BeerName
From
Bar
Join frequents on bar.Name = frequents.BarName
join sells on bar.name = sells.BarName
join likes on frequents.DrinkerName = likes.DrinkerName

Error Code 1452 When attempting to Alter Table Constraint

ALTER TABLE `charter`
ADD CONSTRAINT `charter_ibfk_3` FOREIGN KEY (`CHAR_DESTINATION`)
REFERENCES `airport` (`AIRPORT_CODE`);
I am attempting to create this relationship:
Charter and Airport ERD Diagram
CREATE TABLE `antonellacammarota` (
`CUS_CODE` int(6) NOT NULL DEFAULT '0',
PRIMARY KEY (`CUS_CODE`),
FOREIGN KEY (`CUS_CODE`) REFERENCES `CUSTOMER` (`CUS_CODE`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
insert into customer values (10076, "Cammarota", "Antonella", "T", "805", "555-1212", 0);
insert into antonellacammarota(select cus_code from customer where cus_lname = 'Cammarota');
--
-- Table structure for table `airport`
--
CREATE TABLE IF NOT EXISTS `airport` (
`AIRPORT_CODE` varchar(3) NOT NULL DEFAULT '0',
`AIRPORT_NAME` varchar(40) DEFAULT NULL,
`AIRPORT_ADDRESS` varchar(45) DEFAULT NULL,
`AIRPORT_CITY` varchar(25) DEFAULT NULL,
`AIRPORT_STATE` char(2) DEFAULT NULL,
`AIRPORT_ZIP` varchar(10) DEFAULT NULL,
`AIRPORT_COUNTRY` varchar(25) DEFAULT NULL,
`AIRPORT_AREACODE` varchar(3) DEFAULT NULL,
`AIRPORT_PHONE` varchar(8) DEFAULT NULL,
PRIMARY KEY (`AIRPORT_CODE`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
--
-- Constraints for table `airport`
--
ALTER TABLE `charter`
ADD CONSTRAINT `charter_ibfk_3` FOREIGN KEY (`CHAR_DESTINATION`) REFERENCES `airport` (`AIRPORT_CODE`);
--
-- Dumping data for table `airport`
--
INSERT INTO `airport` (`AIRPORT_CODE`, `AIRPORT_NAME`, `AIRPORT_ADDRESS`, `AIRPORT_CITY`, `AIRPORT_STATE`,
`AIRPORT_ZIP`, `AIRPORT_COUNTRY`, `AIRPORT_AREACODE`, `AIRPORT_PHONE`) VALUES
('ATL', 'Hartsfield-Jackson Atlanta Int', '6000 N Terminal Pkwy.', 'Atlanta', 'GA', '30320', 'US', '808', '897-1910'),
('BNA', 'Nashville Int', '1 Terminal Dr.', 'Nashville', 'TN', '37214', 'US', '615', '275-1675'),
('GNV', 'Gainesville Regional', '3880 NE 39th Ave.', 'Gainesville', 'FL', '32609', 'US', '352', '373-0249'),
('MOB', 'Mobile Regional', '8400 Airport Blvd.', 'Mobile', 'AL', '36608', 'US', '800', '357-5373'),
('MOY', 'Monterrey', '', 'Monterrey', '', '', 'Columbia', '', ''),
('STL', 'St. Louis Lambert Int', '10701 Lambert International Blvd.', 'St. Louis', 'MO', '63145', 'US', '314', '426-8000'),
('TYS', 'McGhee Tyson', '2055 Alcoa Hwy', 'Alcoa', 'TN', '37701', 'US', '865', '345-3000');
Use this to find out what entry is screwing things up
SELECT CHAR_TRIP, CHAR_DESTINATION
FROM charter
WHERE CHAR_DESTINATION NOT IN (
SELECT AIRPORT_CODE FROM airport);

How to calculate sum of two columns from two different tables without where clause?

I am using the following sql statement to sum values from two columns from two different tables. The statement can output but not the desired result.
SELECT
SUM(`_income`.rate) AS Income,
SUM(`_expense`.rate) AS Expense,
SUM(_income.rate)-SUM(_expense.rate) AS Balance
FROM `_expense`, `_income`
My table is here:
CREATE TABLE IF NOT EXISTS `_expense` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`item` varchar(100) CHARACTER SET utf8 COLLATE utf8_unicode_ci NOT NULL,
`qnty` int(11) NOT NULL,
`rate` int(11) NOT NULL,
`date` date NOT NULL,
`CreatedByPHPRunner` int(11) NOT NULL,
`remarks` text NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=4 ;
--
-- Dumping data for table _expense
INSERT INTO `_expense` (`id`, `item`, `qnty`, `rate`, `date`, `CreatedByPHPRunner`, `remarks`) VALUES
(2, 'Maian', 2, 20, '2013-08-15', 0, 'A tui kher mai'),
(3, 'Battery', 1, 2100, '2013-08-15', 0, 'A lian chi');
--
-- Table structure for table _income
CREATE TABLE IF NOT EXISTS `_income` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`items` varchar(100) DEFAULT NULL,
`qnty` int(11) DEFAULT NULL,
`rate` int(11) DEFAULT NULL,
`date` date DEFAULT NULL,
`remarks` varchar(255) DEFAULT NULL,
`CreatedByPHPRunner` int(11) DEFAULT NULL,
PRIMARY KEY (`id`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=5 ;
--
-- Dumping data for table _income
INSERT INTO `_income` (`id`, `items`, `qnty`, `rate`, `date`, `remarks`, `CreatedByPHPRunner`) VALUES
(1, 'TV chhe siam', 1, 1500, '2013-08-15', 'Ka hniam hrep', NULL),
(2, 'First Star', 1, 25, '2013-08-15', 'A loose-in aw', NULL),
(3, 'Mobile Chhe siam', 2, 200, '2013-08-13', 'Nokia chhuak ho a nia', NULL),
(4, 'Internet hman man', 1, 1500, '2013-08-14', 'Ka net min hman sak a', NULL);
This should do it:
select income, expense, income-expense balance
from (select sum(rate) income
from _income) i
JOIN (select sum(rate) expense
from _expense) e