Having trouble with creating tables using foreign key [duplicate] - mysql

Question

This question already has answers here:
How can I add a foreign key when creating a new table?
(5 answers)
Closed 4 years ago.
I am trying creating two tables, aluno = student and usuario = user. MySQL Workbench keep showing me that codigo in table usario doesn´t exist. Anyone can help me plz?
drop database `web2`;
CREATE DATABASE `web2` DEFAULT CHARSET latin1;
USE `web2`;
CREATE TABLE `aluno` (
`id_aluno` bigint(20) not null auto_increment,
`nome` varchar(100) not null,
`cpf` varchar(20) not null,
`rg` varchar(20) not null,
`dataDeNascimento` date not null,
`endereco` varchar(50),
`cidade` varchar(150),
`telefoneFixo` varchar(14),
`telefoneCelular` varchar(14),
`email` varchar(30) not null,
PRIMARY KEY (`id_aluno`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=1;
INSERT INTO `aluno` (`id_aluno`, `nome`, `cpf`, `rg`,`dataDeNascimento`, `endereco`, `cidade`, `telefoneFixo`,
`telefoneCelular`,`email`) VALUES ('1', 'Marcela', '255665696363', '2153263699',
'1985-07-08', 'Rua Hum', 'Belo Horizonte', '(35)54321-9876', '(35)54321-9876','marcela#bh.mg');
INSERT INTO `aluno` (`id_aluno`, `nome`, `cpf`, `rg`,`dataDeNascimento`, `endereco`, `cidade`, `telefoneFixo`,
`telefoneCelular`,`email`) VALUES ('2', 'Paulo', '275865696361', '2183255599','1983-02-05', 'Rua Dois', 'Bela Vista', '(11)12345-6789',
'(11)12345-6789', 'paulo#saopaulo.sp');
INSERT INTO `aluno` (`id_aluno`, `nome`, `cpf`, `rg`,`dataDeNascimento`, `endereco`, `cidade`, `telefoneFixo`,
`telefoneCelular`,`email`) VALUES ('3', 'Marcos', '275812656361', '2183255599','1983-02-12', 'Rua Dois', 'Bela Vista', '(11)12345-6790',
'(11)12345-6789', 'paulo#saopaulo.sp');
INSERT INTO `aluno` (`id_aluno`, `nome`, `cpf`, `rg`,`dataDeNascimento`, `endereco`, `cidade`, `telefoneFixo`,
`telefoneCelular`,`email`) VALUES ('4', 'Rodolfo', '569865696361', '2183255599','1983-05-28', 'Rua Dois', 'Bela Vista', '(11)12345-6791',
'(11)12345-6789', 'paulo#saopaulo.sp');
INSERT INTO `aluno` (`id_aluno`, `nome`, `cpf`, `rg`,`dataDeNascimento`, `endereco`, `cidade`, `telefoneFixo`,
`telefoneCelular`,`email`) VALUES ('5', 'Larissa', '275865696361', '2183255599','1983-02-01', 'Rua Dois', 'Bela Vista', '(11)12345-6792',
'(11)12345-6789', 'paulo#saopaulo.sp');
CREATE TABLE `usuario` (
`id` bigint(20) not null auto_increment,
`login` varchar(10) not null,
`senha` varchar(10) not null,
PRIMARY KEY (`id`),
FOREIGN KEY (`codigo`) REFERENCES aluno (`id_aluno`),
UNIQUE KEY (`login`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=1;
INSERT INTO `usuario` (`id`, `login`, `senha`, `codigo` ) VALUES ('1', 'marcela', '54321', '1');
INSERT INTO `usuario` (`id`, `login`, `senha`, `codigo` ) VALUES ('2', 'paulo', '12345', '2');
INSERT INTO `usuario` (`id`, `login`, `senha`, `codigo` ) VALUES ('3', 'gustavo', '52321', '3');
INSERT INTO `usuario` (`id`, `login`, `senha`, `codigo` ) VALUES ('4', 'leandro', '19315', '4');
INSERT INTO `usuario` (`id`, `login`, `senha`, `codigo` ) VALUES ('5', 'bruna', '14045', '5');

Answer 1

Are you missing the "codigo" column name in "CREATE TABLE usuario"
...
`codigo` bigint(20)
...

Answer 2

You need codigo defined in create table statement:
CREATE TABLE `usuario` (
`id` bigint(20) not null auto_increment,
`login` varchar(10) not null,
`senha` varchar(10) not null,
`codigo` bigint(20)
PRIMARY KEY (`id`),
FOREIGN KEY (`codigo`) REFERENCES aluno (`id_aluno`),
UNIQUE KEY (`login`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=1;
The reason for this is that foreign keys are constraints applied to columns, so the table first needs the column to which the foreign key constraint is applied.