I have a problem. I created these 2 queries to get the start and end value:
Start value:
SELECT IF(`Order`.action = "Buy", `Order`.transMarketGross, `Order`.transMarketNet) AS startValue
FROM `Order`
WHERE agentId = (SELECT id FROM Agent WHERE owner = "Alexander") AND
`Order`.dateTimeExecuted <= DATE_SUB(curdate(), INTERVAL 1 MONTH)
ORDER BY `Order`.dateTimeExecuted DESC
LIMIT 1;
End value:
SELECT IF(`Order`.action = "Buy", `Order`.transMarketGross, `Order`.transMarketNet) AS endValue
FROM `Order`
WHERE agentId = ( SELECT id
FROM Agent
WHERE owner = "Alexander")
ORDER BY `Order`.dateTimeExecuted DESC LIMIT 1;
But now I want the start and end value in one result row, so I thought I could add UNION between the 2 queries:
SELECT IF(`Order`.action = "Buy", `Order`.transMarketGross, `Order`.transMarketNet) AS startValue
FROM `Order`
WHERE agentId = ( SELECT id
FROM Agent
WHERE owner = "Alexander") AND `Order`.dateTimeExecuted <= DATE_SUB(curdate(), INTERVAL 1 MONTH)
ORDER BY `Order`.dateTimeExecuted DESC LIMIT 1
UNION
SELECT IF(`Order`.action = "Buy", `Order`.transMarketGross, `Order`.transMarketNet) AS endValue
FROM `Order` WHERE agentId = ( SELECT id
FROM Agent
WHERE owner = "Alexander")
ORDER BY `Order`.dateTimeExecuted DESC LIMIT 1
Using these queries seperately, they do their job, but I get an error on the total query that this query is not valid. Can someone tell me what I am doing wrong and how I can fix this? Also if there are any improvements to simplify the query, let me know!
If you want one row, you might as well use two subqueries:
SELECT (SELECT (CASE WHEN o.action = 'Buy', o.transMarketGross, o.transMarketNet) AS startValue
FROM `Order` o JOIN
Agent a
ON o.agentId = a.id
WHERE a.owner = 'Alexander' AND
o.dateTimeExecuted <= DATE_SUB(curdate(), INTERVAL 1 MONTH)
ORDER BY o.dateTimeExecuted DESC
LIMIT 1
),
(SELECT (CASE WHEN o.action = 'Buy', o.transMarketGross, o.transMarketNet) AS startValue
FROM `Order` o JOIN
Agent a
ON o.agentId = a.id
WHERE a.owner = 'Alexander'
ORDER BY o.dateTimeExecuted DESC
LIMIT 1
);
Note that I made the following changes:
Added table aliases so the query is easier to write and read.
Qualified all column references, so the query is unambiguous.
Replaced the in with JOIN, which seems to be the intention.
Replaced double quotes with the SQL standard single quotes for string delimiters.
Use CASE (the standard) rather than the bespoke IF() for conditional logic.
Related
Here is my query
SELECT
SUM(o.order_disc + o.order_disc_vat) AS manualsale
FROM
orders o
WHERE
o.order_flag IN (0 , 2, 3)
AND o.order_status = '1'
AND (o.assign_sale_id IN (SELECT GROUP_CONCAT(CAST(id AS SIGNED)) AS ids FROM users WHERE team_id = 92))
AND DATE(o.payment_on) = DATE(NOW())
above query return null when i run this query in terminal
When i use subquery below it returns data
SELECT GROUP_CONCAT(CAST(id AS SIGNED)) AS ids FROM users WHERE team_id = 92)
above query returns
'106,124,142,179'
and when i run my first query like below
SELECT
SUM(o.order_disc + o.order_disc_vat) AS manualsale
FROM
orders o
WHERE
o.order_flag IN (0 , 2, 3)
AND o.order_status = '1'
AND (o.assign_sale_id IN (106,124,142,179))
AND DATE(o.payment_on) = DATE(NOW())
it return me value.
Why it is not working with subquery please help
This does not do what you want:
AND (o.assign_sale_id IN (SELECT GROUP_CONCAT(CAST(id AS SIGNED)) AS ids FROM users WHERE team_id = 92))
This compares a single value against a comma-separated list of values, so it never matches (unless there is just one row in users for the given team).
You could phrase this as:
AND assign_sale_id IN (SELECT id FROM users WHERE team_id = 92)
But this would probably be more efficently expressed with exists:
AND EXISTS(SELECT 1 FROM users u WHERE u.team_id = 92 AND u.id = o.assign_sale_id)
Side note: I would also recommend rewriting this condition:
AND DATE(o.payment_on) = DATE(NOW())
To the following, which can take advantage of an index:
AND o.payment_on >= current_date AND o.payment_on < current_date + interval 1 day
Below I cannot do Group by Date the following figures.
I have tried to put Group By in different lines, but not working.
SELECT SUM(a.NetAmount) AS TotalDonation
FROM (
SELECT
(
CASE WHEN bt.BalanceTransactionCurrencyID = 17
THEN bt.BalanceTransactionNet
ELSE
bt.BalanceTransactionNet * (SELECT TOP 1 ExrateValue FROM Exrate WHERE ExrateDate < bt.BalanceTransactionCreated AND bt.BalanceTransactionCurrencyID = CurrencyID ORDER BY ExrateDate Desc)
END
) AS NetAmount
FROM Charge as ch
JOIN BalanceTransaction as bt ON (ch.BalanceTransactionID = bt.BalanceTransactionID)
WHERE ch.ChargeCreatedDate BETWEEN '3-1-2019' AND '3-31-2019'
) AS a
I wanted to see:
Days Total Amount
March 1 xxxx
March 2 xxxx
March 3 xxx
MySQL does not use TOP. Use LIMIT:
SELECT ChargeCreatedDate, SUM(netamount)
FROM (SELECT ch.ChargeCreatedDate,
(CASE WHEN bt.BalanceTransactionCurrencyID = 17
THEN bt.BalanceTransactionNet
ELSE bt.BalanceTransactionNet * (SELECT e.ExrateValue
FROM Exrate e
WHERE e.ExrateDate < bt.BalanceTransactionCreated AND
e.CurrencyID = bt.BalanceTransactionCurrencyID
ORDER BY ExrateDate Desc
LIMIT 1
)
END) AS NetAmount
FROM Charge ch JOIN
BalanceTransaction bt
ON ch.BalanceTransactionID = bt.BalanceTransactionID
WHERE ch.ChargeCreatedDate BETWEEN '2019-03-01' AND '2019-03-31'
) chtbt
GROUP BY ChargeCreatedDate;
If you happen to be using SQL Server, you can replace the LIMIT 1 with FETCH FIRST 1 ROW ONLY.
The following code will hopefully display what you are looking for
SELECT a.Days AS Days, SUM(cast(a.NetAmount as decimal(16,9))) AS TotalDonation
FROM (
SELECT
(
CASE WHEN bt.BalanceTransactionCurrencyID = 17
THEN bt.BalanceTransactionNet
ELSE
bt.BalanceTransactionNet * (SELECT TOP 1 ExrateValue FROM Exrate WHERE ExrateDate < bt.BalanceTransactionCreated AND bt.BalanceTransactionCurrencyID = CurrencyID ORDER BY ExrateDate Desc)
END
) AS NetAmount,
ch.ChargeCreatedDate as Days
FROM Charge as ch
JOIN BalanceTransaction as bt ON (ch.BalanceTransactionID = bt.BalanceTransactionID)
WHERE ch.ChargeCreatedDate BETWEEN '3-1-2019' AND '3-31-2019'
) AS a GROUP BY a.Days
This should be sufficient. You need to SELECT the desired value in the query in order to get it to show up. Also when using the SUM() function you need to specify what the group value will be.
Getting an error
Operand should contain 1 column(s)
PK is ID
The table just dumps data in to the table
need to get the earliest date qty and the latest date qty and display on the same column
Any help appreciated
SELECT ebx_r_history.ItemNumber,
(SELECT r.QuantitySold as newqty, r.lastupdate as lu
FROM ebx_r_history r
WHERE ebx_r_history.ItemNumber = r.ItemNumber AND ebx_r_history.SKU = r.SKU
ORDER BY r.LastUpdate ASC
LIMIT 1),
(SELECT r.QuantitySold as newqty, r.lastupdate as lu
FROM ebx_r_history r
WHERE ebx_r_history.ItemNumber = r.ItemNumber AND ebx_r_history.SKU = r.SKU
ORDER BY r.LastUpdate DESC
LIMIT 1)
FROM
ebx_r_history
GROUP BY ebx_r_history.ItemNumber,
ebx_r_history.SKU
ORDER BY ebx_r_history.LastUpdate
This version may offer a simplified and faster alternative for you. The inner query for "AllItems" does both a min and max of the last update on a per-item number/sku basis, although I believe they would be one-in-the-same record.
So now, join that results back to the history data by item/sku and only those that match either the min or max date. If a true date/time, there would expect to only be one anyhow, vs just a date-only. So, since there would be 2 possible records (one for the min, one for the max), I am applying a MAX( IIF( )) for each respective matching the minimum and maximum dates respectively and must retain the group by clause.
Note, if you are dealing with date-only entries, or possibilities of the exact same item/sku and lastupdate are the same to the second, then you would need an approach more towards limit 1 per ascending/descending basis.
SELECT
AllItems.ItemNumber,
AllItems.SKU,
AllItems.MinUpdate,
MAX( IIF( rh.lastupdate = AllItems.MinUpdate, rh.Quantity.Sold, 0 )) as QtyAtMinDate,
AllItems.MaxUpdate,
MAX( IIF( rh.lastupdate = AllItems.MaxUpdate, rh.Quantity.Sold, 0 )) as QtyAtMaxDate
from
( SELECT
r.ItemNumber,
r.SKU,
MIN( r.lastupdate ) as MinUpdate,
MAX( r.lastupdate ) as MaxUpdate
FROM
ebx_r_history r
group by
r.ItemNumber,
r.SKU ) AllItems
JOIN ebx_r_history rh
ON AllItems.ItemNumber = rh.ItemNumber
AND AllItems.SKU = rh.SKU
AND ( rh.lastUpdate = AllItems.MinUpdate
OR rh.lastUpdate = AllItems.MaxUpdate )
group by
AllItems.ItemNumber,
AllItems.SKU
Per another answer where you were only looking to IGNORE items within the most recent 14 days, you can just add a WHERE clause to the inner query similar via
WHERE r.LastUpdate >= CURDATE() - INTERVAL 14 DAY
If your history table has an auto-incrementing ID column, AND the respective transactions have the lastUpdate sequentially stamped, such as when they are added and not modified by any other operation, then you could just apply similar but MIN/MAX of the ID column, then join back TWICE on the ID and just each row ONCE such as...
SELECT
AllItems.ItemNumber,
AllItems.SKU,
rhMin.LastUpdate as MinUpdate,
rhMin.QuantitySold as MinSold,
rhMax.LastUpdate as MaxUpdate,
rhMax.QuantitySold as MaxSold
from
( SELECT
r.ItemNumber,
r.SKU,
MIN( r.AutoIncrementColumn ) as MinAutoID,
MAX( r.AutoIncrementColumn ) as MaxAutoID
FROM
ebx_r_history r
group by
r.ItemNumber,
r.SKU ) AllItems
JOIN ebx_r_history rhMin
ON AllItems.MinAutoID = rhMin.AutoIncrementColumn
JOIN ebx_r_history rhMax
ON AllItems.MaxAutoID = rhMax.AutoIncrementColumn
order by
rhMax.LastUpdated
Try something like this:
SELECT r1.ItemNumber,
(
SELECT r.QuantitySold
FROM ebx_r_history r
WHERE r1.ItemNumber = r.ItemNumber
AND r1.SKU = r.SKU
ORDER BY r.LastUpdate ASC LIMIT 1
) AS earliestDateQty,
(
SELECT r.QuantitySold
FROM ebx_r_history r
WHERE r1.ItemNumber = r.ItemNumber
AND r1.SKU = r.SKU
ORDER BY r.LastUpdate DESC LIMIT 1
) AS latestDateQty
FROM ebx_r_history r1
GROUP BY r1.ItemNumber,r1.SKU
ORDER BY 3
You had a couple of errors. you were getting two columns inside the inner selects, and you had a couple of places where you might get the error for ambiguous column name.
sqlFiddle here
SELECT T1.ItemNumber,
T1.SKU,
T1.Old_QuantitySold,
T1.Old_LastUpdate,
T2.New_QuantitySold,
T2.New_LastUpdate
FROM
(SELECT itemNumber,SKU,QuantitySold as Old_QuantitySold,LastUpdate as Old_LastUpdate
FROM ebx_r_history r
WHERE NOT EXISTS (SELECT 1 FROM ebx_r_history e
WHERE e.itemNumber = r.itemNumber AND e.SKU = r.SKU
AND e.LastUpdate < r.LastUpdate)
)T1
LEFT JOIN
(SELECT itemNumber,SKU,QuantitySold as New_QuantitySold,LastUpdate as New_LastUpdate
FROM ebx_r_history r
WHERE NOT EXISTS (SELECT 1 FROM ebx_r_history e
WHERE e.itemNumber = r.itemNumber AND e.SKU = r.SKU
AND e.LastUpdate > r.LastUpdate)
)T2 ON (T2.itemNumber = T1.itemNumber AND T2.SKU = T1.SKU)
WHERE T1.Old_LastUpdate >= CURDATE() - INTERVAL 14 DAY
AND T2.New_LastUpdate >= CURDATE() - INTERVAL 14 DAY
ORDER BY T2.New_LastUpdate;
you can do left join or inner join it's up to you, since T1 will always get earliest records and T2 will always get latest records for the ItemNumber,SKU grouping.
UPDATED TO IGNORE DATA OLDER THAN 14 DAYS
SELECT T1.ItemNumber,
T1.SKU,
T1.Old_QuantitySold,
T1.Old_LastUpdate,
T2.New_QuantitySold,
T2.New_LastUpdate
FROM
(SELECT itemNumber,SKU,QuantitySold as Old_QuantitySold,LastUpdate as Old_LastUpdate
FROM ebx_r_history r
WHERE LastUpdate >= CURDATE() - INTERVAL 14 DAY
AND NOT EXISTS (SELECT 1 FROM ebx_r_history e
WHERE e.itemNumber = r.itemNumber AND e.SKU = r.SKU
AND e.LastUpdate >= CURDATE() - INTERVAL 14 DAY
AND e.LastUpdate < r.LastUpdate)
)T1
LEFT JOIN
(SELECT itemNumber,SKU,QuantitySold as New_QuantitySold,LastUpdate as New_LastUpdate
FROM ebx_r_history r
WHERE LastUpdate >= CURDATE() - INTERVAL 14 DAY
AND NOT EXISTS (SELECT 1 FROM ebx_r_history e
WHERE e.itemNumber = r.itemNumber AND e.SKU = r.SKU
AND e.LastUpdate >= CURDATE() - INTERVAL 14 DAY
AND e.LastUpdate > r.LastUpdate)
)T2 ON (T2.itemNumber = T1.itemNumber AND T2.SKU = T1.SKU)
ORDER BY T2.New_LastUpdate;
ignore data older than 14 days sqlFiddle here
If you want to use exact time (14 days ago), you can replace occurences of CURDATE() with NOW()
I have a MySQL table with the structure:
beverages_log(id, users_id, beverages_id, timestamp)
I'm trying to compute the maximum streak of consecutive days during which a user (with id 1) logs a beverage (with id 1) at least 5 times each day. I'm pretty sure that this can be done using views as follows:
CREATE or REPLACE VIEW daycounts AS
SELECT count(*) AS n, DATE(timestamp) AS d FROM beverages_log
WHERE users_id = '1' AND beverages_id = 1 GROUP BY d;
CREATE or REPLACE VIEW t AS SELECT * FROM daycounts WHERE n >= 5;
SELECT MAX(streak) AS current FROM ( SELECT DATEDIFF(MIN(c.d), a.d)+1 AS streak
FROM t AS a LEFT JOIN t AS b ON a.d = ADDDATE(b.d,1)
LEFT JOIN t AS c ON a.d <= c.d
LEFT JOIN t AS d ON c.d = ADDDATE(d.d,-1)
WHERE b.d IS NULL AND c.d IS NOT NULL AND d.d IS NULL GROUP BY a.d) allstreaks;
However, repeatedly creating views for different users every time I run this check seems pretty inefficient. Is there a way in MySQL to perform this computation in a single query, without creating views or repeatedly calling the same subqueries a bunch of times?
This solution seems to perform quite well as long as there is a composite index on users_id and beverages_id -
SELECT *
FROM (
SELECT t.*, IF(#prev + INTERVAL 1 DAY = t.d, #c := #c + 1, #c := 1) AS streak, #prev := t.d
FROM (
SELECT DATE(timestamp) AS d, COUNT(*) AS n
FROM beverages_log
WHERE users_id = 1
AND beverages_id = 1
GROUP BY DATE(timestamp)
HAVING COUNT(*) >= 5
) AS t
INNER JOIN (SELECT #prev := NULL, #c := 1) AS vars
) AS t
ORDER BY streak DESC LIMIT 1;
Why not include user_id in they daycounts view and group by user_id and date.
Also include user_id in view t.
Then when you are queering against t add the user_id to the where clause.
Then you don't have to recreate your views for every single user you just need to remember to include in your where clause.
That's a little tricky. I'd start with a view to summarize events by day:
CREATE VIEW BView AS
SELECT UserID, BevID, CAST(EventDateTime AS DATE) AS EventDate, COUNT(*) AS NumEvents
FROM beverages_log
GROUP BY UserID, BevID, CAST(EventDateTime AS DATE)
I'd then use a Dates table (just a table with one row per day; very handy to have) to examine all possible date ranges and throw out any with a gap. This will probably be slow as hell, but it's a start:
SELECT
UserID, BevID, MAX(StreakLength) AS StreakLength
FROM
(
SELECT
B1.UserID, B1.BevID, B1.EventDate AS StreakStart, DATEDIFF(DD, StartDate.Date, EndDate.Date) AS StreakLength
FROM
BView AS B1
INNER JOIN Dates AS StartDate ON B1.EventDate = StartDate.Date
INNER JOIN Dates AS EndDate ON EndDate.Date > StartDate.Date
WHERE
B1.NumEvents >= 5
-- Exclude this potential streak if there's a day with no activity
AND NOT EXISTS (SELECT * FROM Dates AS MissedDay WHERE MissedDay.Date > StartDate.Date AND MissedDay.Date <= EndDate.Date AND NOT EXISTS (SELECT * FROM BView AS B2 WHERE B1.UserID = B2.UserID AND B1.BevID = B2.BevID AND MissedDay.Date = B2.EventDate))
-- Exclude this potential streak if there's a day with less than five events
AND NOT EXISTS (SELECT * FROM BView AS B2 WHERE B1.UserID = B2.UserID AND B1.BevID = B2.BevID AND B2.EventDate > StartDate.Date AND B2.EventDate <= EndDate.Date AND B2.NumEvents < 5)
) AS X
GROUP BY
UserID, BevID
I need to select how many days since there is a break in my data. It's easier to show:
Table format:
id (autoincrement), user_id (int), start (datetime), end (datetime)
Example data (times left out as only need days):
1, 5, 2011-12-18, 2011-12-18
2, 5, 2011-12-17, 2011-12-17
3, 5, 2011-12-16, 2011-12-16
4, 5, 2011-12-13, 2011-12-13
As you can see there would be a break between 2011-12-13 and 2011-12-16. Now, I need to be able say:
Using the date 2011-12-18, how many days are there until a break:
2011-12-18: Lowest sequential date = 2011-12-16: Total consecutive days: 3
Probably: DATE_DIFF(2011-12-18, 2011-12-16)
So my problem is, how can I select that 2011-12-16 is the lowest sequential date? Remembering that data applies for particular user_id's.
It's kinda like the example here: http://www.artfulsoftware.com/infotree/queries.php#72 but in the reverse.
I'd like this done in SQL only, no php code
Thanks
SELECT qmin.start, qmax.end, DATE_DIFF( qmax.end, qmin.start ) FROM table AS qmin
LEFT JOIN (
SELECT end FROM table AS t1
LEFT JOIN table AS t2 ON
t2.start > t1.end AND
t2.start < DATE_ADD( t1.end, 1 DAY )
WHERE t1.end >= '2011-12-18' AND t2.start IS NULL
ORDER BY end ASC LIMIT 1
) AS qmax
LEFT JOIN table AS t2 ON
t2.end < qmin.start AND
t2.end > DATE_DIFF( qmin.start, 1 DAY )
WHERE qmin.start <= '2011-12-18' AND t2.start IS NULL
ORDER BY end DESC LIMIT 1
This should work - left joins selects one date which can be in sequence, so max can be fineded out if you take the nearest record without sequential record ( t2.anyfield is null ) , same thing we do with minimal date.
If you can calculate days between in script - do it using unions ( eg 1. row - minimal, 2. row maximal )
Check this,
SELECT DATEDIFF((SELECT MAX(`start`) FROM testtbl WHERE `user_id`=1),
(select a.`start` from testtbl as a
left outer join testtbl as b on a.user_id = b.user_id
AND a.`start` = b.`start` + INTERVAL 1 DAY
where a.user_id=1 AND b.`start` is null
ORDER BY a.`start` desc LIMIT 1))
DATEDIFF() show difference of the Two days, if you want to number of consecutive days add one for that result.
If it's not a beauty contents then you may try something like:
select t.start, t2.start, datediff(t2.start, t.start) + 1 as consecutive_days
from tab t
join tab t2 on t2.start = (select min(start) from (
select c1.*, case when c2.id is null then 1 else 0 end as gap
from tab c1
left join tab c2 on c1.start = adddate(c2.start, -1)
) t4 where t4.start <= t.start and t4.start >= (select max(start) from (
select c1.*, case when c2.id is null then 1 else 0 end as gap
from tab c1
left join tab c2 on c1.start = adddate(c2.start, -1)
) t3 where t3.start <= t.start and t3.gap = 1))
where t.start = '2011-12-18'
Result should be:
start start consecutive_days
2011-12-18 2011-12-16 3