Inner Selection, Sum of colunms with conditions order by Region - mysql

Question

After selection I get my new clear table like
SELECT a.sta_name, a.product, a.product_id, a.date, a.active, a.region_id, a.brand, a.brand_id from
(SELECT DISTINCT sta_name, product, product_id, date, active, region_id, brand, brand_id FROM `sv_ziyaret`
WHERE brand_id=2 and date between "2021-07-00" and "2021-07-31" order by region_id) a
so I get my values DISTINCT
sta_name | product | product_id | active | region_id | brand | brand_id| date |
3M A 1 1 1 A1 1 2021-07-02
2M A 1 0 1 A1 1 2021-07-02
5M B 2 0 1 A1 1 2021-07-05
4M B 2 0 2 A1 1 2021-07-06
M A 2 1 2 A1 1 2021-07-10
2M C 3 1 4 A1 1 2021-07-12
3M B 2 1 4 A1 1 2021-07-15
sta_name never repeats with same region_id, products do. What I try to get is
product_id | product | active_on | active_off | region_id
1 A 12 2 1
1 A 7 9 2
2 B 6 10 1
2 B 16 5 2
3 C 10 5 4
My main purpose is to be able to calculate percentage of product's existance in each region. In instance A product has %80 on sale on shalves at region A.
Manualy I am able to get each products result as
SELECT
product, product_id, region_id,
SUM(CASE WHEN sv_ziyaret.active = 1 THEN 1 ELSE 0 END) var,
SUM(CASE WHEN sv_ziyaret.active = 0 THEN 1 ELSE 0 END) yok
FROM
`sv_ziyaret`
WHERE
product_id=37 and date between "2021-07-00" and "2021-07-31" and region_id=7 order by region_id
but this is not a good solution I need it to be able to get each product by giving its brand_id only.
Hope to get a hand realy would same my weak

Answer 1

You are very close to the general solution. You just need GROUP BY AND LAST_DAY().
SELECT
product, product_id, region_id, LAST_DAY(date) month_ending,
SUM(CASE WHEN sv_ziyaret.active = 1 THEN 1 ELSE 0 END) var,
SUM(CASE WHEN sv_ziyaret.active = 0 THEN 1 ELSE 0 END) yok
FROM
sv_ziyaret
WHERE
GROUP BY product, product_id, region_id, LAST_DAY(date)
ORDER BY region_id, LAST_DAY(date), product_id;