as a result of the execution of this query, situations are possible when two rows have the same minimum price, but i still need to select one. I understand perfectly well that the standard limit cannot be dispensed with here. I do not have enough knowledge to understand from which side to approach the solution of this issue. Thank you in advance for your attension.
UPDATE offers t1
SET t1.deleted_at = NOW()
WHERE t1.id
NOT IN
(
SELECT f.id
FROM (
SELECT name, MIN(net_price) as minprice
FROM offers
WHERE
supplier_id = (SELECT id FROM suppliers WHERE name = 'somename')
group BY name
)
AS x inner join (SELECT * FROM offers) AS f ON f.name = x.name AND f.net_price = x.minprice
)
AND
t1.supplier_id = (SELECT id FROM suppliers WHERE name = 'somename');
I don't know somehowe, but this works for me:
UPDATE offers t1
SET t1.deleted_at = NOW()
WHERE t1.id
NOT IN
(
SELECT f.id
FROM (
SELECT id, name, MIN(net_price) as minprice
FROM offers
WHERE
supplier_id = (SELECT id FROM suppliers WHERE name = 'somename')
group BY name
)
AS x inner join (SELECT * FROM offers) AS f ON f.id = x.id
)
AND
t1.supplier_id = (SELECT id FROM suppliers WHERE name = 'somename');
Just add id to subquery select and put it on inner join f.id = x.id
Related
[DB Table]
SELECT b.first_name, b.last_name, a.pod_name, a.category, c.user_id,
SUM(IF(QUARTER(CURDATE())-1 OR (QUARTER(CURDATE())-2) AND a.user_id, 1, 0)) AS flag FROM kudos a
INNER JOIN users b ON a.user_id = b.id INNER JOIN users_groups c ON a.user_id = c.user_id
INNER JOIN groups d ON c.group_id = d.id WHERE a.group_name = 'G2' AND d.id IN (7,8,9,11,12,13,14,15,16,17,21,22,23,24,25,26,27,28)
AND QUARTER(CURDATE())-1 = a.quarter ORDER BY a.final_score+0 DESC
I need to get the user_ids of those users which are both in quarter 1 and 2 from table.
Tried above query but failed to get expected results.
Can someone please guide me on this?
if you only need user_id then you can do this :
select user_id
from tablename
where quarter in (1,2)
group by user_id
having count(distinct quarter) = 2
another way is to use window function, assuming you have one user id in each quarter:
select * from (
select * , count(*) over (partition by user_id) cn
from tablename
where quarter in (1,2)
) t where cn = 2
SELECT p.ID, Name
FROM Policies p
INNER JOIN ProgramYears py ON p.ProgramYearID = py.id
INNER JOIN (SELECT MemberID, max(EffectiveDate) AS EffectiveDate
FROM Policies
GROUP BY MemberID) TEMP
ON p.memberid = TEMP.MemberID
AND p.EffectiveDate = TEMP.effectivedate
AND p.memberid NOT IN (SELECT MemberID
FROM InvoiceDetail
WHERE ProgramYear = NAME)
NOT EXISTS is usually a better substitute for NOT IN, but your choices largely depend on the data and the structure of your tables and indexes.
Try the query below, but compare its execution plan to that of your current query; what works for one scenario may not work for another.
SELECT p.ID, Name
FROM Policies p
INNER JOIN ProgramYears py ON p.ProgramYearID = py.id
INNER JOIN (SELECT MemberID, max(EffectiveDate) AS EffectiveDate
FROM Policies
GROUP BY MemberID) TEMP
ON p.memberid = TEMP.MemberID
AND p.EffectiveDate = TEMP.effectivedate
WHERE NOT EXISTS
(SELECT MemberID
FROM InvoiceDetail AS ID
WHERE ID.ProgramYear = NAME
AND p.MemberId = ID.MemberId)
You can try:
SELECT a.ID, a.Name
FROM (SELECT p.ID, Name,
ROW_NUMBER()OVER(PARTITION BY p.memberid ORDER BY p.EffectiveDate DESC) AS rnk
FROM Policies p
INNER JOIN ProgramYears py ON p.ProgramYearID = py.id
WHERE NOT EXISTS (SELECT MemberID
FROM InvoiceDetail AS ID
WHERE ID.ProgramYear = NAME
AND p.MemberId = ID.MemberId)
) a
WHERE a.rnk = 1
I'm breaking my head trying to modify this query(thx sgeddes) in order to
get at result not only from db_events.events fields, instead join it with some db_system.devices fields
SELECT e.*
FROM db_events.events e
JOIN (
SELECT Max(id) MaxId, device_id
FROM db_events.events
GROUP BY device_id ) e2 on e.Id = e2.MaxId AND e.device_id = e2.device_id
WHERE e.device_id IN (
SELECT device_id
FROM db_system.devices
WHERE vendor = 1)
ORDER BY e.id DESC
How can I get it without repeat the subquery:
SELECT *
FROM db_system.devices
WHERE vendor = 1
I need get db_system.devices.brand and db_system.devices.model joined with final results, and
I tried to modify it step to step, I tried with temporary tables, I suspect it should be something simple, but I have not been able to do it, of course thank you very much...
is this what you want?
SELECT e.*, a.*
FROM db_events.events e
INNER JOIN
(
SELECT Max(id) MaxId, device_id
FROM db_events.events
GROUP BY device_id
) e2 on e.Id = e2.MaxId AND
e.device_id = e2.device_id
INNER JOIN db_system.devices a
ON e.device_id = a.device_id AND
a.vendor = 1
ORDER BY e.id DESC
the condition a.vendor = 1 can also be moved on WHERE clause and the result is still the same since you are using INNER JOIN
SELECT ....
FROM .... JOIN ....
WHERE a.vendor = 1
ORDER BY ...
I want to do this query:
SELECT *
FROM user k
INNER JOIN (
SELECT id, tagName, b.guid, name, owner, publicKey
FROM noteTags a
INNER JOIN (
SELECT *
FROM note
ORDER BY guid
LIMIT 0 , 12
)b ON a.guid = b.guid ORDER BY b.id DESC
)l ON k.owner = l.owner
But I want it to return DISTINCT b.guids.
Structure of the tables:
note
|
|=id
|=name
|=guid
|=owner
|=publicKey
noteTags
|
|=guid
|=tagName
user
|
|=owner
|=username
|=auth
Basically I want to select ALL data (with the limit on the deeper inner join) and return DISTINCT guids
Thanks!
Here's my initial answer,
SELECT *
FROM note a
INNER JOIN user b
ON a.owner = b.owner
INNER JOIN notetags c
ON a.guid = b.guid
INNER JOIN
(
SELECT guid, MAX(tagName) maxTag
FROM notetags
GROUP BY guid
) d ON c.guid = d.guid AND
c.tagName = d.maxTag
How about:
SELECT *
FROM user k
INNER JOIN (
SELECT id, tagName, b.guid, name, owner, publicKey
FROM noteTags a
INNER JOIN (
select id, name, MIN(guid) as guid, owner, publicKey
FROM note
GROUP BY guid
LIMIT 0 , 12
)b ON a.guid = b.guid ORDER BY b.id DESC
)l ON k.owner = l.owner
I'm working with a mysql query that is supposed to select all messages addressed or sent by the user. I need to group all messages with same UID so that I show a single thread for each differente user (this means it should eliminate all messages except the last with same UID). My problem is that I started using GROUP BY to do it but sometimes the row that remains is actually the older message instead of the latest.
This is what I was trying:
SELECT `UID`, `Name`, `Text`, `A`.`Date`
FROM `Users`
INNER JOIN (
(
SELECT *, To_UID AS UID FROM `Messages` WHERE `From_UID` = '$userID' AND `To_UID` != '$userID'
)
UNION ALL
(
SELECT *, From_UID AS UID FROM `Messages` WHERE `To_UID` = '$userID' AND `From_UID` != '$userID'
)
) AS A
ON A.UID = Users.ID
GROUP BY UID // This doesn't work
How can I show only the row with the most resent date per UID?
use DISTINCT and only use ORDER BY date
GROUP BY actually sometimes displays a random row, which isn't always commonly discussed.
you can try some thing like this:
select UID, Name, Text, c.date
from User
inner join (
select if(b.From_UID = '$userID', b.To_UID, b.From_UID) as UID,
*
from Messages as b
inner join(
select if(c.From_UID = '$userID', c.To_UID, c.From_UID) as UID,
max(c.date) as date
from Messages as c
where c.From_UID = '$userID' or c.To_UID = '$userID'
group by UID
) as d on d.date = b.date and d.UID = b.UID
) as e on e.UID = Users.id
)
or create a temp table / stored procedure to make life easier
Temp table
create temp table t
select if(From_UID = '$userID', To_UID, From_UID) as UID, * from Messages
select UID, Name, Text, date
from User
inner join (
select *
from t as t1
inner join(
select
t2.UID,
max(t2.date) as date
from t as t2
group by t2.UID
) as t3 on t3.date = t1.date and t3.UID = t1.UID
) as e on e.UID = Users.id