Express js - how to remove certain field from response - mysql

Question

In my current login api, it returns
"user": {
"id": "3e85decc-2af4-436c-8b7f-e276771234f5",
"email": "cccc#cccc.com",
"password": "$xxxxxxxxxx",
"createdAt": "2021-05-14T08:48:31.000Z",
"updatedAt": "2021-05-14T08:48:31.000Z"
},
"token": "xxxxx"
}
I want to remove the password field in my response, so I use delete user.password in my code, but it's not working
/api/users.js
router.post('/login', (req, res, next) => {
passport.authenticate('local', {session: false}, (err, user, info) =>{
if (err || !user) {...}
req.login(user, {session: false}, (err) => {
if (err) {
res.send(err);
}
const token = jwt.sign(user, 'your_jwt_secret');
console.log(user) // show dataValues and _previousDataValues instead of normal JSON object
delete user.password // not working
return res.json({user, token});
});
})(req, res);
});
I tried to log user object for above file, it returns:
users {
dataValues: {
id: '3e85decc-2af4-436c-8b7f-e276771234f5',
email: 'cccc#cccc.com',
password: '$xxxxxxxxxx',
createdAt: 2021-05-14T08:48:31.000Z,
updatedAt: 2021-05-14T08:48:31.000Z
},
_previousDataValues: {
id: '3e85decc-2af4-436c-8b7f-e276771234f5',
email: 'cccc#cccc.com',
password: '$xxxxxxxxxx',
createdAt: 2021-05-14T08:48:31.000Z,
updatedAt: 2021-05-14T08:48:31.000Z
},
_changed: Set(0) {},
_options: {
isNewRecord: false,
_schema: null,
_schemaDelimiter: '',
raw: true,
attributes: [ 'id', 'email', 'password', 'createdAt', 'updatedAt' ]
},
isNewRecord: false
}
This is my user model. I am using Sequelize.
const Sequelize = require('sequelize');
const DataTypes = Sequelize.DataTypes;
const db = require('../sequelize')
let users = db.define('users', {
id: {
type: DataTypes.UUID,
defaultValue: DataTypes.UUIDV4,
allowNull: false,
primaryKey: true
},
email: {
type: DataTypes.STRING,
allowNull: false,
unique: 'email'
},
password: {
type: DataTypes.STRING,
},
},
{
hooks: {
beforeCount(options) {
options.raw = false;
}
}
}
);
module.exports = users;

Answer 1

Finally solved it using user.get({plain: true})
let plainUser = user.get({plain: true})
delete plainUser['password']
return res.json({user, token});

Answer 2

It's probably not a good idea to delete properties from the Model directly. Try using ToJSON() to convert the Model to a plain Javascript object and delete the password from that.
plainUser = user.ToJSON();
delete plainUser.password

Answer 3

why dont you re-create your result response, something like this:
let response = {
"user": {
"id": user.dataValues.id,
"email": user.dataValues.email,
"createdAt": user.dataValues.createdAt,
"updatedAt": user.dataValues.updatedAt
},
"token": "xxxxx"
}
JSON.stringify(response)

Answer 4

Try below code in your model to override the sequelize toJSON function
const User = db.define('users', {
id: {
type: DataTypes.UUID,
defaultValue: DataTypes.UUIDV4,
allowNull: false,
primaryKey: true
},
email: {
type: DataTypes.STRING,
allowNull: false,
unique: 'email'
},
password: {
type: DataTypes.STRING,
},
},
{
hooks: {
beforeCount(options) {
options.raw = false;
}
}
}
);
User.prototype.toJSON = function () {
const values = Object.assign({}, this.get());
delete values.password;
return values;
};
or using omit() withlodash for cleaner code
User.prototype.toJSON = function () {
const values = {
..._.omit(this.get(), ['password'])
};
return values;
};