I have a database of Time Entries which stores userID, roundedHours, dateSpent, and taskID for each entry (these are daily timecards). I am trying to create one query that will output sums of roundedHours grouped by userID where the taskID meets a specific value between specified dates.
The code I've attempted is below. I need it to be output and grouped by userID but instead, my output is the total sum for both overhead_admin and total_hours (same on each row) and not specific to the userID.
SELECT userName, userID,
(SELECT sum(roundedHours)
FROM `db`.`TimeEntries`
WHERE taskId = 3050483 AND (spendDate BETWEEN '2020-11-02' AND '2020-11-08')) as overhead_admin,
(SELECT sum(roundedHours)
FROM `db`.`TimeEntries`
WHERE (spendDate BETWEEN '2020-11-02' AND '2020-11-08')) as total_hours
FROM `db`.`TimeEntries`
GROUP BY userID
Can anyone help me so that each row will have the total SPECIFIC to that user and NOT summed as a whole? The output I'm getting that is wrong is shown in the image below:
Use conditional aggregation:
SELECT userName, userID,
sum(case when taskId = 3050483 AND (spendDate BETWEEN '2020-11-02' AND '2020-11-08' then roundedHours end) as overhead_admin,
sum(case when spendDate BETWEEN '2020-11-02' AND '2020-11-08' then roundedHours end) as total_hours
FROM `db`.`TimeEntries`
GROUP BY userID
Related
i have One transaction table ( "TableA" ), In TableA have those fields app_id, user_id, points, tr_type, description. so in the transaction have added and subtract tr_type is there. now I want to get total_points (points = added-subtract) of the user_id based on tr_type. For that how I need to write MySQL query>
For type is either add or sub.
So now I want GroupBY of those 3 fields --> app_id, user_id, points
I suspect you want conditional aggregation:
select user_id,
sum(case when tr_type = 'add' then points
when tr_type = 'sub' then - points
end)
from t
group by user_id;
I have my table
I want to get duplicates from the Name and Status column, count them, and sum values from the Sum column. I want to look like this:
I am new to SQL so that it may be an easy answer, but I can't seem to find a solution.
This is how far I got, but I can't seem to get the count and sum without errors.
SELECT name, COUNT(*) AS recovered
FROM complaints
WHERE status = "Recovered"
GROUP BY name
HAVING COUNT(name) > 0
myQuery
You can do conditional aggregation:
select
name,
sum(status = 'Recovered') recovered,
sum(status = 'Unrecovered') unrecovered,
sum(case when status = 'Recovered' then `sum` end) total_recovered_value,
sum(case when status = 'Unrecovered' then `sum` end) total_unrecovered_value
from mytable
group by name
order by name
Side note: sum is a language keyword, hence not a good choice for a column name.
My database table contains value in this way
IMAGE FOR TABLE DATA
I want to track down same email which has been used more than one times for a particular month and year.
In the above scenario, email that has been repeated multiple times was sandeshphuya#gmail.com, jes#gmail.com and ramu#gmail.com for different months. I want to track down customer repetition following their email for each month and year.
The query that I am using right now is
SELECT DATE_FORMAT(booked_on, '%Y-%m') as monthYear, email,
COUNT(*) AS 'Count'
FROM 'tablename'
GROUP BY email,DATE_FORMAT(booked_on, '%Y-%m') HAVING COUNT(*) > 1 ORDER BY `booked_on`;
GROUP BY email was used as it generates the repeated email and GROUP BY DATE_FORMAT(booked_on, '%Y'-%m') was used to track down total email repeated for each month/year.
This prints out data as
IMAGE FOR SELECT QUERY
How can I track down total repeated email following month and year? The expected result is
RESULT EXPECTED
You can use your query as a subquery for a new group by:
select sub.monthYear,count(*)
from
(SELECT DATE_FORMAT(booked_on, '%Y-%m') as monthYear,
email,
COUNT(*) AS 'Count'
FROM 'tablename'
GROUP BY email,DATE_FORMAT(booked_on, '%Y-%m')
HAVING COUNT(*) > 1
ORDER BY `booked_on`) as sub
GROUP BY sub.monthYear
My data:
How can I get there? I tried to make a MySQL view on my table TAX.
CREATE VIEW TaxSplitPerOrder AS
SELECT
OrderNumber, tax_invoiced, total_invoiced, created_at, tax_percent, SUM(tax_invoiced_order_item)
FROM
test
GROUP by OrderNumber;
Can anyone help me?
You need to include all of the other non-summarized columns from your SELECT in the GROUP BY clause. You may want to sum total_invoiced too or else you will still have 2 rows for each order number.
The query:
SELECT OrderNumber, tax_invoiced, total_invoiced, created_at,
MAX(CASE WHEN tax_percent = 21 THEN tax_invoiced_order_item END) tax_21,
MAX(CASE WHEN tax_percent = 6 THEN tax_invoiced_order_item END) tax_6
FROM test
GROUP BY OrderNumber;
I have a table, and I want to get the DISTINCT count of usernames over a certain period of time. Currently I'm running this query
SELECT DISTINCT username FROM user_activity WHERE company_id = 9 AND timestamp BETWEEN '2015-09-00' AND '2015-10-01' AND action = "Login Success";
It works great, however, I have multiple Companies that I want to select the count for. How do I expand the previous query to show me the distinct counts for multiple companies?
select count(distinct username),
sum(case when company_id = 1 then 1 else 0 end) A,
sum(case when company_id = 9 then 1 else 0 end) B
from `user_activity` Where timestamp BETWEEN '2015-09-00' AND '2015-10-01' AND action = "Login Success"
I've done something like this, however, I'm not getting the correct numbers. Ideally I would like to list each count as a different value for ease of reading, like the previous query illustrates. I don't need the count(distinct username) column to appear in my result, just the conditionals.
Thanks in advance.
If you don't mind two rows instead of two columns:
SELECT company_id, COUNT(DISTINCT username)
FROM user_activity
WHERE company_id IN (1,9)
AND timestamp >= '2015-09-01'
AND timestamp < '2015-09-01' + INTERVAL 1 MONTH
AND action = "Login Success"
GROUP BY company_id