I have a table, and I want to get the DISTINCT count of usernames over a certain period of time. Currently I'm running this query
SELECT DISTINCT username FROM user_activity WHERE company_id = 9 AND timestamp BETWEEN '2015-09-00' AND '2015-10-01' AND action = "Login Success";
It works great, however, I have multiple Companies that I want to select the count for. How do I expand the previous query to show me the distinct counts for multiple companies?
select count(distinct username),
sum(case when company_id = 1 then 1 else 0 end) A,
sum(case when company_id = 9 then 1 else 0 end) B
from `user_activity` Where timestamp BETWEEN '2015-09-00' AND '2015-10-01' AND action = "Login Success"
I've done something like this, however, I'm not getting the correct numbers. Ideally I would like to list each count as a different value for ease of reading, like the previous query illustrates. I don't need the count(distinct username) column to appear in my result, just the conditionals.
Thanks in advance.
If you don't mind two rows instead of two columns:
SELECT company_id, COUNT(DISTINCT username)
FROM user_activity
WHERE company_id IN (1,9)
AND timestamp >= '2015-09-01'
AND timestamp < '2015-09-01' + INTERVAL 1 MONTH
AND action = "Login Success"
GROUP BY company_id
Related
need help
I have a table:
user | visit |....
user = 1,2,3,4
visit = 1,2,3,4
QUERY will work, but i want to agragate fields in MYSQL
SELECT COUNT(visit) as c, t.visit, t.user FROM t GROUP BY t.visit, t.user
I need return GROUP BY user fields without duplicate rows in filed user:
t.user, COUNT (t.visit where t.visit=1), COUNT( all t.visit)
user = 1 | visit1 = 10|. visit total = 100
......
To conditionally count a column, count the result of a CASE expression...
SELECT
t.user,
COUNT(CASE WHEN t.visit = 1 THEN 1 END) AS visit_1,
COUNT(*) AS visit_total
FROM
t
GROUP BY
t.user
Notes:
if a CASE expression doesn't have an ELSE clause, it defaults to ELSE NULL.
COUNT() only counts values that are NOT NULL.
I'm having trouble finding the most efficient way of retrieving various different sumed values from a Mysql table.
Let's say I've got 4 columns - userid, amount, paid, referral.
I'd like to retrieve the following based on a user id:
1 - the sum of amount that is paid (marked as 1)
2 - the sum of amount that is unpaid (marked as 0)
3 - the sum of amount that is paid and referral (marked as 1 on both paid and referral columns)
4 - the sum of amount that unpaid and referral (marked as 0 on paid and 1 on referral columns)
I've tried an embedded select statement like this:
SELECT (
SELECT sum(payout)
FROM table1
WHERE ispaid = 0 and userid = '100'
) AS unpaid
(
SELECT sum(payout)
FROM table1
WHERE ispaid = 1 and userid = '100'
) AS paid,
(
SELECT sum(payout)
FROM table1
WHERE ispaid = 0 and isreferral = 1 and userid = '100'
) AS refpending,
(
SELECT sum(payout)
FROM table1
WHERE ispaid = 1 and isreferral = 1 and userid = '100'
) AS refpaid
This works, but its slow (or at least feels like it could be quicker) on my server, around 1.5 seconds.
I'm sure there is a better way of doing this with a group statement but can't get my head around it!
Any help is much appreciated.
Thanks
You can use conditional expressions inside SUM():
SELECT
SUM(CASE WHEN ispaid=0 THEN payout END) AS unpaid,
SUM(CASE WHEN ispaid=1 THEN payout END) AS paid,
SUM(CASE WHEN ispaid=0 AND isreferral=1 THEN payout END) AS refpending,
SUM(CASE WHEN ispaid=0 AND isreferral=1 THEN payout END) AS refpaid
FROM table1
WHERE userid = '100'
If a given row is not matched by any CASE...WHEN clause, then the value of the expression is NULL, and SUM() ignores NULLs. You could also have an ELSE 0 clause in there if you want to be more explicit, since SUM() will not be increased by a 0.
Also make sure you have an index on userid in this table to select only the rows you need.
I have a database of Time Entries which stores userID, roundedHours, dateSpent, and taskID for each entry (these are daily timecards). I am trying to create one query that will output sums of roundedHours grouped by userID where the taskID meets a specific value between specified dates.
The code I've attempted is below. I need it to be output and grouped by userID but instead, my output is the total sum for both overhead_admin and total_hours (same on each row) and not specific to the userID.
SELECT userName, userID,
(SELECT sum(roundedHours)
FROM `db`.`TimeEntries`
WHERE taskId = 3050483 AND (spendDate BETWEEN '2020-11-02' AND '2020-11-08')) as overhead_admin,
(SELECT sum(roundedHours)
FROM `db`.`TimeEntries`
WHERE (spendDate BETWEEN '2020-11-02' AND '2020-11-08')) as total_hours
FROM `db`.`TimeEntries`
GROUP BY userID
Can anyone help me so that each row will have the total SPECIFIC to that user and NOT summed as a whole? The output I'm getting that is wrong is shown in the image below:
Use conditional aggregation:
SELECT userName, userID,
sum(case when taskId = 3050483 AND (spendDate BETWEEN '2020-11-02' AND '2020-11-08' then roundedHours end) as overhead_admin,
sum(case when spendDate BETWEEN '2020-11-02' AND '2020-11-08' then roundedHours end) as total_hours
FROM `db`.`TimeEntries`
GROUP BY userID
I have my table
I want to get duplicates from the Name and Status column, count them, and sum values from the Sum column. I want to look like this:
I am new to SQL so that it may be an easy answer, but I can't seem to find a solution.
This is how far I got, but I can't seem to get the count and sum without errors.
SELECT name, COUNT(*) AS recovered
FROM complaints
WHERE status = "Recovered"
GROUP BY name
HAVING COUNT(name) > 0
myQuery
You can do conditional aggregation:
select
name,
sum(status = 'Recovered') recovered,
sum(status = 'Unrecovered') unrecovered,
sum(case when status = 'Recovered' then `sum` end) total_recovered_value,
sum(case when status = 'Unrecovered' then `sum` end) total_unrecovered_value
from mytable
group by name
order by name
Side note: sum is a language keyword, hence not a good choice for a column name.
I'm trying to write a query to count the customers that purchased at least one from order_type=0 and one order_type=1 during the same month in 2014
I have two tables.
The order table that have:
order_id
customer_id
aquisition_date
orders_category table:
order_id
order_type (the type of the orders it may have 0, 1, 2, 3, 5, 8 ...etc )
I tried with this query but it didn't work, I know it's not complete and I missed the month condition!
Select count(user_id) From order
join orders_category
on order.order_id = orders_category.order_id
Where (order_type=0 or order_type=1)
and extract (year from order.aquisition_date)=2014
group by user_id
having count (case when type_id=0 then null else null end) > 0
and count (case when type_id=1 then null else null end) > 0;
I don't know how to find users with at least 1 order from order_type=0 & 1 order of order_type=1, in the same month.
You could use this query, based on what you already had. However, I suggest you change the name of the table order to orders as order is a reserved word:
select count(distinct user_id)
from (
select user_id, month(aquisition_date)
from orders
inner join order_category
on orders.order_id = order_category.order_id
where order_type in (0, 1)
and year(aquisition_date) = 2014
group by user_id, month(aquisition_date)
having count(distinct order_type) = 2
) as base
SQL fiddle
I selected the month also in the sub-select, as it will be interesting to look at the output of that query on its own during your analysis.