Remove mismatch and add missing json jq - json

Question

Hi I have two file for example:
file1.json
{
"id": "001",
"name" : "my_policy",
"list_1": ["111111111", "22222222","33333333"],
"list_2": ["a", "b","c"],
.....
}
Then I have file2.json (not always has the same field as f1)
{
"list_1": ["111111111","111111122","33333333"],
"list_2": ["a", "b","c","d","e"],
.....
}
How I can via jq merge same keys values in the two file json and in addiction to the merge operation remove from file1 keys the values non present in file2 ?
So get this result:
{
"id": "001",
"policy" : "my_policy",
"list_1": ["111111111","111111122","33333333"],
"list_2": ["a", "b","c","d","e"],
.....
}
I solved the merge operation via:
jq -s 'reduce .[] as $item ({}; reduce ($item | keys_unsorted[]) as $key (.; $item[$key] as $val | ( $val | type) as $ type | .[$key] = if ( $type == "array") then (.[$key] + $val | unique) elif ($type == "object") then (.[$key] + $val) else $val end ))' file1.json f2.json
How I can solve? Or is impossible via jq?

Answer 1

It is quite simple once you figure out how to find the difference among two list items and add/unique them. One way would be to
jq --slurpfile s 2.json -f script.jq 1.json
Where my script contents are
#!/usr/bin/env jq -f
# backup list_1, list_2 from 1.json
.list_1 as $l1 |
.list_2 as $l2 |
# Perform the operation of removing file1 keys not present in 2.json
# for both list_1 and list_2
( ( $l1 - ( $l1 - $s[].list_1 ) ) + $s[].list_1 | unique ) as $f1 |
( ( $l2 - ( $l2 - $s[].list_2 ) ) + $s[].list_2 | unique ) as $f2 |
# Update the original result 1.json with the modified content
.list_1 |= $f1 |
.list_2 |= $f2
or directly from the command line as
jq --slurpfile s 2.json '
.list_1 as $l1 |
.list_2 as $l2 |
( ( $l1 - ( $l1 - $s[].list_1 ) ) + $s[].list_1 | unique ) as $f1 |
( ( $l2 - ( $l2 - $s[].list_2 ) ) + $s[].list_2 | unique ) as $f2 |
.list_1 |= $f1 |
.list_2 |= $f2
' 1.json