I have two ranges of equal size on different sheets in the same spreadsheet. I am trying to find a row (based off of user input) in the first sheet and then use that index to modify a table in the second sheet that counts how many times that certain index has been used before (to make a nice looking pie chart).
This code runs but will not produce results on the second sheet. I've gone through the debugging process and my best guess is that for some reason, my for in loop is not running through. Attached is my code that takes in the beforementioned index and attempts to perform the second half of my goal.
function acceptToEncounterChart(ghostrow) {
var ss = SpreadsheetApp.getActiveSpreadsheet();
SpreadsheetApp.setActiveSheet(ss.getSheets()[1]);
ss = SpreadsheetApp.getActiveSpreadsheet();
var sheet = ss.getSheetByName("Average Encounter Chart");
var range = sheet.getRange("B3:B14")
for(var i in range) {
if(ghostrow == i) {
var before = range[i][0].getValue()
range[i][0].setValue(before + 1);
}
}
SpreadsheetApp.setActiveSheet(ss.getSheets()[0]);
};
Explanation:
I am not entirely sure what is your goal.
However, here is some fixes / improvements starting from the beginning:
You define 2 times the same variable ss with exactly the same value.
You don't need to set the active sheet, if your goal is to just get the sheet, therefore this line is redundant:
SpreadsheetApp.setActiveSheet(ss.getSheets()[1]);
Variable range is not an array but a range object. You can't index it and therefore you can't also use a for loop to iterate over a single object. For the same exact reason, the code inside the if statement is wrong, you can't index range. But you don't see any errors because the if statement evaluates to false.
In JavaScript and in many other programming languages, array indexes start from 0. Since your range starts from cell B3 or row 3, you need to use i+3 to match the data with the range.
For the same reason as the previous point, ghostrow is an index, not a row. The if statement compares an array index i with ghostrow, so ghostrow should not be confused with the actual sheet row. For example, if you choose ghostrow=5 then the current script will increment the value of the cell B8 (remember i+3) by 1.
Solution:
Here is a workable code snippet:
function acceptToEncounterChart(ghostrow) {
var ss = SpreadsheetApp.getActiveSpreadsheet();
var sheet = ss.getSheetByName("Average Encounter Chart");
var data = sheet.getRange("B3:B14").getValues().flat();
data.forEach((v,i)=>{
if(ghostrow == i){
sheet.getRange(i+3,2).setValue(v+1)
}
});
ss.setActiveSheet(ss.getSheets()[0]);
}
Related:
Please explore the official google apps script documentation.
Related
I have a filter applied to a sheet. I want to return just the data from the filter and not the entire range of the sheet.
const sheet = SpreadsheetApp.openById(SHEET_ID).getSheetByName(SHEET_NAME)
const filter = sheet.getFilter();
// This returns the entire sheet's range rather than the filtered range.
const range = filter.getRange().getValues();
Based on the code above, why aren't I getting the desired behaviour according to docs from Google?
I had a similar issue with returning filtered values and realized it is the most convenient to make a code that will skip FilterCriteriaBuilder class with functions.
For that reason I developed a code on this link.
https://github.com/NikolaPlusEqual/GoogleAppsScriptFilters/blob/main/Functions
Simple example for using functions from the repository:
function example(){
var ss = SpreadsheetApp.getActiveSpreadsheet();
var ss1 = ss.getSheetByName("Sheet1");
var range = ss1.getRange(1,1,ss1.getLastRow(),5).getValues();
output = whenNumberGreaterThan(10, range, 3);
Logger.log(output);
}
whenNumberGreaterThan(number, rng, col) is the function from the repository, which will return all values from the rows in the range, that have satisfied "number greater than 10" criteria in the 3rd column of the range. The function is the alternative for FilterCriteriaBuilder Class function whenNumberGreaterThan(number) on this link.
Just copy entire Functions file code into you .gs file and call desired function.
You can get just the values the active filter displays by removing the values in the data that are in rows where isRowHiddenByFilter(rowPosition) returns true.
That said, using JavaScript's Array.filter() would offer much better performance than making multiple API calls to find which rows are hidden.
I've got a Google App Script which is copying rows from one sheet to another, performing various transformations. This logic ultimately gets rows onto the new sheet using sheet.appendRow(row detail). I would like these newly created rows to have a background colour (my intention is to hold a 'latestColour' so I can alternate the shading).
So, is there anyway to add shading within the appendRow method itself, or easily determine the range that the appendRow method processed, such that I can apply additional logic to add the shading.
You can use conditional formatting
=and(A1<>"",A2="")
Although I'm not sure whether I could correctly understand your situation, from your question, I thought that you might be using [Format] --> [Alternating colors] in Google Spreadsheet. And, when a new row is appended by putting the values, you might want to reflect "Alternating colors" in the appended row. If my guess is correct, how about the following sample script?
Sample script:
function myFunction() {
const addValues = ["sample1", "sample2", "sample3"]; // This is a sample appending value. Please replace this for your value.
const sheetName = "Sheet1"; // Please set the sheet name.
// Retrieve banding object from the data range.
const sheet = SpreadsheetApp.getActiveSpreadsheet().getSheetByName(sheetName);
const b = sheet.getDataRange().getBandings();
if (b.length == 0) {
console.log("Bandings are not used.");
return;
}
// Append the value.
sheet.appendRow(addValues);
// Expand the range of banding.
b[0].setRange(sheet.getDataRange());
}
When this script is run, the current banding is retrieved. And, after the value was appended, the banding is updated by including the appended row. In this sample, even when the multiple rows are appended, this script can be used.
Note:
From your question, I guessed that there is one banding in the data range in your sheet. Please be careful this.
References:
getBandings()
setRange(range)
Unfortunately the method appendRow() does not receive formatting settings as input, only an array of values.
However, here is a suggestion if you want to implement your own logic:
Sample code:
function applyColorLastRow() {
var ss = SpreadsheetApp.getActive(); //get active sheets file
var range = ss.getDataRange(); //get populated range, you may want to set a range manually if needed.
var lastRowNum = range.getLastRow(); //getting the last row index of the range.
var lastRowRange = ss.getRange(`${lastRowNum}:${lastRowNum}`); //narrowing the range (using A1 notation) to the last row only to apply color
var lastRowColor = lastRowRange.getCell(1,1).getBackgroundObject().asRgbColor().asHexString();
//Your row coloring logic here...
if (lastRowColor === '#ffffff'){ //toggling white/grey color as an example...
lastRowRange.setBackground('#cccccc'); //apply grey color to all cells in the last row range
} else {
lastRowRange.setBackground('#ffffff'); //apply white color to all cells in the last row range
};
}
My goal is to automate adding 10 rows to a Google Sheet used by a nonprofit organization's business and then replicate the formulas sequences needed in the newly created rows. I had all the code working to accomplish the task and prevent users from messing up the spreadsheet formulas when they manually insert rows. However, the code time out due to the number of rows in the spreadsheet with the looping use of getRange(). My new approach is to jump to a named cell as a starting point instead of the the really slow looping cell search.
I have created a name "EndData", read all the stuff I can find online, trialed and errored the syntax for hours to get the named_cell range into myrange and then activate the range on the worksheet...
Here is the current coding attempt (which leaves the cursor at the top of the column and an
"TypeError: Cannot find function getRangeByName in object Sheet. (line 170, file "macros")"
//Get EOD range, select, index up 3 rows to start row insertions
function getEOD() {
var ss = SpreadsheetApp.getActiveSpreadsheet().getActiveSheet();
Logger.log(ss); //lOG is not helpful, says, "sheet", not SheetName
var MyRange = SpreadsheetApp.getActiveSpreadsheet().getActiveSheet().getRangeByName("EndData");
Logger.log(MyRange); //lOG is not helpful, says, "Range", not RangeAddress
//Activate the named cell, moves with the spreadsheet
MyRange.activate();
};
Had a new idea after I asked for help, here's the working code that gets the job done:
//Get EOD range, select, index up 3 rows to start row insertions
function getEOD() {
var ss = SpreadsheetApp.getActiveSpreadsheet().getActiveSheet();
//Logger.log(ss); //lOG is not helpful, says, "sheet", not SheetName
var rg = SpreadsheetApp.getActiveSpreadsheet().getRangeByName('EndData');
if (rg != null) {
Logger.log(rg.getNumColumns());
}
//Logger.log(rg); //lOG is not helpful, says, "Range", not RangeAddress
//Referenced the Named the EOD cell
//Future, Trying to create a debug status bar
//SpreadsheetApp.getActiveSpreadsheet().toast("looking at row" & i "now")
//Activate the named cell, which moves with spreadsheet growth, down
rg.activate();
//Uncomment for testing purposes, places a Yes on the row 4 columns over
//sheet.setActiveRange(sheet.getRange(0, 4)).setValue('Yes');
//turned off durning testing, writes in data range with this trial code
//Reposition from named cell to insert lines location
ss.getRange(sheet.getCurrentCell().getRow() -2, 1, 1,
sheet.getMaxColumns()).activate();
//Insert ten lines, copy and paste special formulas only
Insert_10_Lines()
//https://stackoverflow.com/questions/59772934/get-range-from-
getrangebyname-activate-range
};
My answer is I have tenacity, I try to limit the variables one at a time to prove how things really work, moved the code that did work in the test script file to a production script file and it didn't work for copy of what I had in test, went back to the test script and it didn't work either, after it had... There are variables in play that seem to be happening at the scripting, savings and running steps that change the interactive responses I am getting. Trial and error again through the production environment came up with a working combination by going to the simples code suggested and getting a combination that works. Here is the the code that is running in product to the main need of my question...
function InsertRows() {
var spreadsheet = SpreadsheetApp.getActive();
var sheet = SpreadsheetApp.getActiveSpreadsheet().getActiveSheet();
//Get range from named cell
var range = SpreadsheetApp.getActiveSpreadsheet().getRangeByName("EOD");
if (range != null) {
Logger.log(range.getNumColumns());
}
//Select the cell as a starting point for code to follow
range.activate(); //start location cell is active and row is selected
Thanks for those that responded for the help! Looks like it is going to take a while to recognize the patterns and figure out what to do to get consistent results in a timely manner...
Try this:
function getEOD() {
var ss=SpreadsheetApp.getActiveSpreadsheet().getActiveSheet();
var MyRange=ss.getRangeByName("EndData");
MyRange.activate();
}
I am trying to get a row with a certain range to copy into the row after text ends. I had it working a few days ago, but cannot figure out where I am going wrong right now.
So far I have:
function getNextRow();
return SpreadsheetApp.getActiveSpreadsheet().getLastRow()+1;
}
function test() {
var ss = SpreadsheetApp.getActiveSpreadsheet();
var range = ss.getRange('a4:e4')
var data = range.getValues();
var nextrow = getNextRow();
ss.getRange(nextrow).setValues(data);
}
I have attempted the copyto, but cannot seem to figure it out again from the google developer's page. Any help is appreciated, thank you!
For one thing, you never specify the sheet you are working with. Which sheet of the spreadsheet should this script act on? Use getActiveSheet to pick the active one, or getSheetByName to pick a particular sheet.
Also, your function getNextRow returns an integer, which is the number of the first row that's below all the data. So far so good. But then you call ss.getRange(nextrow) where nextrow is that integer... not good. This isn't one of the acceptable ways of using this method: it needs either A1 notation, or (row, column) pair of integers for a single cell, or (row, column, number of rows, number of columns) quadruple for a range of more than one cell. Which is what you have, so use
ss.getRange(nextrow, 1, data.length, data[0].length).setValues(data);
This says: starting in the row nextrow, column 1 (meaning A), select the range of same size as data. The pair data.length, data[0].length is how one gets the height and width of data array.
That said, there is an easier way to achieve what you want, using appendRow method. Here's a function that would replace all of your code:
function test() {
var sheet = SpreadsheetApp.getActiveSheet();
var range = sheet.getRange('a4:e4')
var data = range.getValues();
sheet.appendRow(data[0]);
}
This appends the content of A4:E4 in the active sheet to the bottom of the same sheet. The method appendRow takes a one-dimensional array, hence data[0] and not just data (which is two-dimensional).
I have no idea how to code. I use to make website on HTML, so my knowledge is limited. I piece together and alter existing codes. I got decent on Excel VBA, but then needed to start using google sheets. So, that said...
I have a spreadsheet with two sheets, 'MIS' and 'Admin'. I have a bunch of code a formula that assigns a value (1,2,3...) based on how many of two drop-down criteria that each line matches (1 if it matches criteria #1, 2 if matches criteria #2, and 3 if it matches both). The code then hides everything and unhides only those with numbers matching the criteria. I need this to be clean and quick, it's for people who can barely use computers.
The problem is, the code only works on the first page. I tried using the same code, tried amending the code, and I tried inserting 'Admin' in about half a million places. Please help. The admin function is my latest attempt. This is where I inserted 'Admin' in a dozen places. Also, if you see anything I'm using that is slowing down the code, I could use some help with that too. There are 6 functions, which basically do the same thing using the same code but corresponding to different number combinations. The one in question is below.
function Admin(){
var ss = SpreadsheetApp.getActiveSpreadsheet();
var sheet = ss.getSheets('Admin')[0];
var range = sheet.getRange(1, 1, sheet.getLastRow());
sheet.hideRows(8,sheet.getLastRow());
var values = range.getValues();
for (var i=0; i<values.length; i++){
if(values[i][0] === 3){
sheet.showRows(i+1);
}
}
}
This line is your 'only the first sheet' problem, you're sort of combining two methods of defining a sheet:
var sheet = ss.getSheets('Admin')[0];
You can get a specific sheet by name by using the .getSheetByName() method i.e.
var adm_sheet = ss.getSheetByName('Admin');
var mis_sheet = ss.getSheetByName('MIS');
Or you can get a sheet by index
var adm_sheet = ss.getSheets()[0]; //returns first sheet
var mis_sheet = ss.getSheets()[1]; //returns second sheet
Lastly, you can get all of the sheets in your spreadsheet and list them in an array like this:
var sheets = ss.getSheets();
And then use the index of the sheet you need in this array like so:
sheets[0] //the first sheet
sheets[1] //the second sheet