combining two select statements with group by and order by - mysql

Question

I have the following 2 select statements that work and return the info on their own, but was wondering if there was a way to join / combine them into one report with their own separate rows and columns
Select Sum (amount) as PDCGross
From Desk D Left Join
Master M
on D.code = M.desk INNER JOIN
pdc
ON m.number = pdc.number
Where teamid = 3
AND active = 1
And onhold is NULL
And deposit >='2020-10-01'
And deposit <= '2020-10-31'
Group by D.Name
Order by desk.Name Desc
Select Sum (amount) as GrossPDCC
FROM Desk D left JOIN
Master M
on D.code = M.Desk INNER JOIN
DebtorCreditCards P
ON m.number = P.Number
Where teamid = 3
AND IsActive = 1
And OnHoldDate is NULL
And DepositDate >='2020-10-01'
And DepositDate <= '2020-10-31'
Group by D.Name
Order by desk.Name Desc
The return for the 1st statement
PDCPross
2500
1500
1300
The result of the 2nd statement is
PDCCGross
1500
1300
1000
What i am looking for is
PDCPross PDCCGross
2500 1500
1500 1300
1300 1000

Answer 1

On MySQL v 8.0+ or MariaDB 10.2 +, you can use ROW_NUMBER() function:
Assign each query with ROW_NUMBER() then make both query as sub-query. Join the queries using the rownum result and you should be able to see your results side by side. Something like this query example:
SELECT A.PDCGross, B.GrossPDCC FROM
(SELECT ROW_NUMBER() OVER (ORDER BY D.Name DESC) AS rownum, SUM(amount) AS PDCGross
FROM Desk D LEFT JOIN
MASTER M
ON D.code = M.desk INNER JOIN
pdc
ON m.number = pdc.number
WHERE teamid = 3
AND active = 1
AND onhold IS NULL
AND deposit >='2020-10-01'
AND deposit <= '2020-10-31'
GROUP BY D.Name
ORDER BY D.Name DESC) A JOIN
(SELECT ROW_NUMBER() OVER (ORDER BY D.Name DESC) AS rownum, SUM(amount) AS GrossPDCC
FROM Desk D LEFT JOIN
MASTER M
ON D.code = M.Desk INNER JOIN
DebtorCreditCards P
ON m.number = P.Number
WHERE teamid = 3
AND IsActive = 1
AND OnHoldDate IS NULL
AND DepositDate >='2020-10-01'
AND DepositDate <= '2020-10-31'
GROUP BY D.Name
ORDER BY D.Name DESC) B ON A.rownum=B.rownum;