Assign a position value to row based on a SUM - mysql

Question

I'm using the code below to get the total distance for teams that people have registered to and entered data, then assign a position to the team.
SELECT #curRow := #curRow + 1 AS position, ROUND(SUM(d.dist_activity_duration
* CASE
WHEN d.dist_is_distance = 0 THEN s.activity_steps / 2000
WHEN d.dist_is_distance = 1 THEN 1
END)
,2) AS miles, t.team_name AS team_name
FROM distance d
JOIN (SELECT #curRow := 0) r
JOIN activities a
ON a.id = d.dist_activity_id
JOIN steps s
ON s.id = a.steps_id
JOIN members AS m
ON d.member_id = m.id
JOIN teams AS t
ON t.id = m.member_team_id
GROUP BY team_name
ORDER BY miles DESC
The code above outputs the following results
position miles team_name
2 134.05 team 1
1 78.00 team 2
I would like position 1 to be assigned to the team with the highest miles, position 2 the 2nd highest team...and so on.

Answer 1

In MySQL 8+, you would just use row_number():
SELECT ROW_NUMBER() OVER (ORDER BY miles DESC) AS position, t.*
FROM (SELECT ROUND(SUM(d.dist_activity_duration *
CASE WHEN d.dist_is_distance = 0 THEN s.activity_steps / 2000
WHEN d.dist_is_distance = 1 THEN 1
END), 2) AS miles, t.team_name AS team_name
FROM distance d JOIN
activities a
ON a.id = d.dist_activity_id JOIN
steps s
ON s.id = a.steps_id JOIN
members m
ON d.member_id = m.id JOIN
teams t
ON t.id = m.member_team_id
GROUP BY team_name
) t
ORDER BY miles DESC;
Earlier versions of MySQL support variables but they do not play well with GROUP BY and ORDER BY. The solution is a subquery (as above):
SELECT (#rn := #rn + 1) AS position,
FROM (SELECT ROUND(SUM(d.dist_activity_duration *
CASE WHEN d.dist_is_distance = 0 THEN s.activity_steps / 2000
WHEN d.dist_is_distance = 1 THEN 1
END), 2) AS miles, t.team_name AS team_name
FROM distance d JOIN
activities a
ON a.id = d.dist_activity_id JOIN
steps s
ON s.id = a.steps_id JOIN
members m
ON d.member_id = m.id JOIN
teams t
ON t.id = m.member_team_id
GROUP BY team_name
ORDER BY miles DESC
) t CROSS JOIN
(SELECT #rn := 0) params;

Answer 2

This works for me.
SELECT (#rn := #rn + 1) AS position, team_name, miles
FROM (SELECT ROUND(SUM(d.dist_activity_duration
* CASE
WHEN d.dist_is_distance = 0 THEN s.activity_steps / 2000
WHEN d.dist_is_distance = 1 THEN 1
END)
,2) AS miles, t.team_name AS team_name
FROM distance d
JOIN activities a
ON a.id = d.dist_activity_id
JOIN steps s
ON s.id = a.steps_id
JOIN members AS m
ON d.member_id = m.id
JOIN teams AS t
ON t.id = m.member_team_id
GROUP BY team_name
ORDER BY miles DESC
) t CROSS JOIN
(SELECT #rn := 0) params;