[Expected Result]
I Need this result from Single table dont know how to do this.
You can use union all to duplicate each and every row in the resultset:
select custname, city from mytable
union all select custname, city from mytable
An order by clause might be useful:
select custname, city from mytable
union all select custname, city from mytable
order by custname, city
One simple method is:
select t.*
from t
union all
select t.*
from t;
If you care about the ordering, then you need an order by clause, so add:
order by custname;
Add ORDER BY to the UNION. For example:
select * from t union all select * from t order by id
See running example at DB Fiddle.
Related
i have table
i would like to select like this
how to get data count_attendance?
you can use subquery to do that:
select name, gol, count(attendance) as count_data,(Select count(attendance) from tablename n where n.attendance='yes' and n.name=tablename.name and n.gol=tablename.gol) as count_attendance from tablename group by name,gol
Just replace tablename with the name of your table.
As sadly SQL is my weakest skill.
I'm trying to use UNION in a VIEW, where I can get statistics from two different tables with one query.
SELECT COUNT(*) AS `customer_count` FROM `Customers`
UNION
SELECT COUNT(*) AS `supplier_count` FROM `Suppliers`;
[Demo table]
However, it only returns customer_count, with two rows. Is there anyway, to make this work, so it returns customer_count and supplier_count separately?
You would need a cross join to see the results adjacent to each other in one row. So you would select from both the tables without a join condition.
select * from
(select count(*) as customer_count from Customers) x,
(select count(*) as supplier_count from Suppliers) y
select
(SELECT COUNT(*) FROM Customers) as customer_count,
(SELECT COUNT(*) FROM Suppliers) AS supplier_count
Using your Table Demo.
The key is use alias so the field names match on each union select.
In this case TableSource and Total
SELECT 'Customer' as TableSource, Count(City) as Total FROM Customers
UNION
SELECT 'Suppliers' as TableSource, Count(City) as Total FROM Suppliers;
CREATE VIEW `vw_count` AS
select (select count(0) from `tbl`) AS `customer_count`,
(select count(0) from `tbl2`) AS `supplier_count`;
select
OrderNo,
Sum(QtyIn) as QuantityIn,
Sum(QtyOut) as QuantityOut
from
tbl_Assign
group by
OrderNo
I want to select * from table also group by from table. How to do it?
To group by on all columns with a sum you cannot use *, you have to list all of the columns out and every column that isn't a function like Sum must be included in the group by.
So if you have other fields in your database such as OrderName, OrderedBy you can perform a group by like this:
Select
OrderNo,
OrderName,
OrderBy,
Sum(QtyIn) as QuantityIn,
Sum(QtyOut) as QuantityOut
From
tbl_Assign
Group By
OrderNo, OrderName, OrderBy
The following will create one row for every row in the tbl_Assign.
Each row will also show the summary information for the order.
This might not be what you need, but it's useful to understand it anyway.
SELECT T1.*, T2.*
FROM
( select * FROM tbl_Assign ) AS T1
LEFT JOIN ( select
OrderNo,
Sum(QtyIn) as QuantityIn,
Sum(QtyOut) as QuantityOut
from
tbl_Assign
group by
OrderNo
) AS T2
ON T1.OrderNo = T2.OrderNo
Harvey
I have the following table:
CREATE TABLE sometable (my_id INTEGER PRIMARY KEY AUTOINCREMENT, name STRING, number STRING);
Running this query:
SELECT * FROM sometable;
Produces the following output:
1|someone|111
2|someone|222
3|monster|333
Along with these three fields I would also like to include a count representing the amount of times the same name exists in the table.
I've obviously tried:
SELECT my_id, name, count(name) FROM sometable GROUP BY name;
though that will not give me an individual result row for every record.
Ideally I would have the following output:
1|someone|111|2
2|someone|222|2
3|monster|333|1
Where the 4th column represents the amount of time this number exists.
Thanks for any help.
You can do this with a correlated subquery in the select clause:
Select st.*,
(SELECT count(*) from sometable st2 where st.name = st2.name) as NameCount
from sometable st;
You can also write this as a join to an aggregated subquery:
select st.*, stn.NameCount
from sometable st join
(select name, count(*) as NameCount
from sometable
group by name
) stn
on st.name = stn.name;
EDIT:
As for performance, the best way to find out is to try both and time them. The correlated subquery will work best when there is an index on sometable(name). Although aggregation is reputed to be slow in MySQL, sometimes this type of query gets surprisingly good results. The best answer is to test.
Select *, (SELECT count(my_id) from sometable) as total from sometable
The inner query in the following SQL statement is to normalize part of the database (code1, code2, code3, etc.) With the outer query I want to select the codes that aren't in the lookup table (tblicd)
select primarycode from
(
select id, primarycode from myTable
union
select id, secondarycode from myTable
union
select id, tertiarycode from myTable) as t
order by id
where primarycode not in tblicd.icd_id
The query above doesn't run, I'm wondering what I'm doing wrong. The error I get is the multi-part identifier tblicd.icd_id could not be bound
One problem is your ORDER BY and WHERE clauses are reversed. The ORDER BY clause must come after the WHERE clause.
Your WHERE clause is also incorrect. It should be like this:
WHERE primarycode NOT IN (SELECT icd_id FROM tblicd)
ORDER BY id
where primarycode not in tblicd.icd_id
might be
where primarycode not in (SELECT icd_id FROM tblicd )