When creating a copy of a spreadsheet that is linked to a form, a newSheets.getFormUrl() not found error occurs. The new spreadsheet is created since I'm able to add a new editor to it and it appears in the appropriate drive folder. Likewise, the expected new form is created and it is indeed linked to the the new spreadsheet. However, when trying to get a handle on the new form via getFormUrl(), the error occurs. I want to rename the new form and move it to a new folder but can't.
Also, although Spreadsheet.getFormURL() exists in the API, it doesn't appear in the typeahead when keying in the function. My Apps Script runtime is V8.
// generate the response sheet into the folder and add editor
var newSheet = DriveApp.getFileById(templateResponseSheetID).makeCopy('Contact Tracing RESPONSES - ' + name, childDocsFolder);
newSheet.addEditor(email);
var newform = newSheet.getFormUrl();
The problem is that newSheet is a File object but getFormUrl() is a method of Class Spreadsheet
instead of
var newform = newSheet.getFormUrl();
use
var spreadsheet = SpreadsheetApp.open(newSheet);
var url = spreadsheet.getFormUrl()
Related
We are using sheets for our mom & pop store as our invoice. However, my mother-in-law keeps saving over our invoice and we're always having to go back and delete the filled in sections. She cannot seem to remember the steps of making a copy and then opening that. I am using a script (button) to create a copy of the original and it is renamed as the customer name & date into a specific folder. However, once we do that, we still have to navigate to the folder and open the new document. Is there there a way to do this after I click the button on our original document to open of the copy that was made? Here is the script that I am using.
function saveAsSpreadsheet()
{
var sheet = SpreadsheetApp.getActiveSpreadsheet();
var range = sheet.getRange('Carolina Fireworks Order Form!C8');
sheet.setNamedRange('TestRange', range);
var TestRange = sheet.getRangeByName('Carolina Fireworks Order Form!C8').getValues();
Logger.log(TestRange);
var destFolder = DriveApp.getFolderById("1UdK90fEs3gkP4KZuUbmZbvvyVAW5ZMGw");
let name = SpreadsheetApp.getActiveSheet().getRange('C8').getValue();
const ds = Utilities.formatDate(new Date(),SpreadsheetApp.getActive().getSpreadsheetTimeZone(),"MM.dd.yy");
DriveApp.getFileById(sheet.getId()).makeCopy('TestRange', destFolder).setName(`${name}.${ds}`);
}
In your situation, how about the following modification?
From:
DriveApp.getFileById(sheet.getId()).makeCopy('TestRange', destFolder).setName(`${name}.${ds}`);
To:
const file = DriveApp.getFileById(sheet.getId()).makeCopy('TestRange', destFolder).setName(`${name}.${ds}`);
var js = `<script>window.open('${file.getUrl()}');google.script.host.close();</script>`;
var html = HtmlService.createHtmlOutput(js);
SpreadsheetApp.getUi().showModalDialog(html, 'Now loading.');
In this script, the URL is opened using Javascript on the dialog.
This is from this post
Note:
From MetaMan's comment
If you want this to work you will have to disable popup blocking
References:
showModalDialog(userInterface, title)
Window.open()
I can create a new spreadsheet using:
var newWorksheet = SpreadsheetApp.create("newWorksheetName");
However, how do I immediately set it as active so I can edit it?
As far as I know, I need to get the spreadsheet ID, to open it, but I don't know how to find this out automatically.
Try this:
var crNew = SpreadsheetApp.create("newWorksheetName");
var ssNew = SpreadsheetApp.openByUrl(crNew.getUrl());
where ssNew is the new Spreadsheet file.
Then you can use ssNew to directly access the new Spreadsheet file.
For example, the following will give you the name of the first sheet of the newly generated newWorksheetName:
Logger.log(ssNew.getSheets()[0].getName());
Output: Sheet1
Another example would be to change the name of the sheet:
ssNew.getSheets()[0].setName("newname");
I want to import a graphical evaluation (diagram) into a new file using a macro. So the evaluation should not be inserted on a new sheet in the associated file, but a completely new file should be created, in which the graphical evaluation (in the form of a combination diagram) is then copied. The file should be either a Google Sheets or an Excel file. The combination diagram already exists and is located in a Google sheet, but it should be copied into a new file automatically with the help of a macro and the corresponding button. The code below unfortunately only inserts an empty sheet. Where is my error?
The chart will depend on the data in the new Spreadsheet, so I need to have the data in the new spreadsheet using importrange. How can I modify the data range with addRange function. The code below unfortunately does not work. Like this an empty chart is inserted.
Error Exception: Service error: Tables (line 7, file "Macros") (insertChart Line)
function Auswertung2() {
var sheet = SpreadsheetApp.getActive().getSheetByName("Evaluation");
var newSpreadsheet = SpreadsheetApp.create("new spreadsheet");
var newSheet = newSpreadsheet.getSheets()[0];
var chart = sheet.getCharts()[0];
chart = chart.modify().addRange(sheet.getRange("A1:AX80")).setPosition(7, 7, 0, 0).build();
newSheet.insertChart(chart);
};```
Receiving the error,
ReferenceError: "setActiveSelection" is not defined.
Using Google Apps Script on Google Sheets. With this function, I'm wanting to create a new sheet tab on the same workbook using a template from another workbook. Once the new sheet is created, I'd like to change the actively selected cell to cell 'B1'. The template is copying fine, but the error is coming from the line changing the active selection. I've also tried setActiveRange and even just setActiveSheet but they return the same error.
function newReception() {
var templateSpreadsheet = SpreadsheetApp.openById("ID Redacted");
var template = templateSpreadsheet.getSheets()[1];
var currentSpreadsheet = SpreadsheetApp.getActiveSpreadsheet();
var newSheet = template.copyTo(currentSpreadsheet).setName("Untitled
Reception");
setActiveSelection(currentSpreadsheet.getSheetbyName("Untitled
Reception").getRange('B1'));
}
Please advise on a solution. Thanks!
You're getting this issue because you're running .setActiveSelection() on its own. This method is bound to sheets, so you must run it for such. See Class Sheet documentation for more details on this method.
Try defining your sheet as a variable and then running it for your new sheet variable.
var sheet = currentSpreadsheet.getSheetbyName("Untitled Reception");
sheet.setActiveSelection('B1');
I was wondering if someone could offer me some advice.
I have a master spreadsheet, acting as a template. I have written a script which can be run from the menu (using addToUi command), which makes a copy of template spreadsheet.
The problem is that the script gets copied into the new spreadsheet also which I don't want.
Could anyone suggest a possible way around this please?
I did think a possible way was to get the script to open the copied template and delete the script but not sure if this is possible.
Here is the function which does the copying....
function createCopy() {
var myValue = SpreadsheetApp.getActiveSpreadsheet().getActiveSheet().getRange("B8").getValue();
var destinationFolder = DriveApp.getFolderById("xxxxxxxxxxxxxxxx");
DriveApp.getFileById(SpreadsheetApp.getActiveSpreadsheet().getId()).makeCopy(myValue,destinationFolder);
}
(Cell reference B8 holds the value of what I called the copied spreadsheet).
Rayden, I use a function like that to just copy one sheet to a new spreadsheet and it doesn't drag the script with it. gDrive is the id for the Spreadsheet, tabName the individual sheet you want copied, Filename the name of the copy and destination the destination directory.
//******************************************************************************
//- This function takes a tab and makes it its own file
function tabToSheet(gDrive,tabName,fileName,destination){
var sh = SpreadsheetApp.openById(gDrive);
var ss = sh.getSheetByName(tabName);
//create a new document in the location given
var newSheet = SpreadsheetApp.create("TEMPDELETEME");
//copy the tab from current document to new document
ss.copyTo(newSheet);
var id = newSheet.getId();
newSheet.deleteSheet(newSheet.getSheetByName("Sheet1"));
os = newSheet.getSheets()[0];
os.setName(tabName);
var file = DriveApp.getFileById(id);
var folder = DriveApp.getFolderById(destination);
var finalId = file.makeCopy(fileName, folder).getId();
file.setTrashed(true);
return finalId;
}//*****************************************************************************
The difference is that i'm making a new sheet, then copying the tab rather than copying the entire file. You could add another tab and remove the variables if you want to copy multiple tabs.
I was having trouble implementing J.G.'s approach of moving individual sheets, so the approach I took was to add a conditional in front of the script to only run if the spreadsheet id was equal to the id of the original spreadsheet. My use case was trying to suppress a custom menu on the original workbook from reappearing on the copy, so it worked for that.
var bookId = spreadsheet.getId();
if (bookId === 'original spreadsheet id') {
*Function*
}