Assuming that I have a table like this
| id | name | code | method | account | time | date |
|----|--------|------|--------|---------|------|------------|
| 1 | name01 | 200 | GET | 1 | 100 | 2020-06-10 |
| 2 | name01 | 201 | GET | 2 | 150 | 2020-06-10 |
| 3 | name02 | 200 | POST | 4 | 200 | 2020-06-10 |
| 4 | name01 | 200 | GET | 5 | 250 | 2020-06-11 |
| 5 | name02 | 200 | POST | 1 | 300 | 2020-06-11 |
How can I select an exact date range and get the sum of account and average of time?
Notice that same name but different code should be configured as different group.
e.g. select date range 2020-06-10 to 2020-06-11
return:
| name | code | method | account | time |
|--------|------|--------|---------|------|
| name01 | 200 | GET | 6 | 175 |
| name01 | 201 | GET | 2 | 150 |
| name02 | 200 | POST | 5 | 250 |
And if I select the same day like this: 2020-06-10 to 2020-06-10
just return:
| name | code | method | account | time |
|--------|------|--------|---------|------|
| name01 | 200 | GET | 1 | 100 |
| name01 | 201 | GET | 2 | 150 |
| name02 | 200 | POST | 4 | 200 |
You want aggregation:
select
name,
code,
method,
sum(account) account,
avg(time) time
from mytable
where date between '2020-06-10' and '2020-06-11'
group by name, code, method
Related
I have a table like this and i want to output without duplication of the same user. If i use group by it shows only one record on the same column. iam also using left join for location and user name. A little help
+------+---------+----------+---------+
| user | work id | location | time |
+------+---------+----------+---------+
| 1 | 42 | 1 | 2hr |
| 1 | 42 | 1 | 10min |
| 1 | 42 | 1 | 30min |
| 2 | 42 | 1 | 4hr |
| 2 | 42 | 1 | 2.30min |
| 1 | 50 | 2 | 4min |
| 1 | 50 | 2 | 5min |
| 2 | 20 | 3 | 3hr |
| 1 | 20 | 3 | 6hr |
+------+---------+----------+---------+
Iam looking for this
+------+---------+----------+
| user | work id | location |
+------+---------+----------+
| 1 | 42 | 1 |
| 1 | 50 | 2 |
| 1 | 20 | 3 |
| 2 | 42 | 1 |
| 2 | 20 | 3 |
+------+---------+----------+
You simply need a distinct clause here -
SELECT DISTINCT user
,workid
,location
FROM YOUR_TABLE
ORDER BY user
,location
To check a patient's status in a medical test(high, low, average), I have to keep range values for the tests in a table
For a test there can be several ranges.
| range | status |
|-----------|---------|
| 0 - 100 | Low |
| 101- 200 | Average |
| 201 - 300 | High |
For another test, ranges can be different according to the gender
| range | Gender | status |
|-----------|--------|---------|
| 0 - 100 | Male | Low |
| 0 - 105 | Female | Low |
| 100- 200 | Male | Average |
| 105 - 210 | Female | Average |
| 200 - 300 | Male | High |
| 210 - 300 | Female | High |
There can be range data as age, gender, status as well.
How can I map the ranges in database which enables to check which range user is in for a given test result. As an example For a Sugar Test a male user may have a result 45. I need whether the test value is high, low or average.
My initial table solution is shown below. I don't think this is a good solution.
| test | min_age | max_age | range_upper | range_lower | Gender | status |
|------|---------|---------|-------------|-------------|--------|---------|
| 1 | 1 | 10 | 0 | 100 | Male | Low |
| 1 | 1 | 10 | 100 | 200 | Male | Average |
| 1 | 1 | 10 | 200 | 300 | Male | High |
| 1 | 1 | 10 | 0 | 100 | Female | Low |
| 1 | 1 | 10 | 100 | 200 | Female | Average |
| 1 | 1 | 10 | 200 | 300 | Female | High |
Please sorry for my English.
Why do not use range reference instead of pair of values?
Table status_ranges
| id | range_min | range_max | status |
|----|-----------|-----------|---------|
| 1 | 0 | 100 | Low |
| 2 | 101 | 200 | Average |
| 3 | 201 | 300 | High |
Table of tests
| test | value_1 | gender | id_status_of_value_1 | . . .
|------|---------|--------|----------------------|-----
| 1 | 10 | Male | 1 | . . .
| 1 | 120 | Male | 2 |
| 1 | 235 | Male | 3 |
| . . .
I have a simple MySQL table as such:
| CUST_ID | VISIT | PROD_ID |
|---------|-------|---------|
| 1 | 1 | 3473 |
| 1 | 2 | 324 |
| 1 | 2 | 324 |
| 2 | 1 | 426 |
| 2 | 2 | 4418 |
| 3 | 1 | 4523 |
| 4 | 1 | 976 |
| 4 | 1 | 86 |
| 4 | 2 | 3140 |
| 4 | 3 | 1013 |
And I would like to transform it to this:
| CUST_ID | VISIT | PROD_IDs |
|---------|-------|----------|
| 1 | 1 | 3473 |
| 1 | 2 | 324, 324 |
| 2 | 1 | 426 |
| 2 | 2 | 4418 |
| 3 | 1 | 4523 |
| 4 | 1 | 976, 86 |
| 4 | 2 | 3140 |
| 4 | 3 | 1013 |
This is kinda an ugly hack, I get it.
I have no idea how to cleanly create such a thing. I've tried a variety of unsuccessful grouping strategies. Even a clue or hint in the right direction would be great. Thanks.
If you're trying to group by cust_id + visit, then you can do that and use a GROUP CONCAT on the PROD_ID field, for example:
SELECT
CUST_ID,
VISIT,
GROUP_CONCAT(PROD_ID) PROD_IDS
FROM
table
GROUP BY
CUST_ID,
VISIT
Reference: GROUP CONCAT
I have three tables :
em_employee :
emp_number | emp_firstname |
+------------+---------------+
| 1 | Vikram |
| 2 | S. |
| 3 | Gopal |
| 4 | Vaishnavi |
| 5 | Srinivasan |
| 6 | Saravanan
em_project
+------------+------------------------------+
| project_id | name |
+------------+------------------------------+
| 339 | MoneyGram |
| 340 | SERVICE LINE HEAD COMPLIANCE |
| 341 | SERVICE LINE HEAD ANALYTICS |
| 342 | GSI |
| 343 | Tandem |
| 344 | Master Card |
+------------+------------------------------+
em_project_employee:
+------------+------------+
| emp_number | project_id |
+------------+------------+
| 1 | 339 |
| 2 | 340 |
| 3 | 341 |
| 4 | 342 |
| 1 | 343 |
| 6 | 344 |
| 2 | 342 |
+------------+------------+
And I want Output like :
+------------+----------------------------------+
| emp_number | name |
+------------+----------------------------------+
| 1 | MoneyGram , Tandem |
| 2 | SERVICE LINE HEAD COMPLIANCE,GSI |
| 3 | SERVICE LINE HEAD ANALYTICS |
| 4 | GSI |
| 6 | Master Card |
+------------+----------------------------------+
I have tried it with GROUP_CONCAT, but something going wrong. Please help me on this.
Try this query, it produes that output:
SELECT emp_number, GROUP_CONCAT(name) FROM em_project p
INNER JOIN em_project_employee em ON p.project_id = em.project_id
GROUP BY emp_number;
The order of the data will e slightly different from what's in your desired output. If the ordering is important.
GROUP_CONCAT(name ORDER BY p.project_id)
Maybe this will be an easy one for some of you MySQL masters who see this stuff like a level 3 children's book.
I have multiple tables that I'm joining to produce statistical data for a report and I'm getting tripped up at the moment trying to figure it out. It's obviously imperative the figures are correct because it impacts a number of decisions going forward.
Here's the lay of the land (not the full picture, but you'll get the point):
Affiliate Table
+----+-----------+------------+---------------------+
| id | firstname | lastname | created_date |
+----+-----------+------------+---------------------+
| 1 | Mike | Johnson | 2010-11-22 17:44:37 |
| 2 | Trevor | Wilson | 2010-12-23 16:24:24 |
| 3 | Bob | Parker | 2011-11-04 10:33:49 |
+----+-----------+------------+---------------------+
Now our query should only find results for Bob Parker (id 3) so I'll only show example results for Bob.
Affiliate Link Table
+-----+-----------+--------------+-----------+----------+---------------------+
| id | parent_id | affiliate_id | link_type | linkhash | created_date |
+-----+-----------+--------------+-----------+----------+---------------------+
| 21 | NULL | 3 | PRODUCT | fa2e82a7 | 2011-06-15 16:18:37 |
| 27 | NULL | 3 | PRODUCT | 55de2ae7 | 2011-06-23 01:03:00 |
| 28 | NULL | 3 | PRODUCT | 02cae72f | 2011-06-23 01:03:00 |
| 29 | 27 | 3 | PRODUCT | a4dfb2c8 | 2011-06-23 01:03:00 |
| 30 | 28 | 3 | PRODUCT | 72cea1b2 | 2011-06-23 01:03:00 |
| 36 | 21 | 3 | PRODUCT | fa2e82a7 | 2011-06-23 01:07:03 |
| 59 | 21 | 3 | PRODUCT | ec33413f | 2011-11-04 17:49:17 |
| 60 | 27 | 3 | PRODUCT | f701188c | 2011-11-04 17:49:17 |
| 69 | 21 | 3 | PRODUCT | 6dfb89fd | 2011-11-04 17:49:17 |
+-----+-----------+--------------+-----------+----------+---------------------+
Affiliate Stats
+--------+--------------+--------------------+----------+---------------------+
| id | affiliate_id | link_id | order_id | type | created_date |
+--------+--------------+---------+----------+----------+---------------------+
| 86570 | 3 | 21 | NULL | CLICK | 2013-01-01 00:07:31 |
| 86574 | 3 | 21 | NULL | PAGEVIEW | 2013-01-01 00:08:53 |
| 86579 | 3 | 21 | 411 | SALE | 2013-01-01 00:09:52 |
| 86580 | 3 | 36 | NULL | CLICK | 2013-01-01 00:09:55 |
| 86582 | 3 | 36 | NULL | PAGEVIEW | 2013-01-01 00:09:56 |
| 86583 | 3 | 28 | NULL | CLICK | 2013-01-01 00:11:04 |
| 86584 | 3 | 28 | NULL | PAGEVIEW | 2013-01-01 00:11:04 |
| 86586 | 3 | 30 | NULL | CLICK | 2013-01-01 00:30:18 |
| 86587 | 3 | 30 | NULL | PAGEVIEW | 2013-01-01 00:30:20 |
| 86611 | 3 | 69 | NULL | CLICK | 2013-01-01 00:40:19 |
| 86613 | 3 | 69 | NULL | PAGEVIEW | 2013-01-01 00:40:19 |
| 86619 | 3 | 69 | 413 | SALE | 2013-01-01 00:42:12 |
| 86622 | 3 | 60 | NULL | CLICK | 2013-01-01 00:46:00 |
| 86624 | 3 | 60 | NULL | PAGEVIEW | 2013-01-01 00:46:01 |
| 86641 | 3 | 60 | NULL | PAGEVIEW | 2013-01-01 00:55:58 |
| 86642 | 3 | 30 | 415 | SALE | 2013-01-01 00:56:35 |
| 86643 | 3 | 28 | NULL | PAGEVIEW | 2013-01-01 00:56:43 |
| 86644 | 3 | 60 | 417 | SALE | 2013-01-01 00:56:52 |
+--------+--------------+---------+----------+----------+---------------------+
Orders
+------+--------------+---------+---------------------+
| id | affiliate_id | total | created_date |
+------+--------------+---------+---------------------+
| 411 | 3 | 138.62 | 2013-01-01 00:09:50 |
| 413 | 3 | 312.87 | 2013-01-01 00:09:52 |
| 415 | 3 | 242.59 | 2013-01-01 00:09:55 |
| 417 | 3 | 171.18 | 2013-01-01 00:09:55 |
+------+--------------+---------+---------------------+
Now the results that I need should look like this (only show main/parent link id)
+---------+---------+
| link_id | total |
+---------+---------+
| 21 | 451.49 | <- 1 order from parent (21), 1 from child (69)
| 27 | 171.18 | <- 1 order from child (69)
| 28 | 242.59 | <- 1 order from child (30)
+---------+---------+
I'm not quite sure how to write the query so that I can sum where affiliate_link.id and affiliate_link.parent_id are combined. Is this even possible with a couple of JOINs and GROUPing?
I'm not too sure why you have denormalised affiliate_id (by placing it in each table) and, therefore, whether one can rely on all Stats and Orders that stem from a particular Link to have the same affiliate_id as that Link.
If it's possible, I'd suggest changing the AffiliateLink.parent_id column such that parent records point to themselves (rather than NULL):
UPDATE AffiliateLink SET parent_id = id WHERE parent_id IS NULL
Then it's a simple case of joining and grouping:
SELECT AffiliateLink.parent_id AS link_id,
SUM(Orders.total) AS total
FROM AffiliateLink
JOIN AffiliateStats ON AffiliateStats.link_id = AffiliateLink.id
JOIN Orders ON Orders.id = AffiliateStats.order_id
WHERE AffiliateLink.affiliate_id = 3
GROUP BY AffiliateLink.parent_id
See it on sqlfiddle.
If it's not possible to make the change, you can effectively create the resulting AffiliateLink table using UNION (but beware the performance implications, as MySQL will not be able to use indexes on the result):
(
SELECT parent_id, id, affiliate_id FROM AffiliateLink WHERE parent_id IS NOT NULL
UNION ALL
SELECT id , id, affiliate_id FROM AffiliateLink WHERE parent_id IS NULL
) AS AffiliateLink
See it on sqlfiddle.