I am calculating percentage and formatting the value as "0.0". That give me values like 3.7%, 4.1% etc. But when it's 1.0% I want to show as 1% only, how to remove decimal when the there is a whole value?
Thank you.
I am assuming your database values are in decimal format so that 0.01 represents 1%.
If this is not the case, let me know and I will modify the answer.
I created some test data with
SELECT 0.09 as pc
UNION SELECT 0.091
UNION SELECT 0.099
UNION SELECT 0.01
UNION SELECT 0.011
UNION SELECT 0.012
UNION SELECT 0.019
UNION SELECT 0.020
UNION SELECT 0.021
I then added a table to show the raw value plus various other formats.
Finally I added a 4th column that formats the value based on if it is a 'whole percent' or not.
I set the Format property of the textbox to the following expression.
=IIF(
Fields!pc.Value * 100 = CINT(Fields!pc.Value*100)
, "p0"
, "p1"
)
This basically checks if the value when multiplied by 100 is an integer, if it is then we apply p0 as the format code, if not we apply p1 as the format code.
The end result is as follows.
Note: We have only changed the format property of the textbox, not the value expression.
As you can see in the design below, each column's value expression is identical ([pc]), it is only the format property of each textbox that is different. To show the properties panel click on the textbox and then hit F4 in Visual Studio. If you are using Report Builder then I'm not sure if F4 works, but there is a menu option to show the properties panel somewhere.
Finally, you will obviously need to replace the field pc from my example with the actual field name in your report.
How about you wrap an iff statement around your formating?
Something along the lines of
=iif(round(Fields!num.Value) = Fields!num.Value,format(Fields!num.Value,"0%"),format(Fields!num.Value,"0.00%"))
This evaluates the output and if it is 1.0% then it makes it 1% else formats the rest of the value as required
Related
I have a tablix with following results.
SSRS Result
Since i am learning SSRS. i wonder how to Sum line total with respect to product name. Since product name has duplicate values but it has only M and Xl difference. If i use row group it won't total like i expected since it has M and Xl difference. I wonder how to write an expression for the total.
The desired result set
May 31 2011 S043659 Long-Sleeve Logo jerse M 3 $86.52
Long-Sleeve Logo jersey XL 1 $28.84
Total $115.36
mountain bike socks M 6 $34.20
i used this expression but giving me an error.
`IIF((Fields!Product.value = Previous(Fields!Product.value),Sum(Fields!linetotal.value))`
There's actually a few things wrong with your expression.
The IIF doesn't have a 3rd argument for the ELSE value. In this case, you'd want to use 0. So the expression would be IIF the fields match then LineTotal Else 0.
You want to have the SUM on the outside of the IIF, otherwise it will only SUM one row.
The matching without the size is trickier. I have it trim off the last 4 characters to exclude the size for a match - it may not work depending on your other Product names.
=SUM(IIF(LEFT(Fields!Product.value, LEN(Fields!Product.value) - 4) = LEFT(Previous(Fields!Product.value), LEN(Fields!Product.value) - 4), Fields!linetotal.value, 0))
The expression reads the SUM of (IF the Product matches the Previous Product then the Line Total else 0).
All this being said, it would actually be easy to crate a parent group and GROUP BY on the parent product. Unfortunately, your data uses a comma to separate one type (jersey) by size but a space in another (socks) so I don't see how to do it. If they all had a comma, I would create a Calculated Field on the dataset to use the product-line up to the comma.
=LEFT(Fields!Product.value, INSTR(Fields!Product.value, ",") - 1)
IF your Product line is either a comma or space to separate, you might be able to use this for your Calculated Field:
=LEFT(Fields!Product.value,
IIF(INSTR(Fields!Product.value, ",") > 0,
INSTR(Fields!Product.value, ",") - 1,
InStrRev(Fields!Product.value, " ") - 1) )
I have a data set like that:
Data Set Contents
From To Comment
----+---+--------
0 50 Bad
50 70 Good
70 100 Excellent
If I have a value of 75, I need to get Excellent by searching the Dataset.
I know about the lookup function but it is not what I want. How can I do that?
The values should be in percentage.
Note : the value (75) is Average of a column (Calculated) it
calculate student grade from max and student mark Version SQL Server
2016
Note 2 : the dataset is from database not static values
Thank You
Assuming you only ever have a fixed number of 'grades' then this will work. However, I would strongly recommend doing this type of work on the server where possible.
Here we go...
I created two datasets
dsGradeRange with the following sql to recreate your example (more or less)
DECLARE #t TABLE (low int, high int, comment varchar(20))
INSERT INTO #t VALUES
(0,49,'Bad'),
(50,69,'Good'),
(70,100, 'Excellent')
SELECT * FROM #t
dsRandomNumbers This just creates 30 random numbers between 0 and 100
SELECT *
FROM (SELECT top 30 ABS(CHECKSUM(NEWID()) % 100) as myNumber FROM sys.objects) x
ORDER BY myNumber
I added a table to the report to show the grades (just for reference).
I then added a table to show the dsRandomNumbers
Finally I set the expression of the 2nd column to the following expression.
=SWITCH
(
Fields!myNumber.Value < LOOKUP("Bad", Fields!comment.Value, Fields!high.Value, "dsGradeRange"), "Bad",
Fields!myNumber.Value < LOOKUP("Good", Fields!comment.Value, Fields!high.Value, "dsGradeRange"), "Good",
True, "Excellent"
)
This gives the following results
As you can see we only need to compare to the high value of each case, the first match will return the correct comment.
Right click on your dataset and add a calculated field. Go to Field Properties > Fields > Add and add the following expression, which descripes your scenario:
=IIF(Fields!Number.Value < 50, "Bad", "Good")
MY database have values like
3302540.8200
748712.9600
584879.2400
20787.5300
1338075.0000
I need the above values like below in my SSRS reports
3,302,540.82
748,712.96
584,879.24
20,787.53
1,338,075
I tried custom format for number on my text box #,0.######## but while exporting it in excel it is showing the value 1 as 1. (dot is not desirable)
help me with this.
TIA
Using the following as the datasource:
SELECT 3302540.8200 Number UNION
SELECT 748712.9600 UNION
SELECT 584879.2400 UNION
SELECT 20787.5300 UNION
SELECT 1338075.0000 UNION
SELECT 1000 UNION
SELECT 10123.20
You could use the following expression in your output table/Textbox:
=Format(Fields!Number.Value,"#,#.##")
Excel Output:
1,000
10,123.2
20,787.53
584,879.24
748,712.96
1,338,075
3,302,540.82
in your designed report in SSRS ,
type below in format section of your textBox
#,0;(#,0)
it works exactly as what u want
Hey is there any way to create query with simple formula ?
I have a table data with two columns value_one and value_two both are decimal values. I want to select this rows where difference between value_one and value_two is grater then 5. How can i do this?
Can i do something like this ?
SELECT * FROM data WHERE (MAX(value_one, value_two) - MIN(value_one, value_two)) > 5
Example values
value_one, value_two
1,6
9,3
2,3
3,2
so analogical difs are: 5, 6, 1, 1 so the selected row would be only first and second.
Consider an example where smaller number is subtracted with a bigger number:
2 - 5 = -3
So, the result is a difference of two numbers with a negation sign.
Now, consider the reverse scenario, when bigger number is subtracted with the smaller number:
5 - 2 = 3
Pretty simple right.
Basically, the difference of two number remains same, if you just ignore the sign. This is in other words called absolute value of a number.
Now, the question arises how to find the absolute value in MySQL?
Answer to this is the built-in method of MySQL i.e. abs() function which returns an absolute value of a number.
ABS(X):
Returns the absolute value of X.
mysql> SELECT ABS(2);
-> 2
mysql> SELECT ABS(-32);
-> 32
Therefore, without worrying about finding min and max number, we can directly focus on the difference of two numbers and then, retrieving the absolute value of the result. Finally, check if it is greater than 5.
So, the final query becomes:
SELECT *
FROM data
WHERE abs(value_one - value_two) > 5;
You can also do complex operations once the absolute value is calculated like adding or dividing with the third value. Check the code below:
SELECT *
FROM
data
WHERE
(abs(value_one - value_two) / value_three) + value_four > 5;
You can also add multiple conditions using logical operators like AND, OR, NOT to do so. Click here for logical operators.
SELECT *
FROM
data
WHERE
((abs(value_one - value_two) / value_three) + value_four > 5)
AND (value_five != 0);
Here is the link with various functions available in MySQL:
https://dev.mysql.com/doc/refman/5.0/en/mathematical-functions.html
No, you would just use a simple where clause:
select *
from data
where abs(value_one - value_two) > 5;
I have a query having BETWEEN operator but it showing wrong results
My query-
SELECT * FROM register WHERE height BETWEEN '1' AND '6'
It also shows the user with height 10, 12 and 16 which is wrong. What is the problem with this query?
I have another query which work fine but is not proper way of using as it make query lengthy
SELECT * FROM register WHERE height > 1 AND height < 12
Give me idea for right way of getting the query as if more condition is added it would be hard for the query to understand and code.
Assuming height is an integer should it not be
SELECT * FROM register WHERE height BETWEEN 1 AND 6
You don't need the single quotes
If:
1. You can't or don't want to change the column type
2. The charachters in the field are only numbers
You can change your query to:
SELECT *
FROM register
WHERE CONVERT(height, UNSIGNED INTEGER) BETWEEN 1 AND 6
See my example at this SQL fiddle.
Check the data type of your column 'Height' it should be a int or float or double and if it is amongs above run the following query
SELECT * FROM register WHERE height BETWEEN 1 AND 6
If the height field is not numeric, you could convert it before making you comparison.
SELECT * FROM register WHERE CONVERT(height, unsigned) BETWEEN 1 AND 6