I am trying to get result in TimeDiff column in my table where I have run DataMacro on TimeDiff column.
DataDiff is between MyDate and System date and time.
DateDiff("hh";[MyDate];Now())+(Format(Now();"dd\.mm\.yyyy hh:nn";2;1)<Format([MyDate];"dd\.mm\.yyyy hh:nn";2;1))
I would like to have hours stored in my TimeDiff column, but keep getting an error. Could you please help.
Thank you.
Related
Title says it all.
Table looks like this
Table: Time
First Column: startdate (shown as yyyy-mm-dd hh:mm:ss)
Second COlumn: durationminute (shown in minutes)
Since the above doesn't give me an end date, I'm trying to create a query which will do that.
I'm assuming this is going to be a dateadd function but I can't get it to work. The durationminutes is a variable to is dependent on that one row so date_add(minutes, 30, startdate) wouldn't work as there is no constant.
I've tried
date_add(days, durationminutes/1440, startdate)
But am getting a syntax error.
MySQL understands date arithmetics. Assuming that startdate is of date or datetime datatype (as it should be!), you can do:
select t.*,
startdate + interval durationminute minute as enddate
from time t
I have a table called complaints
In complaints there is a datetime column called date.
now i need to receive back in a SQL query every inserted comlaints which came in later than 18:00 of each day.
Anyone got an idea what to do or a solution with a query?
someone said to me i could use a DATE_FORMAT.
In your SQL query use this where condition.
where time(datetimefield) > '18:00:00'
Try this it might help you.
Assuming you have your database set up for 24-hour times, you can do the following:
SELECT * FROM yourTable
WHERE HOUR(TIME(yourTable.yourDateTime)) >= 18;
I want to get the Day of the week as a string and not an integer value from a datetime column from the MySQL Table. So instead of getting 0,1,2.. I would like to have these as Sunday, Monday, tuesday and so on. Is there a date function to achieve this?
Seems you are looking for DAYNAME
SELECT DAYNAME("2008-05-15") from dual
Use DAYNAME
Query
SELECT DAYNAME(date_column) AS `DayName`
FROM your_table_name;
I have a DateTime column in a MySQL table that I'm trying to filter just from the time of the DateTime. So for example I need all rows that the time is 8am-9am on any date. Is this possible? I've looked through all the docs and can't find anything of the sort.
Thanks guys!
Use the TIME function, like this
where TIME(myColumn) >= '08:00:00' and TIME(myColumn) <= '09:00:00'
TIME gets the time part of your value.
I want to get the records from mysql data base based on time.
I have lastquery_date column in my table every time update the date and time in that column.
I want to get time difference with current date is less than 12 mins
How can i get this query..
Please help me
see the link below and develop your own logic :)
TIMEDIFF
Your question is not entirely clear, but I think this is what you want:
SELECT *
FROM your_table
WHERE lastquery_date >= NOW() - INTERVAL 12 MINUTE