Hi can someone tell me what is the error in this sample pivot command
SELECT *
FROM
(
SELECT *
FROM issued
) Src
PIVOT
( SUM(quantity)
FOR team IN (production,wastage,staff)
) AS Pvt;
I would do conditional aggregation instead :
select col,
sum(case when team = 'Production' then qty else 0 end) as production_qty,
sum(case when team = 'wastage' then qty else 0 end) as wastage_qty,
sum(case when team = 'staff' then qty else 0 end) as staff_qty
from issued
group by col --- use actual column name if any
Related
I have a table named incident_summary that structure and data as following:
month,system_id,s_count
202104,1,50
202104,2,6
202105,1,14
202105,2,4
202106,1,1
202106,2,1
I would like to generate the following statistic:
s_count_on_202106,s_count_before_202106
2,74
where
s_count_on_202106 is sum of s_count value on 202106
s_count_before_202106 is sum of s_count value before 202106
I have tried the following SQL:
select
sum(case when month<202106 then s_count else 0 end)
sum(case when month=202106 then s_count else 0 end)
from incident_summary
group by month
However, it does not work, would you help to me to solve the problem?
Try the following Query.
May be it helps you.
SELECT
t1.s_count_on_202106,
t2.s_count_before_202106
FROM
(
SELECT
sum(s_count) AS s_count_on_202106
FROM
incident_summary
WHERE
month = 202106
) AS t1,
(
SELECT
sum(s_count) AS s_count_before_202106
FROM
incident_summary
WHERE
month < 202106
) AS t2
Sum again on your result set.
SELECT SUM(s_count_before_202106)s_count_before_202106, SUM(s_count_on_202106)s_count_on_202106
FROM
(
select
sum(case when month<202106 then s_count else 0 end)s_count_before_202106 ,
sum(case when month=202106 then s_count else 0 end)s_count_on_202106
from incident_summary
group by month
)T;
I am new in sql. I want to count something like:
Select count(*) from table where col1= x and col2=x and Col3=x.
I need to count the same value in all different column.
Any help will be appreciated.
You can use conditional aggregation :
Select sum(case when col1='x' then 1 else 0 end) as count_col1,
sum(case when col2='x' then 1 else 0 end) as count_col2,
sum(case when col3='x' then 1 else 0 end) as count_col3
from tab;
If you want to have sum of these count values, consider the above query as an inner and use the following :
Select q.*,
q.count_col1 + q.count_col2 + q.count_col3 whole_sum
from
(
Select sum(case when col1='x' then 1 else 0 end) as count_col1,
sum(case when col2='x' then 1 else 0 end) as count_col2,
sum(case when col3='x' then 1 else 0 end) as count_col3
from tab
) q
Rextester Demo
We have a table with data from different nodes and one of the column will have status report as "compliant or non-compliant", sample data as below
I want to filter the table in such a way that if any of the checks on a node shows non compliant, it should be flagged as non-compliant and rest as compliant. Using below query i am able to do it
SELECT COUNT(*) AS total_nodes,
SUM(fully_compliant = 0) AS Non_compliant_nodes,
SUM(fully_compliant = 1) AS compliant_nodes
FROM (
SELECT Node, CASE WHEN SUM(Status = 'Compliant') = COUNT(*) THEN 1 ELSE 0 END AS fully_compliant
FROM your_table GROUP BY Node
)
Now, i want to group and split the result by dept as below, how can i achieve this
I think you're looking for this:
select dept,
count(*) as total_nodes,
sum(case when non_compliant_chk = 0 then 1 else 0 end) as compliant_nodes,
sum(case when non_compliant_chk > 0 then 1 else 0 end) as non_compliant_nodes
from (
select dept,
node,
sum(case when 'Non-Compliant' then 1 else 0 end) as non_compliant_chk
from your_table
group by dept,
node
) v
group by dept;
With few modifications to what Brian suggested, I am able to get the desired result
select dept,
count(*) as total_nodes,
sum(case when non_compliant_chk = 0 then 1 else 0 end) as compliant_nodes,
sum(case when non_compliant_chk > 0 then 1 else 0 end) as non_compliant_nodes
from (
select dept,
node,
COUNT(CASE WHEN Compliance-Status = 'Non-Compliant' THEN 1 END) 'non_compliant_chk'
from table WHERE DOR >= DATE(NOW()) - INTERVAL 7 DAY
group by Dept,
Node
) v
group by Dept;
I have a big query and I want to add a subquery to get the availability of accommodation-rooms.
This is the SQL subquery:
,(SELECT (CASE WHEN count(_days) > 0 THEN 'yes' ELSE 'No' END) as available
FROM
(
SELECT count(rtd.room_type_id) as _days
FROM room_type_day as rtd
WHERE rtd.date IN ('2018-06-20', '2018-06-21', '2018-06-22')
GROUP BY rtd.room_type_id
HAVING COUNT(rtd.room_type_id) = 3
) as sub) as availability
Can anyone tell me how to convert this SQL in DQL?
Thak you
EDIT
I try with this changes but the response is null every time:
,(SELECT (CASE WHEN count(rtd.roomType) > 0 THEN 'yes' ELSE 'no' END)
FROM AppBundle:RoomTypeDayCancelationConditionAccommodation as RTDCCA2
LEFT JOIN RTDCCA2.roomTypeDay as rtd
WHERE rtd.date IN ('2018-06-20', '2018-06-21', '2018-06-22')
GROUP BY rtd.roomType
HAVING COUNT(rtd.roomType) = 3
) as disponible
I have two queries:
select count(*) from my_table where status="accepted"
and
select count(*) from my_table where status="rejected"
I was to find the ratio of accepted/reject so I Was wondering if it's possible to combine the two queries so I don't have to execute two queries
Putting this answer since none offered so far is correct
select count(case when status = "accepted" then 1 end) /
count(case when status = "rejected" then 1 end) as Ratio
from my_table
where status in ("accepted","rejected")
If you also need the individual counts
select count(case when status = "accepted" then 1 end) Accepted,
count(case when status = "rejected" then 1 end) Rejected,
count(case when status = "accepted" then 1 end) /
count(case when status = "rejected" then 1 end) as Ratio
from my_table
where status in ("accepted","rejected")
Note: MySQL does not have a divide by zero problem. It returns NULL when Rejected is 0.
select accepted_count, rejected_count, accepted_count/rejected_count ratio
from (
select sum(CASE WHEN status="accepted" THEN 1 ELSE 0 END) accepted_count,
sum(CASE WHEN status="rejected" THEN 1 ELSE 0 END) rejected_count
from my_table
) A
I think this will work:
SELECT (Select count(*) from my_table where status="accepted") / (select count(*) from my_table where status="rejected") AS ratio
select status, count(*) from my_table
where status in ("rejected", "accepted")
group by status;
select sum(case when status='accepted' then 1 else 0 end) as AcceptedCount,
sum(case when status='rejected' then 1 else 0 end) as RejectedCount
from my_table