I have a big query and I want to add a subquery to get the availability of accommodation-rooms.
This is the SQL subquery:
,(SELECT (CASE WHEN count(_days) > 0 THEN 'yes' ELSE 'No' END) as available
FROM
(
SELECT count(rtd.room_type_id) as _days
FROM room_type_day as rtd
WHERE rtd.date IN ('2018-06-20', '2018-06-21', '2018-06-22')
GROUP BY rtd.room_type_id
HAVING COUNT(rtd.room_type_id) = 3
) as sub) as availability
Can anyone tell me how to convert this SQL in DQL?
Thak you
EDIT
I try with this changes but the response is null every time:
,(SELECT (CASE WHEN count(rtd.roomType) > 0 THEN 'yes' ELSE 'no' END)
FROM AppBundle:RoomTypeDayCancelationConditionAccommodation as RTDCCA2
LEFT JOIN RTDCCA2.roomTypeDay as rtd
WHERE rtd.date IN ('2018-06-20', '2018-06-21', '2018-06-22')
GROUP BY rtd.roomType
HAVING COUNT(rtd.roomType) = 3
) as disponible
Related
Hi can someone tell me what is the error in this sample pivot command
SELECT *
FROM
(
SELECT *
FROM issued
) Src
PIVOT
( SUM(quantity)
FOR team IN (production,wastage,staff)
) AS Pvt;
I would do conditional aggregation instead :
select col,
sum(case when team = 'Production' then qty else 0 end) as production_qty,
sum(case when team = 'wastage' then qty else 0 end) as wastage_qty,
sum(case when team = 'staff' then qty else 0 end) as staff_qty
from issued
group by col --- use actual column name if any
We have a table with data from different nodes and one of the column will have status report as "compliant or non-compliant", sample data as below
I want to filter the table in such a way that if any of the checks on a node shows non compliant, it should be flagged as non-compliant and rest as compliant. Using below query i am able to do it
SELECT COUNT(*) AS total_nodes,
SUM(fully_compliant = 0) AS Non_compliant_nodes,
SUM(fully_compliant = 1) AS compliant_nodes
FROM (
SELECT Node, CASE WHEN SUM(Status = 'Compliant') = COUNT(*) THEN 1 ELSE 0 END AS fully_compliant
FROM your_table GROUP BY Node
)
Now, i want to group and split the result by dept as below, how can i achieve this
I think you're looking for this:
select dept,
count(*) as total_nodes,
sum(case when non_compliant_chk = 0 then 1 else 0 end) as compliant_nodes,
sum(case when non_compliant_chk > 0 then 1 else 0 end) as non_compliant_nodes
from (
select dept,
node,
sum(case when 'Non-Compliant' then 1 else 0 end) as non_compliant_chk
from your_table
group by dept,
node
) v
group by dept;
With few modifications to what Brian suggested, I am able to get the desired result
select dept,
count(*) as total_nodes,
sum(case when non_compliant_chk = 0 then 1 else 0 end) as compliant_nodes,
sum(case when non_compliant_chk > 0 then 1 else 0 end) as non_compliant_nodes
from (
select dept,
node,
COUNT(CASE WHEN Compliance-Status = 'Non-Compliant' THEN 1 END) 'non_compliant_chk'
from table WHERE DOR >= DATE(NOW()) - INTERVAL 7 DAY
group by Dept,
Node
) v
group by Dept;
I'm doing a select on two tables with this:
SELECT m.torneio, m.deck, m.top, m.lugar, sum( m.quantidade ) AS quantidade, m.formato AS formato, q.quantidade AS qtorneio, t.season AS season, sum( m.top ) AS totaltops, count( m.lugar = '1' ) AS venceu
FROM `metagame` AS m, quantidade AS q, torneios AS t
WHERE m.torneio = t.nome
AND m.torneio = q.nome
GROUP BY m.deck
My problem is that venceu is counting all instances instead of only the ones when lugar = 1. Why is that?
tried with sum() too with no good results too. How can i fix this?
I am surprised that count( m.lugar = '1' ) syntaxs but it does and returns the sames as count(*). You should probably change it to sum(case when lugar = 1 else 0 end) as venceu. You should also look closely at the group by to be sure it works as you expect (i suspect not).
count(x) does not accept an expression.
It's only counting how many times x is returned.
What you should do is check if m.lugar is 1 and yes add one to the counter else do nothing.
Inline checks can be done like so:
case when m.lugar = '1' then 1 else 0 end
Then add all the one you gets :
sum(case when m.lugar = '1' then 1 else 0 end)
Your final query should look like this:
SELECT
m.torneio,
m.deck,
m.top,
m.lugar,
sum( m.quantidade ) AS quantidade,
m.formato AS formato,
q.quantidade AS qtorneio,
t.season AS season,
sum( m.top ) AS totaltops,
sum(case when m.lugar = '1' then 1 else 0 end) AS venceu
FROM
`metagame` AS m,
quantidade AS q,
torneios AS t
WHERE
m.torneio = t.nome
AND m.torneio = q.nome
GROUP BY
m.deck
If I understand your question you can use this:
sum(case when m.lugar = '1' then 1 else 0 end)
or you can try having clause
SELECT column_name(s)
FROM table_name
WHERE condition
GROUP BY column_name(s)
HAVING condition
ORDER BY column_name(s);
So I want to group by days for statistics so I have data on each day (type 1 is bought and 0 is sold) but the query gives me the same result everyday and that is not correct can someone help me with this code?
SELECT
DATE(from_unixtime(credit_transaction_time)) AS data_date,
total_spend AS credits_spend,
total_bought AS credits_bought
FROM credit_transactions
JOIN (SELECT SUM(`credit_transaction_amount`) AS total_spend FROM credit_transactions WHERE `credit_transaction_type` = 0 GROUP BY DATE(from_unixtime(credit_transaction_time))) AS spend
JOIN (SELECT SUM(`credit_transaction_amount`) AS total_bought FROM credit_transactions WHERE `credit_transaction_type` = 1 GROUP BY DATE(from_unixtime(credit_transaction_time))) AS bought
GROUP BY DATE(from_unixtime(credit_transaction_time))
Use conditional aggregation:
SELECT DATE(from_unixtime(credit_transaction_time)) AS data_date,
SUM(CASE WHEN credit_transaction_type = 0 THEN credit_transaction_amount ELSE 0 END) as credits_spend,
SUM(CASE WHEN credit_transaction_type = 1 THEN credit_transaction_amount ELSE 0 END) as credits_bought
FROM credit_transactions
GROUP BY DATE(from_unixtime(credit_transaction_time));
Your query doesn't work because you don't have an ON condition. In most databases, this would result in a syntax error, but MySQL allows this syntax.
I have seperate queries but i need to reduce the no so put all in one
select count(applicant_id) as registered from student_application where filter_status=0 AND
select count(applicant_id) as filer_select from student_application where filter_status=1 AND
select count(applicant_id) as filter_reject from student_application where filter_status=2
but this shows some errors
Use CASE expression.
Query
select
count(case when filter_status = 0 then applicant_id else null end) as registered,
count(case when filter_status = 1 then applicant_id else null end) as filer_select,
count(case when filter_status = 2 then applicant_id else null end) as filer_reject
from student_application;
SQL Fiddle
You could also use group_by, with the where clause if you're looking for a subset rather than all possible values of filter_status:
SELECT filter_status, COUNT(*)
FROM student_application
WHERE filter_status in (0, 1, 2)
GROUP BY filter_status;