How to insert row number in database in Laravel - mysql

I am trying to insert ROW NUMBER inside table through controller but failed,
I have tried something like this but showing error,
$data = array(
'name'=>$request->name, 'email'=>$request->email, 'password'=>$password, 'status'=>1, 'user_id' =>ROW_NUMBER()
);
I just want to insert ROW NUMBER of table inside user_id.
Also, if not possible can we insert unique serial number inside user_id
Please help me out.


Each row has a column with name 'id' that is unique and Auto increment.
You can pass 'id' value to 'user_id' like below: (but it's not a good idea)
Why it is a bad idea?
Because when you delete your last row (assume id is 5) your next record 'id' is 6 but the user_id that will you retrieve with code below will be 5.
So, use the alternate option that I will give you in the following.
$last_user = User::orderBy('created_at', 'desc')->first();
$new_user = new User;
...
$new_user->user_id = $last_user->id + 1 ;
$new_user->save();
I figure it out from comments that you need a unique id and this your idea to solve this problem.
I have a better idea and hope that will help you.
you can use uniqid() method.
$new_user = new User;
...
$new_user->user_id = uniqid();
$new_user->save();

Related

lastInsertId(tableName_id_seq) returning :Undefined table: 7 ERROR: relation "tableName_id_seq" does not exist

inserting data in my table in a foreach, and i need to have the last ID inserted.
Im inserting a first entity, get the Id and insert a child entity, linked with this ID.
Database POSTGRES - ENV Symfony 4
Code :
$conn = $em->getConnection();
//Here i do an Insert ( always an INSERT )
$Id = $conn->lastInsertId('tableName_id_seq');
This return :
Undefined table: 7 ERROR: relation "tableName_id_seq" does not exist
I feel like my sequence are not created in the DB
I do not close connexion before calling lastInsertID
It's Always un insert before lastInsertID
This Query:
select sequence_schema, sequence_name from information_schema.sequences;
Return 0 rows

With MySQL you don't need to provide the tableName_id_seq
Can you just try $Id = $conn->lastInsertId();

Well no way using lastinsertId(),
I found my way using
RETURNING id
in the Query, and then after the
$preparedQuery->execute()
i do a
$preparedQuery->fetchAll()

How to insert data into two tables in mysql - Laravel

I want to insert data into two tables of mysql,
Tables are as follows:
1) t_entity_details
2) t_preferences
Columns inside the table are as follows:
t_entity_details
- Entity_id (primary key, auto-increment)
- First_Name
- Sex
- TagLine
- Personal_Desc
- DOB
- Lang
t_preferences
- Entity_id (primary key too, No auto-increment)
- other columns......
Now when I submit a form, the Entity_id should be same in both the tables. So how to do that?
Please help me with this.

The Solution is simple. You can use "mysql_insert_id" to get the last incremented/inserted id. You can use that in turn to insert into your second table.
In Eloquent, things are even more simpler, Assuming you know about Eloquent Models,. You insert to the first table:
$insertArray = array('First_Name' => 'Some_value',
'Sex' => 'Some_value',
'TagLine' => 'Some_value',
'Personal_Desc' => 'Some_value',
'DOB' => 'Some_value',
'Lang' => 'Some_value');
$saveResult = EloquentModel::create($insertArray);
You can then get the last insert id as follows:
$entity_id = $saveResult->id;
You use this to insert into the second table:
$insert_secondTable_array = array("Foo" => "bar");
$insert_secondTable_array['EntityId'] = $entity_id;
$result = SecondEloquentModel::create($insert_secondTable_array);
This inserts into both tables.

In this scenario do the query statement as,
insert into t_entity_details (column1,column2,column3,...)
VALUES (value1,value2,value3,...);
insert into t_preferences SELECT * FROM t_entity_details;
i believe this type will solve your problem if you don't do manipulation using other columns.

ezSQL insert and return id or row?

I most recently came across ezSQL and thought it's pretty cool.
Based on the tutorial, I perform the following to create a new row:
$db->query(“INSERT INTO users (name) VALUES ('Amy')”) ;
How do i retrieve the id ( assuming auto-increment ) for the above query ?
THanks!

According to the documentation, the ID should be accessible with $db->insert_id

The return value of your executed query is number of rows that were effected, while the insert id can be found by $db->insert_id.
So the code should be like:
$result = $db->query(“INSERT INTO users (name) VALUES ('Amy')”) ;
if($result){
$insert_id = $db->insert_id;
}else{
echo "Row could not be inserted.";
}
$result value will be 1, which displays the number of rows that were inserted in to database.
$insert_id is the id that you are looking for!

PDO - lastInsertId() for insert query with multiple rows

I can insert 2 pets into a table, and get their lastInsertId() for further processing one at a time (2 queries). I am wondering if there is a way to get two lastInsertIds() and assign them to variables if I am inserting 2 rows in 1 query:
$query = "INSERT INTO pets (pet_name) VALUES (':coco'),(':jojo')";
$pet_insert = $dbh->prepare($query);
$pet_insert->execute(array(':coco' => $coco,':jojo' => $jojo));
$New_PetID = $dbh->lastInsertId();
Is it possible to get the lastInsertId() for coco and for jojo? So something like:
$New_PetID1 = $dbh->lastInsertId();//coco
$New_PetID2 = $dbh->lastInsertId();//jojo
This will give the same ID, any way to get the 2 IDs? Just for reference, this is in a try block.

It's not possible. If you need generated ids for both rows - you need to perform 2 separated INSERT
Important If you insert multiple rows using a single INSERT statement,
LAST_INSERT_ID() returns the value generated for the first inserted
row only. The reason for this is to make it possible to reproduce
easily the same INSERT statement against some other server.
http://dev.mysql.com/doc/refman/5.5/en/information-functions.html#function_last-insert-id

you can add 1 to last insert id to achieve the real last record id.and if you insert more than 2 record just add rowCount - 1 to last_insert_id.
With innodb_autoinc_lock_mode set to 0 (“traditional”) or 1 (“consecutive”), the auto-increment values generated by any given statement will be consecutive, without gaps, because the table-level AUTO-INC lock is held until the end of the statement, and only one such statement can execute at a time.
and
The ID that was generated is maintained in the server on a per-connection basis. This means that the value returned by the function to a given client is the first AUTO_INCREMENT value generated for most recent statement affecting an AUTO_INCREMENT column by that client. This value cannot be affected by other clients, even if they generate AUTO_INCREMENT values of their own. This behavior ensures that each client can retrieve its own ID without concern for the activity of other clients, and without the need for locks or transactions.
for more info read this document http://dev.mysql.com/doc/refman/5.1/en/innodb-auto-increment-handling.html

Please, please avoid the type of solutions given by Bruce. The auto increment value can be set to be different than 1. For instance in case of master to master replication. A little while back a host where one of our applications runs on changed their db setup. I happened to notice -purely by coincidence- that all of a sudden the id's incremented with two instead of one. Would we have had any code like this it could have caused us serious problems.

The documentation states: Returns the ID of the last inserted row or sequence value
You will need to perform two queries to get the id for each inserted row.

I tried to assume that is is not possible until I tried it on my own and figured that IT IS POSSIBLE.
After each execute, add the lastInsertId() and assign a key.
For my example:
// First query
$sql = "INSERT INTO users
(username, email)
values
(:username, :email)";
$sth = $this->db->prepare($sql);
$sth->bindParam(':username', $data['username'], PDO::PARAM_STR);
$sth->bindParam(':email', $data['email'], PDO::PARAM_STR);
// Second Query
$sql2 = "INSERT INTO users
(username, email)
values
(:username, :email)";
$sth2 = $this->db->prepare($sql2);
$sth2->bindParam(':username', $data['username'], PDO::PARAM_STR);
$sth2->bindParam(':email', $data['email'], PDO::PARAM_STR);
// Start trans
$this->db->beginTransaction();
// Execute the two queries
$sth->execute();
$last['ux1'] = $this->db->lastInsertId(); // <---- FIRST KEY
$sth2->execute();
$last['ux2'] = $this->db->lastInsertId(); // <---- SECOND KEY
// Commit
$this->db->commit();
And I was able to retrieve the two last inserted ids
Array (
[create] => Array
(
[ux1] => 117
[ux2] => 118
)
)
I hope this will help others who are seeking the right answer.

Well, since 1000 inserts is a bit longer than 1 insert, the issue of topic is still interesting. Possible workaround would be to make 2 queries. The first one is to insert 1000 rows and the second one is to select them if there is something unique in those inserted rows.
For example with pets:
INSERT INTO pets ( name ) VALUES ( 'coco', 'jojo' );
SELECT id FROM pets WHERE name IN ( 'coco', 'jojo' );
This could give benefit only for big data sets.

I used the array in the first statement and in the second add if condition. So If insert record get its last id then make the second statement. If insert the second array get its last id then repeat the second statement
for ($count=0; $count < count($_POST["laptop_ram_capacity"]); $count++) {
$stmt = $con->prepare('INSERT INTO `ram`
(ram_capacity_id, ram_type_id, ram_bus_id, ram_brand_id, ram_module_id)
VALUES (?,?,?,?,?)');
//excute query//
$stmt->execute(array(
$_POST['laptop_ram_capacity'][$count],
$_POST["laptop_ram_type"][$count],
$_POST["laptop_ram_bus"][$count],
$_POST["laptop_ram_brand"][$count],
$_POST["laptop_ram_module"][$count]
));
//fetsh the data//
$rows = $stmt->rowCount();
// i add the below statment in if condition to repeat the insert and pass the repeated of the last statement//
if ($rows > 0) {
$LASTRAM_ID = $con->lastInsertId();
$stmt = $con->prepare('INSERT INTO `ram_devicedesc_rel`
(ram_id, Parent_device_description_id)
VALUES (?,?)');
//excute query//
$stmt->execute(array(
$LASTRAM_ID,
$LASTdevicedesc_ID
));
//fetsh the data//
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
}

you can use 'multi_query()'
add all the query into one variable like :
'$sql1 = "first insert";'
'$sql2 = "second insert";'
'$sql3 = "third insert";' and so on...
take the count of number of inserts your gonna make.
now execute all the '$sql' queries using 'multi_query()'.
get the last insert id.
now all you have to do is '$rowno = $lastinsertid - $countofinserts'.
so basically you will get a number.
add 1 to it and from the resulting number to the lastinsertid are the insert id's of the insert queries you ran

It is possible! All you need to do is call the PDO lastInsertId() method. This will return the first inserted id when doing multiple or bulk INSERT. Next we need to perform a simple addition subtraction operation with the number of rows affected by the last INSERT statement.
$firstInsertedId = $this->lastInsertId();
$InsertedIds = range($firstInsertedId, ($firstInsertedId + ($stmt->rowCount() - 1)) );
print_r($InsertedIds);

First wpdb insert to mySql new table isn't working

I created a new mySql table and I need the first field to be an index and a key.
I'm not sure I got the terminology right but I simply need that field to automatically increment by 1 with each insert.
So I defined that field as an index and gave it the auto_increment attribute.
Now I try to insert the first row like this:
$wpdb->insert('wp_branches', array(user_id=>$user_id, branchName=>$bname));
The index/key field branchId is missing from this query because I'm counting on the db to automatically give it the value 1 since it's the first insert, and then increment it with every additional insert.
For some reason the row isn't being inserted and db is left empty.
What am I doing wrong?

try like so:
$sql = $wpdb->prepare(
"INSERT INTO `wp_branches` (`user_id`,`branchName`) values (%d,%s)",
$user_id, $bname);
$wpdb->query($sql);
this will protect you against "injections" too.

modified so:
$wpdb->insert('wp_branches', array('user_id' => $user_id, 'branchName' => $bname));