Just an amateur here needing a little help.
I have a table named tbl_inspection_areas.area_description
columns 'area_description' and 'display_tab'.
I want a query that returns 'area_description','display_tab' and the number of times each display tab occurs.
Like in the drawing below.
| tbl_inspection_areas.area_description | tbl_inspection_areas.display_tab | count |
_____________________________________________________________________________________________
| engine | 38 | 2 |
| transmission | 38 | |
| interior | 39 | 1 |
| wheels | 40 | 3 |
| glass | 40 | |
| lights | 40 | |
This is the best I have come up with, but it only displays 3 rows and the count is in 3 seperate columns.
Any help would be great.
SELECT
tbl_inspection_areas.area_description,
tbl_inspection_areas.display_tab,
SUM(CASE WHEN tbl_inspection_areas.display_tab = '38' THEN 1 ELSE 0 END) AS count1,
SUM(CASE WHEN tbl_inspection_areas.display_tab = '39' THEN 1 ELSE 0 END) AS count2,
SUM(CASE WHEN tbl_inspection_areas.display_tab = '40' THEN 1 ELSE 0 END) AS count3,
SUM(CASE WHEN tbl_inspection_areas.display_tab = '46' THEN 1 ELSE 0 END) AS count4
FROM tbl_inspection_areas
GROUP BY tbl_inspection_areas.display_tab
SELECT
tbl_inspection_areas.area_description,
tbl_inspection_areas.display_tab,
COUNT(tbl_inspection_areas.display_tab)
FROM tbl_inspection_areas
GROUP BY tbl_inspection_areas.area_description,
tbl_inspection_areas.display_tab,
Related
I have 3 tables like the following.
Table "mansioni":
id_mansione | desc_mansione
1 | production
2 | office
3 | transport
Table "dipendente": store id, name and surname:
id_dip | nome_dip | cognome_dip
1 | piero | rossi
2 | marco | rossi
Table dipendenti_iddip: store the association between "dipendente" and table "mansioni"
iddip_mansione | num_mansione | id_mansione
1 | 1 | 1
1 | 2 | 2
2 | 1 | 2
2 | 2 | 3
Now I need a query that give me a result like this:
id_dip | nome_dip | cognome_dip | mansione1 | mansione2 | mansione3
1 | piero | rossi | production| office |
2 | marco | rossi | office | transport |
I arrived to the following query but with this I can only see the "id_mansione" and not the "desc mansione" field
select i.id_dip,
i.nome_dip,
i.cognome_dip,
max(case when t.num_mansione='1' then t.id_mansione end) Mansione1,
max(case when t.num_mansione='2' then t.id_mansione end) Mansione2,
max(case when t.num_mansione='3' then t.id_mansione end) Mansione3
from dipendente i
left join dipendenti_iddip t
on i.id_dip = t.iddip_mansione
group by i.id_dip, i.nome_dip, i.cognome_dip
How can I arrive to my result?
Thanks...
Add join on mansioni and replace t.id_mansione with m.desc_mansione
select i.id_dip,
i.nome_dip,
i.cognome_dip,
max(case when t.num_mansione = '1' then m.desc_mansione end) Mansione1,
max(case when t.num_mansione = '2' then m.desc_mansione end) Mansione2,
max(case when t.num_mansione = '3' then m.desc_mansione end) Mansione3
from dipendente i
join dipendenti_iddip t
on i.id_dip = t.iddip_mansione
join mansioni m on m.id_mansione = t.id_mansione
group by i.id_dip
I have following tables products and tests.
select id,pname from products;
+----+---------+
| id | pname |
+----+---------+
| 1 | prd1 |
| 2 | prd2 |
| 3 | prd3 |
| 4 | prd4 |
+----+---------+
select pname,testrunid,testresult,time from tests;
+--------+-----------+------------+-------------+
| pname | testrunid | testresult | time |
+--------+-----------+------------+-------------+
| prd1 | 800 | PASS | 2017-10-02 |
| prd1 | 801 | FAIL | 2017-10-16 |
| prd1 | 802 | PASS | 2017-10-02 |
| prd1 | 803 | NULL | 2017-10-16 |
| prd1 | 804 | PASS | 2017-10-16 |
| prd1 | 805 | PASS | 2017-10-16 |
| prd1 | 806 | PASS | 2017-10-16 |
+--------+-----------+------------+-------------+
I like to count test results for products and if there is no result available,for a product just show a zero for it. something like following table:
+--------+------------+-----------+----------------+---------------+
| pname | total_pass | total_fail| pass_lastweek | fail_lastweek |
+--------+------------+-----------+----------------+---------------+
| prd1 | 5 | 1 | 3 | 1 |
| prd2 | 0 | 0 | 0 | 0 |
| prd3 | 0 | 0 | 0 | 0 |
| prd4 | 0 | 0 | 0 | 0 |
+--------+------------+-----------+----------------++--------------+
I have tried different queries like following, which is just working for one product and is incomplete:
SELECT pname, count(*) as pass_lastweek FROM tests where testresult = 'PASS' AND time
>= '2017-10-11' and pname in (select pname from products) group by pname;
+-------------+---------------+
| pname | pass_lastweek |
+-------------+---------------+
| prd1 | 3 |
+-------------+---------------+
it looks so basic but still I am unable to write it, any idea?
Use conditional aggregation. The COUNT function count NULL values as zeros automatically, therefore, there is no need to take care of that.
select p.pname,
count(case when testresult = 'PASS' then 1 end) as total_pass,
count(case when testresult = 'FAIL' then 1 end) as total_fail,
count(case when testresult = 'PASS' and time >= curdate() - INTERVAL 6 DAY then 1 end) as pass_lastweek ,
count(case when testresult = 'FAIL' and time >= curdate() - INTERVAL 6 DAY then 1 end) as fail_lastweek ,
from products p
left join tests t on t.pname = p.pname
group p.id, p.pname
Generally, you need to LEFT JOIN the first table with the second one before you group. The join will give you a row for each product (even if there are no test results to join it to; INNER JOIN would exclude products with no associated tests) + an additional row for each test result (beyond the first). Then you can group them.
SELECT products.*, tests.* FROM products
LEFT JOIN tests ON products.pname = tests.pname
GROUP BY products.id
Also, I would strongly recommend using a product_id column in the tests table, rather than using pname (if a products.pname changes, your whole DB breaks unless you also update the pname field in kind for every test result). The general query would then look like this:
SELECT products.*, tests.* FROM products
LEFT JOIN tests ON products.id = tests.product_id
GROUP BY products.id
I used 2 queries , the first with conditional count and the second one is to change all null values into 0 :
select pname,
case when total_pass is null then 0 else total_pass end as total_pass,
case when total_fail is null then 0 else total_fail end as total_fail,
case when pass_lastweek is null then 0 else pass_lastweek end as pass_lastweek,
case when fail_lastweek is null then 0 else fail_lastweek end asfail_lastweek from (
select products.pname,
count(case when testresult = 'PASS' then 1 end) as total_pass,
count(case when testresult = 'FAIL' then 1 end) as total_fail,
count(case when testresult = 'PASS' and time >= current_date -7 DAY then 1 end) as pass_lastweek ,
count(case when testresult = 'FAIL' and time >= current_date -7 DAY then 1 end) as fail_lastweek ,
from products
left join tests on tests.pname = products.pname
group 1 ) t1
| product | tests | runs | results |
|---------|-------|------|---------|
| A | AD | 1 | 12 |
| A | AD | 2 | 13 |
| A | AD | 3 | 14 |
| A | SS | 1 | 12 |
| A | TD | 1 | 12 |
| A | TD | 2 | 12 |
| B | AD | 1 | 11 |
| B | SS | 1 | 12 |
| c | AD | 1 | 12 |
| c | AD | 2 | 10 |
| D | AD | 1 | 16 |
| D | SS | 1 | 12 |
I used this query:
select DISTINCT Poduct,
SUM (case param_name when 'AD' then results ELSE 0 END) AS AD,
SUM (case param_name when 'SS' then results ELSE 0 END) AS SS,
SUM (case param_name when 'TD' then results ELSE 0 END) AS TD
FROM [product]
GROUP BY product
ORDER BY product
To get it in this format:
| PRODUCT | AD | SS | TD |
|---------|----|----|----|
| A | 39 | 12 | 24 |
| B | 11 | 12 | 0 |
| C | 22 | 0 | 0 |
| D | 16 | 12 | 0 |
I need it in this format, but the problem is that it's adding up all the test runs on AD, SS, and TD.
What I'm looking for is this:
| PRODUCT | AD | SS | TD |
|---------|----|----|----|
| A | 14 | 12 | 12 |
| B | 11 | 12 | 0 |
| C | 10 | 0 | 0 |
| D | 16 | 12 | 0 |
Which is pulling only the results from the greater run of that test.
Can anyone help?
Try this:
select product, max(ad) ad, max(ss) ss, max(td) td
from (
select Product,
MAX(case tests when 'AD' then results ELSE 0 END) AS AD,
MAX(case tests when 'SS' then results ELSE 0 END) AS SS,
MAX(case tests when 'TD' then results ELSE 0 END) AS TD
FROM product
GROUP BY product, tests
) test_reports
group by product
ORDER BY product;
Demo # SQL Fiddle
I think, assuming fro your expected result, you are wanting to SUM on those columns (AD,SS,TD) based on your highest RUN number. You could use ROW_NUMBER to assign the order based on your requirement and choose the right values set
Try this...
WITH CTE AS
( SELECT *, ROW_NUMBER() OVER(partition BY product,test order by runs desc) rownum FROM product
)
select Product,
SUM (case test when 'AD' then results ELSE 0 END) AS AD,
SUM (case test when 'SS' then results ELSE 0 END) AS SS,
SUM (case test when 'TD' then results ELSE 0 END) AS TD
FROM CTE
WHERE rownum=1
GROUP BY product
ORDER BY product
One way to approach this is to think of a temporary table that has the following fields: product, tests, and max_runs. (i.e. identifying the max run # for each combination of product + tests). If you have such a table, you can JOIN it back to the original (inner join) to select only the row with the max run#.
Then, using your case statement on the result will work.
Putting it all together, you would get this:
select P.product,
sum(case P.tests when 'AD' then P.results ELSE 0 END) AS AD,
sum(case P.tests when 'SS' then P.results ELSE 0 END) AS SS,
sum(case P.tests when 'TD' then P.results ELSE 0 END) AS TD
from product P join
(
SELECT product, tests, max(runs) As max_runs
from product
group by product, tests
) As M
on P.product=M.product and P.tests=M.tests and P.runs=M.max_runs
group by P.product
order by P.product
Check out this SQL Fiddle if you want to play with it.
I am creating a database with the tables below, where shop_id in hours refers to a an id in shop.
Preferably I would have a query to return all data in one row, in stead of needing to post-process a lot of rows to "merge" the result from hours so the end result looks like this.
+-------------------+---------+------+---------+----------------+----------+---------------+---------------+-----+-----+-----+-----+-----+-----+-----+
| name | address | zip | city | municipal | phone | lat | lng | day | day | day | day | day | day | day |
+-------------------+---------+------+---------+----------------+----------+---------------+---------------+-----+-----+-----+-----+-----+-----+-----+
| Coop Marked Budal | false | 7298 | Budalen | Midtre gauldal | 72436410 | 62.8837013245 | 10.4836997986 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
+-------------------+---------+------+---------+----------------+----------+---------------+---------------+-----+-----+-----+-----+-----+-----+-----+
Right now I have come to the query below, wich I feel there must be a better alternative to. So my question is: Is there really another solution to this?
Also, I've seen concat, but I want to avoid having to split strings later on when processing the data.
select shop.name, shop.address, shop.zip, shop.city, shop.municipal, shop.phone, shop.lat, shop.lng,
h.day, hh.day, hhh.day, hhhh.day, hhhhh.day, hhhhhh.day, hhhhhhh.day
from shop
/**
As it requires a unique table name, this was the solution I found.
Could this be shortened?
**/
inner join hours h on shop.id = h.shop_id and h.day = 1
inner join hours hh on shop.id = hh.shop_id and hh.day = 2
inner join hours hhh on shop.id = hhh.shop_id and hhh.day = 3
inner join hours hhhh on shop.id = hhhh.shop_id and hhhh.day = 4
inner join hours hhhhh on shop.id = hhhhh.shop_id and hhhhh.day = 5
inner join hours hhhhhh on shop.id = hhhhhh.shop_id and hhhhhh.day = 6
inner join hours hhhhhhh on shop.id = hhhhhhh.shop_id and hhhhhhh.day = 7;
Tables
shop
+----+-------------------+---------+------+---------+----------------+----------+---------------+---------------+----------+-----------+
| id | name | address | zip | city | municipal | phone | lat | lng | chain_id | county_id |
+----+-------------------+---------+------+---------+----------------+----------+---------------+---------------+----------+-----------+
| 1 | Test | false | 1234 | Test | Test | 12341234| 0.0000 | 0.0000 | 3 | 16 |
+----+-------------------+---------+------+---------+----------------+----------+---------------+---------------+----------+-----------+
hours
+-----+----------+----------+---------+
| day | open | close | shop_id |
+-----+----------+----------+---------+
| 1 | 09:00:00 | 18:00:00 | 1 |
| 2 | 09:00:00 | 18:00:00 | 1 |
| 3 | 09:00:00 | 18:00:00 | 1 |
| 4 | 09:00:00 | 18:00:00 | 1 |
| 5 | 09:00:00 | 18:00:00 | 1 |
| 6 | 09:00:00 | 20:00:00 | 1 |
| 7 | 14:00:00 | 20:00:00 | 1 |
+-----+----------+----------+---------+
You can also use a case .. when to do the pivot, and then group by the shop fields and use an aggregate function to process the day.
select
shop.NAME, shop.address, shop.zip, shop.city, shop.municipal, shop.phone, shop.lat, shop.lng,
MAX(CASE WHEN h.DAY = 1 THEN h.DAY ELSE 0 END) AS Day1,
MAX(CASE WHEN h.DAY = 2 THEN h.DAY ELSE 0 END) AS Day2,
MAX(CASE WHEN h.DAY = 3 THEN h.DAY ELSE 0 END) AS Day3,
MAX(CASE WHEN h.DAY = 4 THEN h.DAY ELSE 0 END) AS Day4,
MAX(CASE WHEN h.DAY = 5 THEN h.DAY ELSE 0 END) AS Day5,
MAX(CASE WHEN h.DAY = 6 THEN h.DAY ELSE 0 END) AS Day6,
MAX(CASE WHEN h.DAY = 7 THEN h.DAY ELSE 0 END) AS Day7
from shop
INNER JOIN HOURS h ON shop.id = h.shop_id
group by
shop.NAME, shop.address, shop.zip, shop.city, shop.municipal, shop.phone, shop.lat, shop.lng;
Just a note about what you want displayed in the day columns:
AFAIK if any of the hours rows for a shop : day is missing, your current query will drop the whole row? If you want this behaviour repeated, you will need to also add in a where clause.
I'm using two tables in the database.
The first contains data related to the successful and unsuccessful payments while the second table contains data regarding the status of services.
The result of the query should combine both tables and as a result list the successful and unsuccessful payments grouped by the days as well as the status of services grouped by days.
First table looks like:
id | charged | date
-----------------------------
8 | OK | 2011-12-03
7 | OK | 2011-12-03
9 | NO | 2011-12-03
11 | OK | 2011-12-04
14 | NO | 2011-12-04
The second table looks like:
id | status | date
--------------------------
8 | 1 | 2011-12-03
9 | 1 | 2011-12-03
11 | 0 | 2011-12-04
12 | 0 | 2011-12-04
14 | 1 | 2011-12-04
The correct query result should be:
date | not_charged | charged | status_1 | status_0
-----------------------------------------------------------
2011-12-04 | 1 | 1 | 1 | 2
2011-12-03 | 1 | 2 | 2 | 0
The query that I've tried looks like this:
SELECT i.date, SUM(
CASE WHEN i.charged = 'NO'
THEN 1 ELSE 0 END ) AS not_charged, SUM(
CASE WHEN i.charged = 'OK'
THEN 1 ELSE 0 END ) AS charged, SUM(
CASE WHEN s.status = '1'
THEN 1 ELSE 0 END ) AS status_1, SUM(
CASE WHEN s.status = '0' THEN 1 ELSE 0 END ) AS status_0
FROM charge i INNER JOIN status s ON s.date = i.date
GROUP BY i.date
But I get the wrong result that looks like this
date | not_charged | charged | status_1 | status_0
---------------------------------------------------------
2011-12-04 | 3 | 3 | 2 | 4
2011-12-03 | 2 | 4 | 6 | 0
What I'm doing wrong and how can I get the correct result?
Thanks for all suggestions.
Try this one -
SELECT date,
SUM(IF(charged = 'NO', 1, 0)) not_charged,
SUM(IF(charged = 'OK', 1, 0)) charged,
SUM(IF(status = 1, 1, 0)) status_1,
SUM(IF(status = 0, 1, 0)) status_0
FROM (
SELECT date, charged, NULL status FROM charge
UNION ALL
SELECT date, NULL charged, status FROM status
) t
GROUP BY date DESC;
+------------+-------------+---------+----------+----------+
| date | not_charged | charged | status_1 | status_0 |
+------------+-------------+---------+----------+----------+
| 2011-12-04 | 1 | 1 | 1 | 2 |
| 2011-12-03 | 1 | 2 | 2 | 0 |
+------------+-------------+---------+----------+----------+
This assumes the ID columns related that service status and payment status together...
SELECT
COALESCE(charge.date, status.date) AS date,
SUM(CASE WHEN charge.charged = 'NO' THEN 1 ELSE 0 END) AS not_charged,
SUM(CASE WHEN charge.charged = 'OK' THEN 1 ELSE 0 END) AS charged,
SUM(CASE WHEN status.status = '0' THEN 1 ELSE 0 END) AS status_0,
SUM(CASE WHEN status.status = '1' THEN 1 ELSE 0 END) AS status_1
FROM
charge
FULL OUTER JOIN
status
ON charge.id = status.id
GROUP BY
COALESCE(charge.date, status.date)
Note, I'm note sure how you want to deal with 7 (No status record) and 12 (no charge record). This currently just counts what is there.
Alternatively, if you don't want to related the records by ID, you can still relate by date but you need to change your logic.
At present you're getting this, because you only relate by date...
id | charged | date id | status | date
----------------------------- --------------------------
8 | OK | 2011-12-03 8 | 1 | 2011-12-03
8 | OK | 2011-12-03 9 | 1 | 2011-12-03
7 | OK | 2011-12-03 8 | 1 | 2011-12-03
7 | OK | 2011-12-03 9 | 1 | 2011-12-03
9 | NO | 2011-12-03 8 | 1 | 2011-12-03
9 | NO | 2011-12-03 9 | 1 | 2011-12-03
11 | OK | 2011-12-04 11 | 0 | 2011-12-04
11 | OK | 2011-12-04 12 | 0 | 2011-12-04
11 | OK | 2011-12-04 14 | 1 | 2011-12-04
14 | NO | 2011-12-04 11 | 0 | 2011-12-04
14 | NO | 2011-12-04 12 | 0 | 2011-12-04
14 | NO | 2011-12-04 14 | 1 | 2011-12-04
Instead you need to consolidate the data down to 1 per date per table, then join...
SELECT
COALESCE(charge.date, status.date) AS date,
charge.not_charged,
charge.charged,
status.status_0,
status.status_1
FROM
(
SELECT
date,
SUM(CASE WHEN charged = 'NO' THEN 1 ELSE 0 END) AS not_charged,
SUM(CASE WHEN charged = 'OK' THEN 1 ELSE 0 END) AS charged
FROM
charge
GROUP BY
date
)
AS charge
FULL OUTER JOIN
(
SELECT
date,
SUM(CASE WHEN charged = '0' THEN 1 ELSE 0 END) AS status_0,
SUM(CASE WHEN charged = '1' THEN 0 ELSE 1 END) AS status_1
FROM
status
GROUP BY
date
)
AS status
ON charge.date = status.date
There are other methods, but hopefully this explains a bit for you.
I suggest using a UNION ALL:
select date,
coalesce(sum(not_charged),0) not_charged,
coalesce(sum(charged),0) charged,
coalesce(sum(status_1),0) status_1,
coalesce(sum(status_0),0) status_0
from (select date,
case charged when 'NO' then 1 end not_charged,
case charged when 'OK' then 1 end charged,
0 status_1,
0 status_0
from charge
union all
select date,
0 not_charged,
0 charged,
case status when '1' then 1 end status_1,
case status when '0' then 1 end status_0
from status) sq
group by date