I´m trying to create Foreign Keys in phpmyadmin, but I get this error:
Error creating foreign key on revision (check data types)
I don´t understand it because the data types are equal. So, what I want is to create a Foreign Key from 'acoustictreatment' to 'filterspecifications' which contains tag, offerid and revision. But I get the error that I mentioned.
This are my tables:
CREATE TABLE `offer` (
`projectid` varchar(20) NOT NULL,
`customer` varchar(255) NOT NULL,
`creator` varchar(255) NOT NULL,
`date` date NOT NULL,
`revision` int(11) NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4;
ALTER TABLE `offer`
ADD PRIMARY KEY (`projectid`,`revision`);
CREATE TABLE `filterspecifications` (
`tag` varchar(100) NOT NULL,
`gasFlow` double NOT NULL,
`dustToHandle` double NOT NULL,
`offerid` varchar(20) NOT NULL,
`selectedFilter` varchar(20) NOT NULL,
`revision` int(11) NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4;
ALTER TABLE `filterspecifications`
ADD PRIMARY KEY (`tag`,`offerid`,`revision`),
ADD KEY `offerid` (`offerid`,`revision`);
ALTER TABLE `filterspecifications`
ADD CONSTRAINT `filterspecifications_ibfk_1`
FOREIGN KEY (`offerid`,`revision`) REFERENCES `offer` (`projectid`, `revision`) ON DELETE CASCADE ON UPDATE CASCADE;
CREATE TABLE `acoustictreatment` (
`tag` varchar(100) NOT NULL,
`offerid` varchar(20) NOT NULL,
`outputFanSilencer` tinyint(1) NOT NULL,
`fanAcousticInsulation` tinyint(1) NOT NULL,
`revision` int(11) NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4;
ALTER TABLE `acoustictreatment`
ADD PRIMARY KEY (`tag`,`offerid`,`revision`);
The solution that I found is to delete the 'acoustictreatment' table and create it again with the foreign key from the beginning. Because what I was trying to do was to create all the tables and then create the foreign keys, but that didn´t work for me
Related
So I have two tables, customers and appointments.
Im trying to create a very simple FK relation between appointments.customer_id and customers.id, however when I do my ALTER TABLE trying to add the FK im getting this error:
MySQL said: Cannot add or update a child row: a foreign key constraint fails (wax.#sql-2c5_100, CONSTRAINT customer_fk FOREIGN KEY (id) REFERENCES customers (id) ON DELETE CASCADE ON UPDATE CASCADE)
This constraint "#sql-2c5_100" seems to be some randomly generated constraint, that I can not find ANYWHERE. I've looked on every table on the database, ive looked on all the tables on the information schema and it simply does not exist.
Thanks!
Edit:
Here's the create table outputs
CREATE TABLE `appointments` (
`id` int(11) unsigned NOT NULL AUTO_INCREMENT,
`customer_id` int(11) unsigned NOT NULL,
`name` varchar(255) DEFAULT NULL
PRIMARY KEY (`id`),
KEY `customer_id` (`customer_id`)
) ENGINE=InnoDB AUTO_INCREMENT=290958 DEFAULT CHARSET=utf8;
CREATE TABLE `customers` (
`id` int(11) unsigned NOT NULL AUTO_INCREMENT,
`first_name` varchar(255) NOT NULL DEFAULT '',
`last_name` varchar(255) NOT NULL DEFAULT '',
`phone` varchar(20) DEFAULT NULL
PRIMARY KEY (`id`),
KEY `sf_id` (`sf_id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
When I'm going to execute this code, I'm getting this error message:
You have an error in your SQL syntax; check the manual that
corresponds to your MySQL server version for the right syntax to use
near 'ADD CONSTRAINT fk_pay_grade_scale FOREIGN KEY pay_scale_id
REFERENCES `pay_s' at line 11
But I don't understand the problem. Your help is appreciated!
CREATE TABLE IF NOT EXISTS `pay_grades` (
`pay_grade_id` int(20) NOT NULL,
`pay_scale_id` tinyint(4) NOT NULL,
`name` varchar(100) NOT NULL,
`basic_salary` decimal(10,2) NOT NULL,
`status` int(2) NOT NULL DEFAULT '1',
PRIMARY KEY (`pay_grade_id`),
INDEX (`pay_scale_id`, `pay_grade_id`),
ADD CONSTRAINT `fk_pay_grade_scale` FOREIGN KEY `pay_scale_id` REFERENCES `pay_scales`(`id`) ON UPDATE CASCADE ON DELETE RESTRICT
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
CREATE TABLE IF NOT EXISTS `pay_scales` (
`id` tinyint(4) NOT NULL,
`name` varchar(100) NOT NULL,
PRIMARY KEY(id)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
You can not use ADD CONSTRAINT in a CREATE TABLE declaration.
Declare your constraint after creating the table or in the CREATE TABLE.
First solution: Add the constraint in CREATE TABLE
CREATE TABLE IF NOT EXISTS `pay_grades` (
`pay_grade_id` int(20) NOT NULL,
`pay_scale_id` tinyint(4) NOT NULL,
`name` varchar(100) NOT NULL,
`basic_salary` decimal(10,2) NOT NULL,
`status` int(2) NOT NULL DEFAULT '1',
PRIMARY KEY (`pay_grade_id`),
INDEX (`pay_scale_id`, `pay_grade_id`),
FOREIGN KEY (`pay_scale_id`) REFERENCES `pay_scales`(`id`) ON UPDATE CASCADE ON DELETE RESTRICT
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
Second solution: Alter table to add the constraint
Create your table without the constraint, and then add your constraint as follow:
ALTER TABLE `pay_grades`
ADD CONSTRAINT `pay_scale_id` FOREIGN KEY REFERENCES `pay_scales`(`id`)
ON UPDATE CASCADE ON DELETE RESTRICT;
MySQL documentation for foreign keys declaration.
It seems the difference in order of table creation. First create primary key table than create the table of foreign key.
CREATE TABLE IF NOT EXISTS `pay_scales` (
`id` tinyint(4) NOT NULL,
`name` varchar(100) NOT NULL,
PRIMARY KEY(id)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
CREATE TABLE IF NOT EXISTS `pay_grades` (
`pay_grade_id` int(20) NOT NULL,
`pay_scale_id` tinyint(4) NOT NULL,
`name` varchar(100) NOT NULL,
`basic_salary` decimal(10,2) NOT NULL,
`status` int(2) NOT NULL DEFAULT '1',
PRIMARY KEY (`pay_grade_id`),
INDEX (`pay_scale_id`, `pay_grade_id`),
ADD CONSTRAINT `fk_pay_grade_scale` FOREIGN KEY `pay_scale_id` REFERENCES `pay_scales`(`id`) ON UPDATE CASCADE ON DELETE RESTRICT
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
Does anybody know why I have the error
Error Code: 1215. Cannot add foreign key constraint
When I try
ALTER TABLE hermanos ADD CONSTRAINT fk_hno_provincia FOREIGN KEY (provincia) REFERENCES p_provincias (id)
On these tables:
CREATE TABLE IF NOT EXISTS `hermanos` (
`codigo` int(11) NOT NULL AUTO_INCREMENT,
`nombre` varchar(255) NOT NULL,
`apellidos` varchar(255) NOT NULL,
`direccion` varchar(255) NOT NULL,
`codigoPostal` int(11) NOT NULL,
`provincia` int(11) NOT NULL,
`numeroHermano` int(11) NOT NULL,
`dni` varchar(9) NOT NULL,
`tipoCuota` int(11) NOT NULL,
`sexo` int(11) NOT NULL,
PRIMARY KEY (`codigo`),
KEY `sexo` (`sexo`),
KEY `pk_hno_cuota` (`tipoCuota`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=6 ;
CREATE TABLE IF NOT EXISTS `p_provincias` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`nombre` varchar(125) DEFAULT NULL,
PRIMARY KEY (`id`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=53 ;
Thanks
The parent and child tables must use the same storage engine.
I noticed that hermanos uses InnoDB and p_provincias uses MyISAM.
For more info, see here
Foreign keys definitions are subject to the following conditions:
Foreign key relationships involve a parent table that holds the
central data values, and a child table with identical values pointing
back to its parent. The FOREIGN KEY clause is specified in the child
table. The parent and child tables must use the same storage engine.
They must not be TEMPORARY tables.
I want to create a database and connect it with two database. But I don't know when i create the Foreign Key to the second database (time_shift table) it always result error 150;
Here is the structure of table outlet:
And this is structure of table time_shift:
And this the query to create new table tide_cart:
create table `tide_chart` (
`id` int(10) not null auto_increment primary key,
`date` date null,
`outletId` int(11) not null,
`timeShiftId` int(11) not null,
`value` varchar(255) not null,
unique (`date`, `outletId`, `timeShiftId`),
foreign key (`outletId`) references `outlet`(`id`)
ON update cascade ON delete cascade,
foreign key (`timeShiftId`) references `time_shift`(`id`)
ON update cascade ON delete cascade
) engine=innoDB;
Please explain to me, why i get error when try to make foreign key connect to table time_shift?
Update: add dump export structure table for outlet and time_shift:
CREATE TABLE `outlet` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`name` varchar(255) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=5 ;
CREATE TABLE `time_shift` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`time_start` time NOT NULL,
`time_end` time NOT NULL,
`is_active` tinyint(4) NOT NULL DEFAULT '1',
`ref_area` int(11) NOT NULL DEFAULT '1',
PRIMARY KEY (`id`),
KEY `ref_area` (`ref_area`)
) ENGINE=MyISAM DEFAULT CHARSET=utf8 AUTO_INCREMENT=7 ;
You need to use the InnoDB engine for your tables. time_shift is using MyISAM.
You must define indexes for outletId and timeShiftId (either UNIQUE or KEY as needed) in order to be able to create a foreign key using that field.
I have a table with a compound primary key "name" and "id". The fields are actually "name","id","phone","amount","units","alias". I have the query
insert into MyTable (name,id,phone,amount) select "henry" as name, id,phone,amount from anotherTable
on duplicate key update phone=values(phone),amount=values(amount).
MySQL spits the following error:
Cannot add or update a child row: a foreign key constraint fails.
BTW, "id" is a foreign key.
Any help?
as requested below, the schema for other table is
CREATE TABLE `otherTable` (
`otherId` int(11) NOT NULL AUTO_INCREMENT,
`DOBId` int(11) NOT NULL,
`bankAccount` int(11) DEFAULT NULL,
`partialAmount` int(11) NOT NULL DEFAULT '0',
`id` int(11) NOT NULL,
`timestamp` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,
`notes` varchar(299) DEFAULT NULL,
`latitude` decimal(8,5) DEFAULT NULL,
`longitude` decimal(8,5) DEFAULT NULL,
PRIMARY KEY (`otherId `),
KEY `DOBId ` (`DOBId `),
KEY `bankAccount ` (`bankAccount `),
KEY `id ` (`id `)
) ENGINE=InnoDB AUTO_INCREMENT=3305 DEFAULT CHARSET=utf8;
for myTable
CREATE TABLE `myTable` (
`name` int(11) NOT NULL,
`id` int(11) NOT NULL,
`appleNumber` int(11) DEFAULT NULL,
`amount` int(11) DEFAULT NULL,
`windowsNumber` int(11) DEFAULT NULL,
`phone` int(11) DEFAULT NULL,
`pens` int(11) DEFAULT NULL,
`pencils` int(11) DEFAULT NULL,
PRIMARY KEY (`name`,`id`),
KEY `id` (`id`),
CONSTRAINT `myTable_ibfk_1` FOREIGN KEY (`id`) REFERENCES `yet_another` (`id`)
The problem appears to be that the FK constraint you have on myTable is referencing the ids of yet_another, so when you are inserting ids from anotherTable you are breaking this FK constraint. Chances are there are ids in anotherTable that do not exist in yet_another table.
Understand this is a shot in the dark, based on the abstracted schema you posted. If you want a more solid answer, I'd have to see the actual schema.
The on duplicate key applies to the primary key. I take it you're using innodb. This is failing on a foreign key constraint. Which values of you table MyTable are foreign keys? Please post the create statement for the table that shows all keys and constraints for more detailed help.
Just a guess, but for grins I'm betting it's a column that's not in the insert that is a foreign key not allowing a null value.