MySQL FOREIGN KEY Constraints Syntax - mysql

Question

When I'm going to execute this code, I'm getting this error message:
You have an error in your SQL syntax; check the manual that
corresponds to your MySQL server version for the right syntax to use
near 'ADD CONSTRAINT fk_pay_grade_scale FOREIGN KEY pay_scale_id
REFERENCES `pay_s' at line 11
But I don't understand the problem. Your help is appreciated!
CREATE TABLE IF NOT EXISTS `pay_grades` (
`pay_grade_id` int(20) NOT NULL,
`pay_scale_id` tinyint(4) NOT NULL,
`name` varchar(100) NOT NULL,
`basic_salary` decimal(10,2) NOT NULL,
`status` int(2) NOT NULL DEFAULT '1',
PRIMARY KEY (`pay_grade_id`),
INDEX (`pay_scale_id`, `pay_grade_id`),
ADD CONSTRAINT `fk_pay_grade_scale` FOREIGN KEY `pay_scale_id` REFERENCES `pay_scales`(`id`) ON UPDATE CASCADE ON DELETE RESTRICT
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
CREATE TABLE IF NOT EXISTS `pay_scales` (
`id` tinyint(4) NOT NULL,
`name` varchar(100) NOT NULL,
PRIMARY KEY(id)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;

Answer 1

You can not use ADD CONSTRAINT in a CREATE TABLE declaration.
Declare your constraint after creating the table or in the CREATE TABLE.
First solution: Add the constraint in CREATE TABLE
CREATE TABLE IF NOT EXISTS `pay_grades` (
`pay_grade_id` int(20) NOT NULL,
`pay_scale_id` tinyint(4) NOT NULL,
`name` varchar(100) NOT NULL,
`basic_salary` decimal(10,2) NOT NULL,
`status` int(2) NOT NULL DEFAULT '1',
PRIMARY KEY (`pay_grade_id`),
INDEX (`pay_scale_id`, `pay_grade_id`),
FOREIGN KEY (`pay_scale_id`) REFERENCES `pay_scales`(`id`) ON UPDATE CASCADE ON DELETE RESTRICT
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
Second solution: Alter table to add the constraint
Create your table without the constraint, and then add your constraint as follow:
ALTER TABLE `pay_grades`
ADD CONSTRAINT `pay_scale_id` FOREIGN KEY REFERENCES `pay_scales`(`id`)
ON UPDATE CASCADE ON DELETE RESTRICT;
MySQL documentation for foreign keys declaration.

Answer 2

It seems the difference in order of table creation. First create primary key table than create the table of foreign key.
CREATE TABLE IF NOT EXISTS `pay_scales` (
`id` tinyint(4) NOT NULL,
`name` varchar(100) NOT NULL,
PRIMARY KEY(id)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
CREATE TABLE IF NOT EXISTS `pay_grades` (
`pay_grade_id` int(20) NOT NULL,
`pay_scale_id` tinyint(4) NOT NULL,
`name` varchar(100) NOT NULL,
`basic_salary` decimal(10,2) NOT NULL,
`status` int(2) NOT NULL DEFAULT '1',
PRIMARY KEY (`pay_grade_id`),
INDEX (`pay_scale_id`, `pay_grade_id`),
ADD CONSTRAINT `fk_pay_grade_scale` FOREIGN KEY `pay_scale_id` REFERENCES `pay_scales`(`id`) ON UPDATE CASCADE ON DELETE RESTRICT
) ENGINE=InnoDB DEFAULT CHARSET=utf8;