Please I need help with adding one more condition to the below database query. I'm using Haversine Formula to get the 15 closest locations to my user's location. I have succeeded in doing this, however I wish to narrow the condition to only display the closest locations if serviceName equals a $serviceName in my query.
I wish to add WHERE serviceName="$serviceName";.
My Query:
$sql = "
SELECT uid, inCallPriceOneTime, lat, lng, distance
FROM
(
SELECT z.uid, z.inCallPriceOneTime, z.lat, z.lng,
p.radius, p.distance_unit *
DEGREES(ACOS(COS(RADIANS(p.latpoint)) *
COS(RADIANS(z.lat)) *
COS(RADIANS(p.longpoint - z.lng))
+ SIN(RADIANS(p.latpoint)) *
SIN(RADIANS(z.lat))))
AS distance
FROM selectedservice AS z
JOIN
(
SELECT $lat AS latpoint, $lng AS longpoint, 50.0 AS radius,
111.045 AS distance_unit
) AS p
WHERE z.lat
BETWEEN p.latpoint - (p.radius / p.distance_unit)
AND p.latpoint + (p.radius / p.distance_unit)
AND z.lng
BETWEEN p.longpoint - (p.radius / (p.distance_unit *
COS(RADIANS(p.latpoint))))
AND p.longpoint + (p.radius / (p.distance_unit *
COS(RADIANS(p.latpoint))))
) AS d
WHERE distance <= radius
ORDER BY distance LIMIT 15";
Any help will be greatly appreciated.
Thanks in advance.
Related
I am trying to adapt this select statement to my tables. This query selects all of the zip codes from a zip code table that are within a certain distance of a given zip code. However, I have a Salon table that stores the zip codes as a foreign from the zip code table. I need to select all of the salons within a certain distance of the given zip code.
DELIMITER //
CREATE PROCEDURE zip_search(lat_param FLOAT(9,6),
long_param FLOAT(9,6), dist_param INT(100)
)
BEGIN
SELECT zipcode
FROM (
SELECT z.zipcode, z.latitude, z.longitude,
p.radius,
p.distance_unit
* DEGREES(ACOS(COS(RADIANS(p.latpoint))
* COS(RADIANS(z.latitude))
* COS(RADIANS(p.longpoint - z.longitude))
+ SIN(RADIANS(p.latpoint))
* SIN(RADIANS(z.latitude)))) AS distance
FROM accounts_zip AS z
JOIN ( /* these are the query parameters */
SELECT lat_param AS latpoint, long_param AS longpoint,
dist_param AS radius, 69.0 AS distance_unit
) AS p ON 1=1
WHERE z.latitude
BETWEEN p.latpoint - (p.radius / p.distance_unit)
AND p.latpoint + (p.radius / p.distance_unit)
AND z.longitude
BETWEEN p.longpoint - (p.radius / (p.distance_unit * COS(RADIANS(p.latpoint))))
AND p.longpoint + (p.radius / (p.distance_unit * COS(RADIANS(p.latpoint))))
) AS d
WHERE distance <= radius
ORDER BY distance;
END //
I tried adding an inner join after selecting from the salon table, however I do not understand sub queries and joins very well. Any thoughts would be greatly appreciated.
DELIMITER //
CREATE PROCEDURE zip_search(lat_param FLOAT(9,6),
long_param FLOAT(9,6), dist_param INT(100)
)
BEGIN
SELECT *
FROM (
SELECT z.zipcode, z.latitude, z.longitude,
p.radius,
p.distance_unit
* DEGREES(ACOS(COS(RADIANS(p.latpoint))
* COS(RADIANS(z.latitude))
* COS(RADIANS(p.longpoint - z.longitude))
+ SIN(RADIANS(p.latpoint))
* SIN(RADIANS(z.latitude)))) AS distance
FROM accounts_salon INNER JOIN accounts_zip ON accounts_salon.id=accounts_zip.id AS z
JOIN ( /* these are the query parameters */
SELECT lat_param AS latpoint, long_param AS longpoint,
dist_param AS radius, 69.0 AS distance_unit
) AS p ON 1=1
WHERE z.latitude
BETWEEN p.latpoint - (p.radius / p.distance_unit)
AND p.latpoint + (p.radius / p.distance_unit)
AND z.longitude
BETWEEN p.longpoint - (p.radius / (p.distance_unit * COS(RADIANS(p.latpoint))))
AND p.longpoint + (p.radius / (p.distance_unit * COS(RADIANS(p.latpoint))))
) AS d
WHERE distance <= radius
ORDER BY distance;
END //
I don't think the ' AS z' in first inner join is necessary, if you try to get the join result of tables accounts_salon and accounts_zip, and treat it as the left table of second inner join, then just continure write the next inner join.
I'm trying to select events in a 5 km radius and order them by likes and from oldest to newest. I know how to select events and order them by likes, but I can't figure this one out. The problem maybe is that the location is stored in a different table.
Database structure:
event plusone (like) location
id_event id_plusone id_location
location_id event_id lat
... user_id lon
... city_id
full_name
....
The SQL statement I'm trying:
SELECT 3956 * 2 * ASIN(
SQRT(POWER(SIN((50.127946 - abs(l.lat)) * pi()/180 / 2),2) + COS(50.127946 * pi()/180 ) *
COS(abs(l.lat) * pi()/180) * POWER(SIN((14.4882912 - l.lon) * pi()/180 / 2), 2) )) AS distance,e.*,COUNT( p.id_plusone ) AS
likes
FROM
event e,location l
LEFT JOIN plusone p ON p.event_id = e.id_event
WHERE
e.location_id = l.id_location AND distance<=5 GROUP BY e.id_event
ORDER BY e.timestamp DESC,likes DESC
The huge column at the beginning is calculation of distance of the event from user position using latitude and longitude.
This is what I get from the SQL debugger:
#1054 - Unknown column 'distance' in 'where clause'
Does anybody know how to do this?
Is hard to track where the error is, you should try to solve the distance part first.
SELECT
event_id,
3956 * 2 * ASIN(SQRT( POWER(SIN((50.127946 - abs(l.lat)) * pi()/180 / 2),2)
+ COS(50.127946 * pi()/180 ) * COS(abs(l.lat) * pi()/180) * POWER(SIN((14.4882912 – l.lon) * pi()/180 / 2), 2) )) AS distance,
FROM event e
JOIN location l
WHERE distance <= 5
And then join to back to the event table
SELECT e.*, count(p.id_plusone)
FROM event e
LEFT JOIN plusone p
ON p.event_id = e.id_event
JOIN ( Previous Distance Query) d
ON e.event_id = d.event_id
GROUP BY e.id_event
ORDER BY e.timestamp DESC, likes DESC
and btw, this group_by will bring you event_id plus random values for e.* so be carefull
$latitudeD= latitude;
$longitudeD = longitude;
SELECT event,
SQRT(
POW(69.1 * (coordX - $latitudeD), 2) +
POW(69.1 * ($longitudeD - coordY) * COS(coordX / 57.3), 2)) AS distance
FROM db.table WHERE SQRT(
POW(69.1 * (coordX - $latitudeD), 2) +
POW(69.1 * ($longitudeD - coordY) * COS(coordX / 57.3), 2)) < 50 ORDER BY distance
;
I'm attempting to assign the closest location to a community based on the community postcode and using the Haversine formula with SQL described here. I need to return a single scalar value but I can't seem to avoid having the second calculated distance value which is needed to determine the closest location. Help.
UPDATE Community AS c
JOIN Postcode p on p.id = c.postcode_id
JOIN (
SELECT 100.0 AS radius, 111.045 AS distance_unit
) AS a
SET c.location_id = (
SELECT l.id,
a.distance_unit
* DEGREES(ACOS(COS(RADIANS(p.latitude))
* COS(RADIANS(l.latitude))
* COS(RADIANS(p.longitude - l.longitude))
+ SIN(RADIANS(p.latitude))
* SIN(RADIANS(l.latitude)))) AS distance
FROM Location AS l
WHERE l.latitude
BETWEEN p.latitude - (a.radius / a.distance_unit)
AND p.latitude + (a.radius / a.distance_unit)
AND l.longitude
BETWEEN p.longitude - (a.radius / (a.distance_unit * COS(RADIANS(p.latitude))))
AND p.longitude + (a.radius / (a.distance_unit * COS(RADIANS(p.latitude))))
HAVING distance <= a.radius
ORDER BY distance
LIMIT 1
)
Using the structure you have, you need to move the distance calculation into the WHERE and ORDER BY clauses:
SET c.location_id = (
SELECT l.id
FROM Location AS l
WHERE l.latitude
BETWEEN p.latitude - (a.radius / a.distance_unit)
AND p.latitude + (a.radius / a.distance_unit)
AND l.longitude
BETWEEN p.longitude - (a.radius / (a.distance_unit * COS(RADIANS(p.latitude))))
AND p.longitude + (a.radius / (a.distance_unit * COS(RADIANS(p.latitude))))
AND a.distance_unit
* DEGREES(ACOS(COS(RADIANS(p.latitude))
* COS(RADIANS(l.latitude))
* COS(RADIANS(p.longitude - l.longitude))
+ SIN(RADIANS(p.latitude))
* SIN(RADIANS(l.latitude)))) <= a.radius
ORDER BY a.distance_unit
* DEGREES(ACOS(COS(RADIANS(p.latitude))
* COS(RADIANS(l.latitude))
* COS(RADIANS(p.longitude - l.longitude))
+ SIN(RADIANS(p.latitude))
* SIN(RADIANS(l.latitude))))
LIMIT 1
)
I am trying to count of coupons sold by each store from the list of stores within 20 miles range. I know the following syntax will work if there is only 1 store.
SELECT sum(couponscount) as count where restaurant IN (SELECT storename where bhal bhal bhal and output is one value)
What is I the IN (SELECTstorenamewhere bhal bhal bhal and output is multiple values) will return multiple values?
Like in my case the complete SQL is like and its not working
SELECT sum(couponscount) as count FROM `coupons` having `restaurant` IN (SELECT `storename`, ((ACOS(SIN(-27.561264299999998 * PI()/180) * SIN(latitude * PI()/180) + COS(-27.561264299999998 * PI()/180) * COS(latitude * PI()/180) * COS((153.07304890000003 – longitude) * PI()/180)) *180 / PI( )) *60 * 1.1515) AS `distance` FROM `stores` WHERE `status`=’active’ HAVING `distance` <=20)
Is there anyway to make it working?
SELECT sum(couponscount) AS COUNT,restaurant
FROM `coupons`
WHERE `restaurant` IN
(SELECT `storename`
FROM `stores`
WHERE `status`='active'
AND
((ACOS(SIN(-27.561264299999998 * PI()/180) * SIN(latitude * PI()/180) + COS(-27.561264299999998 * PI()/180) * COS(latitude * PI()/180) * COS((153.07304890000003 – longitude) * PI()/180)) *180 / PI()) *60 * 1.1515) <=20)
GROUP BY restaurant
Also use proper quotes for active.
Presumably, you want to get the count of coupons from stores within a distance of 20. Moving the having condition to a where clause should do what you want:
SELECT sum(couponscount) as count
FROM `coupons`
WHERE `restaurant` IN (SELECT `storename`
FROM `stores`
WHERE `status` = 'active' AND
((ACOS(SIN(-27.561264299999998 * PI()/180) * SIN(latitude * PI()/180) + COS(-27.561264299999998 * PI()/180) * COS(latitude * PI()/180) * COS((153.07304890000003 – longitude) * PI()/180)) *180 / PI( )) *60 * 1.1515) <= 20
);
You had a major syntax problem because your subquery returned two columns. When you use a subquery with in, you can only return one column, in this case, storename. I moved the code for the distance calculation to the where clause. No having clause is needed either in the subquery or the outer query.
I have a MySQL Routine that is getting records within a 50 mile radius when passed Latitude and Longitude via utilizing the Haversin equation.
While this works great, and is pretty speedy (considering it's searching through 82k records), I am thinking that I can get better performance by creating a similar procedure utilizing a POINT column.
So, in my table I created an extra column called Location, gave it a datatype of POINT, updated my data to pass lat & lon to the Location column. Data is valid, and is fine., and added a Spatial Index
The question is, how can I convert the following query to use the Location column, instead of lat and lon columns.
SET #LAT := '37.953';
SET #LON := '-105.688';
SELECT DISTINCT
BPZ.`store_id`,
3956 * 2 * ASIN(SQRT(POWER(SIN((#LAT - abs(Z.`lat`)) * pi()/180 / 2),2) + COS(#LAT * pi()/180 ) * COS(abs(Z.`lat`) * pi()/180) * POWER(SIN((#LON - Z.`lon`) * pi()/180 / 2), 2))) as distance,
c.`name`,c.`address`,c.`city`,c.`state`,c.`phone`,c.`zip`,c.`premise_type`
FROM
`zip_codes` as Z,
`brand_product_zip` as BPZ
LEFT JOIN `customers` c ON c.`store_id` = BPZ.`store_id`
WHERE
BPZ.`zip` = Z.`zip`
AND
3956 * 2 * ASIN(SQRT(POWER(SIN((#LAT - abs(Z.`lat`)) * pi()/180 / 2),2) + COS(#LAT * pi()/180 ) * COS(abs(Z.`lat`) * pi()/180) * POWER(SIN((#LON - Z.`lon`) * pi()/180 / 2), 2))) <= 50
ORDER BY
distance LIMIT 20
I understand that this has been asked before, however, everything I see points to calculations based on lat and lon and not the POINT column
Updated Code:
SET #lat = 41.92;
SET #lon = -72.65;
SET #kmRange = 80.4672; -- = 50 Miles
SELECT *, (3956 * 2 * ASIN(SQRT(POWER(SIN((#lat - abs(`lat`)) * pi()/180 / 2),2) + COS(#lat * pi()/180 ) * COS(abs(`lat`) * pi()/180) * POWER(SIN((lon - `lon`) * pi()/180 / 2), 2)))) as distance
FROM `zip_codes`
WHERE MBRContains(LineString(Point(#lat + #kmRange / 111.1, #lon + #kmRange / (111.1 / COS(RADIANS(#lat)))), Point(#lat - #kmRange / 111.1, #lon - #kmRange / (111.1 / COS(RADIANS(#lat))))), `Location`)
Order By distance
LIMIT 20
Have you looked into hilbert curves solutions? A spatial index doesn't deliver the exact solution? . With a mysql spatial index you can use mbrcontains:
CREATE TABLE lastcrawl (id INT NOT NULL PRIMARY KEY, pnt POINT NOT NULL) ENGINE=MyISAM;
INSERT
INTO lastcrawl
VALUES (1, POINT(40, -100));
SET #lat = 40;
SET #lon = -100;
SELECT *
FROM lastcrawl
WHERE MBRContains
(
LineString
(
Point
(
#lat + 10 / 111.1,
#lon + 10 / ( 111.1 / COS(RADIANS(#lat)))
),
Point (
#lat - 10 / 111.1,
#lon - 10 / ( 111.1 / COS(RADIANS(#lat)))
)
),
pnt
);
Look here: MySQL - selecting near a spatial point.
Here: http://www.drdobbs.com/database/space-filling-curves-in-geospatial-appli/184410998
The article Nearest-location finder for MySQL explains in detail various options, and the best choice for use with the Spatial Extensions starting with MySQL 5.6.
From the article, this sample query lists zip codes within a 50 mile radius from given coordinates (42.81, -70.81):
SELECT zip, primary_city,
latitude, longitude, distance_in_mi
FROM (
SELECT zip, primary_city, latitude, longitude,r,
69.0 * DEGREES(ACOS(COS(RADIANS(latpoint))
* COS(RADIANS(latitude))
* COS(RADIANS(longpoint) - RADIANS(longitude))
+ SIN(RADIANS(latpoint))
* SIN(RADIANS(latitude)))) AS distance_in_mi
FROM zip
JOIN (
SELECT 42.81 AS latpoint, -70.81 AS longpoint, 50.0 AS r
) AS p
WHERE latitude
BETWEEN latpoint - (r / 69)
AND latpoint + (r / 69)
AND longitude
BETWEEN longpoint - (r / (69 * COS(RADIANS(latpoint))))
AND longpoint + (r / (69 * COS(RADIANS(latpoint))))
) d
WHERE distance_in_mi <= r
ORDER BY distance_in_mi;