I have 2 query:
SELECT CustomerID,count(b.BookingStatus) as 'NotComplete'
FROM Booking b, Customer c
WHERE c.CustomerID=b.BookingCustomerID
AND(b.BookingStatus='Pending'
OR b.BookingStatus='OTW')
GROUP BY c.CustomerID
SELECT c.CustomerID, r.*
FROM Customer c,Regular r
WHERE c.CustomerID=r.RegularCID
Result:
1st query
2nd query
How to combine these 2 result together?
also, display the zero(count) as well.
Thanks!
this is what I get after few hours of trying..obviously it's not what I want..
SELECT c.CustomerID,count(b.BookingStatus) as 'NotComplete',r.RegularID
FROM Booking b, Customer c
JOIN Regular r on r.RegularCID=c.CustomerID
WHERE c.CustomerID=b.BookingCustomerID
AND (b.BookingStatus='Pending'
or b.BookingStatus='OTW'
or b.BookingStatus='Started'
or b.BookingStatus='Unclaimed'
or b.BookingStatus='Confirmed')
GROUP by r.RegularID
You can JOIN to the Regular table and then LEFT JOIN to a derived table of counts in the Booking table. We do it this way to avoid having to GROUP BY all the columns in the Regular table:
SELECT c.CustomerID, r.*, b.NotComplete
FROM Customer c
JOIN Regular r ON r.RegularCID = c.CustomerID
LEFT JOIN (SELECT BookingCustomerID, COUNT(*) AS NotComplete
FROM Booking
WHERE BookingStatus IN ('Pending', 'OTW', 'Started', 'Unclaimed', 'Confirmed')
GROUP BY BookingCustomerID) b ON b.BookingCustomerID = c.CustomerID
Use join on regular table, and subquery on your first select
SELECT t1.*, r.RegularCID FROM (
SELECT CustomerID,count(b.BookingStatus) as 'NotComplete',
FROM Booking b
INNER JOIN Customer c ON c.CustomerID=b.BookingCustomerID
WHERE (b.BookingStatus='Pending' OR b.BookingStatus='OTW')
GROUP BY c.CustomerID) t1
LEFT JOIN Regular r on r.CustomerID = t1.CustomerID
Related
There are 3 types of adventures for which I used distinct function in query.
There is only one 1 customer who have booked all types of adventures.
The query i used to fetch the data is:
select c.customerid,c.name
from customer c
inner join booking b
on c.customerid = b.customerid
inner join destination d
on b.destinationid=d.destinationid
inner join adventure a
on d.adventureid=a.adventureid
group by c.customerid
having count(distinct b.bid)=(select count(*) from bid)
or count(distinct a.adventuretype)=(
select count(distinct a.adventuretype)
from adventure
)
You can get the customer ids using aggregation and having:
select b.customerid
from booking b join
destination d
on b.destinationid = d.destinationid join
adventure a
on d.adventureid = a.adventureid
group by b.customerid
having count(distinct a.advtype) = 3;
Or, if you don't want to hardcode the "3", you can use:
having count(distinct a.advtype) = (select count(distinct advtype from adventure)
I'll leave it up to you to add in the customer name (using join, exists, or in).
When i added a left join for getting count of foreign table, its multiply my sum value of other left join table with the count, also I cant use distinct sum here as two values can be same:
SELECT c.id as company_id, SUM(ct.amount) as total_billed, count(l.id) as load_count
FROM tbl_companies c
LEFT JOIN tbl_company_transactions ct ON c.id = ct.company_id
LEFT JOIN tbl_loads l ON c.id = l.company_id
GROUP BY c.id;
You need to pre-aggregate the data:
SELECT c.id as company_id, ct.total_billed,
l.load_count
FROM tbl_companies c LEFT JOIN
(SELECT ct.company_id, SUM(ct.amount) as total_billed
FROM tbl_company_transactions ct
GROUP BY ct.company_id
) ct
ON c.id = ct.company_id LEFT JOIN
(SELECT l.company_id, COUNT(*) as load_count
FROM tbl_loads l
GROUP BY l.company_id
) l
ON c.id = l.company_id;
As you have observed, the JOIN multiplies the number of rows and affects the aggregations.
You could isolate aggregate statistics and join results afterwards.
WITH
tranStats AS (
SELECT company_id, SUM(amount) AS total_billed
FROM tbl_company_transactions
GROUP BY company_id
),
loadStats AS (
SELECT company_id, COUNT(1) AS load_count
FROM tbl_loads
GROUP BY company_id
)
SELECT id, total_billed, load_count
FROM tbl_companies c
LEFT JOIN tranStats t ON t.company_id = c.id
LEFT JOIN loadStats l ON l.company_id = c.id
Gordon's answer is more scalable but for this specific query you only need one subquery — which may also offer a performance boost since joins on the pre-aggregated data may not be able to use indexes.
SELECT c.id as company_id, SUM(ct.amount) as total_billed, l.load_count
FROM tbl_companies c
LEFT JOIN tbl_company_transactions ct ON c.id = ct.company_id
LEFT JOIN (
SELECT company_id, count(*) as load_count
FROM tbl_loads
GROUP BY company_id
) l ON c.id = l.company_id
GROUP BY c.id;
The important thing to grasp is that if you need results of an aggregate function like SUM() or COUNT(), you need to be careful when you perform more than one join with multiple rows.
I am struggling to get this query to work . I have three tables and I want to do a query to get the red area.
Each circle is a table with different structure. I have managed a lot of combinations of inner joins but i specially cant get all the red areas.
A Payments : idPayment , idInvoice , Amount , date.
B Invoice : idInvoice , amount date.
C PromissoryNotes: IdNote , idInvoice, amount, date.
so far ...
SELECT B.idInvoice,A.idPayment,C.idNote FROM (Invoice b INNER JOIN payments a ON a.idInvoice=b.idInvoice) LEFT OUTER JOIN PromissoryNotes c ON c.idInvoice=b.idInvoice ORDER BY idInvoice.
DOESNT QUITE WORK
Any suggestions?
You were pretty close -- another OUTER JOIN and some WHERE criteria will do the trick:
SELECT B.idInvoice, A.idPayment, C.idNote
FROM Invoice b
LEFT JOIN payments a ON a.idInvoice=b.idInvoice
LEFT JOIN PromissoryNotes c ON c.idInvoice=b.idInvoice
WHERE a.idInvoice IS NOT NULL
OR c.idInvoice IS NOT NULL
ORDER BY B.idInvoice
What this basically says is give me all results from table B, where there's a match in table a or table c.
Condensed SQL Fiddle Demo
You could do this two ways:
1) Create a set A that is the inner join of B and A, create a set C that is the inner join of B and C, then union A and C.
2) Create a sub query that inner joins A and B, then full outer join to a sub query that inner joins C and B.
Example of 1)
SELECT b.idInvoice FROM Invoice B
JOIN Payments A on A.IdInvoice = B.IdInvoice
UNION
SELECT b.idInvoice FROM Invoice B
JOIN PromissoryNotes C on c.idInvoice = B.id Invoice
Example of 2)
SELECT idInvoice FROM
(
SELECT b.idInvoice FROM Invoice B
JOIN Payments A on A.IdInvoice = B.IdInvoice
) B FULL OUTER JOIN
(
SELECT b.idInvoice FROM Invoice B
JOIN Payments A on A.IdInvoice = B.IdInvoice
) C on b.idInvoice = C.idInvoice
Try
SELECT B.idInvoice, A.idPayment, C.idNote FROM Invoice B INNER JOIN payments A ON A.idInVoice = B.idInvoice INNER JOIN PromissoryNotes C ON C.idInvoice = B.idInvoice ORDER BY idInvoice
INNER JOIN means you get the intersection of both tables. So this is what you want.
Does this do the trick?
SELECT
ZZ.idInvoice,
ZZ.idPayment,
YY.idInvoice,
YY.idNote
FROM
(SELECT idInvoice, idPayment
FROM Invoice b
INNER JOIN payments a ON a.idInvoice=b.idInvoice) AS ZZ
FULL OUTER JOIN
(SELECT idInvoice, idNote
FROM PromissoryNotes c
INNER JOIN payments a ON a.idInvoice=c.idInvoice) AS YY ON ZZ.idInvoice = YY.idInvoice
SELECT p.idInvoice, p.idPayment, idNote
FROM Payments p JOIN Invoice i ON p.adInvoice-i.adInvoice RIGHT OUTER JOIN PromissoryNotes
UNION
SELECT i.idInvoice, idPayment, idNote
FROM Invoice i JOIN PromissoryNotes pn ON i.idInvoice=pn.idInvoice RIGHT OUTER JOIN Payments
You need to include the outer joins because the resulting tables that are to be unioned must have the same schema. I believe these are the desired fields from the query.
I need to get the id and timestamps of table sellers and all other columns (without knowing the column names) from these results returned from this MySql statement:
SELECT * FROM sellers a
LEFT JOIN users b ON a.user_id = b.id
LEFT JOIN country_types c ON a.country_type_id = c.id
LEFT JOIN language_types d ON a.language_type_id = d.id
WHERE a.email=?
The seller id though is incorrectly set because users, country_types, and language_types all have a value id. How can I set seller_id and seller_timestamp? I tried this but it is incorrect:
SELECT a.id seller_id, a.timestamp seller_timestamp, * FROM sellers a ...
You want this:
SELECT a.id as seller_id, a.timestamp as seller_timestamp, a.*, b.*, c.*, d.*
FROM sellers a
LEFT JOIN users b ON a.user_id = b.id
LEFT JOIN country_types c ON a.country_type_id = c.id
LEFT JOIN language_types d ON a.language_type_id = d.id
WHERE a.email=?
Im not sure but try alias, for example:
a.id AS seller_id
and etc.
In joins you can't select other columns in this way:
SELECT a.id seller_id, a.timestamp seller_timestamp, * FROM sellers a...
You need to write required column names.
I would like to get the data from one table, and count all results from other table, depending on the first table data, here is what I tried:
SELECT
cars.*, (
SELECT
COUNT(*)
FROM
uploads
WHERE
uploads.cid = cars.customer
) AS `count`,
FROM
`cars`
WHERE
customer = 11;
I dont really have an idea why its not working, as I'm not a regular MySQL user/coder...
Could anyone direct me in the right direction with this one?
SELECT
c.*, COUNT(u.cid) AS count
FROM
cars c
LEFT JOIN
uploads u
ON
u.cid=c.customer
WHERE
u.customer = 11;
GROUP BY c.cid
Try it by joining both tables using LEFT JOIN
SELECT a.customer, COUNT(b.cid) totalCount
FROM cars a
LEFT JOIN uploads b
ON a.customer = b.cid
WHERE a.customer = 11
GROUP BY a.customer
using COUNT(*) in LEFT JOIN will have records to have a minimum count of 1.
SELECT cars.*,COUNT(uploads.*) as uplloaded
from cars
left outer join uploads on uploads.cid = cars.customer
where cars.customer = 11
group by uploads.cid;
Try this :
SELECT customer, COUNT(cid) totalCount
FROM cars
INNER JOIN uploads
ON (customer = cid)
WHERE customer = 11
GROUP BY customer