I'm doing UNION in MySQL that I'm unable to troubleshoot for a while.
Error says that
syntax is incorrect around t1.*
Those 2 SELECTs work ok separately, checked. But UNION fails. I'm not custom to MySQL syntax, maybe something is wrong with that.
SELECT (
t1.*,
a.region_count
FROM
(
SELECT
data_region,
COUNT(*) AS region_count
FROM
t2
GROUP BY
data_region
) AS a
LEFT OUTER JOIN
t1
ON
t1.values_att0 = a.data_region
WHERE
t1.name_0 = 'region'
) AS b
UNION
SELECT (
t1.*,
c.age_gen_count
FROM
(
SELECT
data_dage,
data_gen,
COUNT(*) AS age_gen_count
FROM
t2
GROUP BY
data_dage,
data_gen
) AS c
LEFT JOIN
t1
ON
t1.values_att0 = c.data_dage AND
t1.id_question_1 = c.data_gen
WHERE
t1.name_0 = 'age' AND
t1.q_name_1 = 'gen'
)
You are using parenthesis around your SELECT field, this is your syntax error origin (the UNION is not the cause). Just remove them:
SELECT
t1.*,
a.region_count
FROM
(
SELECT
data_region,
COUNT(*) AS region_count
FROM t2
GROUP BY data_region
) AS a
LEFT OUTER JOIN t1
ON t1.values_att0 = a.data_region
WHERE t1.name_0 = 'region'
UNION ALL
SELECT
t1.*,
c.age_gen_count
FROM
(
SELECT
data_dage,
data_gen,
COUNT(*) AS age_gen_count
FROM t2
GROUP BY data_dage, data_gen
) AS c
LEFT JOIN t1
ON t1.values_att0 = c.data_dage
AND t1.id_question_1 = c.data_gen
WHERE t1.name_0 = 'age'
AND t1.q_name_1 = 'gen'
Related
I am trying to join two tables and get the count and grouped by specific field. However, it outputs same count values even if the other table consist only two rows. How should I fix this?
Here's my code:
SELECT tbl1.preferredDay, COUNT(tbl1.preferredDay) as count_1, COUNT(tbl2.preferredDay) as count_2
FROM tblschedule as tbl1
LEFT JOIN tblappointments as tbl2 ON (tbl1.preferredDay = tbl2.preferredDay)
WHERE tbl1.preferredDay = tbl2.preferredDay
GROUP BY preferredDay;
Here is the output but it should be [15, 0][3, 3]
Your query is based on left join it will return the same count().
This is a working query for Mysql 8:
with tbl1 as (
SELECT preferredDay, count(1) as count_1
FROM tblschedule
GROUP BY preferredDay
),
tbl2 as (
SELECT preferredDay, count(1) as count_2
FROM tblappointments
GROUP BY preferredDay
)
select t1.preferredDay, t1.count_1, t2.count_2
from tbl1 t1
inner join tbl2 t2 on t1.preferredDay = t2.preferredDay
There are two WITHs to get separately the count and then an INNER JOIN to join those results
For Mysql 5.7 and lower :
select t1.preferredDay, t1.count_1, t2.count_2
from (
SELECT preferredDay, count(1) as count_1
FROM tblschedule
GROUP BY preferredDay
) as t1
inner join (
SELECT preferredDay, count(1) as count_2
FROM tblappointments
GROUP BY preferredDay
) as t2 on t1.preferredDay = t2.preferredDay
I'm getting the callback error 'Incorrect parameters in the call to native function \'json_object\' for the below query in node.js but the same query works when I try it out in the mysql workbench?
SELECT t1.typeId AS typeId,
UNIX_TIMESTAMP(t1.hour) AS hour,
t2.userInfo AS userInfo
FROM UserCommits t1
INNER JOIN ( SELECT t1.id AS id,
JSON_OBJECT("id", t1.id,
"name", t1.name,
"birthUnix", UNIX_TIMESTAMP(t1.birthDate),
"gender", t1.gender,
"image", t2.secure_url,
"connectionInfo", t3.connectionInfo) AS userInfo
FROM Users t1
LEFT JOIN (
SELECT userId,
secure_url
FROM UserProfileImages
WHERE id IN (
SELECT MAX(id)
FROM UserProfileImages
GROUP BY userId
)
) t2
ON t1.id = t2.userId
LEFT JOIN (
SELECT connectionId,
JSON_OBJECT(
"id", id,
"createdUnix", UNIX_TIMESTAMP(createdDt)
) AS connectionInfo
FROM UserConnections
WHERE userId = 98
) t3
ON t1.id = t3.connectionId
) t2
ON t1.userId = t2.id
WHERE t1.locationId = 41
Found the issue..
To insert a JSON_Object from a subquery into another JSON_Object there mysql checks that there is a 1 to 1 relationship. I fixed the issue by updating the subquery to include a Group By statement on the join column.
(
SELECT connectionId,
JSON_OBJECT(
"id", id,
"createdUnix", UNIX_TIMESTAMP(createdDt)
) AS connectionInfo
FROM UserConnections
WHERE id IN (
SELECT MAX(id)
FROM UserConnections
WHERE userId = ${ownerId}
GROUP BY connectionId
)
)
I have the following query:
SELECT c.text1, sum(c.num1), sum(c.num2), sum(c.num3),
(SELECT count(id) FROM table2 WHERE type = 1 AND txt = c.text1 AND spec_id = c.sp_id)
FROM table1 as c
WHERE c.type = 1
GROUP BY c.text1, c.sp_id
Is there a workaround to loose the c.sp_id from the GroupBy clause somehow? I know that if I remove it MySQL will return an error.
Or is there a way to group the results of this query by c.text1 only?
If I understand the problem correctly, you need to do two separate aggregations. This is one version of the query:
SELECT c.text1, c.sum1, c.sum2, c.sum3, t2.cnt
FROM (SELECT c.text1, sum(c.num1) as sum1, sum(c.num2) as cum2, sum(c.num3) as sum3
FROM table1 c
GROUP BY c.text1
) c LEFT JOIN
(SELECT txt, count(*) as cnt
FROM table2 t2
WHERE t2.type = 1 AND
EXISTS (SELECT 1
FROM table1 c2
WHERE t.txt = c2.txt AND c2.type = 1 AND
t.spec_id = c2.sp_id
)
) t2
ON t2.txt = c.text1
WHERE c.type = 1;
I have a database of magento with double images, I want to delete those but first i got to detect them with a sql query.
I have tried this code
select t1.VALUE from catalog_product_entity_media_gallery t1
join catalog_product_entity_media_gallery t2 on (t1.value = t2.value)
this one:
select * from catalog_product_entity_media_gallery where value=value
and this one:
select
*
from
(
select
value
from
catalog_product_entity_media_gallery
group by
value
having count(*) > 1
) as t
inner join catalog_product_entity_media_gallery on (
catalog_product_entity_media_gallery.value = t.value
)
the first gives an error and the second- and third one gives back every product.
Give this one a try:
select
*
from (
select
entity_id,attribute_id,value,
MIN(value_id) value_id
from catalog_product_entity_media_gallery
group by
entity_id,attribute_id,value
having COUNT(*) > 1
) A1
inner join catalog_product_entity_media_gallery A2 on
A1.entity_id = A2.entity_id and
A1.attribute_id = A2.attribute_id and
A1.value = A2.value and
A1.value_id = A2.value_id
You can just get the min id by value, then except the other records:
select
*
from catalog_product_entity_media_gallery t1
where exists
( select * from
(select value, min(value_id) as min_value_id
from catalog_product_entity_media_gallery
group by value
) as t2
where t1.value=t2.value and t1.value_id=t2.min_value_id
)
If you want delete the duplicated rows, change exists to not exists.
delete
from catalog_product_entity_media_gallery t1
where not exists
( select * from
(select value, min(value_id) as min_value_id
from catalog_product_entity_media_gallery
group by value
) as t2
where t1.value=t2.value and t1.value_id=t2.min_value_id
)
I have a query like this.
SELECT count(*)
FROM table1 e
WHERE e.column1=1
AND e.id IN
(SELECT MAX(ID)
FROM table2 A
WHERE A.column1=1
AND A.date=CURDATE()
GROUP BY A.column2);
When I run this query it is taking too much of time as I am having thousands of records. How can I tune the query to perform better.
Thanks in advance.
EDIT: column2 in table2 is id of Table1
Change in (. . .) To use join instead. Like
SELECT count(*)
FROM table1 AS e
Inner join
(
SELECT MAX(ID)
FROM table2 A
WHERE A.column1 = 1
AND A.date = CURDATE()
GROUP BY A.column2
) t2 on e.id = t2.id
WHERE e.column1 = 1
Maybe:
SELECT count(*)
FROM table1 e
WHERE e.column1=1
AND EXISTS
(SELECT *
FROM table2 A
WHERE A.column1=1
AND A.date=CURDATE()
AND A.ID = e.id);