I need to do an sql order by which covers a few cases...
I first need to order by a column expiry (epoch string), where this is greater than now or it is empty (non-expiring).
So expired records (those where expiry is less than now) will always come after the non-expired records.
Then within each of these cases, there needs to be a secondary search which is alphabetical.
tTABLE
id
name
expiry
active
My attempt so far:
select * from `tTABLE` WHERE `active`='1'
ORDER BY
CASE WHEN `expiry` > 1571410101 THEN 1
CASE WHEN `expiry` = '' THEN 2 ELSE 3 END,`expiry`
DESC
I think you want:
SELECT t.*
FROM `tTABLE` t
WHERE active = 1
ORDER BY (CASE WHEN expiry > unixtime()
THEN 1 -- explicit future expires first
WHEN expiry IS NULL
THEN 2 -- no expires second
ELSE 3
END),
name;
I'm not sure how this will work in MySql, but in Oracle the following SQL works:
SELECT *,
CASE WHEN expiry > 1571410101 THEN 1
WHEN expiry = '' THEN 2
ELSE 3
END exp
FROM tTABLE
WHERE active = '1'
ORDER BY exp DESC
I think the same will also work for MySql.
Related
i want to get data from table, and example of data like this:
Event Name
Start Date
End Date
Event 1
2022-07-30 00:00:00
2022-08-06 23:59:59
Event 2
2022-08-08 00:00:00
2022-08-15 23:59:59
value of example is "2022-08-07 00:00:00", what i want is get data "Event 1" as the latest event because there is no event starting in "2022-08-07".
and when the value of example "2022-08-08 12:12:12", what i want is get data "Event 2" because there is a event starting from that date. And when the value is "2022-08-09 08:00:00" i want to still get the data "Event 2", because the date is still lower than end date.
How to query in MySQL, so i can result like that?
Assuming proper column names, it would be as below for your initial query (swap out the date for each of your examples):
SELECT *
FROM table
WHERE StartDate <= "2022-08-07 00:00:00"
ORDER BY StartDate desc
LIMIT 1;
Of course if you're basing it of when you run the SQL:
SELECT *
FROM table
WHERE StartDate <= now()
ORDER BY StartDate desc
LIMIT 1;
My approach would be the following nested SELECTs - replace the mentioned timestamp '2022-08-16 12:12:12' with NOW() or any timestamp you need in your case
SELECT * FROM
(
(
SELECT a.*,-1 AS mynumber
FROM `testtest2` AS a
WHERE start<='2022-08-16 12:12:12' AND end >='2022-08-16 12:12:12'
)
UNION
(
SELECT a.*,b.mynumber
FROM `testtest2` AS a,
(SELECT COUNT(*) AS mynumber FROM `testtest2` WHERE start<='2022-08-16 12:12:12' AND end >='2022-08-16 12:12:12') AS b
WHERE end<='2022-08-16 12:12:12' ORDER BY end DESC LIMIT 1
)
) c
WHERE mynumber<=0
Explanation
One SELECT retrieves all events currently active (start <= timestamp AND end >= timestamp) and sets the column mynumber to the fixed value -1 (which clearly is < 0).
The next SELECT retrieves events that have already passed, sorted descending by the column end and only retrieve the first (= newest/last) event. The column mynumber is filled with the numer of events that are currently running - so this column contains either a 0 (if there are no events currently running) or a positive number (> 0) if there are other events running.
These two SELECTs are combined using UNION and used as source for the outer SELECT which only retrieves events with a value <=0 for the column mynumber.
This way you get either the active events OR (in case there are no active events) the last/newest event which has already passed.
I have a query like this to get status without adding fields.
SELECT * ,
IF(DATEDIFF(STR_TO_DATE(end_date, "%Y-%m-%d"), CURDATE())<=0,"End","Running") status
FROM agreements
the query is running but I want to add status if the end date is less than 3 days then the status will show "will be ended"
so there will be 3 statuses in the query, END, RUNNING, Will be END
You can use CASE ..WHEN statements; also your STR_TO_DATE(end, '%Y-%m-%d') usage is unnecessary because DATEDIFF() function considers date part only for the calculation:
SELECT * ,
CASE WHEN DATEDIFF(end_date, CURDATE()) <= 0 THEN 'End'
WHEN DATEDIFF(end_date, CURDATE()) < 3 THEN 'Will Be End'
ELSE 'Running'
END status
FROM agreements
If t_date(column_name) is Today's date then
select * from `schedules`
ORDER BY available_seats <= 0 , STR_TO_DATE(departure_time,'%h:%i%p');
Else
select * from `schedules`
ORDER BY (available_seats <= 0 && (STR_TO_DATE(departure_time,'%h:%i%p') >= TIME(NOW()))), (STR_TO_DATE(departure_time,'%h:%i%p') <= TIME(NOW())), STR_TO_DATE(departure_time,'%h:%i%p');
END
Query 1 is for t_date = DATE(now())
Query 2 is for t_date != DATE(now())
How can i make it in a single query with condition on order by??
You can use CASE like below
SELECT *
FROM `schedules`
ORDER BY
available_seats <= 0 ,
CASE WHEN t_date <> CURRENT_DATE() AND (available_seats <= 0 && (STR_TO_DATE(departure_time,'%h:%i%p') >= TIME(NOW())))
THEN
(STR_TO_DATE(departure_time,'%h:%i%p') <= TIME(NOW()))
WHEN t_date = CURRENT_DATE()
THEN STR_TO_DATE(departure_time,'%h:%i%p')
ELSE STR_TO_DATE(departure_time,'%h:%i%p') END,
STR_TO_DATE(departure_time,'%h:%i%p')
In English, what are you actually trying to get your order by and maybe adjust your question for clarification...
However, I think you might want all "available_seats" values less or equal to zero FIRST, THEN based on the date from today. If that is the case, you may want something like..
order by
case when available_seats <= 0 then 1 else 2 end,
STR_TO_DATE(departure_time,'%h:%i%p')
But it should all be possible in a simple single query, but there is no context to what the seats, dates are for and what you want and why... Are you looking for something like "Sold-out" events sorted to top of list, then based on date of event with closest coming event listed first?
The case/when I have above basically puts any returned records that have available seats <= 0 in the first order sequence regardless of actual 0 or negative value... Then, anything else, if 1 seat or 1000 seats left are sorted after. The SECOND part of the order by is just on the date_time field itself. Since the order by is regardless of the "formatted" column that might be retrieved in the field list, I am just ordering by the date/based conversion as you had.
I want to perform a different SELECT based on the column data. For example I have a table http://sqlfiddle.com/#!2/093a2 where I want compare start_date and end_date only if use_schedule = 1. Otherwise select all data. (A different select) Basically I only want to compare the start and end date if only use_schedule is 1 and if use_schedule is 0 then select rest of the data.
An example may be something like
select id, name from table
where use_schedule = 0
else
select id, name, start_date from table
where use_schedule = 0 and current_date >= start_date.
Basically I have the data where schedule is enabled only then look into start and end date. Because if schedule is not enabled there is no point of looking into the dates. Just select the data. With schedule enabled, I want to be more selective in selecting the scheduled data.
I am trying to figure out if MySQL CASE or IF statements would work but not able to do so. How can I run this select?
Thanks.
You can use UNION to mix and match the results of 2 different SQL queries into one result set:
select id, name, null from table
where use_schedule = 0
union
select id, name, start_date from table
where use_schedule = 1 and current_date >= start_date
Note that both queries have to have compatible output fields (same number and type for this to work). The use of UNION automatically merges only distinct records - if you want to keep double results use UNION ALL instead.
In this specific case a more extensive WHERE-clause would also work obviously:
where use_schedule = 0 or (use_schedule = 1 and current_date >= start_date)
But given the question I'm assuming your real case is a bit more complex.
Documentation over at MySQL site.
Use CASE, in this case..:
SELECT id, name,
(CASE
WHEN start_date >= DATE(NOW()) AND use_schedule = 1
THEN start_date
ELSE NULL
END) AS cols FROM campaigns
This way it selects only the schedule 0 OR the 1 with a date bigger or equals to now;
I used DATE(NOW()) so that it removes the time which you are not interested in.
I have a report that displays a graph. The X axis uses the date from the below query. Where the query returns no date, I am getting gaps and would prefer to return a value. Is there any way to force a date where there are no records?
SELECT
DATE(instime),
CASE
WHEN direction = 1 AND duration > 0 THEN 'Incoming'
WHEN direction = 2 THEN 'Outgoing'
WHEN direction = 1 AND duration = 0 THEN 'Missed'
END AS type,
COUNT(*)
FROM taxticketitem
GROUP BY
DATE(instime),
CASE
WHEN direction = 1 AND duration > 0 THEN 'Incoming'
WHEN direction = 2 THEN 'Outgoing'
WHEN direction = 1 AND duration = 0 THEN 'Missed'
END
ORDER BY DATE(instime)
One possible way is to create a table of dates and LEFT JOIN your table with them. The table could look something like this:
CREATE TABLE `datelist` (
`date` DATE NOT NULL,
PRIMARY KEY (`date`)
);
and filled with all dates between, say Jan-01-2000 through Dec-31-2050 (here is my Date Generator script).
Next, write your query like this:
SELECT datelist.date, COUNT(taxticketitem.id) AS c
FROM datelist
LEFT JOIN taxticketitem ON datelist.date = DATE(taxticketitem.instime)
WHERE datelist.date BETWEEN `2012-01-01` AND `2012-12-31`
GROUP BY datelist.date
ORDER BY datelist.date
LEFT JOIN and counting not null values from right table's ensures that the count is correct (0 if no row exists for a given date).
You would need to have a set of dates to LEFT JOIN your table to it. Unfortunately, MySQL lacks a way to generate it on the fly.
You would need to prepare a table with, say, 100000 consecutive integers from 0 to 99999 (or how long you think your maximum report range would be):
CREATE TABLE series (number INT NOT NULL PRIMARY KEY);
and use it like this:
SELECT DATE(instime) AS r_date, CASE ... END AS type, COUNT(instime)
FROM series s
LEFT JOIN
taxticketitems ti
ON ti.instime >= '2013-01-01' + INTERVAL number DAY
AND ti.instime < '2013-01-01' + INTERVAL number + 1 DAY
WHERE s.number <= DATEDIFF('2013-02-01', '2013-01-01')
GROUP BY
r_date, type
Had to do something similar before.
You need to have a subselect to generate a range of dates. All the dates you want. Easiest with a start date added to a number:-
SELECT DATE_ADD(SomeStartDate, INTERVAL (a.I + b.1 * 10) DAY)
FROM integers a, integers b
Given a table called integers with a single column called i with 10 rows containing 0 to 9 that SQL will give you a range of 100 days starting at SomeStartDate
You can then left join your actual data against that to get the full range.