SQL problem with JOIN statement (multiple results from 1 table) - mysql

So I have a SQL query that selects quiz_questions and quiz_question_options
But when I run my SQL query I only get 1 result from quiz_option (in my database I have 3 options for each question). How would I be able to display all 3 options for every question?
Tables:
quiz_question
-id (PK)
-quiz_id(FK)
-question
quiz_question_option
`-id (PK)
-quiz_question_id(FK)
-quiz_option`
This is my code so far:
SELECT quiz_question.question,quiz_question_option.quiz_option
FROM quiz_question_option
LEFT JOIN quiz_question
ON quiz_question.id = quiz_question_option.quiz_question_id
ORDER BY RAND() LIMIT 5
The limit will change depending on user input
EDIT:
The result i get is:
question |quiz_option
1.question|1.answer
2.question|2.answer
What I need to get is:
question |quiz_option
1.question|1.answer
1.question|2.asnwer
1.question|3.answer
2.question|1.answer
2.question|2.answer
3.question|3.answer
etc...
2.EDIT:
I need to make a sql query for my project (website)
so the user will select how many questions he wants to have.
On the next page it would display the questions. I already have the code to display random questions. But I don't know how to display the options for the selected question.

seems you want to ignore the relationship. what you want to achieve is something like cross join
select t1.question, t2.quiz_option
from quiz_question_option t1
cross join quiz_question t2

I believe INNER join would help you.
Try this:
SELECT quiz_question.question, quiz_question_option.quiz_option
FROM quiz_question_option AS O
INNER JOIN quiz_question AS Q
ON Q.id= O.quiz_question_id

Related

SQL Temporary Table or Select

I've got a problem with MySQL select statement.
I have a table with different Department and statuses, there are 4 statuses for every department, but for each month there are not always every single status but I would like to show it in the analytics graph that there is '0'.
I have a problem with select statement that it shows only existing statuses ( of course :D ).
Is it possible to create temporary table with all of the Departments , Statuses and amount of statuses as 0, then update it by values from other select?
Select statement and screen how it looks in perfect situation, and how it looks in bad situation :
SELECT utd.Departament,uts.statusDef as statusoforder,Count(uts.statusDef) as Ilosc_Statusow
FROM ur_tasks_details utd
INNER JOIN ur_tasks_status uts on utd.StatusOfOrder = uts.statusNR
WHERE month = 'Sierpien'
GROUP BY uts.statusDef,utd.Departament
Perfect scenario, now bad scenario :
I've tried with "union" statements but i don't know if there is a possibility to take only "the highest value" for every department.
example :
I've also heard about
With CTE tables, but I don't really get how to use it. Would love to get some tips on it!
Thanks for your help.
Use a cross join to generate the rows you want. Then use a left join and aggregation to bring in the data:
select d.Departament, uts.statusDef as statusoforder,
Count(uts.statusDef) as Ilosc_Statusow
from (select distinct utd.Departament
from ur_tasks_details utd
) d cross join
ur_tasks_status uts left join
ur_tasks_details utd
on utd.Departament = d.Departament and
utd.StatusOfOrder = uts.statusNR and
utd.month = 'Sierpien'
group by uts.statusDef, d.Departament;
The first subquery should be your source of all the departments.
I also suspect that month is in the details table, so that should be part of the on clause.

Group records by UserID, select where on one column value and sum another

Using SQL in MySQLWorkbench I'd like to group records by 'UserID',
select only the records that match where 'Weeks' are in(5,6,7,8) and sum the values for each user in 'Score'.
The records are actually stored in two tables that I am joining, a lineup table and lineup history table:
INNER JOIN vi_lineup on vi_lineup.lineup_master_id = vi_lineup_master.lineup_master_id
Obviously, I am a newbie. I did search S.O. first but did not find a matching question. I'll keep looking and hope someone answers here. Thanks for any help.
A comment asked about the Weeks. The game is based on a weekly model and we number them sequentially. Here's a working query joining the tables and selecting records based on the weeks:
select * FROM vi_lineup LU
INNER JOIN vi_lineup_master LM
WHERE (LU.week > 4 and LU.week < 9)
AND LU.lineup_master_id = LM.lineup_master_id
Limit 0,148000;
What I would like to do now is Group the records by LM.UserID and sum the values in LU.Score
Thanks!
You have not told us where userid or score comes from. But assuming you can clarify that yourself, the "basic" structure of the query will be like this:
SELECT
??.UserID, SUM(??.score) AS sum_score
FROM vi_lineup lu
INNER JOIN vi_lineup_master lm ON lu.lineup_master_id = lm.lineup_master_id
WHERE lu.week between 5 and 8
GROUP BY
??.UserID
You will need to replace each ?? with the correct table alias "lu" or "lm"

Query to join 3 tables

I need to write a query to join 3 tables.
My tables are:
ucommerce_customer
ucommerce_order
ucommerce_order_line
All 3 tables have a column called order_id.
The table ucommerce_order has a column called order_status.
When the order_status is set to "open" I want to display the order details.
ResultSet myRs = myStmt.executeQuery
("SELECT * FROM ucommerce_customer
INNER JOIN ucommerce_order
INNER JOIN ucommerce_order_line
WHERE ucommerce_order.order_status = 'open'");
My query ignores the order status and displays all orders, open and closed.
Also I have several products so ucommerce_order_line has several entries for the same order_id, my query displays duplicate entries and it duplicates the entire list as well.
How can I write a query that will show only open orders without duplicating everything?
In MySQL, the on/using clause is optional. This is very sad because someone can make mistakes like you did. Your question only mentions one column, so perhaps that is all that is needed for the join:
SELECT *
FROM ucommerce_customer INNER JOIN
ucommerce_order
USING (orderId) INNER JOIN
ucommerce_order_line
USING (OrderId)
WHERE ucommerce_order.order_status = 'open';
I would be surprised if the customer table really had a column called OrderId (seems like a bad idea in most situations), so the first USING clause might want to use CustomerId.
I would recommend to use a natural join instead. Maybe that's where the errors are coming from.
The duplicates can be removed by running SELECT DISTINCT * ...

Stuck on a DQL left join query

I have two tables:
Users <----> Questions
They use a ManyToMany relation table to keep track of which user answered which question.
Users <----> UsersQuestions <----> Questions
Now I need to write a query which fetches all the questions a specific user id has NOT answered yet.
The following native query works fine:
SELECT * FROM questions q
WHERE q.id NOT IN (
SELECT question_id FROM users_questions
WHERE user_id = 4
);
But I directly access the UsersQuestions table in this query and I haven't found a way to do so in Doctrine yet, I don't even think it's possible.
The only way to access that table is by joining on a property of my Question class, thus I tried to rewrite the query to the following one which also works fine as a native query:
SELECT * questions q
LEFT JOIN users_questions uq
ON q.id = uq.question_id AND uq.user_id = 4
WHERE uq.user_id IS NULL;
I was assuming that I could simply rewrite this into DQL as the following query:
SELECT q FROM MyBundle:Question q
LEFT JOIN q.usersAnswered uq WITH uq.id = 4
WHERE uq.id IS NULL
When I call $query->getSql() I get the following output:
SELECT * FROM mybundle_questions g0_
LEFT JOIN users_questions u2_
ON g0_.id = u2_.question_id
LEFT JOIN mybundle_users g1_
ON g1_.id = u2_.user_id AND (g1_.id = 4)
WHERE g1_.id IS NULL
Which to me looks fine given my very basic knowledge on Doctrine and queries in general. However, this fetches and returns ALL the questions which are in the table and not only the ones which this users hasn't answered yet.
Did I make a mistake somewhere? Or is there any other/easier way to fetch these unanswered questions? I feel like I'm reinventing the wheel here.
Been stuck on this for days and every attempt that I make in native SQL works fine, but I can't translate it to DQL. Any help would be appreciated.
I've solved my problem with the following query. Looks like it WAS possible to create a subquery after all.
SELECT q FROM MyBundle:Question q
WHERE q.id NOT IN (
SELECT uq.id FROM MyBundle:User u
INNER JOIN u.questionsAnswered uq
WHERE u.id = 4
)
Which Doctrine translates to the following query:
SELECT * FROM myBundle_questions g0_
WHERE g0_.id NOT IN (
SELECT g1_.id FROM myBundle_users g2_
INNER JOIN users_questions u3_
ON g2_.id = u3_.user_id
INNER JOIN myBundle_questions g1_
ON g1_.id = u3_.question_id
WHERE g2_.id = ?
)
For some reason the previous query, although it looked good in my eyes, didn't work. Must have something to do with how Doctrine handles the left join / null situations. However, this query in which I approach the problem from a different angle work perfectly.

MYSQL many to many 3 tables query

EDIT. I missed the one main issue I was having. I want to display all the unique 'device_MAC' rows. So I want this query to output 3 rows (as per the original query). The issue I am having is connecting the data table to the remote_node table via dt_short = rn_short where the maximum timestamp for dt_short in the data table.
I am having trouble running a query on 3 tables (2 have many to many relations).
What I am trying to do:
Get each distinct rn_IEEE from the remotenodes table with the maximum timestamp (in the example this will get 3 rows with 3 distinct short addresses rn_short)
Join with the devicenames table on device_IEEE
Get each distinct dt_short from the data table with the maximum timestamp
Join dt_short with rn_short from the query above
Now the problem I am running into is that I can do the queries for the above individually, I have even gotten the first 3 of them together into a query but I cannot seem to properly join the last bit of data to get the result that I want.
I have been going in circles trying to solve this. Here is a link to SQL Fiddle which contains all the test data and the query as far as I got it, it does what i want for the first line but from table 'data' after the first line is NULL:
See this SQL fiddle
After going through your requirements and the data, it looks like you just need to change your query to include an INNER JOIN on the data table instead of a LEFT JOIN
See SQL Fiddle with Demo
select rn.*, dn.*, d.*
from remotenodes rn
inner join devicenames dn
on rn.rn_IEEE = dn.device_IEEE
and rn.rn_timestamp = (SELECT MAX(rn_timestamp) FROM remotenodes
WHERE rn.rn_IEEE = rn_IEEE
GROUP BY rn_IEEE)
inner join data d
on rn.rn_short = d.dt_short
AND d.dt_timestamp = (SELECT MAX(d2.dt_timestamp) AS ts
FROM data d2
WHERE d.dt_short = d2.dt_short
GROUP BY d2.dt_short)
what you have done the query in your SQL fiddle is right.Instead of using left join use inner join so that it will give you the first row
cheers.
Thanks for all your answers everyone. I managed to solve the problem by using views.
It's not the most efficient way but I think it will do for now.
Here is the SQL Fiddle link:
http://sqlfiddle.com/#!2/4076e/8
Try this query, for me its returning one row:
SELECT rn_short, rn_IEEE, device_name
FROM
(SELECT DISTINCTROW dt_short FROM (SELECT * FROM `data` ORDER BY `dt_timestamp` DESC) as data ) as a
JOIN
(SELECT rn_IEEE, rn_short, device_name FROM devicenames dn JOIN (SELECT DISTINCTROW rn_IEEE, rn_short FROM (SELECT * FROM `remotenodes` ORDER BY `rn_timestamp` DESC) as remotenodes GROUP BY rn_IEEE) as rn ON dn.device_IEEE = rn.rn_IEEE) as b
ON a.dt_short = b.rn_short