Reading JSON values from web browser? - json

Question

I have a random JSON generated online and I am able to print all the values. But how do I read each array separately? For example, the below JSON contains different attributes, how do I read the string name that is an array containing 4 values.
JSON reader:
public class JsonHelper
{
public static T[] getJsonArray<T>(string json)
{
string newJson = "{ \"array\": " + json + "}";
Wrapper<T> wrapper = JsonUtility.FromJson<Wrapper<T>>(newJson);
return wrapper.array;
}
[System.Serializable]
private class Wrapper<T>
{
public T[] array;
}
}
[System.Serializable]
public class RootObject
{
public string name;
public string height;
public string mass ;
}
The below script is used to access the JSON online through RESTApi GET service. I am able to receive the whole text but how I read one single value of name or height or mass?
Script:
using UnityEngine.Networking;
using System.Linq;
using System.Linq.Expressions;
using UnityEngine.UI;
using System.IO;
public class GetData : MonoBehaviour {
// Use this for initialization
void Start () {
StartCoroutine(GetNames());
}
IEnumerator GetNames()
{
string GetNameURL = "https://swapi.co/api/people/1/?format=json";
using(UnityWebRequest www = UnityWebRequest.Get(GetNameURL))
{
// www.chunkedTransfer = false;
yield return www.Send();
if(www.isNetworkError || www.isHttpError)
{
Debug.Log(www.error);
}
else
{
if(www.isDone)
{
string jsonResult = System.Text.Encoding.UTF8.GetString(www.downloadHandler.data);
Debug.Log(jsonResult); //I am getting the result here
}
}
}
}
}

Answer 1

Your API call to 'https://swapi.co/api/people/1/?format=json' returns a single object, not an array.
So after you get your json, you can access name and height etc like:
if (www.isDone)
{
string jsonResult = System.Text.Encoding.UTF8.GetString(www.downloadHandler.data);
Debug.Log(jsonResult); //I am getting the result here
RootObject person = JsonUtility.FromJson<RootObject>(jsonResult);
// then you can access each property
Debug.Log(person.name);
Debug.Log(person.height);
}