How to serialize Json string in apex - json

Question

I need to parse this json string to values.
"start": { "dateTime": "2013-02-02T15:00:00+05:30" }, "end": { "dateTime": "2013-02-02T16:00:00+05:30" },
The problem is I am using JSONParser in apex (salesforce).
And my class is:
public class wrapGoogleData{
public string summary{get;set;}
public string id{get;set;}
public string status;
public creator creator;
public start start;
public wrapGoogleData(string entnm,string ezid,string sta, creator c,start s){
summary= entnm;
id= ezid;
status = sta;
creator = c;
start = s;
}
}
public class creator{
public string email;
public string displayName;
public string self;
}
public class start{
public string datetimew;
}
I am able to get all the datat from this except the datetime in the above string. As datetime is a reserved keyword in apex so i am not able to give the variable name as datetime in my class.
Any suggestion !!
Json Parser code:
JSONParser parser = JSON.createParser(jsonData );
while (parser.nextToken() != null) {
// Start at the array of invoices.
if (parser.getCurrentToken() == JSONToken.START_ARRAY) {
while (parser.nextToken() != null) {
// Advance to the start object marker to
// find next invoice statement object.
if (parser.getCurrentToken() == JSONToken.START_OBJECT) {
// Read entire invoice object, including its array of line items.
wrapGoogleData inv = (wrapGoogleData)parser.readValueAs(wrapGoogleData.class);
String s = JSON.serialize(inv);
system.debug('Serialized invoice: ' + s);
// Skip the child start array and start object markers.
//parser.skipChildren();
lstwrap.put(inv.id,inv);
}
}
}
}

Answer 1

Similar to Kumar's answer but without using an external app.
Changing your start class was the right idea
public class start{
public string datetimew;
}
Now, just parse the JSON before you run it through the deserializer.
string newjsondata = jsonData.replace('"dateTime"','"datetimew"');
JSONParser parser = JSON.createParser(newjsondata);
while (parser.nextToken() != null) {
...
}

Answer 2

Use string.replace() function and replace keys named dateTime with something like dateTime__x and then you can parse using Json.deserialize if you have converted your json to apex using json to apex convertor app on heruko platform
http://json2apex.herokuapp.com/
The above link points to an app that will convert Json into apex class and then you can use Json.serialize to parse json into apex class structure.