CSS - Change css background of class text without sub element - html

I'm working on a project based on a wordpress theme that is regularly updated so I can't change the HTML (without making maintenance hell anyway). I added a stylesheet that allows me to change the appearance of the site and all I have to do is add an "include" with each update.
I have an availability calendar that shows as follows:
As you can see, the "31" is barely visible.
The html output:
<td class="calendar-end" data-curent-date="1564531200">
31
</td>
I want to edit the text's css to add a reversed gradient (white on the red section, grey on the white section) so that the text is properly readable. See my css below
background: linear-gradient(135deg, #ffffff 0%,#ffffff 48%,#4d5567 48%,#4d5567 100%);
-webkit-background-clip: text;
-webkit-text-fill-color: transparent;
This gives the following result (when adding <p> tags to the element via chrome inspector and giving it the css rule)
My issue is, I don't know how to create a rule for the text as it's not a subelement.
Normally I would engulf the 31 with <p> tags so I could create a rule for .calendar-end p but thats not possible because of the HTML restrictions...
Is there a way that I am not aware of to affect the text inside the td via a specific css rule?
If I try to apply my code to the .calendar-end class it causes a conflict with the background gradient and I end up with completely invisible text (same gradient as background)
I am not sure what I am asking is even possible but css isn't my strong suit and I'm hoping someone here is more knowledgeable than I am on the subject :D
Thanks for any help all!

With chrome you can consider multiple background like below (doesn't work on firefox, raised a bug)
.calendar-end {
color: transparent;
background:
linear-gradient(135deg, #ffffff 48%, #4d5567 48%),
linear-gradient(135deg, red 48%, #fff 48%);
-webkit-background-clip:
text,
padding-box;
background-clip:
text,
padding-box;
width:100px;
height:100px;
font-size:100px;
}
<div class="calendar-end" data-curent-date="1564531200">
31
</div>
For the other browser consider a pseudo element. Simply make sure to not specify any z-index to main element to have the pseudo element behind (related: Why can't an element with a z-index value cover its child?)
.calendar-end {
background:
linear-gradient(135deg, #ffffff 48%, #4d5567 48%);
-webkit-background-clip: text;
background-clip: text;
-webkit-text-fill-color: transparent;
color: transparent;
width:100px;
height:100px;
font-size:100px;
position:relative;
}
.calendar-end:before {
content:"";
position:absolute;
z-index:-1;
top:0;
left:0;
right:0;
bottom:0;
background: linear-gradient(135deg, red 48%, #fff 48%);
}
<div class="calendar-end" data-curent-date="1564531200">
31
</div>
In case the gradient will be the same for text and background you can optimize the code like below:
.calendar-end {
background-image:
linear-gradient(135deg, #ffffff 49%, #4d5567 50%);
-webkit-background-clip: text;
background-clip: text;
-webkit-text-fill-color: transparent;
color: transparent;
width:100px;
height:100px;
font-size:100px;
position:relative;
}
.calendar-end:before {
content:"";
position:absolute;
z-index:-1;
top:0;
left:0;
right:0;
bottom:0;
background-image: inherit;
transform:rotate(180deg);
}
<div class="calendar-end" data-curent-date="1564531200">
31
</div>

Related

When creating a circle sector in css, a slim line is visible in Chrome and IE

I am a novice when it comes to css and am creating a custom audio player using a mixture of css and jquery. The progress bar of this audio player is a ring, which uses circle sectors to display progress. The sector is created using linear-gradient, like so:
background-image:
linear-gradient(-75deg, black 50%, transparent 50%),
linear-gradient(90deg, transparent 50%, white 50%);
In firefox this works perfectly, but in both chrome and ie, a very slim white line is visible on the outside of half of the circle, presumably where part of the linear-gradient is supposed to cover.
I have created a jsfiddle that displays the issue, https://jsfiddle.net/9dagsrzz/
Is there something that I am doing wrong that causes this, or is there a fix I can apply that removes this line?
Thank you for your time.
Edit - it has been over a month and I thought I would update and say that I have still not been able to find a complete solution to this problem. The best way of dealing with the issue is to include a covering border, as suggested by Pustur below.
Samiskeen,
I'm no CSS expert either but I do know that each browser has its required prefixes when dealing with gradients:
-moz- is for Mozilla Firefox
-webkit- is for Apple Safari, Google Chrome, and also for ios and Android
-o- is for Opera
-ms- is for Microsoft IE and presumably Edge
You can have all of these present on their own line and the browser will pick the correct one.
Example:
background-image:
-moz-linear-gradient(-75deg, black 50%, transparent 50%),
-moz-linear-gradient(90deg, transparent 50%, white 50%);
-webkit-linear-gradient(-75deg, black 50%, transparent 50%),
-webkit-linear-gradient(90deg, transparent 50%, white 50%);
-o-linear-gradient(-75deg, black 50%, transparent 50%),
-o-linear-gradient(90deg, transparent 50%, white 50%);
-ms-linear-gradient(-75deg, black 50%, transparent 50%),
-ms-linear-gradient(90deg, transparent 50%, white 50%);
The website http://caniuse.com lists the major CSS rules, attributes and whether browser specific versions are required.(Nixon, p. 439).
Play around with the prefixes, they should help correct your problem.
Good Luck.
Jim
Not sure if this is a definitive solution or the best, but it seems to work fine at least on chrome.
HTML:
<!-- divs instead of spans -->
<div id="container">
<div id="position_indicator"></div>
<div id="inside"></div>
</div>
CSS:
#container {
width: 100px;
height: 100px;
background-color: black;
position: relative;
padding: 20px;
}
#inside {
width: 90px;
height: 90px;
background-color: black;
border-radius: 100%;
position: absolute;
margin-left: 5px;
margin-top: 5px;
}
#position_indicator {
border: 1px solid black; /* Fix the border issue! */
margin-left: -1px; /* Compensate for the new border */
margin-top: -1px; /* Compensate for the new border */
width: 100px;
height: 100px;
border-radius: 100%;
position: absolute;
background-color: black;
background-image: linear-gradient(-75deg, black 50%, transparent 50%), linear-gradient(90deg, transparent 50%, white 50%);
}
Fiddle

CSS apply gradient to right triangle shape with solid fill

I want to apply the same gradient to the triangle (class="triangle-right") as the rectangle (class="fillblue"). I have seen some other examples but they are not working for me. Combining both shapes and using a single class would be awesome too!
JS FIDDLE HERE!
CSS:
.fillblue {
background: rgb(208,228,247); /* Old browsers */
background: -moz-linear-gradient(top, rgba(208,228,247,1) 0%, rgba(115,177,231,1) 24%, rgba(10,119,213,1) 50%, rgba(83,159,225,1) 79%, rgba(135,188,234,1) 100%); /* FF3.6+ */
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,rgba(208,228,247,1)), color-stop(24%,rgba(115,177,231,1)), color-stop(50%,rgba(10,119,213,1)), color-stop(79%,rgba(83,159,225,1)), color-stop(100%,rgba(135,188,234,1))); /* Chrome,Safari4+ */
background: -webkit-linear-gradient(top, rgba(208,228,247,1) 0%,rgba(115,177,231,1) 24%,rgba(10,119,213,1) 50%,rgba(83,159,225,1) 79%,rgba(135,188,234,1) 100%); /* Chrome10+,Safari5.1+ */
background: -o-linear-gradient(top, rgba(208,228,247,1) 0%,rgba(115,177,231,1) 24%,rgba(10,119,213,1) 50%,rgba(83,159,225,1) 79%,rgba(135,188,234,1) 100%); /* Opera 11.10+ */
background: -ms-linear-gradient(top, rgba(208,228,247,1) 0%,rgba(115,177,231,1) 24%,rgba(10,119,213,1) 50%,rgba(83,159,225,1) 79%,rgba(135,188,234,1) 100%); /* IE10+ */
background: linear-gradient(to bottom, rgba(208,228,247,1) 0%,rgba(115,177,231,1) 24%,rgba(10,119,213,1) 50%,rgba(83,159,225,1) 79%,rgba(135,188,234,1) 100%); /* W3C */
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#d0e4f7',
endColorstr='#87bcea',GradientType=0 ); /* IE6-9 */
height: 40px;
width: 100px;
display: inline-block;
float: left;
color: white;
text-align: center;
line-height: 40px;
font-weight: bold;
}
.triangle-right {
width: 0;
height: 0;
border-top: 20px solid transparent;
border-left: 40px solid lightblue;
border-bottom: 20px solid transparent;
float: left;
}
HTML:
<div class="fillblue">Step 1</div><div class="triangle-right"></div>
Part 1: Giving the triangle a gradient
The easiest way to achieve this would be to invert your triangle. and extend the length of the element with the gradient.
JSFiddle demo.
Inverting the triangle
Rather than giving the border-left on the triangle a solid colour, you want to give the top and bototm borders the colour (in this case we want to match the background colour, so lets make these white as that's the JSFiddle background colour):
.triangle-right {
...
border-top: 20px solid white;
border-left: 40px solid transparent;
border-bottom: 20px solid white;
}
If you're unsure what this achieves, here is an example of the triangle when the top and bottom borders are set to red instead of white:
Increasing the width of your gradient element
As your triangle is 40px wide, we need to increase the width of our gradient element by 40px. For this I've used padding to ensure the text remains in the same place:
.fillblue {
...
padding-right: 40px;
}
With the same red triangle we used above, this is what it now looks like:
Positioning the inverted triangle on top of our gradient element
Now we simply need to set a negative margin on our inverted triangle to make it appear on top of our gradient element:
.triangle-right {
...
margin-left: -40px;
}
Finally, using the red triangle again, our finished result looks like this:
Part 2: Combining both shapes into one element
To do this we can make use of the :after pseudo-element.
JSFiddle demo.
First off, lets modify our HTML:
<div class="fillblue">Step 1</div>
Now lets give our .fillblue element relative positioning. We do this so that we can absolutely position our triangle in the next step:
.fillblue {
...
position: relative;
}
Now we modify our previous .triangle-right styling to use this :after pseudo-element instead:
.fillblue:after {
width: 0;
height: 0;
border-top: 20px solid white;
border-left: 40px solid transparent;
border-bottom: 20px solid white;
}
Finally we give it the new properties to position it correctly and actually make it display:
.fillblue:after {
...
content: '';
position: absolute;
top: 0;
right: 0;
}
I wanted to suggest using border-image: linear-gradient(...); but then I looked up https://developer.mozilla.org/en-US/docs/Web/CSS/border-top and saw that it's not possible to apply a border-image to just 1 of the borders, and then make the other borders transparent. There's also no border-left-image, so that won't work either. Since border-image is a relatively new addition to CSS (it's part of CSS3), it's not integrated in CSS as well as the other border styles. That's why doing this with borders is not possible. (It looks like this (simple webkit-only demo) if you do try to add a border-image, and then try to override it with transparent borders - it doesn't work)
Assuming you want to keep using borders to create your triangle, I would say this is not possible.
The only way you could make it work then is by changing the div to a square that's got a diagonal gradient, and is rotated 45 degrees via CSS transforms. That would end up being something like this:
.triangle-right {
display:inline-block;
background: -webkit-gradient(linear, left top, right bottom, color-stop(0%,rgba(208,228,247,1)), color-stop(24%,rgba(115,177,231,1)), color-stop(50%,rgba(10,119,213,1)), color-stop(79%,rgba(83,159,225,1)), color-stop(100%,rgba(135,188,234,1))); /* Chrome,Safari4+ */
/* etc. */
width:28px; /* ~ sqrt(2*40^2)/2 */
height:28px;
-webkit-transform: rotate(45deg);
/* etc. */
margin-top:6px;
margin-left:-14px;
}
Demo
Keep in mind that that is probably not the best solution, since it'd rely purely on transforms, which are not supported in every browser, and there are no good fallbacks for it. It does have one advantage over James Donnely's solution, which is that it keeps its soft borders instead of becoming jagged.
It does have other significant downsides though, namely that you're relying on fixing its position with transform and margin. It is possible other browsers don't handle this exactly the same as Chrome does, and therefore show your triangle differently. They should all show it the same way, but there's always a chance some browser decides to do things slightly differently.
Explanation of the code: The /* etc. */ stands for the other browser prefixes, the width and height are 28px because that's the height of the rotated square, its diagonal length (sqrt(width^2 + height^2)). This is also the reason the margin-left needs to be -14px (half of this diagonal length): it needs to move 14 pixels to the left, so that its corner is moved over the .fillblue element.
As was asked below in the comments, it is also possible to scale the triangle to be wider (or slimmer). This can be done by simply changing the transformation to scale(2, 1) rotate(45deg) so that it applies the stretching and rotating in the right order. A demo of this can be found at http://jsfiddle.net/x61Lyar0/2/.
PS: If you want your arrow to be less pointy, you can apply border-radius: 0 2px 0 0; (or border-top-right-radius: 2px) to smooth it out just a little bit.

How do you add text gradient using css?

<div class="firstname">
<p class="names">DANIEL</p>
</div>
The above is the html.
h1.method1 {
background: -webkit-linear-gradient(top, #878787, #000);
background: linear-gradient(top, #878787, #000);
-webkit-background-clip: text;
-webkit-text-fill-color: transparent;}
h1.method2 {
-webkit-mask-image: -webkit-linear-gradient(top, rgba(0,0,0,1), rgba(0,0,0,.5) 50%, rgba(0,0,0,1));
-webkit-mask-image: linear-gradient(top, rgba(0,0,0,1), rgba(0,0,0,.5) 50%, rgba(0,0,0,1));}
The above is what i tried to do using .names selector, and the .firstname .names selector, and i tried a.names selector, I am not sure if the method doesnt work or i am using the wrong selector. But overall i just want to have the text to have a little bit of gradient to look good.
Use the text-shadow css property with inset at the end of the rule. This is the most cross browser way to do it. IE9 may not support it but that's it.
Use rgba color for greater control and edit the alpha channel in your browser (like firebug)
source: http://css-tricks.com/snippets/css/gradient-text/
This is WebKit only, but is the cleanest way to accomplish it as the text remains editable and selectable web text.
h1 {
font-size: 72px;
background: -webkit-linear-gradient(#eee, #333);
-webkit-background-clip: text;
-webkit-text-fill-color: transparent;
}

Weird CSS3 Transition (flickering)

When I hover unto my button, it gives a white flash first when starting the transition. Why does it sort of flickers when I apply a css3 transition to my button? My browser is Google Chrome
See here
<button>Log In</button>​
CSS:
button {
background: #ff3019;
background: -moz-linear-gradient(top, #ff3019 0%, #cf0404 100%);
background: -webkit-gradient(linear, left top, left bottom, color-stop(0%,#ff3019), color-stop(100%,#cf0404));
background: -webkit-linear-gradient(top, #ff3019 0%,#cf0404 100%);
background: -o-linear-gradient(top, #ff3019 0%,#cf0404 100%);
background: -ms-linear-gradient(top, #ff3019 0%,#cf0404 100%);
background: linear-gradient(top, #ff3019 0%,#cf0404 100%);
filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#ff3019', endColorstr='#cf0404',GradientType=0 );
border:1px solid #890000;
display:block;
margin:0 auto;
width:200px;
padding:5px 0;
border-radius:8px;
color:#fff;
font-weight:700;
text-shadow:0 1px 1px #000+50;
box-shadow:0 2px 3px #000+150;
-webkit-transition:background linear .5s;
}
button:hover {
background:#ff3019;
}
button:active {
background:#cf0404;
}
​
I got rid of the flickering. Add «-webkit-backface-visibility: hidden;» to the elements you are transitioning. Voilà!
Miguel is right about backface-visiblity fixing the annoying flash. However, I'm using transform scale and the SVG animated will not be sharp after scaling. It is sharp if you don't use the backface-visiblity property.
So either you got a nice animation with a blurry graphic, or a nice looking graphic with screen flashes.
You can however add the following line to the parent of the object to be transitioned, which will fix the flashing of the screen and still renders your graphic sharp after scaling.
-webkit-transform: translate3D(0, 0, 0);
I believe it is currently an issue without a fix. I too have run into this before playing around and could not get it to work. Using a solid color seems to be fine, or faking it with a background image.
Similar Question here: Webkit support for gradient transitions
More detail: http://screenflicker.com/mike/code/transition-gradient/
The flicker you're noticing is actually the button's background color being changed to transparent (so, the button "flashes" or turns white in your Fiddle because the body's background-color is white).
If you overlay your button on top of another element with the exact same size/height/background-color (including gradients), the "flicker" won't be noticeable.
Check here for an example using your fiddle: http://jsfiddle.net/hrDff/12/
Still definitely a bug tho...
I think the issue is that you are switching from a linear-gradient background to a solid background color for Google Chrome and Microsoft Edge web browsers. To fix this issue you would add a similar linear-gradient background to your pseudo classes, in this case the :hover and the :active. I tried it myself on your jsfiddle and I had no flashing in the rendering while hovering over the button.
background: -webkit-linear-gradient(top, #ff3019 0%,#cf0404 100%);
background: -o-linear-gradient(top, #ff3019 0%,#cf0404 100%);
background: -ms-linear-gradient(top, #ff3019 0%,#cf0404 100%);
background: linear-gradient(top, #ff3019 0%,#cf0404 100%);
I changed the top color of the linear-gradient to give a noticeable change to the hover effect.
button:hover {
background: -webkit-linear-gradient(top, #ff5e4c 0%,#cf0404 100%);
background: -o-linear-gradient(top, #ff5e4c 0%,#cf0404 100%);
background: -ms-linear-gradient(top, #ff5e4c 0%,#cf0404 100%);
background: linear-gradient(top, #ff5e4c 0%,#cf0404 100%);
}
There are no more issues with flashing when I hover over the button in Chrome or Microsoft Edge. I hope this helps.
With a similar issue, Jan's suggestions helped improve for all background images but one. I got rid of the flickering of the last one by noticing two conflicting positioning rules. I had for a position:static one rule margin-top:-3em (minus) and the other one margin-top:5em (plus). Thus, I suggest you carefully check the consistency of the positioning when you experience such an issue.
In your case Michelle, I've been testing with a longer delay 1s to 3s, which helped me understand what is that clearer stage, a flash with a very short delay. Your gradient starts with no background in fact and what you see is the background of the page. I got this information by changing the background of the body of my test page from ivory to black.
When I tried your gradient on a black background I got a black stage/flash (easier to see at 3s).
Perhaps it should be wise to test the order of your rules, and also try to understand why the gradient starts from the background of the body or parent and not from your background.
A workaround could be to set your button in a div with your button red background at the exact size and shape of your button.
I solved the blinking like this:
Html as follows:
<div class="pswp__item" style="display: block; transform: translate3d(464px, 0px, 0px);"><div class="pswp__zoom-wrap" style="transform: translate3d(87px, 248px, 0px) scale(0.57971);"><img class="pswp__img" src="/platform/advice/feedback/downloads?attachmentIds=1304495004557536" style="opacity: 1; width: 414px; height: 414px;"></div></div>
css as follows:
.pswp__zoom-wrap{
transform-style: preserve-3d;
-webkit-transform-style: preserve-3d;
}
.pswp__zoom-wrap *{
-webkit-backface-visibility: hidden!important;
backface-visibility: hidden!important;
}
.pswp__item{
transform: translate3D(0, 0, 0);
-webkit-transform: translate3D(0, 0, 0);
}
This link fixed it for me. You just have to add a line to the css of the element that's flickering:
http://nathanhoad.net/how-to-stop-css-animation-flicker-in-webkit

Simulate image "overlay" with CSS

Basically I'm trying to simulate Photoshop's image overlay thing using images and CSS for a menu.
There are 2 versions of the menu background image: one is the normal state (pink), and one the active state (blue). The entire menu is wrapped in a DIV with the normal (pink) image as background.
How can I make it so each active menu link uses the corresponding slice of the blue image?
Like this:
My code so far
Do you think this is possible with CSS?
CSS Only solution for modern browsers:
ul {
background-color:#ff00ff;
background-image: -moz-radial-gradient(50% 50%, ellipse closest-side, #ffffff 0%,#ff00ff 110%);
background-image: -webkit-radial-gradient(50% 50%, ellipse closest-side, #ffffff 0%,#ff00ff 110%);
background-image: -o-radial-gradient(50% 50%, ellipse closest-side, #ffffff 0%,#ff00ff 110%);
background-image: -ms-radial-gradient(50% 50%, ellipse closest-side, #ffffff 0%,#ff00ff 110%);
background-image: radial-gradient(50% 50%, ellipse closest-side, #ffffff 0%,#ff00ff 110%);
height:50px;
width:400px;
margin:0;
padding:0;
border-radius:25px;
overflow:hidden;
}
li {
width:100px;
height:50px;
float:left;
}
li:hover {
background-color:rgba(0,0,255,0.2);
}
Click to see a working demo: http://jsfiddle.net/AlienWebguy/ZLg4B/
If you need to support older browsers and can't use css3, there is a number of ways to do this. One of them:
You can cut out the blue image of the entire thing (you can actually make it wider)
then
li.active {
background: url('path/to/yourImage.png') no-repeat -50px 0;
/* 50px or however wide that rounded tip is */
}
li.active.first {
background-position: left top;
}
li.active.last {
background-position: right top;
}
/* you'll need to add 'active', 'first' and 'last' classes accordingly. */
Are you ever going to have links at the rounded parts? If not, you could just take a pixel-wide slice of the blue image and set that to the :hover state background with repeat-x.
There are definitely other ways to do this but this is the most straightforward IMHO.
Edit: After seeing your fiddle, perhaps this isn't the case. I would consider using JavaScript to calculate appropriate x-offsets for each link, and using a slice of the overlay image in that way. Or you could just make the first link a "special case" and use a generic different-color background for the rest of the links.