I am trying to count number of questions and answers for every company but I want to count them in a single query.
So the problem is this: table pitanje (question) is linked with tvrtka (company)
pitanje.tvrtka_id=tvrtka.tvrtka_id and table answer (odgovor) is linked with question table odgovor.pitanje_id = pitanje.pitanje_id
I have tried with something similar to this and got some faulty results (I counted question and answers separately for testing).
SELECT tvrtka.naziv,
(SELECT COUNT(*) FROM pitanje WHERE tvrtka.tvrtka_id = pitanje.tvrtka_id) AS brojPitanja,
(SELECT COUNT(*) FROM odgovor WHERE odgovor.pitanje_id = pitanje.pitanje_id) AS brojOdgovora
FROM tvrtka
ORDER BY tvrtka.tvrtka_id
But all I get is some MySQL errors (unknown column, not uniqe alias etc.) now and can't get even to a faulty results.
If someone can just explain me the concept of the code above. A lot of answers are written like this but I can't figure out how to do it on my example.
With englisch names it would be something like this:
SELECT
c.name,
COUNT(DISTINCT q.question_id) as numQuestions,
COUNT(a.answer_id) as numAnswers
FROM company c
LEFT JOIN questions q ON q.company_id = c.company_id
LEFT JOIN answers a ON a.question_id = q.question_id
GROUP BY c.name
I let it to you, to translate the table and column names back to your schema.
What is wrong with my code?
Here:
(SELECT COUNT(*) FROM pitanje WHERE tvrtka.tvrtka_id = pitanje.tvrtka_id) AS brojPitanja,
(SELECT COUNT(*) FROM odgovor WHERE odgovor.pitanje_id = pitanje.pitanje_id) AS brojOdgovora
in your second subquery with WHERE odgovor.pitanje_id = pitanje.pitanje_id you are trying to reference a table (pitanje) from another subquery. This is not possible. You can only reference a table in the FROM clause of the outer query, which is tvrtka.
Related
I've got a problem with MySQL select statement.
I have a table with different Department and statuses, there are 4 statuses for every department, but for each month there are not always every single status but I would like to show it in the analytics graph that there is '0'.
I have a problem with select statement that it shows only existing statuses ( of course :D ).
Is it possible to create temporary table with all of the Departments , Statuses and amount of statuses as 0, then update it by values from other select?
Select statement and screen how it looks in perfect situation, and how it looks in bad situation :
SELECT utd.Departament,uts.statusDef as statusoforder,Count(uts.statusDef) as Ilosc_Statusow
FROM ur_tasks_details utd
INNER JOIN ur_tasks_status uts on utd.StatusOfOrder = uts.statusNR
WHERE month = 'Sierpien'
GROUP BY uts.statusDef,utd.Departament
Perfect scenario, now bad scenario :
I've tried with "union" statements but i don't know if there is a possibility to take only "the highest value" for every department.
example :
I've also heard about
With CTE tables, but I don't really get how to use it. Would love to get some tips on it!
Thanks for your help.
Use a cross join to generate the rows you want. Then use a left join and aggregation to bring in the data:
select d.Departament, uts.statusDef as statusoforder,
Count(uts.statusDef) as Ilosc_Statusow
from (select distinct utd.Departament
from ur_tasks_details utd
) d cross join
ur_tasks_status uts left join
ur_tasks_details utd
on utd.Departament = d.Departament and
utd.StatusOfOrder = uts.statusNR and
utd.month = 'Sierpien'
group by uts.statusDef, d.Departament;
The first subquery should be your source of all the departments.
I also suspect that month is in the details table, so that should be part of the on clause.
So I have a SQL query that selects quiz_questions and quiz_question_options
But when I run my SQL query I only get 1 result from quiz_option (in my database I have 3 options for each question). How would I be able to display all 3 options for every question?
Tables:
quiz_question
-id (PK)
-quiz_id(FK)
-question
quiz_question_option
`-id (PK)
-quiz_question_id(FK)
-quiz_option`
This is my code so far:
SELECT quiz_question.question,quiz_question_option.quiz_option
FROM quiz_question_option
LEFT JOIN quiz_question
ON quiz_question.id = quiz_question_option.quiz_question_id
ORDER BY RAND() LIMIT 5
The limit will change depending on user input
EDIT:
The result i get is:
question |quiz_option
1.question|1.answer
2.question|2.answer
What I need to get is:
question |quiz_option
1.question|1.answer
1.question|2.asnwer
1.question|3.answer
2.question|1.answer
2.question|2.answer
3.question|3.answer
etc...
2.EDIT:
I need to make a sql query for my project (website)
so the user will select how many questions he wants to have.
On the next page it would display the questions. I already have the code to display random questions. But I don't know how to display the options for the selected question.
seems you want to ignore the relationship. what you want to achieve is something like cross join
select t1.question, t2.quiz_option
from quiz_question_option t1
cross join quiz_question t2
I believe INNER join would help you.
Try this:
SELECT quiz_question.question, quiz_question_option.quiz_option
FROM quiz_question_option AS O
INNER JOIN quiz_question AS Q
ON Q.id= O.quiz_question_id
Situation Overview
The current question is a problem about selecting values from two tables table A (material) and table B (MaterialRevision). However, The PK of table A might or Might not exist in Table B. When it doesnt exists, the query described in this question wont return the values of table A, but IT SHOULD. So basically here's whats happening :
The query is only returning values when A.id exists in B.id, when In fact, I need it to return values from A when A.id ALSO dont exist in B.id.
Problem:
Suppose two tables. Table Material and Table Material Revision.
Notice that the PK idMaterial is a FK in MaterialRevision.
Current "Mock" Tables
Query Objective
Obs: remember these two tables are a simplification of the real
tables.
For each Material, print the material variables and the last(MAX) RevisionDate from MaterialRevision. In case theres no RevisionDate, print BLANK ("") for the "last revision date".
What is wrongly happening
For each Material, print the material variables and the last(MAX) RevisionDate from MaterialRevision. In case theres no Revision for the Material, doesnt print the Material (SKIP).
Current Code
SELECT
Material.idMaterial,
Material.nextRevisionDate,
Material.obsolete,
lastRevisionDate
FROM Material,
(SELECT MaterialRevision.idMaterial, max(MaterialRevision.revisionDate) as "revisionDate" from MaterialRevision
GROUP BY MaterialRevision.idMaterial
) AS Revision
WHERE (Material.idMaterial = Revision.idMaterial AND Material.obsolete = 0)
References and Links used to reach the state described in this question
Why is MAX() 100 times slower than ORDER BY ... LIMIT 1?
MySQL get last date records from multiple
MySQL - How to SELECT based on value of another SELECT
MySQL Query Select where id does not exist in the JOIN table
PS I hope this question is correctly understood since it took me a lot of time to build it. I researched a lot in stackoverflow and after
several failed attempts I had no option but to ask for help.
You should use JOIN :
SELECT m.idMaterial, m.nextRevisionDate, mr.revisionDate AS "lastRevisionDate"
FROM Material m
LEFT JOIN MaterialRevision AS mr ON mr.idMaterial = m.idMaterial AND mr.revisionDate = (
SELECT MAX(ch.revisionDate) from MaterialRevision ch
WHERE mr.idMaterial = ch.idMaterial)
WHERE m.obsolete = 0
Here is an explanation of what INNER JOIN, LEFT JOIN and RIGHT JOIN are. (You will love them if you often cross tables in your queries)
As m.obsolete will always be true, I ommited it in the SELECT clause
You should use the left outer join instead of using the cross product.
You're query should be something like this:
SELECT idMaterial, nextRevisionableDate, obsolete,
revisionDate AS lastRevisionDate
FROM Material
LEFT OUTER JOIN MaterialRevision AS mr On
Material.idMaterial = MaterialRevision.id
AND mr.revisionDate = (SELECT MAX(ch.revisionDate) from MaterialRevision ch
WHERE mr.idMaterial = ch.idMaterial)
WHERE obsolete = 0;
Here you can find some documentation about types of join.
I have two tables:
Users <----> Questions
They use a ManyToMany relation table to keep track of which user answered which question.
Users <----> UsersQuestions <----> Questions
Now I need to write a query which fetches all the questions a specific user id has NOT answered yet.
The following native query works fine:
SELECT * FROM questions q
WHERE q.id NOT IN (
SELECT question_id FROM users_questions
WHERE user_id = 4
);
But I directly access the UsersQuestions table in this query and I haven't found a way to do so in Doctrine yet, I don't even think it's possible.
The only way to access that table is by joining on a property of my Question class, thus I tried to rewrite the query to the following one which also works fine as a native query:
SELECT * questions q
LEFT JOIN users_questions uq
ON q.id = uq.question_id AND uq.user_id = 4
WHERE uq.user_id IS NULL;
I was assuming that I could simply rewrite this into DQL as the following query:
SELECT q FROM MyBundle:Question q
LEFT JOIN q.usersAnswered uq WITH uq.id = 4
WHERE uq.id IS NULL
When I call $query->getSql() I get the following output:
SELECT * FROM mybundle_questions g0_
LEFT JOIN users_questions u2_
ON g0_.id = u2_.question_id
LEFT JOIN mybundle_users g1_
ON g1_.id = u2_.user_id AND (g1_.id = 4)
WHERE g1_.id IS NULL
Which to me looks fine given my very basic knowledge on Doctrine and queries in general. However, this fetches and returns ALL the questions which are in the table and not only the ones which this users hasn't answered yet.
Did I make a mistake somewhere? Or is there any other/easier way to fetch these unanswered questions? I feel like I'm reinventing the wheel here.
Been stuck on this for days and every attempt that I make in native SQL works fine, but I can't translate it to DQL. Any help would be appreciated.
I've solved my problem with the following query. Looks like it WAS possible to create a subquery after all.
SELECT q FROM MyBundle:Question q
WHERE q.id NOT IN (
SELECT uq.id FROM MyBundle:User u
INNER JOIN u.questionsAnswered uq
WHERE u.id = 4
)
Which Doctrine translates to the following query:
SELECT * FROM myBundle_questions g0_
WHERE g0_.id NOT IN (
SELECT g1_.id FROM myBundle_users g2_
INNER JOIN users_questions u3_
ON g2_.id = u3_.user_id
INNER JOIN myBundle_questions g1_
ON g1_.id = u3_.question_id
WHERE g2_.id = ?
)
For some reason the previous query, although it looked good in my eyes, didn't work. Must have something to do with how Doctrine handles the left join / null situations. However, this query in which I approach the problem from a different angle work perfectly.
EDIT. I missed the one main issue I was having. I want to display all the unique 'device_MAC' rows. So I want this query to output 3 rows (as per the original query). The issue I am having is connecting the data table to the remote_node table via dt_short = rn_short where the maximum timestamp for dt_short in the data table.
I am having trouble running a query on 3 tables (2 have many to many relations).
What I am trying to do:
Get each distinct rn_IEEE from the remotenodes table with the maximum timestamp (in the example this will get 3 rows with 3 distinct short addresses rn_short)
Join with the devicenames table on device_IEEE
Get each distinct dt_short from the data table with the maximum timestamp
Join dt_short with rn_short from the query above
Now the problem I am running into is that I can do the queries for the above individually, I have even gotten the first 3 of them together into a query but I cannot seem to properly join the last bit of data to get the result that I want.
I have been going in circles trying to solve this. Here is a link to SQL Fiddle which contains all the test data and the query as far as I got it, it does what i want for the first line but from table 'data' after the first line is NULL:
See this SQL fiddle
After going through your requirements and the data, it looks like you just need to change your query to include an INNER JOIN on the data table instead of a LEFT JOIN
See SQL Fiddle with Demo
select rn.*, dn.*, d.*
from remotenodes rn
inner join devicenames dn
on rn.rn_IEEE = dn.device_IEEE
and rn.rn_timestamp = (SELECT MAX(rn_timestamp) FROM remotenodes
WHERE rn.rn_IEEE = rn_IEEE
GROUP BY rn_IEEE)
inner join data d
on rn.rn_short = d.dt_short
AND d.dt_timestamp = (SELECT MAX(d2.dt_timestamp) AS ts
FROM data d2
WHERE d.dt_short = d2.dt_short
GROUP BY d2.dt_short)
what you have done the query in your SQL fiddle is right.Instead of using left join use inner join so that it will give you the first row
cheers.
Thanks for all your answers everyone. I managed to solve the problem by using views.
It's not the most efficient way but I think it will do for now.
Here is the SQL Fiddle link:
http://sqlfiddle.com/#!2/4076e/8
Try this query, for me its returning one row:
SELECT rn_short, rn_IEEE, device_name
FROM
(SELECT DISTINCTROW dt_short FROM (SELECT * FROM `data` ORDER BY `dt_timestamp` DESC) as data ) as a
JOIN
(SELECT rn_IEEE, rn_short, device_name FROM devicenames dn JOIN (SELECT DISTINCTROW rn_IEEE, rn_short FROM (SELECT * FROM `remotenodes` ORDER BY `rn_timestamp` DESC) as remotenodes GROUP BY rn_IEEE) as rn ON dn.device_IEEE = rn.rn_IEEE) as b
ON a.dt_short = b.rn_short